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6.1 - Law of Sines
An oblique triangle is a triangle that has no right angles.

                       C

                                   a
                   b

               A                       B
                           c


  To solve an oblique triangle, you need to know the
 measure of at least one side and the measures of any
other two parts of the triangle – two sides, two angles,
              or one angle and one side.


                               2
Four Cases for solving a triangle…




                     3
Four Cases for solving a triangle…
 1. Two angles and any side (AAS or ASA)
                                   A
           A
                 c                     c
                                           B
       C




                               3
Four Cases for solving a triangle…
 1. Two angles and any side (AAS or ASA)
                                        A
           A
                  c                         c
                                                B
       C
 2. Two sides and an angle opposite one of them (SSA)
                                c

                      C     a




                                    3
Four Cases for solving a triangle…
 1. Two angles and any side (AAS or ASA)
                                              A
           A
                  c                               c
                                                      B
       C
 2. Two sides and an angle opposite one of them (SSA)
                                      c

                      C       a
 3. Three sides (SSS)
                                  c
                     b

                          a


                                          3
Four Cases for solving a triangle…
 1. Two angles and any side (AAS or ASA)
                                            A
           A
                  c                             c
                                                    B
       C
 2. Two sides and an angle opposite one of them (SSA)
                                    c

                      C     a
 3. Three sides (SSS)
                                c
                     b
                                                            c
                            a
 4. Two sides and their included angle (SAS)                B
                                                        a
                                        3
Case 1 and Case 2:




                     4
Law of Sines
Case 1 and Case 2:

    If ABC is an oblique triangle with sides a, b, and c, then


            C                   C

                                             a
                 a
    b
                                h
            h                          b
A                    B                                       B
        c                                         c
                                       A
    Acute Triangle                         Obtuse Triangle




                                 4
Example 1 (ASA):
Find the remaining angle and sides of the triangle.




                                 5
Example 1 (ASA):
Find the remaining angle and sides of the triangle.
                                        C
                                            10°

                                                      a = 4.5 ft
                                              b
                                                                60°
                                                                      B
                                                            c
                                                      A




                                 5
Example 1 (ASA):
Find the remaining angle and sides of the triangle.
                                        C
                                             10°
   The third angle in the triangle is
           A = 180° – A – B                          a = 4.5 ft
           = 180° – 10° – 60°                  b
                                                             60°
                 = 110°
                                                110°             B
                                                           c
                                                    A




                                   5
Example 1 (ASA):
Find the remaining angle and sides of the triangle.
                                          C
                                              10°
   The third angle in the triangle is
           A = 180° – A – B                           a = 4.5 ft
           = 180° – 10° – 60°                   b
                                                              60°
                 = 110°
                                                 110°             B
                                                            c
                                                     A
   Use the Law of Sines to find side b and c.




                                   5
Example 1 (ASA):
Find the remaining angle and sides of the triangle.
                                          C
                                               10°
   The third angle in the triangle is
           A = 180° – A – B                             a = 4.5 ft
           = 180° – 10° – 60°             4.15 ft b
                                                                60°
                 = 110°
                                                   110°             B
                                                              c
                                                       A
   Use the Law of Sines to find side b and c.




                                    5
Example 1 (ASA):
Find the remaining angle and sides of the triangle.
                                          C
                                               10°
   The third angle in the triangle is
           A = 180° – A – B                             a = 4.5 ft
           = 180° – 10° – 60°             4.15 ft b
                                                                60°
                 = 110°
                                                   110°             B
                                                              c
                                                       A
                                                            0.83 ft
   Use the Law of Sines to find side b and c.




                                    5
Watch out for SSA!




         6
Watch out for SSA!
SSA is not a congruency property.
SO, if we are given t wo sides and the NON-included angle in a
triangle, there are three possible scenarios…




                                 6
Watch out for SSA!
SSA is not a congruency property.
SO, if we are given t wo sides and the NON-included angle in a
triangle, there are three possible scenarios…
      âž¡ Option 1: No triangle is formed




                                 6
Watch out for SSA!
SSA is not a congruency property.
SO, if we are given t wo sides and the NON-included angle in a
triangle, there are three possible scenarios…
      âž¡ Option 1: No triangle is formed
      âž¡ Option 2: One triangle is formed




                                 6
Watch out for SSA!
SSA is not a congruency property.
SO, if we are given t wo sides and the NON-included angle in a
triangle, there are three possible scenarios…
      âž¡ Option 1: No triangle is formed
      âž¡ Option 2: One triangle is formed
      âž¡ Option 3: Two triangles are formed




                                 6
Watch out for SSA!
SSA is not a congruency property.
SO, if we are given t wo sides and the NON-included angle in a
triangle, there are three possible scenarios…
      âž¡ Option 1: No triangle is formed
      âž¡ Option 2: One triangle is formed
      âž¡ Option 3: Two triangles are formed
  How is it determined? If …




                                 6
Watch out for SSA!
SSA is not a congruency property.
SO, if we are given t wo sides and the NON-included angle in a
triangle, there are three possible scenarios…
      âž¡ Option 1: No triangle is formed
      âž¡ Option 2: One triangle is formed
      âž¡ Option 3: Two triangles are formed
  How is it determined? If …
     opp ≥ adj
 0 or 1 triangle
                                 6
Watch out for SSA!
SSA is not a congruency property.
SO, if we are given t wo sides and the NON-included angle in a
triangle, there are three possible scenarios…
      âž¡ Option 1: No triangle is formed
      âž¡ Option 2: One triangle is formed
      âž¡ Option 3: Two triangles are formed
  How is it determined? If …
     opp ≥ adj                       opp ≤ adj
 0 or 1 triangle                0 or 2 triangles
                                 6
Example 2 (SSA):
Use the Law of Sines to solve the triangle.
A = 110°, a = 125 inches, b = 100 inches




                                   7
Example 2 (SSA):
Use the Law of Sines to solve the triangle.
A = 110°, a = 125 inches, b = 100 inches
                                       C

                                                           a = 125 in
                                       b = 100 in
                                                        110°
                                                                        B
                                                               c
                                                    A




                                   7
Example 2 (SSA):
Use the Law of Sines to solve the triangle.
A = 110°, a = 125 inches, b = 100 inches
                                       C
   There is either 0 or 1 triangle
  satisfying the given conditions
                                                           a = 125 in
         because opp ≥ adj
                                       b = 100 in
                                                        110°
                                                                        B
                                                               c
                                                    A




                                   7
Example 2 (SSA):
Use the Law of Sines to solve the triangle.
A = 110°, a = 125 inches, b = 100 inches
                                       C
   There is either 0 or 1 triangle
  satisfying the given conditions
                                                           a = 125 in
         because opp ≥ adj
                                       b = 100 in
                                                        110°       48.74°
                                                                        B
                                                               c
                                                    A




                                   7
Example 2 (SSA):
Use the Law of Sines to solve the triangle.
A = 110°, a = 125 inches, b = 100 inches
                                       C 21.26°
   There is either 0 or 1 triangle
  satisfying the given conditions
                                                        a = 125 in
         because opp ≥ adj
                                    b = 100 in
                                                     110°       48.74°
                                                                     B
                                                            c
                                                 A




     C ≈ 180° – 110° – 48.74°
    = 21.26°

                                7
Example 2 (SSA):
Use the Law of Sines to solve the triangle.
A = 110°, a = 125 inches, b = 100 inches
                                       C 21.26°
   There is either 0 or 1 triangle
  satisfying the given conditions
                                                        a = 125 in
         because opp ≥ adj
                                    b = 100 in
                                                     110°         48.74°
                                                                     B
                                                            c
                                                 A     48.23 in




     C ≈ 180° – 110° – 48.74°
    = 21.26°

                                7
Example 3 (SSA):
Use the Law of Sines to solve the triangle.
A = 76°, a = 18 inches, b = 20 inches




                                   8
Example 3 (SSA):
Use the Law of Sines to solve the triangle.
A = 76°, a = 18 inches, b = 20 inches
 There is either 0 or 2 triangles
 satisfying the given conditions
        because opp ≤ adj




                                    8
Example 3 (SSA):
Use the Law of Sines to solve the triangle.
A = 76°, a = 18 inches, b = 20 inches
 There is either 0 or 2 triangles
                                              C
 satisfying the given conditions
        because opp ≤ adj
                                                         b = 20 in
                                         a = 18 in
                                                               76°
                                                                     A
                                                     B




    There is no angle whose sine is 1.078.

                                    8
Example 4 (SSA):
Use the Law of Sines to solve the triangle.
A = 58°, a = 11.4 cm, b = 12.8 cm




                                 9
Example 4 (SSA):                                       C
Use the Law of Sines to solve the triangle.
A = 58°, a = 11.4 cm, b = 12.8 cm
                                                               b = 12.8 cm
                                         a = 11.4 cm

                                                                  58°
                                                                    A
                                                 B1        c




                                 9
Example 4 (SSA):                                       C
Use the Law of Sines to solve the triangle.
A = 58°, a = 11.4 cm, b = 12.8 cm
   There is either 0 or 2                                      b = 12.8 cm
                                         a = 11.4 cm
   triangles that can be
    formed (opp ≤ adj)                                            58°
                                                                    A
                                                  B1       c




                                  9
Example 4 (SSA):                                       C
Use the Law of Sines to solve the triangle.
A = 58°, a = 11.4 cm, b = 12.8 cm
   There is either 0 or 2                                      b = 12.8 cm
                                         a = 11.4 cm
   triangles that can be
    formed (opp ≤ adj)                                 72.2°      58°
                                                                    A
                                                  B1       c




                                  9
Example 4 (SSA):                                       C
                                                           49.8°
Use the Law of Sines to solve the triangle.
A = 58°, a = 11.4 cm, b = 12.8 cm
   There is either 0 or 2                                        b = 12.8 cm
                                         a = 11.4 cm
   triangles that can be
    formed (opp ≤ adj)                                 72.2°        58°
                                                                      A
                                                  B1         c




 C ≈ 180° – 58° – 72.2° = 49.8°

                                  9
Example 4 (SSA):                                       C
                                                           49.8°
Use the Law of Sines to solve the triangle.
A = 58°, a = 11.4 cm, b = 12.8 cm
   There is either 0 or 2                                        b = 12.8 cm
                                         a = 11.4 cm
   triangles that can be
    formed (opp ≤ adj)                                 72.2°        58°
                                                                      A
                                                  B1         c
                                                        10.3 cm




 C ≈ 180° – 58° – 72.2° = 49.8°
                                              Example continues …
                                  9
Example 4 (SSA) continued:
Use the Law of Sines to solve the second triangle.    C
A = 58°, a = 11.4 cm, b = 12.8 cm                         49.8°


                                                                b = 12.8 cm
                                        a = 11.4 cm
                                             a=11.4 cm
                                                      72.2°        58°
                                                                     A
                                                B1          c
                                                       10.3 cm




                                10
Example 4 (SSA) continued:
Use the Law of Sines to solve the second triangle.     C
A = 58°, a = 11.4 cm, b = 12.8 cm                          49.8°


                                                                 b = 12.8 cm
                                        a = 11.4 cm
                                             a=11.4 cm
                                                       72.2°           58°
                                                                        A
                                                B1           c
                                                        10.3 cm
                                           C

                                                           b = 12.8 cm
                                         a = 11.4 cm
                                                                       58°
                                                                             A
                                                         B2        c

                                10
Example 4 (SSA) continued:
Use the Law of Sines to solve the second triangle.     C
A = 58°, a = 11.4 cm, b = 12.8 cm                          49.8°


      B2 ≈ 180° – 72.2° = 107.8 °                                b = 12.8 cm
                                        a = 11.4 cm
                                             a=11.4 cm
                                                       72.2°           58°
                                                                        A
                                                B1           c
                                                        10.3 cm
                                           C

                                                           b = 12.8 cm
                                         a = 11.4 cm
                                                                       58°
                                                  107.8°
                                                                             A
                                                         B2        c

                                10
Example 4 (SSA) continued:
Use the Law of Sines to solve the second triangle.     C
A = 58°, a = 11.4 cm, b = 12.8 cm                          49.8°


      B2 ≈ 180° – 72.2° = 107.8 °                                b = 12.8 cm
                                        a = 11.4 cm
                                             a=11.4 cm
                                                       72.2°           58°
     C ≈ 180° – 58° – 107.8° = 14.2°                                    A
                                                B1           c
                                                         10.3 cm
                                           C
                                                 14.2°

                                                           b = 12.8 cm
                                         a = 11.4 cm
                                                                       58°
                                                  107.8°
                                                                             A
                                                         B2        c

                                10
Example 4 (SSA) continued:
Use the Law of Sines to solve the second triangle.     C
A = 58°, a = 11.4 cm, b = 12.8 cm                          49.8°


      B2 ≈ 180° – 72.2° = 107.8 °                                b = 12.8 cm
                                        a = 11.4 cm
                                             a=11.4 cm
                                                       72.2°           58°
     C ≈ 180° – 58° – 107.8° = 14.2°                                    A
                                                B1           c
                                                         10.3 cm
                                           C
                                                 14.2°

                                                           b = 12.8 cm
                                         a = 11.4 cm
                                                                       58°
                                                  107.8°
                                                                             A
                                                         B2        c
                                                                 3.3 cm
                                10
Area of an Oblique Triangle




                    11
Area of an Oblique Triangle




                    11
Area of an Oblique Triangle


Example 5:
Find the area of the triangle.
A = 74°, b = 103 inches, c = 58 inches




                             11
Area of an Oblique Triangle

                                                           C
Example 5:
                                             103 in
Find the area of the triangle.                                 a
                                                b
A = 74°, b = 103 inches, c = 58 inches
                                               74°
                                         A                         B
                                                       c
                                                      58 in




                             11
Area of an Oblique Triangle

                                                           C
Example 5:
                                             103 in
Find the area of the triangle.                                 a
                                                b
A = 74°, b = 103 inches, c = 58 inches
                                               74°
                                         A                         B
                                                       c
                                                      58 in




                             11
Area of an Oblique Triangle

                                                           C
Example 5:
                                             103 in
Find the area of the triangle.                                 a
                                                b
A = 74°, b = 103 inches, c = 58 inches
                                               74°
                                         A                         B
                                                       c
                                                      58 in




                             11
Area of an Oblique Triangle

                                                           C
Example 5:
                                             103 in
Find the area of the triangle.                                 a
                                                b
A = 74°, b = 103 inches, c = 58 inches
                                               74°
                                         A                         B
                                                       c
                                                      58 in




                             11
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?




                                12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?




                                12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?




           14°




                                12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?




    Flagpole height: b


              14°




                                12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?




    Flagpole height: b


              14°




                                12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?




    Flagpole height: b


              14°




                                12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?




    Flagpole height: b
                         16 m
              14°




                                12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?




    Flagpole height: b
                         16 m
              14°




                                12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?


         20°

    Flagpole height: b
                         16 m
               14°




                                12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?


         20°
                         70°
    Flagpole height: b
                               16 m
               14°




                                      12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?


         20°
                         70°
                                 34°
    Flagpole height: b
                               16 m
               14°




                                       12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?


                         A
         20°
                             70°
                                     34°        B
    Flagpole height: b
                                   16 m
                         C
               14°




                                           12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?


                         A
         20°
                             70°
                                     34°        B
    Flagpole height: b
                                   16 m
                         C
               14°




                                           12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?


                         A
         20°
                             70°
                                     34°        B
    Flagpole height: b
                                   16 m
                         C
               14°




                                           12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?


                         A
         20°
                             70°
                                     34°        B
    Flagpole height: b
                                   16 m
                         C
               14°




                                           12
Application:
A flagpole at a right angle to the horizontal is located on a slope
that makes an angle of 14° with the horizontal. The flagpole
casts a 16-meter shadow up the slope when the angle of
elevation from the tip of the shadow to the sun is 20°. How tall
is the flagpole?


                         A
         20°
                             70°
                                     34°        B
    Flagpole height: b
                                   16 m
                         C
               14°




The flagpole is approximately 9.5 meters tall.


                                           12
Homework:

Assignment #2 p. 436
#7, 8, 13, 19-22, 29-31, 35,
36, 39, 40, 42

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PC 6.1 Notes

  • 1. 6.1 - Law of Sines
  • 2. An oblique triangle is a triangle that has no right angles. C a b A B c To solve an oblique triangle, you need to know the measure of at least one side and the measures of any other two parts of the triangle – two sides, two angles, or one angle and one side. 2
  • 3. Four Cases for solving a triangle… 3
  • 4. Four Cases for solving a triangle… 1. Two angles and any side (AAS or ASA) A A c c B C 3
  • 5. Four Cases for solving a triangle… 1. Two angles and any side (AAS or ASA) A A c c B C 2. Two sides and an angle opposite one of them (SSA) c C a 3
  • 6. Four Cases for solving a triangle… 1. Two angles and any side (AAS or ASA) A A c c B C 2. Two sides and an angle opposite one of them (SSA) c C a 3. Three sides (SSS) c b a 3
  • 7. Four Cases for solving a triangle… 1. Two angles and any side (AAS or ASA) A A c c B C 2. Two sides and an angle opposite one of them (SSA) c C a 3. Three sides (SSS) c b c a 4. Two sides and their included angle (SAS) B a 3
  • 8. Case 1 and Case 2: 4
  • 9. Law of Sines Case 1 and Case 2: If ABC is an oblique triangle with sides a, b, and c, then C C a a b h h b A B B c c A Acute Triangle Obtuse Triangle 4
  • 10. Example 1 (ASA): Find the remaining angle and sides of the triangle. 5
  • 11. Example 1 (ASA): Find the remaining angle and sides of the triangle. C 10° a = 4.5 ft b 60° B c A 5
  • 12. Example 1 (ASA): Find the remaining angle and sides of the triangle. C 10° The third angle in the triangle is A = 180° – A – B a = 4.5 ft = 180° – 10° – 60° b 60° = 110° 110° B c A 5
  • 13. Example 1 (ASA): Find the remaining angle and sides of the triangle. C 10° The third angle in the triangle is A = 180° – A – B a = 4.5 ft = 180° – 10° – 60° b 60° = 110° 110° B c A Use the Law of Sines to find side b and c. 5
  • 14. Example 1 (ASA): Find the remaining angle and sides of the triangle. C 10° The third angle in the triangle is A = 180° – A – B a = 4.5 ft = 180° – 10° – 60° 4.15 ft b 60° = 110° 110° B c A Use the Law of Sines to find side b and c. 5
  • 15. Example 1 (ASA): Find the remaining angle and sides of the triangle. C 10° The third angle in the triangle is A = 180° – A – B a = 4.5 ft = 180° – 10° – 60° 4.15 ft b 60° = 110° 110° B c A 0.83 ft Use the Law of Sines to find side b and c. 5
  • 16. Watch out for SSA! 6
  • 17. Watch out for SSA! SSA is not a congruency property. SO, if we are given t wo sides and the NON-included angle in a triangle, there are three possible scenarios… 6
  • 18. Watch out for SSA! SSA is not a congruency property. SO, if we are given t wo sides and the NON-included angle in a triangle, there are three possible scenarios… âž¡ Option 1: No triangle is formed 6
  • 19. Watch out for SSA! SSA is not a congruency property. SO, if we are given t wo sides and the NON-included angle in a triangle, there are three possible scenarios… âž¡ Option 1: No triangle is formed âž¡ Option 2: One triangle is formed 6
  • 20. Watch out for SSA! SSA is not a congruency property. SO, if we are given t wo sides and the NON-included angle in a triangle, there are three possible scenarios… âž¡ Option 1: No triangle is formed âž¡ Option 2: One triangle is formed âž¡ Option 3: Two triangles are formed 6
  • 21. Watch out for SSA! SSA is not a congruency property. SO, if we are given t wo sides and the NON-included angle in a triangle, there are three possible scenarios… âž¡ Option 1: No triangle is formed âž¡ Option 2: One triangle is formed âž¡ Option 3: Two triangles are formed How is it determined? If … 6
  • 22. Watch out for SSA! SSA is not a congruency property. SO, if we are given t wo sides and the NON-included angle in a triangle, there are three possible scenarios… âž¡ Option 1: No triangle is formed âž¡ Option 2: One triangle is formed âž¡ Option 3: Two triangles are formed How is it determined? If … opp ≥ adj 0 or 1 triangle 6
  • 23. Watch out for SSA! SSA is not a congruency property. SO, if we are given t wo sides and the NON-included angle in a triangle, there are three possible scenarios… âž¡ Option 1: No triangle is formed âž¡ Option 2: One triangle is formed âž¡ Option 3: Two triangles are formed How is it determined? If … opp ≥ adj opp ≤ adj 0 or 1 triangle 0 or 2 triangles 6
  • 24. Example 2 (SSA): Use the Law of Sines to solve the triangle. A = 110°, a = 125 inches, b = 100 inches 7
  • 25. Example 2 (SSA): Use the Law of Sines to solve the triangle. A = 110°, a = 125 inches, b = 100 inches C a = 125 in b = 100 in 110° B c A 7
  • 26. Example 2 (SSA): Use the Law of Sines to solve the triangle. A = 110°, a = 125 inches, b = 100 inches C There is either 0 or 1 triangle satisfying the given conditions a = 125 in because opp ≥ adj b = 100 in 110° B c A 7
  • 27. Example 2 (SSA): Use the Law of Sines to solve the triangle. A = 110°, a = 125 inches, b = 100 inches C There is either 0 or 1 triangle satisfying the given conditions a = 125 in because opp ≥ adj b = 100 in 110° 48.74° B c A 7
  • 28. Example 2 (SSA): Use the Law of Sines to solve the triangle. A = 110°, a = 125 inches, b = 100 inches C 21.26° There is either 0 or 1 triangle satisfying the given conditions a = 125 in because opp ≥ adj b = 100 in 110° 48.74° B c A C ≈ 180° – 110° – 48.74° = 21.26° 7
  • 29. Example 2 (SSA): Use the Law of Sines to solve the triangle. A = 110°, a = 125 inches, b = 100 inches C 21.26° There is either 0 or 1 triangle satisfying the given conditions a = 125 in because opp ≥ adj b = 100 in 110° 48.74° B c A 48.23 in C ≈ 180° – 110° – 48.74° = 21.26° 7
  • 30. Example 3 (SSA): Use the Law of Sines to solve the triangle. A = 76°, a = 18 inches, b = 20 inches 8
  • 31. Example 3 (SSA): Use the Law of Sines to solve the triangle. A = 76°, a = 18 inches, b = 20 inches There is either 0 or 2 triangles satisfying the given conditions because opp ≤ adj 8
  • 32. Example 3 (SSA): Use the Law of Sines to solve the triangle. A = 76°, a = 18 inches, b = 20 inches There is either 0 or 2 triangles C satisfying the given conditions because opp ≤ adj b = 20 in a = 18 in 76° A B There is no angle whose sine is 1.078. 8
  • 33. Example 4 (SSA): Use the Law of Sines to solve the triangle. A = 58°, a = 11.4 cm, b = 12.8 cm 9
  • 34. Example 4 (SSA): C Use the Law of Sines to solve the triangle. A = 58°, a = 11.4 cm, b = 12.8 cm b = 12.8 cm a = 11.4 cm 58° A B1 c 9
  • 35. Example 4 (SSA): C Use the Law of Sines to solve the triangle. A = 58°, a = 11.4 cm, b = 12.8 cm There is either 0 or 2 b = 12.8 cm a = 11.4 cm triangles that can be formed (opp ≤ adj) 58° A B1 c 9
  • 36. Example 4 (SSA): C Use the Law of Sines to solve the triangle. A = 58°, a = 11.4 cm, b = 12.8 cm There is either 0 or 2 b = 12.8 cm a = 11.4 cm triangles that can be formed (opp ≤ adj) 72.2° 58° A B1 c 9
  • 37. Example 4 (SSA): C 49.8° Use the Law of Sines to solve the triangle. A = 58°, a = 11.4 cm, b = 12.8 cm There is either 0 or 2 b = 12.8 cm a = 11.4 cm triangles that can be formed (opp ≤ adj) 72.2° 58° A B1 c C ≈ 180° – 58° – 72.2° = 49.8° 9
  • 38. Example 4 (SSA): C 49.8° Use the Law of Sines to solve the triangle. A = 58°, a = 11.4 cm, b = 12.8 cm There is either 0 or 2 b = 12.8 cm a = 11.4 cm triangles that can be formed (opp ≤ adj) 72.2° 58° A B1 c 10.3 cm C ≈ 180° – 58° – 72.2° = 49.8° Example continues … 9
  • 39. Example 4 (SSA) continued: Use the Law of Sines to solve the second triangle. C A = 58°, a = 11.4 cm, b = 12.8 cm 49.8° b = 12.8 cm a = 11.4 cm a=11.4 cm 72.2° 58° A B1 c 10.3 cm 10
  • 40. Example 4 (SSA) continued: Use the Law of Sines to solve the second triangle. C A = 58°, a = 11.4 cm, b = 12.8 cm 49.8° b = 12.8 cm a = 11.4 cm a=11.4 cm 72.2° 58° A B1 c 10.3 cm C b = 12.8 cm a = 11.4 cm 58° A B2 c 10
  • 41. Example 4 (SSA) continued: Use the Law of Sines to solve the second triangle. C A = 58°, a = 11.4 cm, b = 12.8 cm 49.8° B2 ≈ 180° – 72.2° = 107.8 ° b = 12.8 cm a = 11.4 cm a=11.4 cm 72.2° 58° A B1 c 10.3 cm C b = 12.8 cm a = 11.4 cm 58° 107.8° A B2 c 10
  • 42. Example 4 (SSA) continued: Use the Law of Sines to solve the second triangle. C A = 58°, a = 11.4 cm, b = 12.8 cm 49.8° B2 ≈ 180° – 72.2° = 107.8 ° b = 12.8 cm a = 11.4 cm a=11.4 cm 72.2° 58° C ≈ 180° – 58° – 107.8° = 14.2° A B1 c 10.3 cm C 14.2° b = 12.8 cm a = 11.4 cm 58° 107.8° A B2 c 10
  • 43. Example 4 (SSA) continued: Use the Law of Sines to solve the second triangle. C A = 58°, a = 11.4 cm, b = 12.8 cm 49.8° B2 ≈ 180° – 72.2° = 107.8 ° b = 12.8 cm a = 11.4 cm a=11.4 cm 72.2° 58° C ≈ 180° – 58° – 107.8° = 14.2° A B1 c 10.3 cm C 14.2° b = 12.8 cm a = 11.4 cm 58° 107.8° A B2 c 3.3 cm 10
  • 44. Area of an Oblique Triangle 11
  • 45. Area of an Oblique Triangle 11
  • 46. Area of an Oblique Triangle Example 5: Find the area of the triangle. A = 74°, b = 103 inches, c = 58 inches 11
  • 47. Area of an Oblique Triangle C Example 5: 103 in Find the area of the triangle. a b A = 74°, b = 103 inches, c = 58 inches 74° A B c 58 in 11
  • 48. Area of an Oblique Triangle C Example 5: 103 in Find the area of the triangle. a b A = 74°, b = 103 inches, c = 58 inches 74° A B c 58 in 11
  • 49. Area of an Oblique Triangle C Example 5: 103 in Find the area of the triangle. a b A = 74°, b = 103 inches, c = 58 inches 74° A B c 58 in 11
  • 50. Area of an Oblique Triangle C Example 5: 103 in Find the area of the triangle. a b A = 74°, b = 103 inches, c = 58 inches 74° A B c 58 in 11
  • 51. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? 12
  • 52. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? 12
  • 53. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? 14° 12
  • 54. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? Flagpole height: b 14° 12
  • 55. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? Flagpole height: b 14° 12
  • 56. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? Flagpole height: b 14° 12
  • 57. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? Flagpole height: b 16 m 14° 12
  • 58. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? Flagpole height: b 16 m 14° 12
  • 59. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? 20° Flagpole height: b 16 m 14° 12
  • 60. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? 20° 70° Flagpole height: b 16 m 14° 12
  • 61. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? 20° 70° 34° Flagpole height: b 16 m 14° 12
  • 62. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? A 20° 70° 34° B Flagpole height: b 16 m C 14° 12
  • 63. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? A 20° 70° 34° B Flagpole height: b 16 m C 14° 12
  • 64. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? A 20° 70° 34° B Flagpole height: b 16 m C 14° 12
  • 65. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? A 20° 70° 34° B Flagpole height: b 16 m C 14° 12
  • 66. Application: A flagpole at a right angle to the horizontal is located on a slope that makes an angle of 14° with the horizontal. The flagpole casts a 16-meter shadow up the slope when the angle of elevation from the tip of the shadow to the sun is 20°. How tall is the flagpole? A 20° 70° 34° B Flagpole height: b 16 m C 14° The flagpole is approximately 9.5 meters tall. 12
  • 67. Homework: Assignment #2 p. 436 #7, 8, 13, 19-22, 29-31, 35, 36, 39, 40, 42