1. Lesson 6
Finding Total Displacement and
Average Velocity from
Velocity and Time
Done by Example
2. Example
A canoeist paddles 2.0 m/s [E] for 15 minutes.A canoeist paddles 2.0 m/s [E] for 15 minutes.
She then paddles 3.0 m/s [N] for 20 minutes.She then paddles 3.0 m/s [N] for 20 minutes.
Determine:Determine:
(a) Total displacement(a) Total displacement
(b) Average velocity(b) Average velocity
Solution
Δd1 = v1 Δt = 2.0 m/s [E] x (15 min.x 60s/min.)
= 1.8 km [E]
Δd2 = v2 Δt = 3.0 m/s [N] x (20 min.x 60s/min.)
= 3.6 km [N]
The next step is to draw a non-scaled vector
diagram, since the two displacement vectors
are not linear.
3. The length ofThe length of Δd1 should be
half of the length of Δd2. And
this is what has been drawn
(do by eye no need to
measure).
If we do the calc. we find
that |ΔdT| = 4.0 km. The
angle is calc. using Tan-1
=(3.6/1.8) = 630
So, ΔdT = 4.0km [E630
N]
We calc |vav|=|ΔdT |/ ΔtT, get
{4.0km/(35min/(60min/hr))}
= 6.9km/h [E630
N]
N
W E
d 1 = 1 .8 k m
d2=3.6km
d
T=
1.82
+3.62
km
4. Practice Questions
From Nelson TB
Page 65 #9,Page 65 #9,
Page 94 #49, 53Page 94 #49, 53
From McGraw-Hill TB
1.1. A hiker walks at 5.0 km/h [N35E] for 48.0 min.A hiker walks at 5.0 km/h [N35E] for 48.0 min.
He then heads west at 4.5 km/h for 40.0 min.He then heads west at 4.5 km/h for 40.0 min.
Finally he heads 6.0 km [N30W] for an additionalFinally he heads 6.0 km [N30W] for an additional
1.50 hours and arrives at his campsite.1.50 hours and arrives at his campsite.
Determine: a.) Total displacement – a scaledDetermine: a.) Total displacement – a scaled
diagram is required. b.) Average velocity for thediagram is required. b.) Average velocity for the
entire hike.entire hike.
Ans. 9.2 km [N24W] , 3.1 km/h [N24W]
5. Practice Questions
2. A runner runs 15.0 km [N35E] and then
7.5 km [N25W]. Entire trip takes 2.0 h.
Determine: a.) Total displacement b.)
Average velocity
Ans. 20.0km [N16E], 9.9 km/h [N16E]
6. Practice Questions
2. A runner runs 15.0 km [N35E] and then
7.5 km [N25W]. Entire trip takes 2.0 h.
Determine: a.) Total displacement b.)
Average velocity
Ans. 20.0km [N16E], 9.9 km/h [N16E]