On the Zeros of Analytic Functions inside the Unit Disk
1. International Journal of Engineering Inventions
e-ISSN: 2278-7461, p-ISSN: 2319-6491
Volume 2, Issue 5 (March 2013) PP: 54-60
www.ijeijournal.com Page | 54
On the Zeros of Analytic Functions inside the Unit Disk
M. H. Gulzar
Department of Mathematics, University of Kashmir, Srinagar 190006
Abstract: In this paper we find an upper bound for the number of zeros of an analytic function inside the unit
disk by restricting the coefficients of the function to certain conditions.
AMS Mathematic Subject Classification 2010: 30C 10, 30C15
Keywords and Phrases: Bound, Analytic Function, Zeros
I. Introduction and Statement of Results
A well-known result due to Enestrom and Kakeya [5] states that a polynomial
n
j
j
j zazP
0
)( of degree n
with
0...... 011 aaaa nn
has all its zeros in .1z
Q. G. Mohammad [6] initiated the problem of finding an upper bound for the number of zeros of P(z) satisfying
the above conditions in
2
1
z . Many generalizations and refinements were later given by researchers on the
bounds for the number of zeros of P(z) in 10, z (for reference see [1]),[2], [4]etc.).
In this paper we consider the same problem for analytic functions and prove the following results:
Theorem 1: Let 0)(
0
j
j
j zazf be analytic for 1z , where njia jjj ,......,1,0, . If for
some 0 ,
......210 ,
then the number of zeros of f(z) in 10,
0
z
M
a
, does not exceed
0
0
00 22
log
1
log
1
a
j
j
,
where
1
00 22
j
jM
Taking 0 , the following result immediately follows from Theorem 1:
Corollary 1: Let 0)(
0
j
j
j zazf be analytic for 1z , where njia jjj ,......,1,0, . If
......210 ,
then the number of zeros of f(z) in 10,
0
z
M
a
, does not exceed
2. On the Zeros of Analytic Functions inside the Unit Disk
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0
0
00 2
log
1
log
1
a
j
j
,
where
1
00 2
j
jM .
If the coefficients ja are real i.e. njj ,....,1,0,0 , we get the following result from Theorem 1:
Corollary 2 : Let 0)(
0
j
j
j zazf be analytic for 1z , where
......210 aaa ,
then the number of zeros of f(z) in 10,
0
z
M
a
, does not exceed
0
002
log
1
log
1
a
aa
,
where
02 aM .
Taking 0)1( k , 1k , we get the following result from Theorem 1:
Corollary 3 : Let 0)(
0
j
j
j zazf be analytic for 1z , where
njia jjj ,......,1,0, . If for some 1k ,
......210 k ,
then the number of zeros of f(z) in 10,
0
z
M
a
, does not exceed
0
0
00 2)12(
log
1
log
1
a
k
j
j
,
where
1
00 2)12(
j
jkM
Applying Theorem 1 to the function –if(z), we get the following result:
Theorem 2 : Let 0)(
0
j
j
j zazf be analytic for 1z , where njia jjj ,......,1,0, . If for
some 0 ,
......210 ,
then the number of zeros of f(z) in 10,
0
z
M
a
, does not exceed
3. On the Zeros of Analytic Functions inside the Unit Disk
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0
0
00 22
log
1
log
1
a
j
j
,
where
1
00 22
j
jM .
Theorem 3 : Let 0)(
0
j
j
j zazf be analytic for 1z . If for some 0 ,
......210 aaa ,
and for real some ,
nja j ,.......,1,0,
2
arg
,
then the number of zeros of f(z) in 10,
0
z
M
a
, does not exceed
0
1
0 sin)1sin)(cos(
log
1
log
1
a
aa
j
j
,
where
1
0 sin)sin)(cos(
j
jaM .
Taking 0 , Theorem 3 reduces to the following result:
Corollary 4:Let 0)(
0
j
j
j zazf be analytic for 1z . If,
......210 aaa ,
and for some real ,
nja j ,.......,1,0,
2
arg
,
then the number of zeros of f(z) in 10,
0
z
M
a
, does not exceed
0
1
0 sin)1sin(cos
log
1
log
1
a
aa
j
j
,
where
1
0 sin)sin(cos
j
jaaM .
Taking 0)1( ak , 1k , we get the following result from Theorem 3:
4. On the Zeros of Analytic Functions inside the Unit Disk
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Corollary 5:Let 0)(
0
j
j
j zazf be analytic for 1z . If,
......210 aaak ,
and for some real ,
nja j ,.......,1,0,
2
arg
,
then the number of zeros of f(z) in 10,0
z
M
a
does not exceed
0
1
0 sin)1sin(cos
log
1
log
1
a
aak
j
j
,
where
1
00 sin)sin(cos2
j
jaakM .
2. Lemmas
For the proofs of the above results we need the following results:
Lemma 1 : Let f(z) be analytic for 1z , 0)0( f and Mzf )( for 1z ,
Then the number of zeros of f(z) in 10, z , does not exceed
)0(
log
1
log
1
f
M
(see [7] , page 171 ).
Lemma 2 : If for some t>0, 1 jj ata and ,...2,1,0,
2
arg ja j
, for some real , then
sin)(cos)( 111 jjjjjj ataataata .
The proof of Lemma 2 follows from a lemma of Govil and Rahman [3].
3. Proofs of Theorems:
Proof of Theorem 1: Consider the function
)()1()( zfzzF
......))(1( 2
210 zazaaz
......)()( 2
21100 zaazaaa
......)()( 2
21100 zzz
......})(){( 21100 zzii .
For 1z ,
03221100 ......)( zF
......2110
0
00 22
j
j .
5. On the Zeros of Analytic Functions inside the Unit Disk
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Since F(z) is analytic for 1z , 0)0( 0 aF , it follows , by using Lemma 1, that the number of zeros of
F(z) in 10, z , does not exceed
0
0
00 22
log
1
log
1
a
j
j
.
On the other hand, consider
)()1()( zfzzF
......))(1( 2
210 zazaaz
......)()( 2
21100 zaazaaa
)(0 zqa ,
where
......)()()( 2
2110 zaazaazq
......)()( 2
2110 zzz
......})(){( 2
2110 zzi
For 1z ,
............)( 21102110 zq
M
j
j
1
00 22 .
Since q(z ) is analytic for 1z , q(0)=0, it follows , by Schwarz’s lemma , that
zMzq )( for 1z .
Hence for 1z ,
)()( 0 zqazF
)(0 zqa
zMa 0
0
if
M
a
z
0
.
This shows that all the zeros of F(z) lie in
M
a
z
0
. Since the zeros of f(z) are also the zeros of F(z), it
follows that all the zeros of f(z) lie in
M
a
z
0
. Thus, the number of zeros of f(z) in
10,
0
z
M
a
, does not exceed
6. On the Zeros of Analytic Functions inside the Unit Disk
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0
0
00 22
log
1
log
1
a
j
j
.
Proof of Theorem 2: Consider the function
)()1()( zfzzF
......))(1( 2
210 zazaaz
......)()( 2
21100 zaazaaa
......)()( 2
21100 zaazaaza
For 1z , we have, by using the hypothesis and Lemma 2,
sin)(cos)[()( 10100 aaaaazF
......sin)(cos)( 2121 aaaa
1
0 sin)1sin)(cos(
j
jaa .
Since F(z) is analytic for 1z , 0)0( 0 aF , it follows , by using the lemma 1, that the number of zeros
of F(z) in 10, z , does not exceed
0
1
0 sin)1sin)(cos(
log
1
log
1
a
aa
j
j
.
Again , Consider the function
)()1()( zfzzF
......))(1( 2
210 zazaaz
......)()( 2
21100 zaazaaa
......)()( 2
21100 zaazaaza
)(0 zqa ,
where
......)()()( 2
2110 zaazaazq
......)()( 2
2110 zaazaaz
For 1z , by using lemma 2, we have,
sin)(cos)()( 1010 aazq
......sin)(cos)( 2121 aaaa
Maa
j
j
1
0 sin)sin)(cos( .
Since q(z ) is analytic for 1z , q(0)=0, it follows , by Schwarz’s lemma , that
zMzq )( for 1z .
Hence for 1z ,
)()( 0 zqazF
7. On the Zeros of Analytic Functions inside the Unit Disk
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)(0 zqa
zMa 0
0
if
M
a
z
0
.
This shows that all the zeros of F(z) lie in
M
a
z
0
. Since the zeros of f(z) are also the zeros of F(z), it
follows that all the zeros of f(z) lie in
M
a
z
0
. Thus, the number of zeros of f(z) in
10,
0
z
M
a
, does not exceed
0
1
0 sin)1sin)(cos(
log
1
log
1
a
aa
j
j
.
References
[1] K. K. Dewan, Extremal Properties and Coefficient estimates for polynomials with restricted zeros and on location of zeros of
polynomials, Ph.D Thesis,IIT Delhi, !980.
[2] K. K.Dewan, Theory of Polynomials and Applications,Deep & Deep Publications Pvt. Ltd., New Delhi, 2007.
[3] N. K. Govil and Q. I. Rahman, On the Enestrom-Kakeya Theorem, Tohoku Math. J .20(1968), 126-136.
[4] M. H. Gulzar, On the number of zeros of a polynomial in a prescribed region, Research Journal of Pure Algebra-2(2), Feb. 2012, 35-
46.
[5] M. Marden, Geometry of Polynomials, IInd. Ed. Math. Surveys, No.3, Amer. Math. Soc. Providence, R.I. 1966.
[6] Q. G. Mohammad, On the Zeros of Polynomials, Amer. Math. Monthly, 72 (1965), 631-633.
[7] E. C Titchmarsh, The Theory of Functions, 2nd
edition, Oxford University Press, London, 1939.