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MEASURE OF CENTRAL
TENDANCY
By Saim waheed and Muqadas Fatima
PARTS
MEASURE OF CENTRAL TENDANCY
MEAN MODE MEDIAN
MEAN
•. The mean is simply the sum of the values
divided by the total number of items in the
set.
Advantages
•It is easy to understand and easy to
calculate.
•It is capable of further mathematical
treatment.
Disadvantages
•mean cannot be obtained if a single
observation is missing or lost.
UNGROUPED DATA
Mean =
Xn
n
Example of Ungrouped Data
• Numbers = 6, 11, 7
• Add the numbers: 6 + 11 + 7 = 24
• Divide by how many numbers (there are 3 numbers): 24 / 3 = 8
The mean is 8
GROUPED DATA
Mean =
𝑓𝑥
n
• To calculate the mean of grouped data, the first step is to determine
the midpoint. (Midpoint formula L.L+U.L/2) These midpoints must
then be multiplied by the frequencies of the corresponding classes.
The sum of the products divided by the total number of values will
be the value of the mean
Example of Grouped Data
Class X (L.L+U.L/2) f fX
1-5 3 3 3x3=9
6-10 8 2 2x8=16
11-15 13 8 8x13=104
16-20 18 7 7x18=126
21-25 23 4 4x23=92
∑f=24 ∑Fx=347
Calculation
= 14.458
X =
∑fX
n
=
347
24
Uses of Mean
•It use for making decisions about wages,
production and purchasing.
• It can also be valuable in day-to-day
operations that involve data
Mode
•The mode is the most frequently occurring
value.
Advantages
Mode is easy to calculate.
Mode can be conveniently located.
Disadvantages
 It is not capable of further mathematical
treatment.
UNGROUPED DATA
The most frequent and repeated numbers or
values is mode in ungrouped data
Example of Ungrouped data
Numbers = 12,13,12,113,12,1,1,3,4.
The Mode is 12
GROUPED DATA
•The maximum frequency is mode in
grouped data.
Formula of Grouped Data
Mode = l +
fm−f1
2fm−f1−f2
× h
• l = lower class boundary of modal class.
• h = class interval of modal class.
• fm = frequency of modal class.
• f1 = frequency of the class preceding modal class.
• f2 = frequency of the class succeeding the modal class
Example of Grouped data.
Class interval Frequency Class boundaries
1-3 2 0.5-3.5
4-6 3 3.5-6.5
7-9 5 6.5-9.5
10-12 4 f1 9.5-12.5
13-15 6 f 12.5-15.5
16-18 2 f2 15.5-18.5
19-21 1 18.5-21.5
Calculation
l=12.5, h=3, f=6, f1=4, f2=2
Mode = l +
fm−f1
2fm−f1−f2
× h
Mode = 12.5 +
6−4
2(6)−4−2
× 3
Mode = 12.5 +
2
12−6
× 3
Mode = 13.5
Uses
•It is used in models of cars or
flavours of soda (beverages
company).
Median
•The median is the value in the middle of a
data set, For a small data set, first you count
the number of data points (n) and arrange
the data points in increasing order.
Advantages
• It is easy to understand and easy to
calculate.
•Can be determined graphically.
Disadvantages
•In case of even number of observations
median cannot be determined exactly.
•It is not capable of further mathematical
treatment.
If Two Numbers or even numbers in the
middle
•In that case we find the middle pair of
numbers, & then find the value that is half
way between them. This is easily done by
adding them together and dividing by 2 .
Example.
3, 13, 7, 5, 21, 23, 23, 40, 23, 14, 12, 56, 23, 29
In order
3, 5, 7, 12, 13, 14, 21, 23, 23, 23, 23, 29, 40, 56
21 + 23 = 44
Then 44 ÷ 2 = 22
Uses
•Median helps the employees to
know the middle point of their
salaries in their careers

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Saim & Muqadas.pptx

  • 1. MEASURE OF CENTRAL TENDANCY By Saim waheed and Muqadas Fatima
  • 2. PARTS MEASURE OF CENTRAL TENDANCY MEAN MODE MEDIAN
  • 3. MEAN •. The mean is simply the sum of the values divided by the total number of items in the set.
  • 4. Advantages •It is easy to understand and easy to calculate. •It is capable of further mathematical treatment.
  • 5. Disadvantages •mean cannot be obtained if a single observation is missing or lost.
  • 7. Example of Ungrouped Data • Numbers = 6, 11, 7 • Add the numbers: 6 + 11 + 7 = 24 • Divide by how many numbers (there are 3 numbers): 24 / 3 = 8 The mean is 8
  • 8. GROUPED DATA Mean = 𝑓𝑥 n • To calculate the mean of grouped data, the first step is to determine the midpoint. (Midpoint formula L.L+U.L/2) These midpoints must then be multiplied by the frequencies of the corresponding classes. The sum of the products divided by the total number of values will be the value of the mean
  • 9. Example of Grouped Data Class X (L.L+U.L/2) f fX 1-5 3 3 3x3=9 6-10 8 2 2x8=16 11-15 13 8 8x13=104 16-20 18 7 7x18=126 21-25 23 4 4x23=92 ∑f=24 ∑Fx=347
  • 11. Uses of Mean •It use for making decisions about wages, production and purchasing. • It can also be valuable in day-to-day operations that involve data
  • 12. Mode •The mode is the most frequently occurring value.
  • 13. Advantages Mode is easy to calculate. Mode can be conveniently located.
  • 14. Disadvantages  It is not capable of further mathematical treatment.
  • 15. UNGROUPED DATA The most frequent and repeated numbers or values is mode in ungrouped data
  • 16. Example of Ungrouped data Numbers = 12,13,12,113,12,1,1,3,4. The Mode is 12
  • 17. GROUPED DATA •The maximum frequency is mode in grouped data.
  • 18. Formula of Grouped Data Mode = l + fm−f1 2fm−f1−f2 × h • l = lower class boundary of modal class. • h = class interval of modal class. • fm = frequency of modal class. • f1 = frequency of the class preceding modal class. • f2 = frequency of the class succeeding the modal class
  • 19. Example of Grouped data. Class interval Frequency Class boundaries 1-3 2 0.5-3.5 4-6 3 3.5-6.5 7-9 5 6.5-9.5 10-12 4 f1 9.5-12.5 13-15 6 f 12.5-15.5 16-18 2 f2 15.5-18.5 19-21 1 18.5-21.5
  • 20. Calculation l=12.5, h=3, f=6, f1=4, f2=2 Mode = l + fm−f1 2fm−f1−f2 × h Mode = 12.5 + 6−4 2(6)−4−2 × 3 Mode = 12.5 + 2 12−6 × 3 Mode = 13.5
  • 21. Uses •It is used in models of cars or flavours of soda (beverages company).
  • 22. Median •The median is the value in the middle of a data set, For a small data set, first you count the number of data points (n) and arrange the data points in increasing order.
  • 23. Advantages • It is easy to understand and easy to calculate. •Can be determined graphically.
  • 24. Disadvantages •In case of even number of observations median cannot be determined exactly. •It is not capable of further mathematical treatment.
  • 25. If Two Numbers or even numbers in the middle •In that case we find the middle pair of numbers, & then find the value that is half way between them. This is easily done by adding them together and dividing by 2 .
  • 26. Example. 3, 13, 7, 5, 21, 23, 23, 40, 23, 14, 12, 56, 23, 29 In order 3, 5, 7, 12, 13, 14, 21, 23, 23, 23, 23, 29, 40, 56 21 + 23 = 44 Then 44 ÷ 2 = 22
  • 27. Uses •Median helps the employees to know the middle point of their salaries in their careers