5. (2) 0 < x < a 时 V(x)
xO a
0)( =xV
ψ
ψ
E
xm
=− 2
22
d
d
2
h
ψ
ψ
22
2
2
d
d
h
mE
x
−=
02
2
2
=+ ψ
ψ
k
dx
d
2
2 2
h
mE
k =令
)sin()( δψ += kxAx
0)( =aψ0)0( =ψ波函数连续
退出返回
6. )sin()( δψ += kxAx V(x)
xO a
0=δ0)0( =ψ
kxAx sin)( =ψ
0)( =aψ 0sin =kaA
πnka =0sin =ka
)21( L,,n =
a
n
k
π
=
2
2 2
h
mE
k = 22
22
2
h
mE
a
n
=
π
退出返回
10. 2. 势垒贯穿
)()()(
d
d
2 2
22
xExxV
xm
ψψ =⎥
⎦
⎤
⎢
⎣
⎡
+−
h
1) 梯形势
1 2
O x
U
0U
=)(xV
0
00
0 ≥
<
xU
x
)()(
d
d
2
112
22
xEx
xm
ψψ =−
h
0<x
2
2
1
2
h
mE
k =0)()(
d
d
1
2
112
2
=+ xkx
x
ψψ
xikBexikAex 11
1
)( −+=ψ
退出返回
12. 1 2
O x
U
0U
xikBexikAex 11
1
)( −+=ψ
xkCex 2
2
)( −=ψ
0
2
0
1
d
d
d
d
==
=
xx xx
ψψ
)0()0( 21 ψψ =
C
k
ik
BA
1
2
=−CBA =+
A
kik
ik
C
21
12
−
=A
kik
kik
B
21
21
−
+
=
退出返回