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Seismic design and assessment of
                        Seismic design and assessment of
                           Masonry Structures
                           Masonry Structures

                           Lesson 9, continued
                                           October 2004




                                              Masonry Structures, lesson 9 part 2 slide 1




 Limitations of the storey mechanism approach

To perform a separate analysis for each storey, it is necessary to make assumptions on the
boundary conditions of the piers, i.e. on their rotational restraints: fixed-fixed, or fixed-
free, or other.
These assumptions are strongly affected by the strength and stiffness of the coupling
horizontal structural elements: plain unreinforced masonry spandrel beams, or r.c. slabs, or
r.c. ring beams, which may or may not crack or fail as horizontal loads increase.
The state of stress of these elements cannot be determined accurately on the basis of a
separate analysis for each storey, but only from a global analysis of the whole multi-storey
structure. In principle, only by knowing how much the coupling element are stressed can
the engineer judge if cracking or failure can be expected, and, as a consequence, what kind
of boundary conditions can be assumed for the piers.
A variation in the axial force of the piers may take place under the overturning effect of the
horizontal loads, affecting the flexural and shear strength of the individual piers. This effect
may not be of relevance in low-rise squat buildings, but it can be in a more general context.
Again, an evaluation of this effect can be made only very approximately with a separate
storey-by-storey analysis.


                                              Masonry Structures, lesson 9 part 2 slide 2
Limitations of the storey mechanism approach

The storey-mechanism approach must therefore always be applied with a clear
understanding of its meaning and limitations, otherwise it can lead, in some cases, to
unrealistic and unconservative results.
The engineer can improve to some extent the results with a proper choice of boundary
conditions (end rotation) for the piers, but still some structural configurations of multi-
storey walls or buildings cannot be analysed properly with such method.




                                           Masonry Structures, lesson 9 part 2 slide 3




URM MASONRY
SPANDREL
BEAMS UNDER                                                                 at first cracking
SEISMIC
ACTION




Crack patterns from
an experimental
cyclic test on a full-                                                      at ultimate
scale masonry
building prototype
(University of Pavia,
1994)




                                           Masonry Structures, lesson 9 part 2 slide 4
Strength of urm spandrel beams

Very little information is available on the behaviour of urm spandrel beams
subjected to cyclic shear. A proposal for strength evaluation which could be
suitable for applications is as follows.
Unreinforced masonry spandrels can be considered as structurally effective
only if they are regularly bonded to the adjoining walls and resting on a floor
tie beam or on an effective lintel.
The verification of unreinforced masonry coupling beams, in presence of a
known axial horizontal force, is carried out in analogy of the vertical walls.
If the axial load is not known from the model (for instance, when the analysis
is carried out with the hypothesis of in-plane infinitely rigid floors), but
horizontal elements with tensile strength (such as steel ties or r.c. ring beams)
are present in proximity of the masonry beam, the resisting values may be
assumed not greater than the following values associated to the shear and
flexural failure mechanisms.

                                       Masonry Structures, lesson 9 part 2 slide 5




Strength of urm spandrel beams

 The shear strength Vt of an unreinforced masonry coupling
 beam, connected to a r.c. ring beam or a lintel and effectively
 bonded at the ends, may be computed in a simplified way as
 follows:

          Vt = h t fv0
 where: h is the section height of the masonry beam;
          t is the width (thickness) of the beam
          fv0 = is the shear strength in absence of compression.




                                       Masonry Structures, lesson 9 part 2 slide 6
Strength of urm spandrel beams
      The maximum resisting moment, associated to the flexural mechanism, always in
      presence of horizontal elements resisting to tension actions in order to balance the
      horizontal compression in masonry beams, may be evaluated as follows:
                                             [
                             M u = H p h / 2 1 − H p /(0.85 f hu ht )   ]
      where: Hp is the minimum between the tension strength of the element in tension
      placed horizontally and the value 0.4fhuht
      fhu= is the compression strength of masonry in the horizontal direction (in the plane of
      the wall).
      The shear strength, associated to this mechanism, may be computed as:
              V p = 2M u / l
      where l is the clear span of the masonry beam.
      The value of shear strength for the unreinforced masonry beam element shall be
      assumed as the minimum between Vt and Vp.



                                                  Masonry Structures, lesson 9 part 2 slide 7




   Non linear static modelling: beyond the storey mechanism approach

                     “Storey mechanism”                    Refined finite
                                                             element
                              Ok up to 2
                           (3?) storeys




                                                                               Gambarotta & Lagomarsino, Papa
                                 Macro-element modelling                           & Nappi., Lourenço,…
Tomaževič, Braga & Dolce
                                                             fascia




                                                                             maschio




                                                                            nodo




MAS3D (Braga,          PEFV (D’Asdia &           SAM (Magenes, Della                   TREMURI (Lagomarsino,
Liberatore, Spera)           Viskovic)            Fontana, Bolognini)                      Penna & Galasco)

                                                  Masonry Structures, lesson 9 part 2 slide 8
Requirements for non linear models
•   Low or moderate computational burden to allow the modeling of whole
    buildings:
     • discretization of the structure with macro-elements: the elements have
        dimensions comparable to the inter-storey height or with the size of openings
        (doors, windows), to reduce the number of degrees of freedom of the model.

•   Reliability of results:
     • all the fundamental failure mechanisms should be accounted for with suitable
       failure criteria;
     • the model should give a good estimate of the overall deformational behaviour
       under horizontal loads.




                                          Masonry Structures, lesson 9 part 2 slide 9




Overview of some macroelement models for urm




    EQUIVALENT TRUSS
    APPROACH
    (Pagano et al., 1984-1990)




                                          Masonry Structures, lesson 9 part 2 slide 10
Overview of some macroelement models for urm




   MULTI-FAN MODEL, MAS3D (Braga,
   Liberatore, Spera, 1990-2000)
   No-tension stress field simulated as a set of
   “radial” stress fields for which an
   analytical formulation in closed form exists.


                                          Masonry Structures, lesson 9 part 2 slide 11




 Overview of some macroelement models for urm




 Pier or spandrel elem.




  “Joint” element

PEFV (D’Asdia & Viskovic 1990-today)
Linear elastic finite elements with variable
(adaptive) geometry.                   Masonry Structures, lesson 9 part 2 slide 12
Overview of some macroelement models for urm

TREMURI
(Lagomarsino, Penna,
Galasco 1997- today)


 Beam-columns-type
 elements with
 internal degrees of
 freedom and
 coupling of
 rotation/axial
 displacement to
 simulate rocking.
 Allows dynamic
 analysis also.

                                              Masonry Structures, lesson 9 part 2 slide 13




 Overview of some macroelement models for urm
 SAM (Magenes, Della Fontana, Bolognini 1998- today)
 Equivalent 3–d frame model
 •Simplified strength criteria for all elements, including r.c. ring beams, easily adaptable
 to code-like formulations.

 •Simplified multi-linear constitutive rules are used (extension of concepts already
 present in early storey-mechanism formulations)

 •Flexural (“rocking”) failure:a plastic hinge is introduced at the end of the effective
 length where Mu is attained
 •Shear failure: plastic shear deformation γ occurs when Vu is attained

 •Suitable for both urm and reinforced masonry.

 •Crude idealization but effective results especially for prediction of behaviour at
 ultimate

                                              Masonry Structures, lesson 9 part 2 slide 14
Nonlinear equivalent frame
                                       rigid          i
                                       offset
                                                                 H1                                                       θ = chord rotation
                                                     i'
                                                                                                                          ϕ = flexural deform.

                                     effective
                                                                                                                          γ = shear deformation
                                      length                 Heff



                                                     j'
                                        rigid                    H2
                                        offset
                                                     j
                                                                                                                     V
                                                     V
                                                                                                                                 Spandrel
Shear force-                                                                  Pier element                                        element
                                                                                                                     V
shear                                                V                                                                u
                                                      u
deformation
behaviour in
the case of                                                                                                        αV
                                                                                                                      u
shear failure
mechanism                                                                                                                                        γ
                                                                                                 γ                              γ       γ
                                                                                                                                 1       2
                                                                                 γ = θu− ϕ

                                                                                               Masonry Structures, lesson 9 part 2 slide 15




Nonlinear equivalent frame

                        80

                        70                                                     F.E.M.
                                                                               SAM (w. brittle spandrels)
Total base shear (kN)




                        60

                        50

                        40

                        30

                        20

                        10

                        0

                             0.000   0.005   0.010       0.015        0.020   0.025    0.030   0.035   0.040

                                        Total displacement at 3rd floor (m)


URM wall with weak spandrels:                                                         Damage pattern predicted by
No storey mechanism                                                                   refined nonlinear f.e.m. analysis




                                                                                               Masonry Structures, lesson 9 part 2 slide 16
Nonlinear equivalent frame

Comparison with experiments:
full scale, two-storey, brick
masonry building, subjected to
quasi static cyclic loading
(University of Pavia, 1994-95)


                  150
                                                                                                                                          160
                                Wall D - Door wall
                  100                                                                                                                     140

                                                                                                                                          120




                                                                                                                        Base shear (kN)
Base shear (kN)




                   50
                                                                                                                                          100
                     0                                                                                                                     80
                                                                                                                                                                                Exp. 1st cycle envelope
                   -50                                                                                                                     60                                   Exp. 2nd cycle envelope
                                                                                                                                                                                Exp. 3rd cycle envelope
                                                                                                                                           40                                   SAM pushover analysis
                  -100
                                                                                                                                           20
                  -150                                                                                                                      0
                           -25      -20   -15   -10    -5          0          5      10   15     20      25                                     0             5          10            15       20        25
                                          Equivalent displacement δeq (mm)
                                                                                                                                                         Equivalent displacement δeq (mm)


                                                                                                                     Masonry Structures, lesson 9 part 2 slide 17




                    5-storey urm wall with r.c. ring beams

                                 1.22



                                 2.25



                                 1.45



                                 2.25



                                 1.45



             19.12
                                 2.25



                                 1.45



                                 2.25




                                 1.63




                                 2.25


                         0.64

                                                3.70        1.05       1.74       1.05    2.73    1.05        2.03       2.56                   2.03   1.05       2.73   1.05   1.74   1.05    3.70


                                                                                                                        29.26



                                                                                                                     Masonry Structures, lesson 9 part 2 slide 18
5-storey urm wall with r.c. ring beams: equivalent frame model




                                                               Masonry Structures, lesson 9 part 2 slide 19




5-storey urm wall: nonliner equivalent frame pushover analysis
                                                                       Global angular deformation (%)
                                                               0.000   0.078     0.156       0.234      0.312   0.390    0.468
                                                        1400                                                                  0.42
 Pushover analysis with
                                                                                                            Analysis A
 first-mode (linear) force                              1200                                                                 0.36
 distribution.
                                                                                                                                     Base shear coefficient
                                Total base shear (kN)




                                                        1000                                                                 0.30
                                                                                                            Analysis B
 R.c. beams: elasto-plastic
                                                         800                                                                 0.24
 beam elements (w. flexural                                                                                 Analysis C
 hinging).                                               600                                                                 0.18
                                                                                                            Analysis G

 The analyses from A to G                                400
                                                                                         No r.c. ring
                                                                                                                             0.12

 show the effect of                                                                        beams
                                                         200                                                                 0.06
 decreasing strength and
 stiffness of the r.c. beams                               0                                                                 0.00
 on the response of the wall.                                  0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09
                                                                               Roof displacement (m)


                                                               Masonry Structures, lesson 9 part 2 slide 20
5-storey urm wall: nonliner equivalent frame pushover analysis

                                                 20                                                                           5th FLOOR
Coupling elements (masonry                                               soft storey
spandrels and r.c. beams) can
                                                 16                                                                           4th FLOOR
affect not only the strength,
                                                                                                                 global overturning
but also the overall deformed                                                                                    of cantilever walls
shape and collapse mechanism                     12
                                                                                                                              3rd FLOOR




                                   Height (m)
                                                                                                                              2nd FLOOR
                                                             8


                                                                                                                              1st FLOOR
                                                             4
                                                                                                                        Analysis A
                                                                                                                        Analysis C
                                                                                 soft storey                            Analysis G
                                                             0
                                                                 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08
                                                                                Horizontal displacement (m)


                                                                 Masonry Structures, lesson 9 part 2 slide 21




Nonlinear equivalent frame

 Comparison of a 3-d storey –                                1000
                                                                                Forza alla base-Spostamento

 mechanism analysis and a 3-d                                 900
                                                                                                       storey mechanism
 nonlinear frame analysis: two                                                                                                 POR
                                                                                                                               SAM
                                                              800
 storey urm building with rigid
                                                              700
 floor diaphragms and r.c. ring
                                                              600
 beams.                                                                                                                    SAM
                                                Forza [KN]




                                                              500

 The flexural and shear strength                              400

 criteria of masonry walls are                                300

 kept the same for both methods                               200


                                                              100


                                                                 0
                                                                     0                 0.01                      0.02                0.03
                                                                                              Spostame nto [m]




                                                                 Masonry Structures, lesson 9 part 2 slide 22
Use of nonlinear static analysis in seismic design/assessment

The non linear static analysis is based on the application of gravity loads and of a
horizontal force system that, keeping constant the relative ratio between the acting
horizontal forces, is scaled in order to monotonically increase the horizontal displacement
of a control point on the structure (for example, the centre of the mass of the roof), up to
the achievement of the ultimate conditions.

A suitable distribution of lateral loads should be applied to the building. At least two
different distributions must be applied:

-a “modal” pattern, based on lateral forces that are proportional to mass multiplied by the
displacement associated to the first mode shape
- a “uniform” pattern, based on lateral forces that are proportional to mass regardless of
elevation (uniform response acceleration).

Lateral loads shall be applied at the location of the masses in the model, taking into
account accidental eccentricity.



                                            Masonry Structures, lesson 9 part 2 slide 23




Use of nonlinear static analysis in seismic design/assessment

The relation between base shear force and the control displacement (the “capacity
curve”) should be determined by pushover analysis for values of the control
displacement ranging between zero and a sufficiently large value, which must exceed by
a suitable margin the displacement demand which will be estimated under the design
earthquake (target displacement) .

The target displacement is calculated as the seismic demand derived from the design
response spectrum by converting the capacity curve into an idealized force-displacement
curve of an equivalent single-degree-of-freedom system.

For the evaluation of the displacement demand of the equivalent s.d.o.f. system,
different procedures can be followed, depending on:
• how the seismic input is represented (acceleration spectra, displacement spectra,
composite A-D spectra);
• how the inelastic and hysteretic behaviour of the structure is accounted for (equivalent
viscous damping, ductility demand, energy dissipation demand).



                                            Masonry Structures, lesson 9 part 2 slide 24
Use of nonlinear static analysis in seismic design/assessment

 An example of procedure (e.g. as adopted by EC8 and Italian code):

                                                                                              Forza alla base-Spostamento
                                                                         800
                                                                                                                                            T ET T O
                                                                         705
              Step 1: carry out                                          700

              the pushover                                               600                         DLS
              analysis with the                                          564                                                              ULS

                                                      Base shear (kN)
              chosen force                                               500

                                                            Forza [KN]
              distribution. Plot                                         400

              capacity curve
                                                                         300
              and determine the
              performance                                                200

              limit states of
                                                                         100
              interest
                                                                          0
                                                                               0                             0.01                0.0146                0.02
                                                                                                        Spostamento [m]
                                                                                               Roof displacement (m)

                                                                                    Masonry Structures, lesson 9 part 2 slide 25




 Use of nonlinear static analysis in seismic design/assessment


                                                                                                                          Γ = ∑m iΦ 2i
Φvibration of the structure,mass displacementdirection, normalized
 array that represents the
                            in the considered
                                              in the first mode of
                                                                                                                               mΦ
         to the unit value of the relative component of the control point.
                                                                                                                              ∑ i i
                    2000       Fb
                                                                                                                                 Fb
                    1800
                                                                                                                          F* =
                    1600                                                                                                         Γ
  Base shear [kN]




                    1400
                    1200                   Step 2: determine an
                    1000                   equivalent bilinear
                    800
                    600
                                           s.d.o.f. system
                    400
                    200                                                                  dc
                      0
                                                                                                                                                          dc
                           0          5     10      15                         20   25          30                                              d* =
                                           Roof displacement [cm]                                                                                         Γ
                                    N                                               m*
                       m* = ∑ mi Φ i                             T * = 2π
                                    i =1                                            k*

                                                                                    Masonry Structures, lesson 9 part 2 slide 26
Use of nonlinear static analysis in seismic design/assessment


                                                    Forza alla base-Spostamento
                            900


                            800
                                                                                                          Capacity
                   F*max                                                                                   curve
                            700
                            F*y
                            600
       0.8F*max
       0.7F*max
                            500                            Sistema equivalente SDOF
                                                           TETTO
               Forza [KN]




                                                     Equivalent
        Base shear (kN)




                            400                            Bilineare
                                                      bilinear
                                                       SDOF
                            300


                            200


                            100


                             0
                                  0   d*y                                  0.01        d*max                           0.02
                                                                          Displacement
                                                                       Spostamento [m]       (m)




                                                                          Masonry Structures, lesson 9 part 2 slide 27




Use of nonlinear static analysis in seismic design/assessment
                                                                                                         Elastic displacement spectrum
 Step 3: using the elastic
 response spectrum, calculate
                                                                                                     ∗
 the displacement demand on                                      if T*≥TC                          d max = d e , max = S De ( T *)
 the sdof system

                                                                 if T*<TC
                                                                                             d e , max ⎡               TC ⎤
                                                                                                       ⎢1 + (q * − 1 ) T * ⎥ ≥ d e , max
                                                                            ∗
                                                                          d max =
                                                                                               q* ⎣                        ⎦

                                                                                                                              elastic acceleration
                                                                                      m* S e (T * )                           spectrum
                                                                                  q =   *

                                                         d* =
                                                                  dc                     Fy*
                                              ∗
                                            d max                 Γ
                                                                                      N                                           m*
                                                                           m* = ∑ mi Φ i                             T * = 2π
                                                                                      i =1
                                                                                                                                  k*

                                                                          Masonry Structures, lesson 9 part 2 slide 28
Use of nonlinear static analysis in seismic design/assessment

 Step 4: convert the displacement demand on the
 equivalent sdof into the control displacement
 and find target point on capacity curve and                                    Γd max = d c ,max
                                                                                   *

 compare with displacement capacity.

                                                                2000
                                                                                                Stato Limite DS
                                                                1800
                                                                1600




                                        Taglio alla base [kN]
                                                                1400
                                                                1200
                                                                1000
                                                                 800
                                                                 600
                                                                 400
                   ∗                                             200
                 d max                                                                  d c , max
                                                                   0
                                                                       0   5      10       15        20     25    30
                                                                               Spostamento copertura [cm]




                                      Masonry Structures, lesson 9 part 2 slide 29




Use of nonlinear static analysis in seismic design/assessment

                           Available on ftp site:
            Relevant chapters of new Italian seismic code
            (English translation available! Thanks Paolo)
                   Relevant chapters of FEMA 356
                         Eurocode 8 (see Annex B)




                                      Masonry Structures, lesson 9 part 2 slide 30
When and how to use storey-mechanism method

Eurocode 8: “For low-rise masonry buildings, in which structural wall
behaviour is dominated by shear, each storey may be analyzed
independently. Such requirements are deemed to be satisfied if the number of
storey is 3 or less and if the average aspect ratio of structural walls is less
than 1.0.
….
New Italian seismic code: “For buildings with number of storeys greater
than two, the structural model should take into account the effects due to the
variation of the vertical forces due to the seismic action and should guarantee
the local and global equilibrium. “




                                           Masonry Structures, lesson 9 part 2 slide 31




Earlier use of storey-mechanism method (Tomaževič)


                                                       du Φu
                                                µu =     =              Ultimate ductility
                                                       de Φe


                                                          q2 +1        q behaviour factor
                                                   µu ≥
                                                            2          (force reduction factor),
                                                                       specified by code (e.g.
                                                                       1.5-2.0 for urm)


            Φ = d/h storey drift

                                                                                          a S ⋅ β0
                      H du , j ≥ Vdesign , j = υ j ⋅ Wtot ⋅ S d (T ; q ) = k j ⋅ Wtot ⋅
                                                                                          g q


                                           Masonry Structures, lesson 9 part 2 slide 32
Use of storey-mechanism method with present EC8 procedure

•Evaluate elastic period of building T1 , e.g. using approximate formulae.

•Estimate elastic base shear from elastic acceleration spectrum:

  Fel,base = Se(T1) Wtot /g = Se(T1) Mtot

•Evaluate ratio between interstorey shear Vj of the storey j being considered and the
total base shear:                             N
              υ j = V j / Fbase             Vj =   ∑F
                                                   i= j
                                                          i

where Fi is the seismic force at the i-th floor.

•The equivalent sdof is defined by putting F* = Vj and d*= interstorey displacement

 •Evaluate q* = υj Fel,base /F*y

•Calculate d*max= d*y [1+(q*-1)Tc/T1] (not greater than q d*y ) and check d*max≤ du


                                               Masonry Structures, lesson 9 part 2 slide 33

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Lesson9 2nd Part

  • 1. Seismic design and assessment of Seismic design and assessment of Masonry Structures Masonry Structures Lesson 9, continued October 2004 Masonry Structures, lesson 9 part 2 slide 1 Limitations of the storey mechanism approach To perform a separate analysis for each storey, it is necessary to make assumptions on the boundary conditions of the piers, i.e. on their rotational restraints: fixed-fixed, or fixed- free, or other. These assumptions are strongly affected by the strength and stiffness of the coupling horizontal structural elements: plain unreinforced masonry spandrel beams, or r.c. slabs, or r.c. ring beams, which may or may not crack or fail as horizontal loads increase. The state of stress of these elements cannot be determined accurately on the basis of a separate analysis for each storey, but only from a global analysis of the whole multi-storey structure. In principle, only by knowing how much the coupling element are stressed can the engineer judge if cracking or failure can be expected, and, as a consequence, what kind of boundary conditions can be assumed for the piers. A variation in the axial force of the piers may take place under the overturning effect of the horizontal loads, affecting the flexural and shear strength of the individual piers. This effect may not be of relevance in low-rise squat buildings, but it can be in a more general context. Again, an evaluation of this effect can be made only very approximately with a separate storey-by-storey analysis. Masonry Structures, lesson 9 part 2 slide 2
  • 2. Limitations of the storey mechanism approach The storey-mechanism approach must therefore always be applied with a clear understanding of its meaning and limitations, otherwise it can lead, in some cases, to unrealistic and unconservative results. The engineer can improve to some extent the results with a proper choice of boundary conditions (end rotation) for the piers, but still some structural configurations of multi- storey walls or buildings cannot be analysed properly with such method. Masonry Structures, lesson 9 part 2 slide 3 URM MASONRY SPANDREL BEAMS UNDER at first cracking SEISMIC ACTION Crack patterns from an experimental cyclic test on a full- at ultimate scale masonry building prototype (University of Pavia, 1994) Masonry Structures, lesson 9 part 2 slide 4
  • 3. Strength of urm spandrel beams Very little information is available on the behaviour of urm spandrel beams subjected to cyclic shear. A proposal for strength evaluation which could be suitable for applications is as follows. Unreinforced masonry spandrels can be considered as structurally effective only if they are regularly bonded to the adjoining walls and resting on a floor tie beam or on an effective lintel. The verification of unreinforced masonry coupling beams, in presence of a known axial horizontal force, is carried out in analogy of the vertical walls. If the axial load is not known from the model (for instance, when the analysis is carried out with the hypothesis of in-plane infinitely rigid floors), but horizontal elements with tensile strength (such as steel ties or r.c. ring beams) are present in proximity of the masonry beam, the resisting values may be assumed not greater than the following values associated to the shear and flexural failure mechanisms. Masonry Structures, lesson 9 part 2 slide 5 Strength of urm spandrel beams The shear strength Vt of an unreinforced masonry coupling beam, connected to a r.c. ring beam or a lintel and effectively bonded at the ends, may be computed in a simplified way as follows: Vt = h t fv0 where: h is the section height of the masonry beam; t is the width (thickness) of the beam fv0 = is the shear strength in absence of compression. Masonry Structures, lesson 9 part 2 slide 6
  • 4. Strength of urm spandrel beams The maximum resisting moment, associated to the flexural mechanism, always in presence of horizontal elements resisting to tension actions in order to balance the horizontal compression in masonry beams, may be evaluated as follows: [ M u = H p h / 2 1 − H p /(0.85 f hu ht ) ] where: Hp is the minimum between the tension strength of the element in tension placed horizontally and the value 0.4fhuht fhu= is the compression strength of masonry in the horizontal direction (in the plane of the wall). The shear strength, associated to this mechanism, may be computed as: V p = 2M u / l where l is the clear span of the masonry beam. The value of shear strength for the unreinforced masonry beam element shall be assumed as the minimum between Vt and Vp. Masonry Structures, lesson 9 part 2 slide 7 Non linear static modelling: beyond the storey mechanism approach “Storey mechanism” Refined finite element Ok up to 2 (3?) storeys Gambarotta & Lagomarsino, Papa Macro-element modelling & Nappi., Lourenço,… Tomaževič, Braga & Dolce fascia maschio nodo MAS3D (Braga, PEFV (D’Asdia & SAM (Magenes, Della TREMURI (Lagomarsino, Liberatore, Spera) Viskovic) Fontana, Bolognini) Penna & Galasco) Masonry Structures, lesson 9 part 2 slide 8
  • 5. Requirements for non linear models • Low or moderate computational burden to allow the modeling of whole buildings: • discretization of the structure with macro-elements: the elements have dimensions comparable to the inter-storey height or with the size of openings (doors, windows), to reduce the number of degrees of freedom of the model. • Reliability of results: • all the fundamental failure mechanisms should be accounted for with suitable failure criteria; • the model should give a good estimate of the overall deformational behaviour under horizontal loads. Masonry Structures, lesson 9 part 2 slide 9 Overview of some macroelement models for urm EQUIVALENT TRUSS APPROACH (Pagano et al., 1984-1990) Masonry Structures, lesson 9 part 2 slide 10
  • 6. Overview of some macroelement models for urm MULTI-FAN MODEL, MAS3D (Braga, Liberatore, Spera, 1990-2000) No-tension stress field simulated as a set of “radial” stress fields for which an analytical formulation in closed form exists. Masonry Structures, lesson 9 part 2 slide 11 Overview of some macroelement models for urm Pier or spandrel elem. “Joint” element PEFV (D’Asdia & Viskovic 1990-today) Linear elastic finite elements with variable (adaptive) geometry. Masonry Structures, lesson 9 part 2 slide 12
  • 7. Overview of some macroelement models for urm TREMURI (Lagomarsino, Penna, Galasco 1997- today) Beam-columns-type elements with internal degrees of freedom and coupling of rotation/axial displacement to simulate rocking. Allows dynamic analysis also. Masonry Structures, lesson 9 part 2 slide 13 Overview of some macroelement models for urm SAM (Magenes, Della Fontana, Bolognini 1998- today) Equivalent 3–d frame model •Simplified strength criteria for all elements, including r.c. ring beams, easily adaptable to code-like formulations. •Simplified multi-linear constitutive rules are used (extension of concepts already present in early storey-mechanism formulations) •Flexural (“rocking”) failure:a plastic hinge is introduced at the end of the effective length where Mu is attained •Shear failure: plastic shear deformation γ occurs when Vu is attained •Suitable for both urm and reinforced masonry. •Crude idealization but effective results especially for prediction of behaviour at ultimate Masonry Structures, lesson 9 part 2 slide 14
  • 8. Nonlinear equivalent frame rigid i offset H1 θ = chord rotation i' ϕ = flexural deform. effective γ = shear deformation length Heff j' rigid H2 offset j V V Spandrel Shear force- Pier element element V shear V u u deformation behaviour in the case of αV u shear failure mechanism γ γ γ γ 1 2 γ = θu− ϕ Masonry Structures, lesson 9 part 2 slide 15 Nonlinear equivalent frame 80 70 F.E.M. SAM (w. brittle spandrels) Total base shear (kN) 60 50 40 30 20 10 0 0.000 0.005 0.010 0.015 0.020 0.025 0.030 0.035 0.040 Total displacement at 3rd floor (m) URM wall with weak spandrels: Damage pattern predicted by No storey mechanism refined nonlinear f.e.m. analysis Masonry Structures, lesson 9 part 2 slide 16
  • 9. Nonlinear equivalent frame Comparison with experiments: full scale, two-storey, brick masonry building, subjected to quasi static cyclic loading (University of Pavia, 1994-95) 150 160 Wall D - Door wall 100 140 120 Base shear (kN) Base shear (kN) 50 100 0 80 Exp. 1st cycle envelope -50 60 Exp. 2nd cycle envelope Exp. 3rd cycle envelope 40 SAM pushover analysis -100 20 -150 0 -25 -20 -15 -10 -5 0 5 10 15 20 25 0 5 10 15 20 25 Equivalent displacement δeq (mm) Equivalent displacement δeq (mm) Masonry Structures, lesson 9 part 2 slide 17 5-storey urm wall with r.c. ring beams 1.22 2.25 1.45 2.25 1.45 19.12 2.25 1.45 2.25 1.63 2.25 0.64 3.70 1.05 1.74 1.05 2.73 1.05 2.03 2.56 2.03 1.05 2.73 1.05 1.74 1.05 3.70 29.26 Masonry Structures, lesson 9 part 2 slide 18
  • 10. 5-storey urm wall with r.c. ring beams: equivalent frame model Masonry Structures, lesson 9 part 2 slide 19 5-storey urm wall: nonliner equivalent frame pushover analysis Global angular deformation (%) 0.000 0.078 0.156 0.234 0.312 0.390 0.468 1400 0.42 Pushover analysis with Analysis A first-mode (linear) force 1200 0.36 distribution. Base shear coefficient Total base shear (kN) 1000 0.30 Analysis B R.c. beams: elasto-plastic 800 0.24 beam elements (w. flexural Analysis C hinging). 600 0.18 Analysis G The analyses from A to G 400 No r.c. ring 0.12 show the effect of beams 200 0.06 decreasing strength and stiffness of the r.c. beams 0 0.00 on the response of the wall. 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 Roof displacement (m) Masonry Structures, lesson 9 part 2 slide 20
  • 11. 5-storey urm wall: nonliner equivalent frame pushover analysis 20 5th FLOOR Coupling elements (masonry soft storey spandrels and r.c. beams) can 16 4th FLOOR affect not only the strength, global overturning but also the overall deformed of cantilever walls shape and collapse mechanism 12 3rd FLOOR Height (m) 2nd FLOOR 8 1st FLOOR 4 Analysis A Analysis C soft storey Analysis G 0 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 Horizontal displacement (m) Masonry Structures, lesson 9 part 2 slide 21 Nonlinear equivalent frame Comparison of a 3-d storey – 1000 Forza alla base-Spostamento mechanism analysis and a 3-d 900 storey mechanism nonlinear frame analysis: two POR SAM 800 storey urm building with rigid 700 floor diaphragms and r.c. ring 600 beams. SAM Forza [KN] 500 The flexural and shear strength 400 criteria of masonry walls are 300 kept the same for both methods 200 100 0 0 0.01 0.02 0.03 Spostame nto [m] Masonry Structures, lesson 9 part 2 slide 22
  • 12. Use of nonlinear static analysis in seismic design/assessment The non linear static analysis is based on the application of gravity loads and of a horizontal force system that, keeping constant the relative ratio between the acting horizontal forces, is scaled in order to monotonically increase the horizontal displacement of a control point on the structure (for example, the centre of the mass of the roof), up to the achievement of the ultimate conditions. A suitable distribution of lateral loads should be applied to the building. At least two different distributions must be applied: -a “modal” pattern, based on lateral forces that are proportional to mass multiplied by the displacement associated to the first mode shape - a “uniform” pattern, based on lateral forces that are proportional to mass regardless of elevation (uniform response acceleration). Lateral loads shall be applied at the location of the masses in the model, taking into account accidental eccentricity. Masonry Structures, lesson 9 part 2 slide 23 Use of nonlinear static analysis in seismic design/assessment The relation between base shear force and the control displacement (the “capacity curve”) should be determined by pushover analysis for values of the control displacement ranging between zero and a sufficiently large value, which must exceed by a suitable margin the displacement demand which will be estimated under the design earthquake (target displacement) . The target displacement is calculated as the seismic demand derived from the design response spectrum by converting the capacity curve into an idealized force-displacement curve of an equivalent single-degree-of-freedom system. For the evaluation of the displacement demand of the equivalent s.d.o.f. system, different procedures can be followed, depending on: • how the seismic input is represented (acceleration spectra, displacement spectra, composite A-D spectra); • how the inelastic and hysteretic behaviour of the structure is accounted for (equivalent viscous damping, ductility demand, energy dissipation demand). Masonry Structures, lesson 9 part 2 slide 24
  • 13. Use of nonlinear static analysis in seismic design/assessment An example of procedure (e.g. as adopted by EC8 and Italian code): Forza alla base-Spostamento 800 T ET T O 705 Step 1: carry out 700 the pushover 600 DLS analysis with the 564 ULS Base shear (kN) chosen force 500 Forza [KN] distribution. Plot 400 capacity curve 300 and determine the performance 200 limit states of 100 interest 0 0 0.01 0.0146 0.02 Spostamento [m] Roof displacement (m) Masonry Structures, lesson 9 part 2 slide 25 Use of nonlinear static analysis in seismic design/assessment Γ = ∑m iΦ 2i Φvibration of the structure,mass displacementdirection, normalized array that represents the in the considered in the first mode of mΦ to the unit value of the relative component of the control point. ∑ i i 2000 Fb Fb 1800 F* = 1600 Γ Base shear [kN] 1400 1200 Step 2: determine an 1000 equivalent bilinear 800 600 s.d.o.f. system 400 200 dc 0 dc 0 5 10 15 20 25 30 d* = Roof displacement [cm] Γ N m* m* = ∑ mi Φ i T * = 2π i =1 k* Masonry Structures, lesson 9 part 2 slide 26
  • 14. Use of nonlinear static analysis in seismic design/assessment Forza alla base-Spostamento 900 800 Capacity F*max curve 700 F*y 600 0.8F*max 0.7F*max 500 Sistema equivalente SDOF TETTO Forza [KN] Equivalent Base shear (kN) 400 Bilineare bilinear SDOF 300 200 100 0 0 d*y 0.01 d*max 0.02 Displacement Spostamento [m] (m) Masonry Structures, lesson 9 part 2 slide 27 Use of nonlinear static analysis in seismic design/assessment Elastic displacement spectrum Step 3: using the elastic response spectrum, calculate ∗ the displacement demand on if T*≥TC d max = d e , max = S De ( T *) the sdof system if T*<TC d e , max ⎡ TC ⎤ ⎢1 + (q * − 1 ) T * ⎥ ≥ d e , max ∗ d max = q* ⎣ ⎦ elastic acceleration m* S e (T * ) spectrum q = * d* = dc Fy* ∗ d max Γ N m* m* = ∑ mi Φ i T * = 2π i =1 k* Masonry Structures, lesson 9 part 2 slide 28
  • 15. Use of nonlinear static analysis in seismic design/assessment Step 4: convert the displacement demand on the equivalent sdof into the control displacement and find target point on capacity curve and Γd max = d c ,max * compare with displacement capacity. 2000 Stato Limite DS 1800 1600 Taglio alla base [kN] 1400 1200 1000 800 600 400 ∗ 200 d max d c , max 0 0 5 10 15 20 25 30 Spostamento copertura [cm] Masonry Structures, lesson 9 part 2 slide 29 Use of nonlinear static analysis in seismic design/assessment Available on ftp site: Relevant chapters of new Italian seismic code (English translation available! Thanks Paolo) Relevant chapters of FEMA 356 Eurocode 8 (see Annex B) Masonry Structures, lesson 9 part 2 slide 30
  • 16. When and how to use storey-mechanism method Eurocode 8: “For low-rise masonry buildings, in which structural wall behaviour is dominated by shear, each storey may be analyzed independently. Such requirements are deemed to be satisfied if the number of storey is 3 or less and if the average aspect ratio of structural walls is less than 1.0. …. New Italian seismic code: “For buildings with number of storeys greater than two, the structural model should take into account the effects due to the variation of the vertical forces due to the seismic action and should guarantee the local and global equilibrium. “ Masonry Structures, lesson 9 part 2 slide 31 Earlier use of storey-mechanism method (Tomaževič) du Φu µu = = Ultimate ductility de Φe q2 +1 q behaviour factor µu ≥ 2 (force reduction factor), specified by code (e.g. 1.5-2.0 for urm) Φ = d/h storey drift a S ⋅ β0 H du , j ≥ Vdesign , j = υ j ⋅ Wtot ⋅ S d (T ; q ) = k j ⋅ Wtot ⋅ g q Masonry Structures, lesson 9 part 2 slide 32
  • 17. Use of storey-mechanism method with present EC8 procedure •Evaluate elastic period of building T1 , e.g. using approximate formulae. •Estimate elastic base shear from elastic acceleration spectrum: Fel,base = Se(T1) Wtot /g = Se(T1) Mtot •Evaluate ratio between interstorey shear Vj of the storey j being considered and the total base shear: N υ j = V j / Fbase Vj = ∑F i= j i where Fi is the seismic force at the i-th floor. •The equivalent sdof is defined by putting F* = Vj and d*= interstorey displacement •Evaluate q* = υj Fel,base /F*y •Calculate d*max= d*y [1+(q*-1)Tc/T1] (not greater than q d*y ) and check d*max≤ du Masonry Structures, lesson 9 part 2 slide 33