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OBJECTIVES
Determine the heat capacity of the calorimeter .
And to measure the calefaction of water at a
temperature of 0 C in a calorimeter due to the
action of the ambient temperature as a function of
time.

Determine the electrical conductivity of copper
and aluminium by recording a current-voltage
characteristic line.
Test of the Wiedmann-Franz law.
APPARATUS
 Calorimeter vessel, 500 ml

Immersion heater

 Heat conductivity rod, Cu

Temperature meter digital

 Heat conductivity rod, Al

Temperature probe

 Magnetic stirrer

Surface temperature probe

 Heat conductive paste

Stopwatch

 Gauze bag

Supporting block

 Rheostat

Glass beaker, short, 400 ml

Universal measuring amplifier

Digital multimeter

Connecting cord, 500 mm, blue

Connecting cord, 500 mm, red
THERMAL
CONDUCTIVITY
ESTIMATION
Methods of Heat Transfer
1. Convection
Heat transfer by collective movement of
molecules within fluids.
Mass transfer takes place through diffusion
2. Radiation
The transfer of energy to or from a body by
means of the emission or absorption of
electromagnetic radiation. It doesn't require a
medium.
3. Conduction or diffusion
Thermal conductivity
Thermal conductivity is the property of the

material that indicates its ability to conduct
heat.
The thermal conductivity of this metal
is, like electrical conductivity, determined
largely by the free electrons. Suppose now
that the metal has different temperatures at
its ends. The electrons are moving slightly
faster at the hot end and slower at the cool
end.
The faster electrons transmit energy to the
Thermal conductivity in
metals
Metals are particularly good conductors of

heat because their particles are very
closely packed so the vibrations are
passed on very quickly. They also contain
large numbers of "free electrons".
As the metal is heated, the free electrons

closest
source are heated.

to the heat

This makes them move faster and they

travel
through the
metal, colliding with both atoms and other
electrons.
Heat capacity
The heat capacity of a substance is the amount of heat required to
change its temperature by one degree, and has units of energy
per degree

Q = C dt
where
Q = amount of heat supplied (J)
C = heat capacity of the system or object
(J/K)
dt = temperature rise (K,)
The SI unit for heat capacity is J/K (joule per
kelvin).
Fourier’s law oF heat
conduction

If a temperature difference exists
between different locations of a
body, heat conduction occurs.
The quantity of heat dQ transported with
time dt is a
function of the cross-sectional area A and
the
Temperature gradient dT/dx
perpendicular to the surface.
i.e.,
Can find λ.
As free electrons are mainly responsible for heat conduction in
metals,
They can be considered as a Fermi gas.
They obey Fermi-Dirac distribution.
So no of particles with momentum p,

<np>=1/[z-1eβεp ]+1
z-1 =e- βμ
=1/[eβ(εp-μ) ]+1
μ= εF (1-π2/12(KT/ εF )2 +………)
So at T=0 and also at room temperature,

μ=εF

where εF = Fermi Energy
So at T=0 and room temperature,

<np>= 1/eβ(εp- εF)+1

So electronic energy can’t go beyond Fermi energy so
the electrons which are sitting below Fermi energy are
mainly responsible for conduction.
Experimental set-up for thermal conductivity.
Procedure for Thermal
conductivity estimation
1.Measurement of heat capacity of lower calorimeter

The heat capacity of the calorimeter is
obtained from results of the mixing experiment
and the following formula:

cw = Specific heat capacity of water, mW =
Mass of the water, Tw = Temperature of the hot
water, T = Mixing temperature and T =
procedure

• Weigh the calorimeter at room
temperature.
• Measure and record the room
temperature and the temperature of
the preheated water provided.
• After filling the calorimeter with hot
water, determine the mixing
temperature in the calorimeter.
• Reweigh the calorimeter to
2)Determination of the influence of the surroundings

The addition of heat from the
surroundings is calculated from the
temperature increase
(Temperature (T) rise of the cold
water in the calorimeter)
ΔQ=(cwmw+C)(T-T0)

Where T0 = Temperature at time t =
0 sec.
procedure
Weigh the empty lower calorimeter.
Add ice to the lower calorimeter till the
temperature reaches to 0 C.
Then remove the ice and take the
temperature readings in 1 min interval till
the temperature rises to 10 C.
Reweigh the calorimeter to determine
the mass of the water that it contains.
Sample reading
Calefaction of cold water,
Time(min)

Temperature(0C)

ΔQsurr(J)

1

1

0

2

1.2

294.3

3

1.3

515.2

Slope of the graph gives us
dQsurr/dt
3. Determination of the heat flow through metal rod thermal
conductivity

Equation for the measurement of the
thermal conductivity of
Aluminium/copper rod is given by
Procedure
Weigh the empty, lower calorimeter.
Insert the insulated end of the metal rod into the

upper calorimeter vessel. To improve the heat
transfer, cover the end of the metal rod with
heat-conduction paste.
 When doing so, care must be taken to ensure
that the non-insulated end of the rod remains
completely immersed in the cold water during
the experiment.
Using an immersion heater, bring the water in
Keep the water in the lower calorimeter
at 0 C with the help of ice.
The measurement can be begun when
a constant temperature gradient has
become established between the upper
and lower surface probes.
At the onset of measurement, remove
the ice from the lower calorimeter.
Measure and record the change in the
differential temperature and the
temperature of the water in the lower
calorimeter for a period of 5 minutes.
Sample Calculation
Time(s)

Temp of lower
calorimeter(0C)

ΔT(0C)

ΔQ(J)

0

3

30.57

0

20

3.2

30.48

190.6

40

3.3

30.32

270.8

ΔQ=(cwmw+C)(T-T0)
Slope of the graph gives,
dQtotal/dt.
So (dQ/dt)rod=(dQ/dt)tot-(dQ/dt)surr
Since at steady state,
dT/dx=ΔT/ Δx
We can find λ using Fourier's
conduction formula.
Electrical
Conductivity
Estimation
ohm’s law
Ohm's
law
states
that
the current through a conductor
between
two
points
is
directly proportional to the potential
difference across the two points.
Here the constant for proportionality
is R, is the Resistance.

V=I R
Conductivity
Resistance can also be defined as,
R=ρL / A
Where,
ρ = Resistivity
L=

Length
A = Cross sectional area
The inverse of resistivity is called
Conductivity.
Electrical conductivity
σ = 1/ρ,
Experimental Setup for Electrical conductivity measurement
Measurement of the electrical conductivity.

This is the Circuit diagram for the
measurement of Electrical Conductivity.
Procedure
Perform
the
experimental
set-up
according to the circuit
diagram.
Adjust amplifier and voltage in variable
transformer described as
in the
manual.
Set the rheostat to its maximum value and
slowly decrease
the value during the experiment.
Sample reading
For copper,
Voltage(mV)

Current(mA)

2.3

0.40

3.6

0.45

8.9

0.50

From the graph,
Slope will give us R
So Electrical conductivity,
σ= l / AR;
Relation between
electrical
and
thermal
conductivity???
Wiedemann-Franz law
At a given temperature, the thermal and
electrical conductivities of metals are
proportional, but raising the temperature
increases the thermal conductivity while
decreasing the electrical conductivity. This
behaviour is quantified in the WiedemannFranz Law.
λ / σ = LT or L= λ / σT
where,
Results
Heat Capacity of Calorimeter = 85.23 J/K
Thermal conductivity of Aluminium =315.56 Wm-1K-1
Literature value = 205 Wm-1K-1
Thermal conductivity of Copper =952.94 Wm-1K-1
Literature value = 386 Wm-1K-1
Electrical conductivity of Aluminium =3.651*107 Ω-1m-1
Literature value = 3.75*107 Ω-1m-1
Electrical conductivity of Copper =5.764*107 Ω-1m-1
Literature value = 5.882*107 Ω-1m-1
PRECAUTIONS & Discussion
Care should be taken to ensure the
immersion heater used is not exposed to
air for long.
Always maintain minimum water level
in the upper calorimeter while
maintaining at 100 C.
Handle temperature probes with care.
Bending front portion too much damage
Obtained values for electrical
conductivity are very close to the
literature values. But for thermal
conductivity it is significantly different.
This is because,
It is very difficult to obtain a constant
temperature gradient since we have to
keep both the calorimeter in fixed
temperatures.
Even though after coming to steady
state the system will get disturbed due
Presented by,
Suhas K Ramesh
Rollno-10094
IISER BHOPAL
Links
•http://www.engineeringtoolbox.com/heat-capacity-d_338.html
•http://www.chm.davidson.edu/vce/calorimetry/heatcapacity.html
•http://www.ndted.org/EducationResources/CommunityCollege/Materials/Physical_Chemi
cal/ThermalConductivity.htm
•http://www.eos.ubc.ca/ubcgif/iag/foundations/properties/resistivity.htm

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Thermal and electrical conductivity of metals

  • 1.
  • 2. OBJECTIVES Determine the heat capacity of the calorimeter . And to measure the calefaction of water at a temperature of 0 C in a calorimeter due to the action of the ambient temperature as a function of time. Determine the electrical conductivity of copper and aluminium by recording a current-voltage characteristic line. Test of the Wiedmann-Franz law.
  • 3. APPARATUS  Calorimeter vessel, 500 ml Immersion heater  Heat conductivity rod, Cu Temperature meter digital  Heat conductivity rod, Al Temperature probe  Magnetic stirrer Surface temperature probe  Heat conductive paste Stopwatch  Gauze bag Supporting block  Rheostat Glass beaker, short, 400 ml Universal measuring amplifier Digital multimeter Connecting cord, 500 mm, blue Connecting cord, 500 mm, red
  • 5. Methods of Heat Transfer 1. Convection Heat transfer by collective movement of molecules within fluids. Mass transfer takes place through diffusion 2. Radiation The transfer of energy to or from a body by means of the emission or absorption of electromagnetic radiation. It doesn't require a medium. 3. Conduction or diffusion
  • 6. Thermal conductivity Thermal conductivity is the property of the material that indicates its ability to conduct heat. The thermal conductivity of this metal is, like electrical conductivity, determined largely by the free electrons. Suppose now that the metal has different temperatures at its ends. The electrons are moving slightly faster at the hot end and slower at the cool end. The faster electrons transmit energy to the
  • 7. Thermal conductivity in metals Metals are particularly good conductors of heat because their particles are very closely packed so the vibrations are passed on very quickly. They also contain large numbers of "free electrons". As the metal is heated, the free electrons closest source are heated. to the heat This makes them move faster and they travel through the metal, colliding with both atoms and other electrons.
  • 8. Heat capacity The heat capacity of a substance is the amount of heat required to change its temperature by one degree, and has units of energy per degree Q = C dt where Q = amount of heat supplied (J) C = heat capacity of the system or object (J/K) dt = temperature rise (K,) The SI unit for heat capacity is J/K (joule per kelvin).
  • 9. Fourier’s law oF heat conduction If a temperature difference exists between different locations of a body, heat conduction occurs. The quantity of heat dQ transported with time dt is a function of the cross-sectional area A and the Temperature gradient dT/dx perpendicular to the surface. i.e., Can find λ.
  • 10. As free electrons are mainly responsible for heat conduction in metals, They can be considered as a Fermi gas. They obey Fermi-Dirac distribution. So no of particles with momentum p, <np>=1/[z-1eβεp ]+1 z-1 =e- βμ =1/[eβ(εp-μ) ]+1 μ= εF (1-π2/12(KT/ εF )2 +………) So at T=0 and also at room temperature, μ=εF where εF = Fermi Energy So at T=0 and room temperature, <np>= 1/eβ(εp- εF)+1 So electronic energy can’t go beyond Fermi energy so the electrons which are sitting below Fermi energy are mainly responsible for conduction.
  • 11. Experimental set-up for thermal conductivity.
  • 12. Procedure for Thermal conductivity estimation 1.Measurement of heat capacity of lower calorimeter The heat capacity of the calorimeter is obtained from results of the mixing experiment and the following formula: cw = Specific heat capacity of water, mW = Mass of the water, Tw = Temperature of the hot water, T = Mixing temperature and T =
  • 13. procedure • Weigh the calorimeter at room temperature. • Measure and record the room temperature and the temperature of the preheated water provided. • After filling the calorimeter with hot water, determine the mixing temperature in the calorimeter. • Reweigh the calorimeter to
  • 14. 2)Determination of the influence of the surroundings The addition of heat from the surroundings is calculated from the temperature increase (Temperature (T) rise of the cold water in the calorimeter) ΔQ=(cwmw+C)(T-T0) Where T0 = Temperature at time t = 0 sec.
  • 15. procedure Weigh the empty lower calorimeter. Add ice to the lower calorimeter till the temperature reaches to 0 C. Then remove the ice and take the temperature readings in 1 min interval till the temperature rises to 10 C. Reweigh the calorimeter to determine the mass of the water that it contains.
  • 16. Sample reading Calefaction of cold water, Time(min) Temperature(0C) ΔQsurr(J) 1 1 0 2 1.2 294.3 3 1.3 515.2 Slope of the graph gives us dQsurr/dt
  • 17. 3. Determination of the heat flow through metal rod thermal conductivity Equation for the measurement of the thermal conductivity of Aluminium/copper rod is given by
  • 18. Procedure Weigh the empty, lower calorimeter. Insert the insulated end of the metal rod into the upper calorimeter vessel. To improve the heat transfer, cover the end of the metal rod with heat-conduction paste.  When doing so, care must be taken to ensure that the non-insulated end of the rod remains completely immersed in the cold water during the experiment. Using an immersion heater, bring the water in
  • 19. Keep the water in the lower calorimeter at 0 C with the help of ice. The measurement can be begun when a constant temperature gradient has become established between the upper and lower surface probes. At the onset of measurement, remove the ice from the lower calorimeter. Measure and record the change in the differential temperature and the temperature of the water in the lower calorimeter for a period of 5 minutes.
  • 20. Sample Calculation Time(s) Temp of lower calorimeter(0C) ΔT(0C) ΔQ(J) 0 3 30.57 0 20 3.2 30.48 190.6 40 3.3 30.32 270.8 ΔQ=(cwmw+C)(T-T0) Slope of the graph gives, dQtotal/dt. So (dQ/dt)rod=(dQ/dt)tot-(dQ/dt)surr Since at steady state, dT/dx=ΔT/ Δx We can find λ using Fourier's conduction formula.
  • 22. ohm’s law Ohm's law states that the current through a conductor between two points is directly proportional to the potential difference across the two points. Here the constant for proportionality is R, is the Resistance. V=I R
  • 23. Conductivity Resistance can also be defined as, R=ρL / A Where, ρ = Resistivity L= Length A = Cross sectional area The inverse of resistivity is called Conductivity. Electrical conductivity σ = 1/ρ,
  • 24. Experimental Setup for Electrical conductivity measurement
  • 25. Measurement of the electrical conductivity. This is the Circuit diagram for the measurement of Electrical Conductivity.
  • 26. Procedure Perform the experimental set-up according to the circuit diagram. Adjust amplifier and voltage in variable transformer described as in the manual. Set the rheostat to its maximum value and slowly decrease the value during the experiment.
  • 27. Sample reading For copper, Voltage(mV) Current(mA) 2.3 0.40 3.6 0.45 8.9 0.50 From the graph, Slope will give us R So Electrical conductivity, σ= l / AR;
  • 29. Wiedemann-Franz law At a given temperature, the thermal and electrical conductivities of metals are proportional, but raising the temperature increases the thermal conductivity while decreasing the electrical conductivity. This behaviour is quantified in the WiedemannFranz Law. λ / σ = LT or L= λ / σT where,
  • 30. Results Heat Capacity of Calorimeter = 85.23 J/K Thermal conductivity of Aluminium =315.56 Wm-1K-1 Literature value = 205 Wm-1K-1 Thermal conductivity of Copper =952.94 Wm-1K-1 Literature value = 386 Wm-1K-1 Electrical conductivity of Aluminium =3.651*107 Ω-1m-1 Literature value = 3.75*107 Ω-1m-1 Electrical conductivity of Copper =5.764*107 Ω-1m-1 Literature value = 5.882*107 Ω-1m-1
  • 31. PRECAUTIONS & Discussion Care should be taken to ensure the immersion heater used is not exposed to air for long. Always maintain minimum water level in the upper calorimeter while maintaining at 100 C. Handle temperature probes with care. Bending front portion too much damage
  • 32. Obtained values for electrical conductivity are very close to the literature values. But for thermal conductivity it is significantly different. This is because, It is very difficult to obtain a constant temperature gradient since we have to keep both the calorimeter in fixed temperatures. Even though after coming to steady state the system will get disturbed due
  • 33. Presented by, Suhas K Ramesh Rollno-10094 IISER BHOPAL