SlideShare ist ein Scribd-Unternehmen logo
1 von 34
PUT HW ON THE CORNER OF YOUR DESK! 
GT Geometry Drill 10/21/14 
1. Identify the hypothesis of the conditional 
statement “Two angles are complementary if 
the sum of their measures is 90 degrees.” 
2. Provide a counterexample to show that 
each statement is false. 
If the sum of two integers is even, then the 
integers are even 
3. Write the converse of each and then 
decided if it is true or false. 
Angle is a right angle if its measure is 90 
degrees
Is the conclusion a result of inductive or 
deductive reasoning? 
There is a myth that you can balance an egg on 
its end only on the spring equinox. A person 
was able to balance an egg on July 8, 
September 21, and December 19. Therefore this 
myth is false. 
Since the conclusion is based on a pattern of 
observations, it is a result of inductive reasoning.
Is the conclusion a result of inductive or 
deductive reasoning? 
There is a myth that the Great Wall of China is 
the only man-made object visible from the 
Moon. The Great Wall is barely visible in 
photographs taken from 180 miles above Earth. 
The Moon is about 237,000 miles from Earth. 
Therefore, the myth cannot be true. 
The conclusion is based on logical reasoning from 
scientific research. It is a result of deductive 
reasoning.
There is a myth that an eelskin wallet will 
demagnetize credit cards because the skin of 
the electric eels used to make the wallet holds 
an electric charge. However, eelskin products 
are not made from electric eels. Therefore, the 
myth cannot be true. Is this conclusion a result 
of inductive or deductive reasoning? 
The conclusion is based on logical reasoning from 
scientific research. It is a result of deductive 
reasoning.
2-4 
Biconditional Statements 
and Definitions 
Review properties of equality and use 
them to write algebraic proofs. 
Identify properties of equality and 
congruence. 
Holt McDougal Geometry 
Objectives 
Write and analyze biconditional 
statements.
2-4 
Biconditional Statements 
and Definitions 
deductive reasoning 
Holt McDougal Geometry 
Vocabulary 
biconditional statement 
definition 
polygon 
triangle 
quadrilateral
2-4 
Biconditional Statements 
and Definitions 
Deductive reasoning is the process of using 
logic to draw conclusions from given facts, 
definitions, and properties. 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
When you combine a conditional statement and its 
converse, you create a biconditional statement. 
A biconditional statement is a statement that 
can be written in the form “p if and only if q.” This 
means “if p, then q” and “if q, then p.” 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
p q means p q and q p 
Writing Math 
The biconditional “p if and only if q” can also be 
written as “p iff q” or p  q. 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
Example 1A: Identifying the Conditionals within a 
Biconditional Statement 
Write the conditional statement and converse 
within the biconditional. 
An angle is obtuse if and only if its measure is 
greater than 90° and less than 180°. 
Let p and q represent the following. 
p: An angle is obtuse. 
q: An angle’s measure is greater than 90° and 
less than 180°. 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
Let p and q represent the following. 
p: An angle is obtuse. 
q: An angle’s measure is greater than 90° and 
less than 180°. 
Holt McDougal Geometry 
Example 1A Continued 
The two parts of the biconditional p  q are p  q 
and q  p. 
Conditional: If an  is obtuse, then its measure is 
greater than 90° and less than 180°. 
Converse: If an angle's measure is greater 
than 90° and less than 180°, then it is obtuse.
2-4 
Biconditional Statements 
and Definitions 
For a biconditional statement to be true, 
both the conditional statement and its 
converse must be true. If either the 
conditional or the converse is false, then 
the biconditional statement is false. 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
In geometry, biconditional statements are used to write 
definitions. 
A definition is a statement that describes a 
mathematical object and can be written as a true 
biconditional. 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
In the glossary, a polygon is defined as a closed 
plane figure formed by three or more line 
segments. 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
A triangle is defined as a three-sided polygon, 
and a quadrilateral is a four-sided polygon. 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
Example 4: Writing Definitions as Biconditional 
Write each definition as a biconditional. 
A figure is a pentagon if and only if it is a 5-sided 
polygon. 
Holt McDougal Geometry 
Statements 
A. A pentagon is a five-sided polygon. 
B. A right angle measures 90°. 
An angle is a right angle if and only if it measures 90°.
2-4 
Biconditional Statements 
and Definitions 
Check It Out! Example 4 
Write each definition as a biconditional. 
4a. A quadrilateral is a four-sided polygon. 
A figure is a quadrilateral if and only if it is a 
4-sided polygon. 
4b. The measure of a straight angle is 180°. 
An  is a straight  if and only if its measure is 
180°. 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
A proof is an argument that uses logic, definitions, 
properties, and previously proven statements to show 
that a conclusion is true. 
An important part of writing a proof is giving 
justifications to show that every step is valid. 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
Remember! 
The Distributive Property states that 
a(b + c) = ab + ac. 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
Example 1: Solving an Equation in Algebra 
Solve the equation 4m – 8 = –12. Write a 
justification for each step. 
4m – 8 = –12 Given equation 
+8 +8 Addition Property of Equality 
4m = –4 Simplify. 
m = –1 Simplify. 
Holt McDougal Geometry 
Division Property of Equality
2-4 
Biconditional Statements 
and Definitions 
Check It Out! Example 1 
Solve the equation . Write a justification for 
each step. 
t = –14 Simplify. 
Holt McDougal Geometry 
Given equation 
Multiplication Property of Equality.
2-4 
Biconditional Statements 
and Definitions 
Like algebra, geometry also uses numbers, variables, 
and operations. For example, segment lengths and 
angle measures are numbers. So you can use these 
same properties of equality to write algebraic proofs in 
geometry. 
Helpful Hint 
Holt McDougal Geometry 
A B 
AB represents the length AB, so you can think of 
AB as a variable representing a number.
2-4 
Biconditional Statements 
and Definitions 
Example 3: Solving an Equation in Geometry 
Write a justification for each step. 
NO = NM + MO 
4x – 4 = 2x + (3x – 9) 
Holt McDougal Geometry 
Segment Addition Post. 
Substitution Property of 
Equality 
4x – 4 = 5x – 9 Simplify. 
–4 = x – 9 
5 = x 
Subtraction Property of 
Equality 
Addition Property of 
Equality
2-4 
Biconditional Statements 
and Definitions 
Check It Out! Example 3 
Write a justification for each step. 
mABC = mABD + mDBC  Add. Post. 
8x° = (3x + 5)° + (6x – 16)° Subst. Prop. of Equality 
8x = 9x – 11 Simplify. 
–x = –11 Subtr. Prop. of Equality. 
x = 11 
Holt McDougal Geometry 
Mult. Prop. of Equality.
2-4 
Biconditional Statements 
and Definitions 
You learned in Chapter 1 that segments with 
equal lengths are congruent and that angles with 
equal measures are congruent. So the Reflexive, 
Symmetric, and Transitive Properties of Equality 
have corresponding properties of congruence. 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
Remember! 
Numbers are equal (=) and figures are congruent 
(). 
Holt McDougal Geometry
2-4 
Biconditional Statements 
and Definitions 
Example 4: Identifying Property of Equality and 
Identify the property that justifies each statement. 
A. QRS  QRS 
B. m1 = m2 so m2 = m1 
C. AB  CD and CD  EF, so AB  EF. 
D. 32° = 32° 
Holt McDougal Geometry 
Congruence 
Symm. Prop. of 
= 
Trans. Prop of 
 
Reflex. Prop. of 
. 
Reflex. Prop. of 
=
2-4 
Biconditional Statements 
and Definitions 
Check It Out! Example 4 
Identify the property that justifies each statement. 
4a. DE = GH, so GH = DE. 
4b. 94° = 94° 
4c. 0 = a, and a = x. So 0 = x. 
4d. A  Y, so Y  A 
Holt McDougal Geometry 
Sym. Prop. of = 
Reflex. Prop. of = 
Trans. Prop. of = 
Sym. Prop. of 
2-4 
Biconditional Statements 
and Definitions 
Holt McDougal Geometry 
Lesson Quiz: Part I 
Solve each equation. Write a justification for each 
step. 
1. 
Given 
z – 5 = –12 Mult. Prop. of = 
z = –7 Add. Prop. of =
2-4 
Biconditional Statements 
and Definitions 
Holt McDougal Geometry 
Lesson Quiz: Part II 
Solve each equation. Write a justification for each 
step. 
2. 6r – 3 = –2(r + 1) 
Given 
6r – 3 = –2r – 2 
8r – 3 = –2 
Distrib. Prop. 
Add. Prop. of = 
6r – 3 = –2(r + 1) 
8r = 1 Add. Prop. of = 
Div. Prop. of =
2-4 
Biconditional Statements 
and Definitions 
Holt McDougal Geometry 
Lesson Quiz: Part III 
Identify the property that justifies each 
statement. 
3. x = y and y = z, so x = z. 
4. DEF  DEF 
5. AB  CD, so CD  AB. 
Trans. Prop. of = 
Reflex. Prop. of  
Sym. Prop. of 
2-4 
Biconditional Statements 
and Definitions 
Converse: If an  measures 90°, then the  is right. 
Biconditional: An  is right iff its measure is 90°. 
Holt McDougal Geometry 
Lesson Quiz 
1. For the conditional “If an angle is right, then 
its measure is 90°,” write the converse and a 
biconditional statement. 
2. Determine if the biconditional “Two angles are 
complementary if and only if they are both 
acute” is true. If false, give a counterexample. 
False; possible answer: 30° and 40° 
3. Write the definition “An acute triangle is a 
triangle with three acute angles” as a 
biconditional. 
A triangle is acute iff it has 3 acute s.

Weitere ähnliche Inhalte

Was ist angesagt?

11.coupled fixed point theorems in partially ordered metric space
11.coupled fixed point theorems in partially ordered metric space11.coupled fixed point theorems in partially ordered metric space
11.coupled fixed point theorems in partially ordered metric space
Alexander Decker
 
Geometry Section 3-5 1112
Geometry Section 3-5 1112Geometry Section 3-5 1112
Geometry Section 3-5 1112
Jimbo Lamb
 
Ch3.7 Deductive Reasoning
Ch3.7 Deductive ReasoningCh3.7 Deductive Reasoning
Ch3.7 Deductive Reasoning
mdicken
 
sarminIJMA1-4-2015 forth paper after been publishing
sarminIJMA1-4-2015 forth paper after been publishingsarminIJMA1-4-2015 forth paper after been publishing
sarminIJMA1-4-2015 forth paper after been publishing
Mustafa El-sanfaz
 

Was ist angesagt? (20)

Numerical solution of heat equation through double interpolation
Numerical solution of heat equation through double interpolationNumerical solution of heat equation through double interpolation
Numerical solution of heat equation through double interpolation
 
Geometry section 4-1 1112
Geometry section 4-1 1112Geometry section 4-1 1112
Geometry section 4-1 1112
 
Relations
RelationsRelations
Relations
 
11.coupled fixed point theorems in partially ordered metric space
11.coupled fixed point theorems in partially ordered metric space11.coupled fixed point theorems in partially ordered metric space
11.coupled fixed point theorems in partially ordered metric space
 
SMALL_2013
SMALL_2013SMALL_2013
SMALL_2013
 
(8) Lesson 7.2 - Congruence
(8) Lesson 7.2 - Congruence(8) Lesson 7.2 - Congruence
(8) Lesson 7.2 - Congruence
 
Inequality
InequalityInequality
Inequality
 
CMSC 56 | Lecture 16: Equivalence of Relations & Partial Ordering
CMSC 56 | Lecture 16: Equivalence of Relations & Partial OrderingCMSC 56 | Lecture 16: Equivalence of Relations & Partial Ordering
CMSC 56 | Lecture 16: Equivalence of Relations & Partial Ordering
 
Geometry Section 3-5 1112
Geometry Section 3-5 1112Geometry Section 3-5 1112
Geometry Section 3-5 1112
 
CMSC 56 | Lecture 15: Closures of Relations
CMSC 56 | Lecture 15: Closures of RelationsCMSC 56 | Lecture 15: Closures of Relations
CMSC 56 | Lecture 15: Closures of Relations
 
Geometry Section 5-1 1112
Geometry Section 5-1 1112Geometry Section 5-1 1112
Geometry Section 5-1 1112
 
CMSC 56 | Lecture 13: Relations and their Properties
CMSC 56 | Lecture 13: Relations and their PropertiesCMSC 56 | Lecture 13: Relations and their Properties
CMSC 56 | Lecture 13: Relations and their Properties
 
Ch3.7 Deductive Reasoning
Ch3.7 Deductive ReasoningCh3.7 Deductive Reasoning
Ch3.7 Deductive Reasoning
 
Chapter 2: Relations
Chapter 2: RelationsChapter 2: Relations
Chapter 2: Relations
 
Lindley smith 1972
Lindley smith 1972Lindley smith 1972
Lindley smith 1972
 
CMSC 56 | Lecture 14: Representing Relations
CMSC 56 | Lecture 14: Representing RelationsCMSC 56 | Lecture 14: Representing Relations
CMSC 56 | Lecture 14: Representing Relations
 
Ijciet 10 01_044
Ijciet 10 01_044Ijciet 10 01_044
Ijciet 10 01_044
 
Deep learning book_chap_02
Deep learning book_chap_02Deep learning book_chap_02
Deep learning book_chap_02
 
sarminIJMA1-4-2015 forth paper after been publishing
sarminIJMA1-4-2015 forth paper after been publishingsarminIJMA1-4-2015 forth paper after been publishing
sarminIJMA1-4-2015 forth paper after been publishing
 
6th. Grade-2 integers
6th. Grade-2 integers6th. Grade-2 integers
6th. Grade-2 integers
 

Andere mochten auch

Factoring review day 2
Factoring review day 2Factoring review day 2
Factoring review day 2
jbianco9910
 
1004 quiz day with review
1004 quiz day with review1004 quiz day with review
1004 quiz day with review
jbianco9910
 
Proofs day 2 and test review
Proofs day 2 and test reviewProofs day 2 and test review
Proofs day 2 and test review
jbianco9910
 
001 int techintro
001  int techintro001  int techintro
001 int techintro
jbianco9910
 
Welcome1stdaypwpt2014
Welcome1stdaypwpt2014Welcome1stdaypwpt2014
Welcome1stdaypwpt2014
jbianco9910
 
3009 implicitdefere
3009 implicitdefere3009 implicitdefere
3009 implicitdefere
jbianco9910
 
2001 transformations reflections etc
2001 transformations reflections etc2001 transformations reflections etc
2001 transformations reflections etc
jbianco9910
 
Are of circle and sectors
Are of circle and sectorsAre of circle and sectors
Are of circle and sectors
jbianco9910
 
Trig review day 1 2013
Trig review day 1 2013Trig review day 1 2013
Trig review day 1 2013
jbianco9910
 
Traps and kites updated2014
Traps and kites updated2014Traps and kites updated2014
Traps and kites updated2014
jbianco9910
 
8004 side splitter 2014
8004  side splitter 20148004  side splitter 2014
8004 side splitter 2014
jbianco9910
 
3002 a more with parrallel lines and anglesupdated 10 22-13
3002 a  more with parrallel lines and anglesupdated 10 22-133002 a  more with parrallel lines and anglesupdated 10 22-13
3002 a more with parrallel lines and anglesupdated 10 22-13
jbianco9910
 

Andere mochten auch (20)

Succession Gardening: Continue to Enjoy the Fruits of Your Labor - Sonoma Cou...
Succession Gardening: Continue to Enjoy the Fruits of Your Labor - Sonoma Cou...Succession Gardening: Continue to Enjoy the Fruits of Your Labor - Sonoma Cou...
Succession Gardening: Continue to Enjoy the Fruits of Your Labor - Sonoma Cou...
 
New Companion Planting App Offers Crop-Boosting Advice - Scotland
New Companion Planting App Offers Crop-Boosting Advice - ScotlandNew Companion Planting App Offers Crop-Boosting Advice - Scotland
New Companion Planting App Offers Crop-Boosting Advice - Scotland
 
Organic Gardening Technology
Organic Gardening TechnologyOrganic Gardening Technology
Organic Gardening Technology
 
Factoring review day 2
Factoring review day 2Factoring review day 2
Factoring review day 2
 
1004 quiz day with review
1004 quiz day with review1004 quiz day with review
1004 quiz day with review
 
Proofs day 2 and test review
Proofs day 2 and test reviewProofs day 2 and test review
Proofs day 2 and test review
 
001 int techintro
001  int techintro001  int techintro
001 int techintro
 
Welcome1stdaypwpt2014
Welcome1stdaypwpt2014Welcome1stdaypwpt2014
Welcome1stdaypwpt2014
 
3009 implicitdefere
3009 implicitdefere3009 implicitdefere
3009 implicitdefere
 
Permaculture Guilding and Companion Planting - Upisf
Permaculture Guilding and Companion Planting - UpisfPermaculture Guilding and Companion Planting - Upisf
Permaculture Guilding and Companion Planting - Upisf
 
Day 3 review
Day 3 reviewDay 3 review
Day 3 review
 
Condandlogic
CondandlogicCondandlogic
Condandlogic
 
2001 transformations reflections etc
2001 transformations reflections etc2001 transformations reflections etc
2001 transformations reflections etc
 
Are of circle and sectors
Are of circle and sectorsAre of circle and sectors
Are of circle and sectors
 
Trig review day 1 2013
Trig review day 1 2013Trig review day 1 2013
Trig review day 1 2013
 
Traps and kites updated2014
Traps and kites updated2014Traps and kites updated2014
Traps and kites updated2014
 
8004 side splitter 2014
8004  side splitter 20148004  side splitter 2014
8004 side splitter 2014
 
Vegetables Companion Planting Guide - Wikipedia
Vegetables Companion Planting Guide - WikipediaVegetables Companion Planting Guide - Wikipedia
Vegetables Companion Planting Guide - Wikipedia
 
Vegetable Gardening Plant Combinations: Companion Planting No Dig - Word
Vegetable Gardening Plant Combinations: Companion Planting No Dig - WordVegetable Gardening Plant Combinations: Companion Planting No Dig - Word
Vegetable Gardening Plant Combinations: Companion Planting No Dig - Word
 
3002 a more with parrallel lines and anglesupdated 10 22-13
3002 a  more with parrallel lines and anglesupdated 10 22-133002 a  more with parrallel lines and anglesupdated 10 22-13
3002 a more with parrallel lines and anglesupdated 10 22-13
 

Ähnlich wie Deductivereasoning and bicond and algebraic proof updated 2014s

Ähnlich wie Deductivereasoning and bicond and algebraic proof updated 2014s (20)

Gch2 l6
Gch2 l6Gch2 l6
Gch2 l6
 
Chapter4001 and 4002 traingles
Chapter4001 and 4002 trainglesChapter4001 and 4002 traingles
Chapter4001 and 4002 traingles
 
Ao dand aoe
Ao dand aoeAo dand aoe
Ao dand aoe
 
Ao dand aoe
Ao dand aoeAo dand aoe
Ao dand aoe
 
HGeo 2.2 Conditional Statements.ppt
HGeo 2.2 Conditional Statements.pptHGeo 2.2 Conditional Statements.ppt
HGeo 2.2 Conditional Statements.ppt
 
ag_mod10_les03_-M28-AnglesOfElevationandDepression3.ppt
ag_mod10_les03_-M28-AnglesOfElevationandDepression3.pptag_mod10_les03_-M28-AnglesOfElevationandDepression3.ppt
ag_mod10_les03_-M28-AnglesOfElevationandDepression3.ppt
 
ag_mod10_les03_-M28-AnglesOfElevationandDepression3.ppt
ag_mod10_les03_-M28-AnglesOfElevationandDepression3.pptag_mod10_les03_-M28-AnglesOfElevationandDepression3.ppt
ag_mod10_les03_-M28-AnglesOfElevationandDepression3.ppt
 
Geometry 201 unit 2.6
Geometry 201 unit 2.6Geometry 201 unit 2.6
Geometry 201 unit 2.6
 
Congruent figures
Congruent figuresCongruent figures
Congruent figures
 
5-1Perpendicular & Angle Bisectors.ppsx
5-1Perpendicular & Angle Bisectors.ppsx5-1Perpendicular & Angle Bisectors.ppsx
5-1Perpendicular & Angle Bisectors.ppsx
 
Gch1 l3
Gch1 l3Gch1 l3
Gch1 l3
 
Gch2 l4
Gch2 l4Gch2 l4
Gch2 l4
 
Gch2 l5
Gch2 l5Gch2 l5
Gch2 l5
 
(8) Lesson 5.2 - Geometric Proof
(8) Lesson 5.2 - Geometric Proof(8) Lesson 5.2 - Geometric Proof
(8) Lesson 5.2 - Geometric Proof
 
Congruent figures 2013
Congruent figures 2013Congruent figures 2013
Congruent figures 2013
 
Chapter 5 unit f 001
Chapter 5 unit f 001Chapter 5 unit f 001
Chapter 5 unit f 001
 
Demo slides in math editedppt
Demo slides in math editedpptDemo slides in math editedppt
Demo slides in math editedppt
 
Ratiosandpropday1 updated 2013
Ratiosandpropday1 updated 2013Ratiosandpropday1 updated 2013
Ratiosandpropday1 updated 2013
 
(7) Lesson 7.2
(7) Lesson 7.2(7) Lesson 7.2
(7) Lesson 7.2
 
Gch1 l4
Gch1 l4Gch1 l4
Gch1 l4
 

Mehr von jbianco9910

Proving quads are parralelograms
Proving quads are parralelogramsProving quads are parralelograms
Proving quads are parralelograms
jbianco9910
 
Special parralelogrmas day 1
Special parralelogrmas day 1Special parralelogrmas day 1
Special parralelogrmas day 1
jbianco9910
 
Polygons day 2 2015
Polygons day 2 2015Polygons day 2 2015
Polygons day 2 2015
jbianco9910
 
Parralelogram day 1 with answersupdated
Parralelogram day 1 with answersupdated  Parralelogram day 1 with answersupdated
Parralelogram day 1 with answersupdated
jbianco9910
 
Parralelogram day 2
Parralelogram day 2 Parralelogram day 2
Parralelogram day 2
jbianco9910
 
Chapter 5 review drill
Chapter 5 review drillChapter 5 review drill
Chapter 5 review drill
jbianco9910
 
Pytha drill into lines of concurrency day 2
Pytha drill into lines of concurrency day 2Pytha drill into lines of concurrency day 2
Pytha drill into lines of concurrency day 2
jbianco9910
 
Pytha drill into lines of concurrency
Pytha drill into lines of concurrencyPytha drill into lines of concurrency
Pytha drill into lines of concurrency
jbianco9910
 
Triang inequality drill and review
Triang inequality drill and reviewTriang inequality drill and review
Triang inequality drill and review
jbianco9910
 
5004 pyth tring inequ and more
5004 pyth tring inequ and more5004 pyth tring inequ and more
5004 pyth tring inequ and more
jbianco9910
 
Chapter 5 unit f 003 review and more updated
Chapter 5 unit f 003 review and more updatedChapter 5 unit f 003 review and more updated
Chapter 5 unit f 003 review and more updated
jbianco9910
 
5002 more with perp and angle bisector and cea
5002 more with perp and angle bisector and cea5002 more with perp and angle bisector and cea
5002 more with perp and angle bisector and cea
jbianco9910
 
5002 more with perp and angle bisector and cea updated
5002 more with perp and angle bisector and cea updated5002 more with perp and angle bisector and cea updated
5002 more with perp and angle bisector and cea updated
jbianco9910
 

Mehr von jbianco9910 (20)

Olivia’s math problem2
Olivia’s math problem2Olivia’s math problem2
Olivia’s math problem2
 
Olivia’s math problem2
Olivia’s math problem2Olivia’s math problem2
Olivia’s math problem2
 
Olivia's 100 day of school
Olivia's 100 day of  schoolOlivia's 100 day of  school
Olivia's 100 day of school
 
Oliviamath problem
Oliviamath problemOliviamath problem
Oliviamath problem
 
Olivia’s math problem
Olivia’s math problemOlivia’s math problem
Olivia’s math problem
 
Olivia’s math problem
Olivia’s math problemOlivia’s math problem
Olivia’s math problem
 
Proving quads are parralelograms
Proving quads are parralelogramsProving quads are parralelograms
Proving quads are parralelograms
 
Special parralelogrmas day 1
Special parralelogrmas day 1Special parralelogrmas day 1
Special parralelogrmas day 1
 
Polygons day 2 2015
Polygons day 2 2015Polygons day 2 2015
Polygons day 2 2015
 
Parralelogram day 1 with answersupdated
Parralelogram day 1 with answersupdated  Parralelogram day 1 with answersupdated
Parralelogram day 1 with answersupdated
 
Parralelogram day 2
Parralelogram day 2 Parralelogram day 2
Parralelogram day 2
 
Chapter 5 review drill
Chapter 5 review drillChapter 5 review drill
Chapter 5 review drill
 
Pytha drill into lines of concurrency day 2
Pytha drill into lines of concurrency day 2Pytha drill into lines of concurrency day 2
Pytha drill into lines of concurrency day 2
 
Pytha drill into lines of concurrency
Pytha drill into lines of concurrencyPytha drill into lines of concurrency
Pytha drill into lines of concurrency
 
Triang inequality drill and review
Triang inequality drill and reviewTriang inequality drill and review
Triang inequality drill and review
 
5004 pyth tring inequ and more
5004 pyth tring inequ and more5004 pyth tring inequ and more
5004 pyth tring inequ and more
 
Chapter 5 unit f 003 review and more updated
Chapter 5 unit f 003 review and more updatedChapter 5 unit f 003 review and more updated
Chapter 5 unit f 003 review and more updated
 
5002 more with perp and angle bisector and cea
5002 more with perp and angle bisector and cea5002 more with perp and angle bisector and cea
5002 more with perp and angle bisector and cea
 
5002 more with perp and angle bisector and cea updated
5002 more with perp and angle bisector and cea updated5002 more with perp and angle bisector and cea updated
5002 more with perp and angle bisector and cea updated
 
Review day 2
Review day 2Review day 2
Review day 2
 

Deductivereasoning and bicond and algebraic proof updated 2014s

  • 1. PUT HW ON THE CORNER OF YOUR DESK! GT Geometry Drill 10/21/14 1. Identify the hypothesis of the conditional statement “Two angles are complementary if the sum of their measures is 90 degrees.” 2. Provide a counterexample to show that each statement is false. If the sum of two integers is even, then the integers are even 3. Write the converse of each and then decided if it is true or false. Angle is a right angle if its measure is 90 degrees
  • 2. Is the conclusion a result of inductive or deductive reasoning? There is a myth that you can balance an egg on its end only on the spring equinox. A person was able to balance an egg on July 8, September 21, and December 19. Therefore this myth is false. Since the conclusion is based on a pattern of observations, it is a result of inductive reasoning.
  • 3. Is the conclusion a result of inductive or deductive reasoning? There is a myth that the Great Wall of China is the only man-made object visible from the Moon. The Great Wall is barely visible in photographs taken from 180 miles above Earth. The Moon is about 237,000 miles from Earth. Therefore, the myth cannot be true. The conclusion is based on logical reasoning from scientific research. It is a result of deductive reasoning.
  • 4. There is a myth that an eelskin wallet will demagnetize credit cards because the skin of the electric eels used to make the wallet holds an electric charge. However, eelskin products are not made from electric eels. Therefore, the myth cannot be true. Is this conclusion a result of inductive or deductive reasoning? The conclusion is based on logical reasoning from scientific research. It is a result of deductive reasoning.
  • 5. 2-4 Biconditional Statements and Definitions Review properties of equality and use them to write algebraic proofs. Identify properties of equality and congruence. Holt McDougal Geometry Objectives Write and analyze biconditional statements.
  • 6. 2-4 Biconditional Statements and Definitions deductive reasoning Holt McDougal Geometry Vocabulary biconditional statement definition polygon triangle quadrilateral
  • 7. 2-4 Biconditional Statements and Definitions Deductive reasoning is the process of using logic to draw conclusions from given facts, definitions, and properties. Holt McDougal Geometry
  • 8. 2-4 Biconditional Statements and Definitions When you combine a conditional statement and its converse, you create a biconditional statement. A biconditional statement is a statement that can be written in the form “p if and only if q.” This means “if p, then q” and “if q, then p.” Holt McDougal Geometry
  • 9. 2-4 Biconditional Statements and Definitions p q means p q and q p Writing Math The biconditional “p if and only if q” can also be written as “p iff q” or p  q. Holt McDougal Geometry
  • 10. 2-4 Biconditional Statements and Definitions Example 1A: Identifying the Conditionals within a Biconditional Statement Write the conditional statement and converse within the biconditional. An angle is obtuse if and only if its measure is greater than 90° and less than 180°. Let p and q represent the following. p: An angle is obtuse. q: An angle’s measure is greater than 90° and less than 180°. Holt McDougal Geometry
  • 11. 2-4 Biconditional Statements and Definitions Let p and q represent the following. p: An angle is obtuse. q: An angle’s measure is greater than 90° and less than 180°. Holt McDougal Geometry Example 1A Continued The two parts of the biconditional p  q are p  q and q  p. Conditional: If an  is obtuse, then its measure is greater than 90° and less than 180°. Converse: If an angle's measure is greater than 90° and less than 180°, then it is obtuse.
  • 12. 2-4 Biconditional Statements and Definitions For a biconditional statement to be true, both the conditional statement and its converse must be true. If either the conditional or the converse is false, then the biconditional statement is false. Holt McDougal Geometry
  • 13. 2-4 Biconditional Statements and Definitions In geometry, biconditional statements are used to write definitions. A definition is a statement that describes a mathematical object and can be written as a true biconditional. Holt McDougal Geometry
  • 14. 2-4 Biconditional Statements and Definitions In the glossary, a polygon is defined as a closed plane figure formed by three or more line segments. Holt McDougal Geometry
  • 15. 2-4 Biconditional Statements and Definitions A triangle is defined as a three-sided polygon, and a quadrilateral is a four-sided polygon. Holt McDougal Geometry
  • 16. 2-4 Biconditional Statements and Definitions Example 4: Writing Definitions as Biconditional Write each definition as a biconditional. A figure is a pentagon if and only if it is a 5-sided polygon. Holt McDougal Geometry Statements A. A pentagon is a five-sided polygon. B. A right angle measures 90°. An angle is a right angle if and only if it measures 90°.
  • 17. 2-4 Biconditional Statements and Definitions Check It Out! Example 4 Write each definition as a biconditional. 4a. A quadrilateral is a four-sided polygon. A figure is a quadrilateral if and only if it is a 4-sided polygon. 4b. The measure of a straight angle is 180°. An  is a straight  if and only if its measure is 180°. Holt McDougal Geometry
  • 18. 2-4 Biconditional Statements and Definitions A proof is an argument that uses logic, definitions, properties, and previously proven statements to show that a conclusion is true. An important part of writing a proof is giving justifications to show that every step is valid. Holt McDougal Geometry
  • 19. 2-4 Biconditional Statements and Definitions Holt McDougal Geometry
  • 20. 2-4 Biconditional Statements and Definitions Remember! The Distributive Property states that a(b + c) = ab + ac. Holt McDougal Geometry
  • 21. 2-4 Biconditional Statements and Definitions Example 1: Solving an Equation in Algebra Solve the equation 4m – 8 = –12. Write a justification for each step. 4m – 8 = –12 Given equation +8 +8 Addition Property of Equality 4m = –4 Simplify. m = –1 Simplify. Holt McDougal Geometry Division Property of Equality
  • 22. 2-4 Biconditional Statements and Definitions Check It Out! Example 1 Solve the equation . Write a justification for each step. t = –14 Simplify. Holt McDougal Geometry Given equation Multiplication Property of Equality.
  • 23. 2-4 Biconditional Statements and Definitions Like algebra, geometry also uses numbers, variables, and operations. For example, segment lengths and angle measures are numbers. So you can use these same properties of equality to write algebraic proofs in geometry. Helpful Hint Holt McDougal Geometry A B AB represents the length AB, so you can think of AB as a variable representing a number.
  • 24. 2-4 Biconditional Statements and Definitions Example 3: Solving an Equation in Geometry Write a justification for each step. NO = NM + MO 4x – 4 = 2x + (3x – 9) Holt McDougal Geometry Segment Addition Post. Substitution Property of Equality 4x – 4 = 5x – 9 Simplify. –4 = x – 9 5 = x Subtraction Property of Equality Addition Property of Equality
  • 25. 2-4 Biconditional Statements and Definitions Check It Out! Example 3 Write a justification for each step. mABC = mABD + mDBC  Add. Post. 8x° = (3x + 5)° + (6x – 16)° Subst. Prop. of Equality 8x = 9x – 11 Simplify. –x = –11 Subtr. Prop. of Equality. x = 11 Holt McDougal Geometry Mult. Prop. of Equality.
  • 26. 2-4 Biconditional Statements and Definitions You learned in Chapter 1 that segments with equal lengths are congruent and that angles with equal measures are congruent. So the Reflexive, Symmetric, and Transitive Properties of Equality have corresponding properties of congruence. Holt McDougal Geometry
  • 27. 2-4 Biconditional Statements and Definitions Holt McDougal Geometry
  • 28. 2-4 Biconditional Statements and Definitions Remember! Numbers are equal (=) and figures are congruent (). Holt McDougal Geometry
  • 29. 2-4 Biconditional Statements and Definitions Example 4: Identifying Property of Equality and Identify the property that justifies each statement. A. QRS  QRS B. m1 = m2 so m2 = m1 C. AB  CD and CD  EF, so AB  EF. D. 32° = 32° Holt McDougal Geometry Congruence Symm. Prop. of = Trans. Prop of  Reflex. Prop. of . Reflex. Prop. of =
  • 30. 2-4 Biconditional Statements and Definitions Check It Out! Example 4 Identify the property that justifies each statement. 4a. DE = GH, so GH = DE. 4b. 94° = 94° 4c. 0 = a, and a = x. So 0 = x. 4d. A  Y, so Y  A Holt McDougal Geometry Sym. Prop. of = Reflex. Prop. of = Trans. Prop. of = Sym. Prop. of 
  • 31. 2-4 Biconditional Statements and Definitions Holt McDougal Geometry Lesson Quiz: Part I Solve each equation. Write a justification for each step. 1. Given z – 5 = –12 Mult. Prop. of = z = –7 Add. Prop. of =
  • 32. 2-4 Biconditional Statements and Definitions Holt McDougal Geometry Lesson Quiz: Part II Solve each equation. Write a justification for each step. 2. 6r – 3 = –2(r + 1) Given 6r – 3 = –2r – 2 8r – 3 = –2 Distrib. Prop. Add. Prop. of = 6r – 3 = –2(r + 1) 8r = 1 Add. Prop. of = Div. Prop. of =
  • 33. 2-4 Biconditional Statements and Definitions Holt McDougal Geometry Lesson Quiz: Part III Identify the property that justifies each statement. 3. x = y and y = z, so x = z. 4. DEF  DEF 5. AB  CD, so CD  AB. Trans. Prop. of = Reflex. Prop. of  Sym. Prop. of 
  • 34. 2-4 Biconditional Statements and Definitions Converse: If an  measures 90°, then the  is right. Biconditional: An  is right iff its measure is 90°. Holt McDougal Geometry Lesson Quiz 1. For the conditional “If an angle is right, then its measure is 90°,” write the converse and a biconditional statement. 2. Determine if the biconditional “Two angles are complementary if and only if they are both acute” is true. If false, give a counterexample. False; possible answer: 30° and 40° 3. Write the definition “An acute triangle is a triangle with three acute angles” as a biconditional. A triangle is acute iff it has 3 acute s.