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1
Angular Momentum
Chapter 11
© 2012, 2016 A. Dzyubenko
© 2004, 2012 Brooks/Cole
Phys 221
adzyubenko@csub.edu
http://www.csub.edu/~adzyubenko
2
Vector Product
 Given two vectors A and B, the vector product
(cross product) A×B is a vector C
having a magnitude

sin
AB
C 
Θ is the angle
between
A and B
3
Vector Product, cont
 The quantity AB sin Θ is equal to the
area of the parallelogram formed by A and B
 The direction of the vector C is perpendicular to
the plane formed by A and B
 This direction is defined by the right-hand rule

sin
AB
4
Some Properties of the Cross Product
 The vector product is not commutative
A
B
B
A 


 The order is important!
Non-commutative…
 If A is parallel to B (Θ = 0º or 180º), then A×B = 0
 A×A= 0
 If A is perpendicular to B, then |A × B | = AB
 The vector product obeys the distributive law:
C
A
B
A
C
B
A 




 )
(

sin
AB
Θ = 90º
5
Some Properties of the
Cross Product, cont
 It is important to preserve the
multiplicative order of A and B
 The derivative of the cross product with respect to
some variable such as t is
dt
d
dt
d
dt
d B
A
B
A
B
A 



 )
(
6
Unit Vectors
 form a set of
mutually perpendicular unit
vectors in a right-handed
coordinate system
k
j
i ˆ
and
,
ˆ
,
ˆ
x
y
z
î
ĵ
k̂
7
Cross Products of Unit Vectors
 Signs are interchangeable in cross product:
 The cross products of the rectangular unit vectors
obey the following rules:
0
ˆ
ˆ
ˆ
ˆ
ˆ
ˆ 




 k
k
j
j
i
i
k
j
i ˆ
and
,
ˆ
,
ˆ
k
i
j
j
i ˆ
ˆ
ˆ
ˆ
ˆ 




i
j
k
k
j ˆ
ˆ
ˆ
ˆ
ˆ 




j
k
i
i
k ˆ
ˆ
ˆ
ˆ
ˆ 




j
i
j
i ˆ
ˆ
)
ˆ
(
ˆ 




x
y
z
8
Determinant Form of Cross Product
or
 The cross product of any two vectors A (Ax, Ay, Az)
and B (Bx, By, Bz) can be expressed in the following
determinant:
k
j
i
k
j
i
B
A ˆ
ˆ
ˆ
ˆ
ˆ
ˆ
y
x
y
x
z
x
z
x
z
y
z
y
z
y
x
z
y
x
B
B
A
A
B
B
A
A
B
B
A
A
B
B
B
A
A
A 




k
j
i
B
A
ˆ
)
(
ˆ
)
(
ˆ
)
(
x
y
y
x
z
x
x
z
y
z
z
y
B
A
B
A
B
A
B
A
B
A
B
A







x
y
z
Trick to use:
9
Vector Product Example
Given
 Find
Result

A B
ˆ ˆ ˆ ˆ
2 3 ; 2
    
A i j B i j
ˆ ˆ ˆ ˆ
(2 3 ) ( 2 )
ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ
2 ( ) 2 2 3 ( ) 3 2
ˆ ˆ ˆ
0 4 3 0 7
     
         
    
A B i j i j
i i i j j i j j
k k k
10
Torque Vector Example
Given the force and location
Find the torque produced
ˆ ˆ
(2.00 3.00 )
ˆ ˆ
(4.00 5.00 )
N
m
 
 
F i j
r i j
ˆ ˆ ˆ ˆ
[(4.00 5.00 )N] [(2.00 3.00 )m]
ˆ ˆ ˆ ˆ
[(4.00)(2.00) (4.00)(3.00)
ˆ ˆ ˆ ˆ
(5.00)(2.00) (5.00)(3.00)
ˆ
2.0 N m
      
   
   
 
r F i j i j
i i i j
j i i j
k
11
Vector Product and Torque
 The torque vector τ is the cross
product of the position vector r
and force F
F
r
τ 

 The magnitude of the torque τ is

 sin
rF

 Vector τ lies in a direction perpendicular to the plane
formed by the position vector r and the applied force F.
Along the axis of rotation!
φ is the angle between r and F
12
Rotational Dynamics
 A particle of mass m
located at position r,
moves with linear momentum p
 The net force on the particle:
 Take the cross product on the left
side of the equation
  dt
dp
F
  



dt
dp
r
τ
F
r
 Add the term 0

 p
r dt
d
p
v
r 

dt
d
dt
d )
( p
r
τ



p
r
p
r
τ 



 dt
d
dt
d
?
13
Angular Momentum
 Define the instantaneous angular momentum L
of a particle relative to the origin O as the cross
product of the particle’s instantaneous position
vector r and its instantaneous linear momentum p
looks similar in form to   dt
dp
F
 The torque acting on a particle
is equal to the time rate of change
of the particle’s angular momentum
p
r
L 

dt
d )
( p
r
τ



dt
d L
τ 

14
  dt
dp
F
Angular Momentum, cont
 Is the rotational analog of Newton’s second law
for translational motion
 Torque causes the angular momentum L to change
just as force causes linear momentum p to change
 Is valid only if Σ τ and L are measured
about the same origin
 The expression is valid for any origin fixed
in an inertial frame
dt
d L
τ 

15
More About Angular Momentum
 The SI unit of angular momentum is
kg·m2/s
 L is perpendicular to the plane
formed by r and p
 The magnitude and the direction of
L depend on the choice of origin
 The magnitude of L is

sin
mvr
L 
φ is the angle between r and p
 L is zero when r is parallel to p (φ = 0º or 180º)
 L = mvr when r is perpendicular to p (φ = 90º)
16
Angular Momentum of a System
of Particles: Motivation
 The net external force on a system of particles
is equal to the time rate of change of the total
linear momentum of the system
 The Newton’s second law for a system of particles
 
dt
d tot
ext
p
F
 Is there a similar statement
that can be made for
rotational motion?
17
Angular Momentum of a System, cont.






i
i
n L
L
L
L
L ...
2
1
tot
 Differentiate with
respect to time: 
 

i
i
i
i
dt
d
dt
d

L
Ltot
 The total angular momentum
varies in time according
to the net external torque:
 The total angular momentum of a system of
particles is the vector sum of the angular
momenta of the individual particles
dt
d tot
ext
L
τ 

18
Angular Momentum of a System
Relative to the System’s
Center of Mass
 The resultant torque acting on a system about an
axis through the center of mass equals the time rate
of change of angular momentum of the system
regardless of the motion of the center of mass
 This theorem applies even if the center of mass is
accelerating, provided τ and L are evaluated relative to
the center of mass
19
Angular Momentum of a Rotating
Rigid Object
I is the moment of inertia of the object

2
i
i
i
i
i
i r
m
r
v
m 

L
The angular momentum
of the whole object is
 Each particle rotates in the xy plane
about the z axis with an angular
speed 
 The magnitude of the angular
momentum of a particle of mass mi
about z axis is

 







 
  i
i
i
i i
i
i
i
z r
m
r
m
L
L 2
2

I
Lz 
20
Angular Momentum of a
Rotating Rigid Object, cont
 If a symmetrical object rotates about a fixed axis passing
through its center of mass, you can write in vector form
 Differentiate with respect to time,
noting that I is constant for a rigid
object


I
dt
d
I
dt
dLz



 I

 ext
ω
L I
 L is the total angular momentum measured
with respect to the axis of rotation
 is the angular acceleration relative to the axis of rotation
21
QQ
 A solid sphere and a hollow sphere have the
same mass and radius. They are rotating with
the same angular speed.
The one with the higher angular momentum is
(a) the solid sphere
(b) the hollow sphere
(c) they both have the same angular speed
(d) impossible to determine
22
Conservation of Angular Momentum
 For an isolated system consisting of N particles
 The total angular momentum of a system is
constant in both magnitude and direction if the
resultant external torque acting on the system is
zero. That is, if the system is isolated
constant
tot 
L
0
tot
ext 

 dt
d L

f
i L
L 
constant
1
tot 
 

N
n
n
L
L
23
Conservation of Angular Momentum, cont
 If the mass of an isolated system
undergoes redistribution in some
way, the system’s moment of
inertia I changes
 A change in I for an isolated
system requires a change in ω
f
f
i
i I
I 
 
f
i L
L 
24
Conservation Laws for an
Isolated System
 Energy,
linear momentum,
and angular momentum
of an isolated system
all remain constant 









f
i
f
i
f
i E
E
L
L
p
p
 Manifestations of some certain symmetries of space
25
Angular Momentum as a
Fundamental Quantity
 The concept of angular momentum is also valid
on a submicroscopic scale
 Angular momentum is an intrinsic property of
atoms, molecules, and their constituents
 Fundamental unit of momentum is
 h is called Planck’s constant

2
h


s
m
kg 2
34
10
054
.
1 

 

s, p, d, f, …
electronic orbitals: L=0, 1, 2, 3, … in terms of 
26
Reading assignment: Gyroscopes
http://aesp.nasa.okstate.edu/fieldguide/pages/skylab/skylabhu1.html
http://www.pbs.org/wgbh/nova/lostsub/torpworks.html

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Angular momentum

  • 1. 1 Angular Momentum Chapter 11 © 2012, 2016 A. Dzyubenko © 2004, 2012 Brooks/Cole Phys 221 adzyubenko@csub.edu http://www.csub.edu/~adzyubenko
  • 2. 2 Vector Product  Given two vectors A and B, the vector product (cross product) A×B is a vector C having a magnitude  sin AB C  Θ is the angle between A and B
  • 3. 3 Vector Product, cont  The quantity AB sin Θ is equal to the area of the parallelogram formed by A and B  The direction of the vector C is perpendicular to the plane formed by A and B  This direction is defined by the right-hand rule  sin AB
  • 4. 4 Some Properties of the Cross Product  The vector product is not commutative A B B A     The order is important! Non-commutative…  If A is parallel to B (Θ = 0º or 180º), then A×B = 0  A×A= 0  If A is perpendicular to B, then |A × B | = AB  The vector product obeys the distributive law: C A B A C B A       ) (  sin AB Θ = 90º
  • 5. 5 Some Properties of the Cross Product, cont  It is important to preserve the multiplicative order of A and B  The derivative of the cross product with respect to some variable such as t is dt d dt d dt d B A B A B A      ) (
  • 6. 6 Unit Vectors  form a set of mutually perpendicular unit vectors in a right-handed coordinate system k j i ˆ and , ˆ , ˆ x y z î ĵ k̂
  • 7. 7 Cross Products of Unit Vectors  Signs are interchangeable in cross product:  The cross products of the rectangular unit vectors obey the following rules: 0 ˆ ˆ ˆ ˆ ˆ ˆ       k k j j i i k j i ˆ and , ˆ , ˆ k i j j i ˆ ˆ ˆ ˆ ˆ      i j k k j ˆ ˆ ˆ ˆ ˆ      j k i i k ˆ ˆ ˆ ˆ ˆ      j i j i ˆ ˆ ) ˆ ( ˆ      x y z
  • 8. 8 Determinant Form of Cross Product or  The cross product of any two vectors A (Ax, Ay, Az) and B (Bx, By, Bz) can be expressed in the following determinant: k j i k j i B A ˆ ˆ ˆ ˆ ˆ ˆ y x y x z x z x z y z y z y x z y x B B A A B B A A B B A A B B B A A A      k j i B A ˆ ) ( ˆ ) ( ˆ ) ( x y y x z x x z y z z y B A B A B A B A B A B A        x y z Trick to use:
  • 9. 9 Vector Product Example Given  Find Result  A B ˆ ˆ ˆ ˆ 2 3 ; 2      A i j B i j ˆ ˆ ˆ ˆ (2 3 ) ( 2 ) ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ 2 ( ) 2 2 3 ( ) 3 2 ˆ ˆ ˆ 0 4 3 0 7                      A B i j i j i i i j j i j j k k k
  • 10. 10 Torque Vector Example Given the force and location Find the torque produced ˆ ˆ (2.00 3.00 ) ˆ ˆ (4.00 5.00 ) N m     F i j r i j ˆ ˆ ˆ ˆ [(4.00 5.00 )N] [(2.00 3.00 )m] ˆ ˆ ˆ ˆ [(4.00)(2.00) (4.00)(3.00) ˆ ˆ ˆ ˆ (5.00)(2.00) (5.00)(3.00) ˆ 2.0 N m                  r F i j i j i i i j j i i j k
  • 11. 11 Vector Product and Torque  The torque vector τ is the cross product of the position vector r and force F F r τ    The magnitude of the torque τ is   sin rF   Vector τ lies in a direction perpendicular to the plane formed by the position vector r and the applied force F. Along the axis of rotation! φ is the angle between r and F
  • 12. 12 Rotational Dynamics  A particle of mass m located at position r, moves with linear momentum p  The net force on the particle:  Take the cross product on the left side of the equation   dt dp F       dt dp r τ F r  Add the term 0   p r dt d p v r   dt d dt d ) ( p r τ    p r p r τ      dt d dt d ?
  • 13. 13 Angular Momentum  Define the instantaneous angular momentum L of a particle relative to the origin O as the cross product of the particle’s instantaneous position vector r and its instantaneous linear momentum p looks similar in form to   dt dp F  The torque acting on a particle is equal to the time rate of change of the particle’s angular momentum p r L   dt d ) ( p r τ    dt d L τ  
  • 14. 14   dt dp F Angular Momentum, cont  Is the rotational analog of Newton’s second law for translational motion  Torque causes the angular momentum L to change just as force causes linear momentum p to change  Is valid only if Σ τ and L are measured about the same origin  The expression is valid for any origin fixed in an inertial frame dt d L τ  
  • 15. 15 More About Angular Momentum  The SI unit of angular momentum is kg·m2/s  L is perpendicular to the plane formed by r and p  The magnitude and the direction of L depend on the choice of origin  The magnitude of L is  sin mvr L  φ is the angle between r and p  L is zero when r is parallel to p (φ = 0º or 180º)  L = mvr when r is perpendicular to p (φ = 90º)
  • 16. 16 Angular Momentum of a System of Particles: Motivation  The net external force on a system of particles is equal to the time rate of change of the total linear momentum of the system  The Newton’s second law for a system of particles   dt d tot ext p F  Is there a similar statement that can be made for rotational motion?
  • 17. 17 Angular Momentum of a System, cont.       i i n L L L L L ... 2 1 tot  Differentiate with respect to time:     i i i i dt d dt d  L Ltot  The total angular momentum varies in time according to the net external torque:  The total angular momentum of a system of particles is the vector sum of the angular momenta of the individual particles dt d tot ext L τ  
  • 18. 18 Angular Momentum of a System Relative to the System’s Center of Mass  The resultant torque acting on a system about an axis through the center of mass equals the time rate of change of angular momentum of the system regardless of the motion of the center of mass  This theorem applies even if the center of mass is accelerating, provided τ and L are evaluated relative to the center of mass
  • 19. 19 Angular Momentum of a Rotating Rigid Object I is the moment of inertia of the object  2 i i i i i i r m r v m   L The angular momentum of the whole object is  Each particle rotates in the xy plane about the z axis with an angular speed   The magnitude of the angular momentum of a particle of mass mi about z axis is               i i i i i i i i z r m r m L L 2 2  I Lz 
  • 20. 20 Angular Momentum of a Rotating Rigid Object, cont  If a symmetrical object rotates about a fixed axis passing through its center of mass, you can write in vector form  Differentiate with respect to time, noting that I is constant for a rigid object   I dt d I dt dLz     I   ext ω L I  L is the total angular momentum measured with respect to the axis of rotation  is the angular acceleration relative to the axis of rotation
  • 21. 21 QQ  A solid sphere and a hollow sphere have the same mass and radius. They are rotating with the same angular speed. The one with the higher angular momentum is (a) the solid sphere (b) the hollow sphere (c) they both have the same angular speed (d) impossible to determine
  • 22. 22 Conservation of Angular Momentum  For an isolated system consisting of N particles  The total angular momentum of a system is constant in both magnitude and direction if the resultant external torque acting on the system is zero. That is, if the system is isolated constant tot  L 0 tot ext    dt d L  f i L L  constant 1 tot     N n n L L
  • 23. 23 Conservation of Angular Momentum, cont  If the mass of an isolated system undergoes redistribution in some way, the system’s moment of inertia I changes  A change in I for an isolated system requires a change in ω f f i i I I    f i L L 
  • 24. 24 Conservation Laws for an Isolated System  Energy, linear momentum, and angular momentum of an isolated system all remain constant           f i f i f i E E L L p p  Manifestations of some certain symmetries of space
  • 25. 25 Angular Momentum as a Fundamental Quantity  The concept of angular momentum is also valid on a submicroscopic scale  Angular momentum is an intrinsic property of atoms, molecules, and their constituents  Fundamental unit of momentum is  h is called Planck’s constant  2 h   s m kg 2 34 10 054 . 1      s, p, d, f, … electronic orbitals: L=0, 1, 2, 3, … in terms of 