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Energy and Cost
Objectives:
4.1 Determine the cost of using an
electrical appliance
4.4 Identify the units that define
electric energy, using the
variables associated with
electric
circuits
Energy


Energy:
 the

Wh
en at is
er g
y?

ability to do work
 all appliances need energy to work
 ex.
a remote control needs energy
from batteries to work
 ex.
a light bulb needs electrical
energy to shine bright
Power


Wh
po at is
we
r?

Power:
 the

rate at which energy is produced
 is the product of potential difference
(voltage) & current intensity
Symbols and Units

Symbol =

Symbol =

Units

Units

=

=
E = P•t
Time

Energy
Joules (J)

Seconds (s)

Power
Watts (W)
A stereo has a power rating of 200W &
is used for 1800 seconds. How much
energy is used?
E = P•t
E = (200)•(1800)
E = 360,000 J
360,000 Joules of energy were
used to work the stereo
A video game has a power rating of
175W & is used for 3600 seconds.
How much energy is used?
E = P•t
E = (175)•(3600)
E = 630,000 J
630,000 Joules of energy were
used to work the video game
A hair dryer has a power rating of
425W & is used for 10 minutes. How
much energy is used?
E = P•t
E = (425)•(600)

Time must be in seconds
10 min x 60 = 600
seconds

E = 255,000 J
255,000 Joules of energy were
used to work the hair dryer
P = V •I
Power
Watts (W)

Current
Amps (A)

Potential
Difference
Volts (V)
A toaster requires 120V & 6A to work.
What is its power?
P = V•I
P = (120)•(6)
P = 720 W
The toaster has 720 watts of
power
An appliance requires 240V & 2A to
work. What is its power?
P = V•I
P = (240)•(2)
P = 480 W
The appliance has a power of
480 watts
Tric
ky

Que
s tio
n

An appliance requires 120V & 12A to work.
It is used for 900 seconds.
How much
energy is used?

P = V•I

E = P•t

P = (120)•(12)

E =(1440)•(900)

P = 1440 W

E =1,296,000 J
Tric
ky

Que
s tio
n

An appliance uses 225V & 4A to work. It is
used for 60 minutes. How much energy is
used?

60min x 60

P = V•I

E = P•t

P = (225)•(4)

E =(900)•(3600)

P = 900 W

E =3,240,000 J
Activties


P. 173, Q. 17-20
E = P•t
Energy
(kWh)

Time
Power

Hours

Watts
(kW)

(hr)
KWh Question


How much energy is used if a
1500 W speaker is used for 3
hours?



E = Pt
= 1.5 kW * 3 hr
= 4.5 kWh



Cost
Every time you use an appliance it
costs money……how do you calculate
how much it will cost?
C=RaPt!

(Usually Given)

Must be in
kW

Remember: 1000 watts = 1 kW

Must be in
hours
A 4800 watt television is used for 5
hours. If the cost of electricity is
$0.04kW•h, what would your bill
read? (How much would it cost?)
Cost = rate of electricity x Power x Time

cost = $0.04 × 4.8kW× 5h
cost = $ 0.96

4800 w = 4.8 kW
A 1500 watt hair dryer is used for
30 minutes. Electricity costs
$0.05/kW•h. How much does it cost
to use this hair dryer for the period
indicated?
Cost = rate of electricity x Power x Time

cost = 0.05 × 1.5kW × 0.5 h
1500 w = 1.5 kW

30 min ÷ 60 min = 0.5 hrs

cost=$ 0.0375
A 3.9 kilowatts curling iron is used
for 10 minutes once a day.
Electricity costs $0.05/kW•h. How
much does it cost to use this curling
iron for a week?
Cost = rate of electricity x Power x Time

cost = 0.05 × 3.9 kW × 0.167 h
10 min ÷ 60 min = 0.167 hrs

cost=$ 0.0325

X 7 days

cost=$ 0.23
Cost & Rating Plates


Every electrical appliance has a
rating plate.
Model: VCANN-1977
Serial No:

Look
for
power

240 V

60 Hz

POWER

2005-13
4000 W

Rating plates allow us to calculate
the electrical cost of an appliance.
The rating plate for an electric hair dryer is given
below.
Model: LHOPE-1979

1500 W

200V

40Hz

If the dryer is used for 30 minutes a day & the cost
of electricity is $0.04/kW•h, how much would it cost
to use every day?

Cost = cost of electricity x power x time
Cost =($0.04/kW•h) x (1.5kW) x (0.5h)
Cost =$0.03 or 3 ¢
The rating plate for a television is given below.
Model: CANNHOPE-2005
2500 W

250V

60Hz

If the TV is used for 2 hours a day & the cost of
electricity is $0.05/kW•h, how much would it cost to
use for a 30-day month?

Cost = cost of electricity x power x time
Cost =($0.05/kW•h) x (2.5kW) x (2h)
Cost =$0.25

x 30 days

Cost =$7.50
No power!!
Recall P = VI
P = (200)(6)

P = 1200 W

The rating plate for an electric appliance is given
below.
Model: NOV-05

30Hz

200V

6A

If the appliance is used for 1 hour a day & the cost
of electricity is $0.0475/kW•h, how much would it
cost to use every day?

?

Cost = cost of electricity x power x time
Cost =($0.0475/kW•h) x (1.2kW) x (1h)
Cost =$0.057 or $0.06
No power!!
Recall P = VI
P = (375)(0.2)

P = 75 W

The rating plate for an electric appliance is given
below.
Model: RAF-2005

375V

0.2A

If the appliance is used for 3 hours a day & the cost
of electricity is $0.05/kW•h, how much would it cost
to use for a week?

?

Cost = cost of electricity x power x time
Cost =($0.05/kW•h) x (0.075kW) x (3h)
Cost =$0.01125

x 7 days

Cost =$0.08
The rating plates of four different electric appliances are
used below

A)

860 W

120V

60 HZ

GIN-4445

B)

1400 W

Each appliance is used for 4 hours.
Which of these appliances would be the most
expensive to use?

15 A

140 V
MAC-2453

C)

10 A
125 V
MANDANE-2445

D)

2A

250 V
66 HZ

I8JUL-6712

P=VxI

Since the cost and
time are the same you
must just look
for power…

P = 10 x 125
P = 1250 W
P=VxI
P = 2 x 250
P = 500 W

By comparing Power it
is clear to see that
appliance “C” would
be the most
expensive!
Recalling Units


Joule : a unit of energy




W

Ex.: 100 W light bulb

Volt : energy per unit charge


A

Ex.: 15 ampere breaker

Watt : a unit of power




Ex.: 25 g of candy contains 276 000 J

ampere : a quantity of charges
per time




J

Ex.: AA battery has 1.5 volts

V
Important Units to Remember
It is important to remember the following units for power and time.

Joules

Watts

W•s

kW

kw•h
V•A•s
Electricity uses the following units:
1. Watt
4. Kilowatt-hour
2. Volt
5. Joule
3. Ampere
Which of the above are units of energy?
1 and 3

B) 2 and 4

C) 1 and 5

D) 4 and 5

A)

Energy

Power

Joules

Watts

W•s

kW

kw•h
V•A•s
Which of the following units are not units
of energy?
1. W
2. V•A•s
3. J
4. A
5. kW•h
6. W•s
Energy Power
1, 3, and 4

B) 1 and 4

C) 1, 4, and 6

D) 4 and 5

A)

Joules

Watts

W•s

kW

kw•h
V•A•s
KEY POINTS
-

FORMULAS
E=Pxt
P=VxI
Cost = cost of electricity x P x t

**make sure you have the correct units in these formulas**

- UNITS

Energy

Power

Joules

Watts

W•s

kW

kw•h
V•A•s
Activities




Student Study Guide, Module II-16
& II-17
WORKSHEET # 16

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AST406 Energy & Cost

  • 1. Energy and Cost Objectives: 4.1 Determine the cost of using an electrical appliance 4.4 Identify the units that define electric energy, using the variables associated with electric circuits
  • 2. Energy  Energy:  the Wh en at is er g y? ability to do work  all appliances need energy to work  ex. a remote control needs energy from batteries to work  ex. a light bulb needs electrical energy to shine bright
  • 3. Power  Wh po at is we r? Power:  the rate at which energy is produced  is the product of potential difference (voltage) & current intensity
  • 4. Symbols and Units Symbol = Symbol = Units Units = =
  • 5. E = P•t Time Energy Joules (J) Seconds (s) Power Watts (W)
  • 6. A stereo has a power rating of 200W & is used for 1800 seconds. How much energy is used? E = P•t E = (200)•(1800) E = 360,000 J 360,000 Joules of energy were used to work the stereo
  • 7. A video game has a power rating of 175W & is used for 3600 seconds. How much energy is used? E = P•t E = (175)•(3600) E = 630,000 J 630,000 Joules of energy were used to work the video game
  • 8. A hair dryer has a power rating of 425W & is used for 10 minutes. How much energy is used? E = P•t E = (425)•(600) Time must be in seconds 10 min x 60 = 600 seconds E = 255,000 J 255,000 Joules of energy were used to work the hair dryer
  • 9. P = V •I Power Watts (W) Current Amps (A) Potential Difference Volts (V)
  • 10. A toaster requires 120V & 6A to work. What is its power? P = V•I P = (120)•(6) P = 720 W The toaster has 720 watts of power
  • 11. An appliance requires 240V & 2A to work. What is its power? P = V•I P = (240)•(2) P = 480 W The appliance has a power of 480 watts
  • 12. Tric ky Que s tio n An appliance requires 120V & 12A to work. It is used for 900 seconds. How much energy is used? P = V•I E = P•t P = (120)•(12) E =(1440)•(900) P = 1440 W E =1,296,000 J
  • 13. Tric ky Que s tio n An appliance uses 225V & 4A to work. It is used for 60 minutes. How much energy is used? 60min x 60 P = V•I E = P•t P = (225)•(4) E =(900)•(3600) P = 900 W E =3,240,000 J
  • 16. KWh Question  How much energy is used if a 1500 W speaker is used for 3 hours?  E = Pt = 1.5 kW * 3 hr = 4.5 kWh  
  • 17. Cost Every time you use an appliance it costs money……how do you calculate how much it will cost? C=RaPt! (Usually Given) Must be in kW Remember: 1000 watts = 1 kW Must be in hours
  • 18. A 4800 watt television is used for 5 hours. If the cost of electricity is $0.04kW•h, what would your bill read? (How much would it cost?) Cost = rate of electricity x Power x Time cost = $0.04 × 4.8kW× 5h cost = $ 0.96 4800 w = 4.8 kW
  • 19. A 1500 watt hair dryer is used for 30 minutes. Electricity costs $0.05/kW•h. How much does it cost to use this hair dryer for the period indicated? Cost = rate of electricity x Power x Time cost = 0.05 × 1.5kW × 0.5 h 1500 w = 1.5 kW 30 min ÷ 60 min = 0.5 hrs cost=$ 0.0375
  • 20. A 3.9 kilowatts curling iron is used for 10 minutes once a day. Electricity costs $0.05/kW•h. How much does it cost to use this curling iron for a week? Cost = rate of electricity x Power x Time cost = 0.05 × 3.9 kW × 0.167 h 10 min ÷ 60 min = 0.167 hrs cost=$ 0.0325 X 7 days cost=$ 0.23
  • 21. Cost & Rating Plates  Every electrical appliance has a rating plate. Model: VCANN-1977 Serial No: Look for power 240 V 60 Hz POWER 2005-13 4000 W Rating plates allow us to calculate the electrical cost of an appliance.
  • 22. The rating plate for an electric hair dryer is given below. Model: LHOPE-1979 1500 W 200V 40Hz If the dryer is used for 30 minutes a day & the cost of electricity is $0.04/kW•h, how much would it cost to use every day? Cost = cost of electricity x power x time Cost =($0.04/kW•h) x (1.5kW) x (0.5h) Cost =$0.03 or 3 ¢
  • 23. The rating plate for a television is given below. Model: CANNHOPE-2005 2500 W 250V 60Hz If the TV is used for 2 hours a day & the cost of electricity is $0.05/kW•h, how much would it cost to use for a 30-day month? Cost = cost of electricity x power x time Cost =($0.05/kW•h) x (2.5kW) x (2h) Cost =$0.25 x 30 days Cost =$7.50
  • 24. No power!! Recall P = VI P = (200)(6) P = 1200 W The rating plate for an electric appliance is given below. Model: NOV-05 30Hz 200V 6A If the appliance is used for 1 hour a day & the cost of electricity is $0.0475/kW•h, how much would it cost to use every day? ? Cost = cost of electricity x power x time Cost =($0.0475/kW•h) x (1.2kW) x (1h) Cost =$0.057 or $0.06
  • 25. No power!! Recall P = VI P = (375)(0.2) P = 75 W The rating plate for an electric appliance is given below. Model: RAF-2005 375V 0.2A If the appliance is used for 3 hours a day & the cost of electricity is $0.05/kW•h, how much would it cost to use for a week? ? Cost = cost of electricity x power x time Cost =($0.05/kW•h) x (0.075kW) x (3h) Cost =$0.01125 x 7 days Cost =$0.08
  • 26. The rating plates of four different electric appliances are used below A) 860 W 120V 60 HZ GIN-4445 B) 1400 W Each appliance is used for 4 hours. Which of these appliances would be the most expensive to use? 15 A 140 V MAC-2453 C) 10 A 125 V MANDANE-2445 D) 2A 250 V 66 HZ I8JUL-6712 P=VxI Since the cost and time are the same you must just look for power… P = 10 x 125 P = 1250 W P=VxI P = 2 x 250 P = 500 W By comparing Power it is clear to see that appliance “C” would be the most expensive!
  • 27. Recalling Units  Joule : a unit of energy   W Ex.: 100 W light bulb Volt : energy per unit charge  A Ex.: 15 ampere breaker Watt : a unit of power   Ex.: 25 g of candy contains 276 000 J ampere : a quantity of charges per time   J Ex.: AA battery has 1.5 volts V
  • 28. Important Units to Remember It is important to remember the following units for power and time. Joules Watts W•s kW kw•h V•A•s
  • 29. Electricity uses the following units: 1. Watt 4. Kilowatt-hour 2. Volt 5. Joule 3. Ampere Which of the above are units of energy? 1 and 3 B) 2 and 4 C) 1 and 5 D) 4 and 5 A) Energy Power Joules Watts W•s kW kw•h V•A•s
  • 30. Which of the following units are not units of energy? 1. W 2. V•A•s 3. J 4. A 5. kW•h 6. W•s Energy Power 1, 3, and 4 B) 1 and 4 C) 1, 4, and 6 D) 4 and 5 A) Joules Watts W•s kW kw•h V•A•s
  • 31. KEY POINTS - FORMULAS E=Pxt P=VxI Cost = cost of electricity x P x t **make sure you have the correct units in these formulas** - UNITS Energy Power Joules Watts W•s kW kw•h V•A•s
  • 32. Activities   Student Study Guide, Module II-16 & II-17 WORKSHEET # 16