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Optics
• Reflection                  • Prisms
• Diffuse reflection          • Rainbows
• Refraction                  • Plane mirrors
• Index of refraction         • Spherical aberration
• Speed of light              • Concave and convex mirrors
• Snell’s law                 • Focal length & radius of curvature
• Geometry problems           • Mirror / lens equation
• Critical angle              • Convex and concave lenses
• Total internal reflection   • Human eye
• Brewster angle              • Chromatic aberration
• Fiber optics                • Telescopes
• Mirages                     • Huygens’ principle
• Dispersion                  • Diffraction
Reflection
Most things we see are thanks to reflections, since most objects
don’t produce their own visible light. Much of the light incident
on an object is absorbed but some is reflected. the wavelengths of
the reflected light determine the colors we see. When white light
hits an apple, for instance, primarily red wavelengths are
reflected, while much of the others are absorbed.
A ray of light heading towards an object is called an incident ray.
If it reflects off the object, it is called a reflected ray. A
perpendicular line drawn at any point on a surface is called a
normal (just like with normal force). The angle between the
incident ray and normal is called the angle of incidence, i, and
the angle between the reflected ray and the normal ray is called
the angle of reflection, r. The law of reflection states that the
angle of incidence is always equal to the angle of reflection.
Law of Reflection


                       Normal line (perpendicular to
                       surface)
inc




                              ys
             i    r




                              ra
 ide




                         t ed
  nt




                          c
                      fle
      ra y




                   re
       s




                 i=r
Diffuse Reflection
Diffuse reflection is when light bounces off a non-smooth surface.
 Each ray of light still obeys the law of reflection, but because the
surface is not smooth, the normal can point in a different for
every ray. If many light rays strike a non-smooth surface, they
could be reflected in many different directions. This explains
how we can see objects even when it seems the light shining upon
it should not reflect in the direction of our eyes. It also helps to
explain glare on wet roads: Water fills in and smoothes out the
rough road surface so that the road becomes more like a mirror.
Speed of Light & Refraction

As you have already learned, light is extremely fast, about
3 × 108 m/s in a vacuum. Light, however, is slowed down by the
presence of matter. The extent to which this occurs depends on
what the light is traveling through. Light travels at about 3/4 of its
vacuum speed (0.75 c ) in water and about 2/3 its vacuum speed
(0.67 c ) in glass. The reason for this slowing is because when
light strikes an atom it must interact with its electron cloud. If
light travels from one medium to another, and if the speeds in
these media differ, then light is subject to refraction (a changing
of direction at the interface).

  Refraction of                           Refraction of
  light waves                             light rays
Reflection & Refraction
At an interface between two media, both reflection and refraction can
occur. The angles of incidence, reflection, and refraction are all measured
with respect to the normal. The angles of incidence and reflection are
always the same. If light speeds up upon entering a new medium, the angle
of refraction, θr , will be greater than the angle of incidence, as depicted on
the left. If the light slows down in the new medium, θr will be less than
the angle of incidence, as shown on the right.
Inc                                Ray Inc                                                ay
    ide                       te d         ide                                          dR
        nt                lec                  nt                                c te
           Ra           ef                        Ra                          fle
              y       R                              y                   Re


                        θr




                                                                   Re
                              Refr
               normal




                                                          normal
                                   ac




                                                                      fr
                                        ted R




                                                                        act
                                             ay
                                                                   θr



                                                                         ed
                                                                            R
                                                                           ay
Axle Analogy
Imagine you’re on a skateboard heading from the sidewalk toward some
grass at an angle. Your front axle is depicted before and after entering the
grass. Your right contacts the grass first and slows, but your left wheel is
still moving quickly on the sidewalk. This causes a turn toward the normal.
If you skated from grass to sidewalk, the same path would be followed. In
this case your right wheel would reach the sidewalk first and speed up, but
your left wheel would still be moving more slowly. The result this time
would be turning away from the normal. Skating from sidewalk to grass is
like light traveling from air to a more
                                                                 overhead view
“optically dense” medium like glass
or water. The slower light travels in
the new medium, the more it bends
toward the normal. Light traveling
                                         sidewalk
from water to air speeds up and            grass
bends away from the normal. As
with a skateboard, light traveling
along the normal will change speed                     θr
but not direction.
Index of Refraction, n
 The index of refraction of a substance is the ratio of the speed in light
 in a vacuum to the speed of light in that substance:
              c
           n=
              v
                                          Medium             n
 n = Index of Refraction
                                          Vacuum             1
 c = Speed of light in vacuum
                                          Air (STP)          1.00029
 v = Speed of light in medium
                                          Water (20º C) 1.33
Note that a large index of refraction
corresponds to a relatively slow          Ethanol            1.36
light speed in that medium.               Glass              ~1.5
                                          Diamond            2.42
θi
               Snell’s Law                                     ni
                                                               nr
                                                          θr
Snell’s law states that a ray of light bends in
such a way that the ratio of the sine of the
angle of incidence to the sine of the angle of
refraction is constant. Mathematically,

            ni sinθ i = nr sinθr
Here ni is the index of refraction in the original
medium and nr is the index in the medium the
light enters. θ i and θr are the angles of
incidence and refraction, respectively.
                                                      Willebrord
                                                        Snell
Snell’s Law Derivation      Two parallel rays are shown.
                            Points A and B are directly
                            opposite one another. The top
                            pair is at one point in time, and
                            the bottom pair after time t.
              A        θ1   The dashed lines connecting
n1        x   •             the pairs are perpendicular to
     A                      the rays. In time t, point A
                  d
          •            •B   travels a distance x, while
                        y
n2                          point B travels a distance y.
                      •B
                            sinθ1 = x / d, so x = d sinθ1

     θ2                     sinθ2 = y / d, so y = d sinθ2
                            Speed of A: v1 = x / t
                            Speed of B: v2 = y / t
                                              Continued…
Snell’s Law Derivation
                                                     (cont.)
              A        θ1
n1        x   •
     A            d
         •             •B                v1   x/ t   x   sinθ1
                        y                   =      =   =                   So,
n2                    •B                 v2   y/ t   y   sinθ2

     θ2
                            v1 / c       sinθ1       1 / n1        sinθ1       n2
                                     =           ⇒             =           =
                            v2 / c       sinθ2       1 / n2        sinθ2       n1


                                     ⇒ n1 sinθ1 = n2 sinθ2
Refraction Problem #1
  Goal: Find the angular displacement of the ray after having passed
  through the prism. Hints:       1. Find the first angle of refraction
                                      using Snell’s law. 19.4712º
                                    2. Find angle ø. (Hint: Use
                                       Geometry skills.) 79.4712º
        Air, n1 = 1
                            30°     3. Find the second angle of
                                       incidence.        10.5288º
                                    4. Find the second angle of
Horiz. ray,                            refraction, θ, using Snell’s Law
parallel to
                                ø
                                    θ                     15.9º
base

              Glass, n2 = 1.5
Refraction Problem #2
Goal: Find the distance the light ray displaced due to the thick
window and how much time it spends in the glass. Some hints are
given.
        20º θ1                       1. Find θ1 (just for fun).    20º
                      H20
                     n1 = 1.3        2. To show incoming & outgoing
                                        rays are parallel, find θ. 20º
                                    3. Find d.    0.504 m
                       glass
   10m
                       n2 = 1.5     4. Find the time the light spends in
                                                           5.2 · 10-8 s
                   d      H20          the glass.
               θ
                                    Extra practice: Find θ if bottom
                                    medium is replaced with air.
                                                         26.4º
Refraction Problem #3
Goal: Find the exit angle relative to the horizontal.


                                          θ = 19.8°
                  36°



air

                 glass              θ=?


      The triangle is isosceles.
      Incident ray is horizontal,
      parallel to the base.
Reflection Problem
Goal: Find incident angle relative to horizontal so that reflected ray
will be vertical.



                                             θ = 10º
        θ


                50º

                  center of
            semicircular mirror
            with horizontal base
Brewster Angle
The Brewster angle is the angle of incidence the produces reflected
and refracted rays that are perpendicular.
 From Snell, n1 sinθb = n2 sinθ.
                                                     n2      θ
 α = θb since α + β = 90º,                                        α
        and θb + β = 90º.                                        β
                                                     n1
                                                          θb θb
 β = θ since α + β = 90º,
       and θ + α = 90º. Thus,
 n1 sinθb = n2 sinθ = n2 sinβ = n2 cosθb


              tanθb = n2 / n1            Sir David
                                         Brewster
Critical Angle
The incident angle that causes         nr
the refracted ray to skim right
                                       ni
along the boundary of a                         θc
substance is known as the critical
angle, θc. The critical angle is the
angle of incidence that produces       From Snell,
an angle of refraction of 90º. If      n1 sinθc = n2 sin 90°
the angle of incidence exceeds
the critical angle, the ray is         Since sin 90° = 1, we
completely reflected and does          have n1 sinθc = n2 and
not enter the new medium. A            the critical angle is
critical angle only exists when
light is attempting to penetrate a                         nr
medium of higher optical density            θc = sin-1
than it is currently traveling in.
                                                           ni
Critical Angle Sample Problem
  Calculate the critical angle for the diamond-air boundary.
  Refer to the Index of Refraction chart for the information.



   air                             θc = sin-1 (nr / ni)
diamond                            = sin-1 (1 / 2.42)
          θc
                                         = 24.4°
                                  Any light shone on this
                              boundary beyond this angle
                              will be reflected back into the
                                          diamond.
Total Internal Reflection
Total internal reflection occurs when light attempts to pass
from a more optically dense medium to a less optically dense
medium at an angle greater than the critical angle. When this
occurs there is no refraction, only reflection.



                n1                          n2 > n1
                n2      θ                   θ > θc


Total internal reflection can be used for practical applications
like fiber optics.
Fiber Optics
                         Fiber optic lines are strands of glass or
                         transparent fibers that allows the transmission
                         of light and digital information over long
                         distances. They are used for the telephone
                         system, the cable TV system, the internet,
                         medical imaging, and mechanical engineering
spool of optical fiber   inspection.

  Optical fibers have many advantages over
  copper wires. They are less expensive,
  thinner, lightweight, and more flexible. They
  aren’t flammable since they use light signals
  instead of electric signals. Light signals from
  one fiber do not interfere with signals in
  nearby fibers, which means clearer TV                 A fiber optic wire
  reception or phone conversations.
                                                            Continued…
Fiber Optics Cont.
Fiber optics are often long strands
of very pure glass. They are very
thin, about the size of a human
hair. Hundreds to thousands of
them are arranged in bundles
(optical cables) that can transmit
light great distances. There are
three main parts to an optical
fiber:
    • Core- the thin glass center where light travels.
    • Cladding- optical material (with a lower index of refraction
    than the core) that surrounds the core that reflects light back into
    the core.
    • Buffer Coating- plastic coating on the outside of an optical
    fiber to protect it from damage.                      Continued…
Light travels through the core of a
fiber optic by continually                 Fiber Optics      (cont.)
reflecting off of the cladding. Due
to total internal reflection, the
cladding does not absorb any of
the light, allowing the light to      There are two types of optical
travel over great distances. Some     fibers:
of the light signal will degrade        • Single-mode fibers- transmit
over time due to impurities in the      one signal per fiber (used in
glass.                                  cable TV and telephones).
                                       • Multi-mode fibers- transmit
                                       multiple signals per fiber (used
                                       in computer networks).
Mirage Pictures
Mirages
Mirages are caused by the refracting properties of a
non-uniform atmosphere.
Several examples of mirages include seeing “puddles”
ahead on a hot highway or in a desert and the lingering
daylight after the sun is below the horizon.




                   More Mirages
                                                       Continued…
Inferior Mirages
                                             A person sees a puddle ahead on
                                             the hot highway because the road
                                             heats the air above it, while the
                                             air farther above the road stays
                                             cool. Instead of just two layers,
                                             hot and cool, there are really
many layers, each slightly hotter than the layer above it. The cooler air has a
slightly higher index of refraction than the warm air beneath it. Rays of
light coming toward the road gradually refract further from the normal,
more parallel to the road. (Imagine the wheels and axle: on a light ray
coming from the sky, the left wheel is always in slightly warmer air than the
right wheel, so the left wheel continually moves faster, bending the axle
more and more toward the observer.) When a ray is bent enough, it
surpasses the critical angle and reflects. The ray continues to refract as it
heads toward the observer. The “puddle” is really just an inverted image of
the sky above. This is an example of an inferior mirage, since the cool are is
above the hot air.
Superior Mirages
Superior mirages occur when a
layer of cool air is beneath a layer
of warm air. Light rays are bent
downward, which can make an
object seem to be higher in the air
and inverted. (Imagine the
wheels and axle on a ray coming
from the boat: the right wheel is
continually in slightly warmer air
than the left wheel. Thus, the right
wheel moves slightly faster and
bends the axle toward the
observer.) When the critical angle
is exceeded the ray reflects. These
mirages usually occur over ice, snow, or cold water. Sometimes superior
images are produced without reflection. Eric the Red, for example, was able to
see Greenland while it was below the horizon due to the light gradually
refracting and following the curvature of the Earth.
Sunlight after Sunset
Lingering daylight after the sun
is below the horizon is another       Apparent
effect of refraction. Light travels position                    Observer
at a slightly slower speed in         of sun
Earth’s atmosphere than in
space. As a result, sunlight is
                                          Actual
refracted by the atmosphere. In
                                          position                 Earth
the morning, this refraction
                                          of sun
causes sunlight to reach us
before the sun is actually above           Atmosphere
the horizon. In the evening, the
sunlight is bent above the horizon after the sun has actually set. So
daylight is extended in the morning and evening because of the
refraction of light. Note: the picture greatly exaggerates this effect as
well as the thickness of the atmosphere.

                                          Different “shapes” of Sun
Dispersion of Light
Dispersion is the separation of light into a spectrum by refraction. The
index of refraction is actually a function of wavelength. For longer
wavelengths the index is slightly small. Thus, red light refracts less than
violet. (The pic is exaggerated.) This effect causes white light to split
into it spectrum of colors. Red light travels the fastest in glass, has a
smaller index of refraction, and bends the least. Violet is slowed down
the most, has the largest index, and bends the most. In other words: the
higher the frequency, the greater the bending.
                                                            Animation
Atmospheric Optics
There are many natural occurrences of light optics in our atmosphere.
                                 One of the most common of these is
                                 the rainbow, which is caused by
                                 water droplets dispersing sunlight.
                                 Others include arcs, halos, cloud
                                 iridescence, and many more.
                                  Photo gallery of atmospheric optics.
Rainbows                        A rainbow is a spectrum
                                              formed when sunlight is
                                              dispersed by water droplets in
                                              the atmosphere. Sunlight
                                              incident on a water droplet is
                                              refracted. Because of
                                              dispersion, each color is
                                              refracted at a slightly different
                                              angle. At the back surface of
                                              the droplet, the light undergoes
                                              total internal reflection. On the
way out of the droplet, the light is once more refracted and dispersed.
Although each droplet produces a complete spectrum, an observer will
only see a certain wavelength of light from each droplet. (The wavelength
depends on the relative positions of the sun, droplet, and observer.)
Because there are millions of droplets in the sky, a complete spectrum is
seen. The droplets reflecting red light make an angle of 42 o with respect to
the direction of the sun’s rays; the droplets reflecting violet light make an
angle of 40o.                                       Rainbow images
Primary Rainbow
Secondary                    Secondary Rainbow
                      The secondary rainbow is a rainbow of radius
                      51°, occasionally visible outside the primary
                      rainbow. It is produced when the light
            Primary
                      entering a cloud droplet is reflected twice
                      internally and then exits the droplet. The color
                      spectrum is reversed in respect to the primary
                      rainbow, with red appearing on its inner edge.
Alexander’s
dark region
Supernumerary Arcs
Supernumerary arcs are faint arcs of color
just inside the primary rainbow. They
occur when the drops are of uniform size.
If two light rays in a raindrop are
scattered in the same direction but have
take different paths within the drop, then
they could interfere with each other
constructively or destructively. The type
of interference that occurs depends on the
difference in distance traveled by the
rays. If that difference is nearly zero or a
multiple of the wavelength, it is
constructive, and that color is reinforced.
If the difference is close to half a
wavelength, there is destructive
interference.
Real vs. Virtual Images
Real images are formed by mirrors or lenses when light rays
actually converge and pass through the image. Real images will be
located in front of the mirror forming them. A real image can be
projected onto a piece of paper or a screen. If photographic film
were placed here, a photo could be created.

Virtual images occur where light rays only appear to have
originated. For example, sometimes rays appear to be coming from
a point behind the mirror. Virtual images can’t be projected on
paper, screens, or film since the light rays do not really converge
there.


Examples are forthcoming.
Plane Mirror
                                                 Object
 Rays emanating from an object at point P
strike the mirror and are reflected with equal
angles of incidence and reflection. After
                                                   P                     P’
reflection, the rays continue to spread. If we
extend the rays backward behind the mirror,                         Virtual
they will intersect at point P’, which is the                       Image
image of point P. To an observer, the rays
appear to come from point P’, but no source is
there and no rays actually converging there .
For that reason, this image at P’ is a virtual
image.                                                    do       di

                                                   O                    I
The image, I, formed by a plane mirror
of an object, O, appears to be a
distance di , behind the mirror, equal
to the object distance do.
             Animation                                         Continued…
Plane Mirror           (cont.)
Two rays from object P strike the mirror at points B and M. Each ray is
reflected such that i = r.
 Triangles BPM and BP’M are                 P       do     B        di    P’
 congruent by ASA (show this),
 which implies that do= di and
 h = h’. Thus, the image is the         h                  M                h’
 same distance behind the mirror
                                        Object                           Image
 as the object is in front of it, and
 the image is the same size as the
 object.

  object                     image
                                                           Mirror

With plane mirrors, the image is reversed left to right (or the front and
back of an image ). When you raise your left hand in front of a mirror,
your image raises its right hand. Why aren’t top and bottom reversed?
Concave and Convex Mirrors
 Concave and convex mirrors are curved mirrors similar to portions
 of a sphere.



 light rays                            light rays




Concave mirrors reflect light          Convex mirrors reflect light
from their inner surface, like         from their outer surface, like
   the inside of a spoon.                 the outside of a spoon.
Concave Mirrors
• Concave mirrors are approximately spherical and have a principal
axis that goes through the center, C, of the imagined sphere and ends
at the point at the center of the mirror, A. The principal axis is
perpendicular to the surface of the mirror at A.
• CA is the radius of the sphere,or the radius
of curvature of the mirror, R .
• Halfway between C and A is the focal
point of the mirror, F. This is the point
where rays parallel to the principal axis will
converge when reflected off the mirror.
• The length of FA is the focal length, f.
• The focal length is half of the radius of the
sphere (proven on next slide).
r = 2f
To prove that the radius of curvature of a concave mirror is
twice its focal length, first construct a tangent line at the
point of incidence. The normal is perpendicular to the
tangent and goes through the center, C. Here, i = r = β. By
alt. int. angles the angle at C is also β, and α = 2 β. s is the
arc length from the principle axis to the pt. of incidence.
Now imagine a sphere centered
at F with radius f. If the incident




                                                          tan
                                                            ge
ray is close to the principle axis,
                                                        β




                                                               ntl
the arc length of the new sphere                          β s




                                                                ine
is about the same as s. From                     β        α
s = r θ, we have s = r β and                  •
                                              C         • f
                                                        F
s ≈ f α = 2 f β. Thus, r β ≈ 2 f β,
and r = 2 f.                                          r
Focusing Light with Concave Mirrors

 Light rays parallel to the principal axis will be
 reflected through the focus (disregarding spherical
 aberration, explained on next slide.)



                           In reverse, light rays passing through the
                           focus will be reflected parallel to the
                           principal axis, as in a flood light.


Concave mirrors can form both real and virtual images, depending on
where the object is located, as will be shown in upcoming slides.
Spherical Aberration

                                                                     F
       •
       F
               •
               C                                             •
                                                             C
                                                                       •

     Spherical Mirror                                        Parabolic Mirror

Only parallel rays close to the principal axis of a spherical mirror will
converge at the focal point. Rays farther away will converge at a point
closer to the mirror. The image formed by a large spherical mirror will be
a disk, not a point. This is known as spherical aberration.
Parabolic mirrors don’t have spherical aberration. They are used to focus
rays from stars in a telescope. They can also be used in flashlights and
headlights since a light source placed at their focal point will reflect light
in parallel beams. However, perfectly parabolic mirrors are hard to make
and slight errors could lead to spherical aberration.         Continued…
Spherical vs. Parabolic Mirrors
Parallel rays converge at the      Parabolic mirrors have no
focal point of a spherical         spherical aberration. The
mirror only if they are close to   mirror focuses all parallel rays
the principal axis. The image      at the focal point. That is why
formed in a large spherical        they are used in telescopes and
mirror is a disk, not a point      light beams like flashlights and
(spherical aberration).            car headlights.
Concave Mirrors: Object beyond C


object                 The image formed
                       when an object is
                       placed beyond C is
         •
         C
                •
                F      located between C and
                       F. It is a real, inverted
             image
                       image that is smaller in
                       size than the object.
         Animation 1
         Animation 2
Concave Mirrors: Object between C and F

                    The image formed
      object        when an object is
                    placed between C and F
      •
      C
               •
               F    is located beyond C. It
                    is a real, inverted image
    image           that is larger in size
                    than the object.
      Animation 1
      Animation 2
Concave Mirrors: Object in front of F
                         The image formed
                         when an object is
                         placed in front of F is
     object              located behind the
                 image
                         mirror. It is a virtual,
 •
 C
       •
       F                 upright image that is
                         larger in size than the
                         object. It is virtual
                         since it is formed only
     Animation           where light rays seem
                         to be diverging from.
Concave Mirrors: Object at C or F

 What happens when an object is placed at C?
   The image will be formed at C also, but it
    will be inverted. It will be real and the
            same size as the object.
Animation
 What happens when an object is placed at F?
    No image will be formed. All rays will
  reflect parallel to the principal axis and will
  never converge. The image is “at infinity.”
Convex Mirrors
• A convex mirror has the
same basic properties as a         light rays
concave mirror but its focus
and center are located behind
the mirror.
• This means a convex mirror
has a negative focal length     • Rays parallel to the principal
(used later in the mirror       axis will reflect as if coming
equation).                      from the focus behind the
                                mirror.
• Light rays reflected from
convex mirrors always           • Rays approaching the mirror
diverge, so only virtual        on a path toward F will reflect
images will be formed.          parallel to the principal axis.
Convex Mirror Diagram
                        The image formed by
                        a convex mirror no
                        matter where the
object                  object is placed will
            image
                        be virtual, upright,
              •
              F
                    •
                    C
                        and smaller than the
                        object. As the object
                        is moved closer to the
                        mirror, the image will
                        approach the size of
                        the object.
Mirror/Lens Equation Derivation
                          From ∆PCO, β = θ + α, so 2β = 2θ + 2α.
                          From ∆PCO, γ = 2θ + α , so -γ = -2θ - α.

    P                           Adding equations yields 2β - γ = α.
             θ                        object   From s = r θ, we have
s        θ
        γ                                      s = r β, s ≈ di α, and
                 β                α
          T           •
                      C                  O     s ≈ di α (for rays
        image                                  close to the principle
                                               axis). Thus:
                                                     s      α≈     s
                                               β= r                d
                                                                  o
        di
                                               γ≈ s
                          do                      di
                                                                 (cont.)
Mirror/Lens Equation Derivation                (cont.)
 From the last slide, β = s / r, α ≈ s / d0 , γ ≈ s / di , and 2 β - γ = α.
                            Substituting into the last equation yields:
    P
                                                        2s    s         s
s        θ
             θ                       object
                                                           r -d  = d
                                                                i    o
        γ        β              α                          2   1    1
          T          •
                     C                   O                 r = di + do
        image
                                                       2    1  1
                                                          = d +d
                                                       2f    i   o

        di                                             1       1  1
                                                             = d +d
                                                       f        i   o
                         do
The last equation applies to convex and concave mirrors, as well as to
lenses, provided a sign convention is adhered to.
Mirror Sign Convention
                     f = focal length
1   1     1
                     di = image distance
f = d i + do
                     do = object distance

               + for real image
      di
               - for virtual image

               + for concave mirrors
       f
               - for convex mirrors
Magnification
                    hi
 By definition, m =
                    ho
m = magnification
hi = image height (negative means inverted)
ho = object height

Magnification is simply the ratio of image height
to object height. A positive magnification means
an upright image.
hi -di
  Magnification Identity: m =   =
                              ho do
To derive this let’s look at two rays. One hits the mirror on the axis.
The incident and reflected rays each make angle θ relative to the axis.
A second ray is drawn through the center and is reflected back on top
of itself (since a radius is always perpendicular to an tangent line of a
                                            circle). The intersection of
                                            the reflected rays
                                    object
                                            determines the location of
         θ                            ho    the tip of the image. Our
               •   C
                                            result follows
           image,                           from similar triangles, with
                                            the negative sign a
           height = hi
                                            consequence of our sign
                                            convention. (In this picture
      di             do                     hi is negative and di is
                                            positive.)
Mirror Equation Sample Problem
             Suppose AllStar, who is 3 and
             a half feet tall, stands 27 feet
             in front of a concave mirror
             with a radius of curvature of
 •
 C
     •
     F       20 feet. Where will his image
             be reflected and what will its
             size be?

                  di = 15.88 feet

                  hi = -2.06 feet
Mirror Equation Sample Problem 2
                  Casey decides to join in
                  the fun and she finds a
                  convex mirror to stand
                  in front of. She sees her
                  image reflected 7 feet
                  behind the mirror which
         •
         F
              •
              C   has a focal length of 11
                  feet. Her image is 1
                  foot tall. Where is she
                  standing and how tall is
                  she? d =19.25 feet
                          o

                         ho = 2.75 feet
Lenses
Lenses are made of transparent            Convex (Converging)
materials, like glass or plastic, that           Lens
typically have an index of refraction
greater than that of air. Each of a lens’
two faces is part of a sphere and can be
convex or concave (or one face may be
flat). If a lens is thicker at the center
than the edges, it is a convex, or        Concave (Diverging)
converging, lens since parallel rays will        Lens
be converged to meet at the focus. A
lens which is thinner in the center than
the edges is a concave, or diverging,
lens since rays going through it will be
spread out.
Lenses: Focal Length

• Like mirrors, lenses have a principal axis perpendicular to their
surface and passing through their midpoint.
• Lenses also have a vertical axis, or principal plane, through their
middle.




• They have a focal point, F, and the focal length is the distance from
the vertical axis to F.
• There is no real center of curvature, so 2F is used to denote twice
the focal length.
Ray Diagrams For Lenses
When light rays travel through a lens, they refract at both surfaces of
the lens, upon entering and upon leaving the lens. At each interface
the bends toward the normal. (Imagine the wheels and axle.) To
simplify ray diagrams, we often pretend that all refraction occurs at
the vertical axis. This simplification works well for thin lenses and
provides the same results as refracting the light rays twice.




    • •
    2F F              • 2F
                      F •                 • •
                                          2F F             • 2F
                                                           F •

            Reality                          Approximation
Convex Lenses

Rays traveling parallel to the principal
axis of a convex lens will refract toward     • •
                                              2F F              • 2F
                                                                F •
the focus.


                                   Rays traveling from the focus will
  • F
  2F •             • 2F
                   F •             refract parallel to the principal axis.




Rays traveling directly through the
center of a convex lens will leave the        • •
                                              2F F              • 2F
                                                                F •
lens traveling in the exact same
direction.
Convex Lens: Object Beyond 2F

                                         The image formed
                                         when an object is
object
                                         placed beyond 2F
                                         is located behind
         •     •            •       •    the lens between F
         2F    F            F       2F   and 2F. It is a real,
                            image        inverted image
                                         which is smaller
                                         than the object
         Experiment with this diagram
                                         itself.
Convex Lens: Object Between 2F and F

                                The image formed
object                          when an object is
                                placed between
                                2F and F is
•
2F
          •
          F
                   •
                   F
                        •
                        2F      located beyond 2F
                                behind the lens.
                                It is a real,
                       image    inverted image,
                                larger than the
                                object.
Convex Lens: Object within F
                             The image formed when an
                             object is placed in front of
                             F is located somewhere
image                        beyond F on the same side
                             of the lens as the object. It
                             is a virtual, upright image
  •
  2F
         •
         F
                    •
                    F
                        •
                        2F   which is larger than the
        object               object. This is how a
                             magnifying glass works.
                             When the object is brought
                             close to the lens, it will be
 convex lens used            magnified greatly.
 as a magnifier
Concave Lenses
                          Rays traveling parallel to the
                          principal axis of a concave lens will
•
2   •
    F         •
              F    •
                   2
                          refract as if coming from the focus.

F                  F

    Rays traveling toward the
                                     2F •
                                     • F             • 2
                                                     F •
    focus will refract parallel to
    the principal axis.
                                                           F


                          Rays traveling directly through the
2F •
• F           • 2
              F •         center of a concave lens will leave
                          the lens traveling in the exact same
                    F
                          direction, just as with a convex lens.
Concave Lens Diagram


                                        No matter where the
                                        object is placed, the
object
                                        image will be on the
                                        same side as the
    •
    2F
          •
          F
                       •
                       F
                             •
                             2F         object. The image is
         image                          virtual, upright, and
                                        smaller than the object
                                        with a concave lens.
         Experiment with this diagram
Lens Sign Convention
                      f = focal length
1   1  1
f = d +d              di = image distance
     i   o
                      do = object distance

              + for real image
    di
              - for virtual image

              + for convex lenses
    f
              - for concave lenses
Lens / Mirror Sign Convention

 The general rule for lenses and mirrors is this:

                        + for real image
             di
                        - for virtual image

and if the lens or mirror has the ability to converge light,
f is positive. Otherwise, f must be treated as negative for
the mirror/lens equation to work correctly.
Lens Sample Problem
                       Tooter, who stands 4 feet
                       tall (counting his
                       snorkel), finds himself 24
                       feet in front of a convex
                       lens and he sees his
                       image reflected 35 feet
•
2F
     •
     F
            •
            F
                •
                2F     behind the lens. What is
                       the focal length of the
                       lens and how tall is his
                       image?
                        f = 14.24 feet
                        hi = -5.83 feet
Lens and Mirror Applet
This application shows where images will be formed
with concave and convex mirrors and lenses. You can
change between lenses and mirrors at the top. Changing
the focal length to negative will change between
concave and convex lenses and mirrors. You can also
move the object or the lens/mirror by clicking and
dragging on them. If you click with the right mouse
button, the object will move with the mirror/lens. The
focal length can be changed by clicking and dragging at
the top or bottom of the lens/mirror. Object distance,
image distance, focal length, and magnification can also
be changed by typing in values at the top.

                Lens and Mirror Diagrams
Convex Lens in Water
    Glass                                                   Glass




  H2O                                            Air

Because glass has a higher index of refraction that water the convex
lens at the left will still converge light, but it will converge at a
greater distance from the lens that it normally would in air. This is
due to the fact that the difference in index of refraction between
water and glass is small compared to that of air and glass. A large
difference in index of refraction means a greater change in speed of
light at the interface and, hence, a more dramatic change of
direction.
Convex Lens Made of Water
           Glass
                   Since water has a higher index of
                   refraction than air, a convex lens made of
                   water will converge light just as a glass
                   lens of the same shape. However, the
Air                glass lens will have a smaller focal length
      n = 1.5      than the water lens (provided the lenses
                   are of same shape) because glass has an
                   index of refraction greater than that of
                   water. Since there is a bigger difference
H2O                in refractive index at the air-glass
                   interface than at the air-water interface,
                   the glass lens will bend light more than
                   the water lens.
Air
      n = 1.33
Air & Water Lenses
                          On the left is depicted a concave lens filled
                          with water, and light rays entering it from an
                          air-filled environment. Water has a higher
                          index than air, so the rays diverge just like
 Air                      they do with a glass lens.
Concave lens made of H2O

To the right is an air-filled convex lens
submerged in water. Instead of
converging the light, the rays diverge
because air has a lower index than water.      H2O

                                              Convex lens made of Air

 What would be the situation with a concave lens made of air
 submerged in water?
Chromatic Aberration
As in a raindrop or a prism, different wave-
lengths of light are refracted at different
angles (higher frequency ↔ greater
bending). The light passing through a lens
is slightly dispersed, so objects viewed
through lenses will be ringed with color.
This is known as chromatic aberration and
it will always be present when a single lens   Chromatic Aberration
is used. Chromatic aberration can be
greatly reduced when a convex lens is
combined with a concave lens with a
different index of refraction. The
dispersion caused by the convex lens will
be almost canceled by the dispersion
caused by the concave lens. Lenses such as
this are called achromatic lenses and are       Achromatic Lens
used in all precision optical instruments.
                                                  Examples
Human eye
The human eye is a fluid-filled object that
focuses images of objects on the retina. The
cornea, with an index of refraction of about
1.38, is where most of the refraction occurs.
Some of this light will then passes through
the pupil opening into the lens, with an index
of refraction of about 1.44. The lens is flexi-    Human eye w/rays
ble and the ciliary muscles contract or relax to change its shape and
focal length. When the muscles relax, the lens flattens and the focal
length becomes longer so that distant objects can be focused on the
retina. When the muscles contract, the lens is pushed into a more
convex shape and the focal length is shortened so that close objects
can be focused on the retina. The retina contains rods and cones to
detect the intensity and frequency of the light and send impulses to the
brain along the optic nerve.
Hyperopia                 The first eye shown suffers from
                                   farsightedness, which is also known
                                   as hyperopia. This is due to a focal
                                   length that is too long, causing the
                                   image to be focused behind the retina,
                                   making it difficult for the person to
                                   see close up things.
   Formation of image behind       The second eye is being helped with a
  the retina in a hyperopic eye.   convex lens. The convex lens helps
                                   the eye refract the light and decrease
                                   the image distance so it is once again
                                   focused on the retina.
                                   Hyperopia usually occurs among
                                   adults due to weakened ciliary
     Convex lens correction        muscles or decreased lens flexibility.
      for hyperopic eye.
Farsighted means “can see far” and the rays focus too far from the lens.
The first eye suffers from
          Myopia                  nearsightedness, or myopia. This is
                                  a result of a focal length that is too
                                  short, causing the images of distant
                                  objects to be focused in front of the
                                  retina.
                                  The second eye’s vision is being
  Formation of image in front     corrected with a concave lens. The
 of the retina in a myopic eye.   concave lens diverges the light rays,
                                  increasing the image distance so that
                                  it is focused on the retina.
                                  Nearsightedness is common among
                                  young people, sometimes the result
                                  of a bulging cornea (which will
    Concave lens correction       refract light more than normal) or an
       for myopic eye.            elongated eyeball.
Nearsighted means “can see near” and the rays focus too near the lens.
Refracting Telescopes
Refracting telescopes are comprised of two convex lenses. The objective
lens collects light from a distant source, converging it to a focus and
forming a real, inverted image inside the telescope. The objective lens
needs to be fairly large in order to have enough light-gathering power so
that the final image is bright enough to see. An eyepiece lens is situated
beyond this focal point by a distance equal to its own focal length. Thus,
each lens has a focal point at F. The rays exiting the eyepiece are nearly
parallel, resulting in a magnified, inverted, virtual image. Besides
magnification, a good telescope also needs resolving power, which is its
ability to distinguish objects with very small angular separations.


                                            F
Reflecting Telescopes
Galileo was the first to use a refracting telescope for astronomy. It is
difficult to make large refracting telescopes, though, because the
objective lens becomes so heavy that it is distorted by its own weight. In
1668 Newton invented a reflecting telescope. Instead of an objective
lens, it uses a concave objective mirror, which focuses incoming parallel
rays. A small plane mirror is placed at this focal point to shoot the light
up to an eyepiece lens (perpendicular to incoming rays) on the side of
the telescope. The mirror serves to gather as much light as possible,
while the eyepiece lens, as in the refracting scope, is responsible for the
magnification.
Huygens’ Principle
Christiaan Huygens, a contemporary of Newton, was
an advocate of the wave theory of light. (Newton
favored the particle view.) Huygens’ principle states
that a wave crest can be thought of as a series of
equally-spaced point sources that produce wavelets
that travel at the same speed as the original wave.
These wavelets superimpose with one another.
Constructive interference occurs along a line parallel
to the original wave at a distance of one wavelength
from it. This principle explains diffraction well:
When light passes through a very small slit, it is as if
only one of these point sources is allowed through.            Christiaan
Since there are no other sources to interfere with it,         Huygens
circular wavefronts radiate outwards in all directions.
                                                           Applet showing reflect


             • • • • •
screen         P
Diffraction: Single Slit
Light enters an opening of width a and is
diffracted onto a distant screen. All points at the
opening act as individual point sources of light.
These point sources interfere with each other, both
constructively and destructively, at different points
on the screen, producing alternating bands of
light and dark. To find the first dark spot, let’s
consider two point sources: one at the left edge,
and one in the middle of the slit. Light from the left
point source must travel a greater distance to point
P on the screen than light from the middle point
source. If this extra distance            Extra
is a half a wavelength, λ/2,              distance
destructive interference will
occur at P and there will
be a dark spot there.                              a/2
           applet                                    a       Continued…
Single Slit   (cont.)
Let’s zoom in on the small triangle in the last slide. Since a / 2 is
extremely small compared to the distanced to the screen, the two
arrows pointing to P are essentially parallel. The extra distance is
found by drawing segment AC perpendicular to BC. This means that
angle A in the triangle is also θ. Since AB is the hypotenuse of a
right triangle, the extra distance is given by (a / 2) sinθ. Thus, using
                               (a / 2) sinθ = λ/2, or equivalently,
                    P



                               a sinθ = λ, we can locate the first dark
                   i nt
                   po




        C                      spot on the screen. Other dark spots can
              To




                               be located by dividing the slit further.
            e  c
            an




                                                       P
        ist




θ                                                 θ
                                                      int
      ad




                                                      po
       tr




                                        θ
    Ex




                                                  To

B                         a/2                     A
screen               P
 Diffraction: Double Slit
 Light passes through two openings, each
 of which acts as a point source. Here a is
 the distance between the openings rather
 than the width of a particular opening. As
 before, if d1 - d2 = n λ (a multiple of the
 wavelength), light from the two sources
 will be in phase and there will a bright             d1
 spot at P for that wavelength. By the                         d2
 Pythagorean theorem, the exact difference
                                                                        L
 in distance is

 d1 - d2 = [ L2 + (x + a / 2)2 ] ½
          - [ L2 + (x - a / 2)2 ] ½
Approximation on next slide.
           Link 1   Link 2                        a        x
Double Slit              (cont.)                screen                P
In practice, L is far greater than a, meaning
that segments measuring d1 and d2 are
virtually parallel. Thus, both rays make an
angle θ relative to the vertical, and the
bottom right angle of the triangle is also θ
(just like in the single slit case). This means
the extra distance traveled is given by a sinθ.            d1
Therefore, the required condition for a bright                      d2
spot at P is that there exists a natural number,                             L
n, such that:
  a sinθ = n λ                                     θ            θ
If white light is shone at the
slits, different colors will be
in phase at different angles.
Electron diffraction                                   a
Diffraction Gratings
A different grating has numerous tiny slits, equally spaced. It
separates white light into its component colors just as a double slit
would. When a sinθ = n λ, light of wavelength λ will be reinforced
at an angle of θ. Since different colors have different wavelengths,
different colors will be reinforced at different angles, and a prism-like
spectrum can be produced. Note, though, that prisms separate light via
refraction rather than diffraction. The pic on the left shows red light
shone through a grating. The CD acts as a diffraction grating since the
tracks are very close together (about 625/mm).
Credits
Snork pics: http://www.geocities.com/EnchantedForest/Cottage/7352/indosnor.html
Snorks icons: http://www.iconarchive.com/icon/cartoon/snorks_by_pino/
Snork seahorse pic: http://members.aol.com/discopanth/private/snork.jpg
Mirror, Lens, and Eye pics:
http://www.physicsclassroom.com/
Refracting Telescope pic: http://csep10.phys.utk.edu/astr162/lect/light/refracting.html
Reflecting Telescope pic: http://csep10.phys.utk.edu/astr162/lect/light/reflecting.html
Fiber Optics:                      http://www.howstuffworks.com/fiber-optic.htm
Willebrord Snell and Christiaan Huygens pics:
http://micro.magnet.fsu.edu/optics/timeline/people/snell.html Chromatic Aberrations:
http://www.dpreview.com/learn/Glossary/Optical/Chromatic_Aberrations_01.htm
                                          Mirage Diagrams:
http://www.islandnet.com/~see/weather/elements/mirage1.htm
Sir David Brewster pic: http://www.brewstersociety.com/brewster_bio.html
Mirage pics:                                   http://www.polarimage.fi/
http://www.greatestplaces.org/mirage/desert1.html
http://www.ac-grenoble.fr/college.ugine/physique/les%20mirages.html
Diffuse reflection: http://www.glenbrook.k12.il.us/gbssci/phys/Class/refln/u13l1d.html
Diffraction: http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/grating.html

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Optics

  • 1. Optics • Reflection • Prisms • Diffuse reflection • Rainbows • Refraction • Plane mirrors • Index of refraction • Spherical aberration • Speed of light • Concave and convex mirrors • Snell’s law • Focal length & radius of curvature • Geometry problems • Mirror / lens equation • Critical angle • Convex and concave lenses • Total internal reflection • Human eye • Brewster angle • Chromatic aberration • Fiber optics • Telescopes • Mirages • Huygens’ principle • Dispersion • Diffraction
  • 2. Reflection Most things we see are thanks to reflections, since most objects don’t produce their own visible light. Much of the light incident on an object is absorbed but some is reflected. the wavelengths of the reflected light determine the colors we see. When white light hits an apple, for instance, primarily red wavelengths are reflected, while much of the others are absorbed. A ray of light heading towards an object is called an incident ray. If it reflects off the object, it is called a reflected ray. A perpendicular line drawn at any point on a surface is called a normal (just like with normal force). The angle between the incident ray and normal is called the angle of incidence, i, and the angle between the reflected ray and the normal ray is called the angle of reflection, r. The law of reflection states that the angle of incidence is always equal to the angle of reflection.
  • 3. Law of Reflection Normal line (perpendicular to surface) inc ys i r ra ide t ed nt c fle ra y re s i=r
  • 4. Diffuse Reflection Diffuse reflection is when light bounces off a non-smooth surface. Each ray of light still obeys the law of reflection, but because the surface is not smooth, the normal can point in a different for every ray. If many light rays strike a non-smooth surface, they could be reflected in many different directions. This explains how we can see objects even when it seems the light shining upon it should not reflect in the direction of our eyes. It also helps to explain glare on wet roads: Water fills in and smoothes out the rough road surface so that the road becomes more like a mirror.
  • 5. Speed of Light & Refraction As you have already learned, light is extremely fast, about 3 × 108 m/s in a vacuum. Light, however, is slowed down by the presence of matter. The extent to which this occurs depends on what the light is traveling through. Light travels at about 3/4 of its vacuum speed (0.75 c ) in water and about 2/3 its vacuum speed (0.67 c ) in glass. The reason for this slowing is because when light strikes an atom it must interact with its electron cloud. If light travels from one medium to another, and if the speeds in these media differ, then light is subject to refraction (a changing of direction at the interface). Refraction of Refraction of light waves light rays
  • 6. Reflection & Refraction At an interface between two media, both reflection and refraction can occur. The angles of incidence, reflection, and refraction are all measured with respect to the normal. The angles of incidence and reflection are always the same. If light speeds up upon entering a new medium, the angle of refraction, θr , will be greater than the angle of incidence, as depicted on the left. If the light slows down in the new medium, θr will be less than the angle of incidence, as shown on the right. Inc Ray Inc ay ide te d ide dR nt lec nt c te Ra ef Ra fle y R y Re θr Re Refr normal normal ac fr ted R act ay θr ed R ay
  • 7. Axle Analogy Imagine you’re on a skateboard heading from the sidewalk toward some grass at an angle. Your front axle is depicted before and after entering the grass. Your right contacts the grass first and slows, but your left wheel is still moving quickly on the sidewalk. This causes a turn toward the normal. If you skated from grass to sidewalk, the same path would be followed. In this case your right wheel would reach the sidewalk first and speed up, but your left wheel would still be moving more slowly. The result this time would be turning away from the normal. Skating from sidewalk to grass is like light traveling from air to a more overhead view “optically dense” medium like glass or water. The slower light travels in the new medium, the more it bends toward the normal. Light traveling sidewalk from water to air speeds up and grass bends away from the normal. As with a skateboard, light traveling along the normal will change speed θr but not direction.
  • 8. Index of Refraction, n The index of refraction of a substance is the ratio of the speed in light in a vacuum to the speed of light in that substance: c n= v Medium n n = Index of Refraction Vacuum 1 c = Speed of light in vacuum Air (STP) 1.00029 v = Speed of light in medium Water (20º C) 1.33 Note that a large index of refraction corresponds to a relatively slow Ethanol 1.36 light speed in that medium. Glass ~1.5 Diamond 2.42
  • 9. θi Snell’s Law ni nr θr Snell’s law states that a ray of light bends in such a way that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is constant. Mathematically, ni sinθ i = nr sinθr Here ni is the index of refraction in the original medium and nr is the index in the medium the light enters. θ i and θr are the angles of incidence and refraction, respectively. Willebrord Snell
  • 10. Snell’s Law Derivation Two parallel rays are shown. Points A and B are directly opposite one another. The top pair is at one point in time, and the bottom pair after time t. A θ1 The dashed lines connecting n1 x • the pairs are perpendicular to A the rays. In time t, point A d • •B travels a distance x, while y n2 point B travels a distance y. •B sinθ1 = x / d, so x = d sinθ1 θ2 sinθ2 = y / d, so y = d sinθ2 Speed of A: v1 = x / t Speed of B: v2 = y / t Continued…
  • 11. Snell’s Law Derivation (cont.) A θ1 n1 x • A d • •B v1 x/ t x sinθ1 y = = = So, n2 •B v2 y/ t y sinθ2 θ2 v1 / c sinθ1 1 / n1 sinθ1 n2 = ⇒ = = v2 / c sinθ2 1 / n2 sinθ2 n1 ⇒ n1 sinθ1 = n2 sinθ2
  • 12. Refraction Problem #1 Goal: Find the angular displacement of the ray after having passed through the prism. Hints: 1. Find the first angle of refraction using Snell’s law. 19.4712º 2. Find angle ø. (Hint: Use Geometry skills.) 79.4712º Air, n1 = 1 30° 3. Find the second angle of incidence. 10.5288º 4. Find the second angle of Horiz. ray, refraction, θ, using Snell’s Law parallel to ø θ 15.9º base Glass, n2 = 1.5
  • 13. Refraction Problem #2 Goal: Find the distance the light ray displaced due to the thick window and how much time it spends in the glass. Some hints are given. 20º θ1 1. Find θ1 (just for fun). 20º H20 n1 = 1.3 2. To show incoming & outgoing rays are parallel, find θ. 20º 3. Find d. 0.504 m glass 10m n2 = 1.5 4. Find the time the light spends in 5.2 · 10-8 s d H20 the glass. θ Extra practice: Find θ if bottom medium is replaced with air. 26.4º
  • 14. Refraction Problem #3 Goal: Find the exit angle relative to the horizontal. θ = 19.8° 36° air glass θ=? The triangle is isosceles. Incident ray is horizontal, parallel to the base.
  • 15. Reflection Problem Goal: Find incident angle relative to horizontal so that reflected ray will be vertical. θ = 10º θ 50º center of semicircular mirror with horizontal base
  • 16. Brewster Angle The Brewster angle is the angle of incidence the produces reflected and refracted rays that are perpendicular. From Snell, n1 sinθb = n2 sinθ. n2 θ α = θb since α + β = 90º, α and θb + β = 90º. β n1 θb θb β = θ since α + β = 90º, and θ + α = 90º. Thus, n1 sinθb = n2 sinθ = n2 sinβ = n2 cosθb tanθb = n2 / n1 Sir David Brewster
  • 17. Critical Angle The incident angle that causes nr the refracted ray to skim right ni along the boundary of a θc substance is known as the critical angle, θc. The critical angle is the angle of incidence that produces From Snell, an angle of refraction of 90º. If n1 sinθc = n2 sin 90° the angle of incidence exceeds the critical angle, the ray is Since sin 90° = 1, we completely reflected and does have n1 sinθc = n2 and not enter the new medium. A the critical angle is critical angle only exists when light is attempting to penetrate a nr medium of higher optical density θc = sin-1 than it is currently traveling in. ni
  • 18. Critical Angle Sample Problem Calculate the critical angle for the diamond-air boundary. Refer to the Index of Refraction chart for the information. air θc = sin-1 (nr / ni) diamond = sin-1 (1 / 2.42) θc = 24.4° Any light shone on this boundary beyond this angle will be reflected back into the diamond.
  • 19. Total Internal Reflection Total internal reflection occurs when light attempts to pass from a more optically dense medium to a less optically dense medium at an angle greater than the critical angle. When this occurs there is no refraction, only reflection. n1 n2 > n1 n2 θ θ > θc Total internal reflection can be used for practical applications like fiber optics.
  • 20. Fiber Optics Fiber optic lines are strands of glass or transparent fibers that allows the transmission of light and digital information over long distances. They are used for the telephone system, the cable TV system, the internet, medical imaging, and mechanical engineering spool of optical fiber inspection. Optical fibers have many advantages over copper wires. They are less expensive, thinner, lightweight, and more flexible. They aren’t flammable since they use light signals instead of electric signals. Light signals from one fiber do not interfere with signals in nearby fibers, which means clearer TV A fiber optic wire reception or phone conversations. Continued…
  • 21. Fiber Optics Cont. Fiber optics are often long strands of very pure glass. They are very thin, about the size of a human hair. Hundreds to thousands of them are arranged in bundles (optical cables) that can transmit light great distances. There are three main parts to an optical fiber: • Core- the thin glass center where light travels. • Cladding- optical material (with a lower index of refraction than the core) that surrounds the core that reflects light back into the core. • Buffer Coating- plastic coating on the outside of an optical fiber to protect it from damage. Continued…
  • 22. Light travels through the core of a fiber optic by continually Fiber Optics (cont.) reflecting off of the cladding. Due to total internal reflection, the cladding does not absorb any of the light, allowing the light to There are two types of optical travel over great distances. Some fibers: of the light signal will degrade • Single-mode fibers- transmit over time due to impurities in the one signal per fiber (used in glass. cable TV and telephones). • Multi-mode fibers- transmit multiple signals per fiber (used in computer networks).
  • 24. Mirages Mirages are caused by the refracting properties of a non-uniform atmosphere. Several examples of mirages include seeing “puddles” ahead on a hot highway or in a desert and the lingering daylight after the sun is below the horizon. More Mirages Continued…
  • 25. Inferior Mirages A person sees a puddle ahead on the hot highway because the road heats the air above it, while the air farther above the road stays cool. Instead of just two layers, hot and cool, there are really many layers, each slightly hotter than the layer above it. The cooler air has a slightly higher index of refraction than the warm air beneath it. Rays of light coming toward the road gradually refract further from the normal, more parallel to the road. (Imagine the wheels and axle: on a light ray coming from the sky, the left wheel is always in slightly warmer air than the right wheel, so the left wheel continually moves faster, bending the axle more and more toward the observer.) When a ray is bent enough, it surpasses the critical angle and reflects. The ray continues to refract as it heads toward the observer. The “puddle” is really just an inverted image of the sky above. This is an example of an inferior mirage, since the cool are is above the hot air.
  • 26. Superior Mirages Superior mirages occur when a layer of cool air is beneath a layer of warm air. Light rays are bent downward, which can make an object seem to be higher in the air and inverted. (Imagine the wheels and axle on a ray coming from the boat: the right wheel is continually in slightly warmer air than the left wheel. Thus, the right wheel moves slightly faster and bends the axle toward the observer.) When the critical angle is exceeded the ray reflects. These mirages usually occur over ice, snow, or cold water. Sometimes superior images are produced without reflection. Eric the Red, for example, was able to see Greenland while it was below the horizon due to the light gradually refracting and following the curvature of the Earth.
  • 27. Sunlight after Sunset Lingering daylight after the sun is below the horizon is another Apparent effect of refraction. Light travels position Observer at a slightly slower speed in of sun Earth’s atmosphere than in space. As a result, sunlight is Actual refracted by the atmosphere. In position Earth the morning, this refraction of sun causes sunlight to reach us before the sun is actually above Atmosphere the horizon. In the evening, the sunlight is bent above the horizon after the sun has actually set. So daylight is extended in the morning and evening because of the refraction of light. Note: the picture greatly exaggerates this effect as well as the thickness of the atmosphere. Different “shapes” of Sun
  • 28. Dispersion of Light Dispersion is the separation of light into a spectrum by refraction. The index of refraction is actually a function of wavelength. For longer wavelengths the index is slightly small. Thus, red light refracts less than violet. (The pic is exaggerated.) This effect causes white light to split into it spectrum of colors. Red light travels the fastest in glass, has a smaller index of refraction, and bends the least. Violet is slowed down the most, has the largest index, and bends the most. In other words: the higher the frequency, the greater the bending. Animation
  • 29. Atmospheric Optics There are many natural occurrences of light optics in our atmosphere. One of the most common of these is the rainbow, which is caused by water droplets dispersing sunlight. Others include arcs, halos, cloud iridescence, and many more. Photo gallery of atmospheric optics.
  • 30. Rainbows A rainbow is a spectrum formed when sunlight is dispersed by water droplets in the atmosphere. Sunlight incident on a water droplet is refracted. Because of dispersion, each color is refracted at a slightly different angle. At the back surface of the droplet, the light undergoes total internal reflection. On the way out of the droplet, the light is once more refracted and dispersed. Although each droplet produces a complete spectrum, an observer will only see a certain wavelength of light from each droplet. (The wavelength depends on the relative positions of the sun, droplet, and observer.) Because there are millions of droplets in the sky, a complete spectrum is seen. The droplets reflecting red light make an angle of 42 o with respect to the direction of the sun’s rays; the droplets reflecting violet light make an angle of 40o. Rainbow images
  • 32. Secondary Secondary Rainbow The secondary rainbow is a rainbow of radius 51°, occasionally visible outside the primary rainbow. It is produced when the light Primary entering a cloud droplet is reflected twice internally and then exits the droplet. The color spectrum is reversed in respect to the primary rainbow, with red appearing on its inner edge. Alexander’s dark region
  • 33. Supernumerary Arcs Supernumerary arcs are faint arcs of color just inside the primary rainbow. They occur when the drops are of uniform size. If two light rays in a raindrop are scattered in the same direction but have take different paths within the drop, then they could interfere with each other constructively or destructively. The type of interference that occurs depends on the difference in distance traveled by the rays. If that difference is nearly zero or a multiple of the wavelength, it is constructive, and that color is reinforced. If the difference is close to half a wavelength, there is destructive interference.
  • 34. Real vs. Virtual Images Real images are formed by mirrors or lenses when light rays actually converge and pass through the image. Real images will be located in front of the mirror forming them. A real image can be projected onto a piece of paper or a screen. If photographic film were placed here, a photo could be created. Virtual images occur where light rays only appear to have originated. For example, sometimes rays appear to be coming from a point behind the mirror. Virtual images can’t be projected on paper, screens, or film since the light rays do not really converge there. Examples are forthcoming.
  • 35. Plane Mirror Object Rays emanating from an object at point P strike the mirror and are reflected with equal angles of incidence and reflection. After P P’ reflection, the rays continue to spread. If we extend the rays backward behind the mirror, Virtual they will intersect at point P’, which is the Image image of point P. To an observer, the rays appear to come from point P’, but no source is there and no rays actually converging there . For that reason, this image at P’ is a virtual image. do di O I The image, I, formed by a plane mirror of an object, O, appears to be a distance di , behind the mirror, equal to the object distance do. Animation Continued…
  • 36. Plane Mirror (cont.) Two rays from object P strike the mirror at points B and M. Each ray is reflected such that i = r. Triangles BPM and BP’M are P do B di P’ congruent by ASA (show this), which implies that do= di and h = h’. Thus, the image is the h M h’ same distance behind the mirror Object Image as the object is in front of it, and the image is the same size as the object. object image Mirror With plane mirrors, the image is reversed left to right (or the front and back of an image ). When you raise your left hand in front of a mirror, your image raises its right hand. Why aren’t top and bottom reversed?
  • 37. Concave and Convex Mirrors Concave and convex mirrors are curved mirrors similar to portions of a sphere. light rays light rays Concave mirrors reflect light Convex mirrors reflect light from their inner surface, like from their outer surface, like the inside of a spoon. the outside of a spoon.
  • 38. Concave Mirrors • Concave mirrors are approximately spherical and have a principal axis that goes through the center, C, of the imagined sphere and ends at the point at the center of the mirror, A. The principal axis is perpendicular to the surface of the mirror at A. • CA is the radius of the sphere,or the radius of curvature of the mirror, R . • Halfway between C and A is the focal point of the mirror, F. This is the point where rays parallel to the principal axis will converge when reflected off the mirror. • The length of FA is the focal length, f. • The focal length is half of the radius of the sphere (proven on next slide).
  • 39. r = 2f To prove that the radius of curvature of a concave mirror is twice its focal length, first construct a tangent line at the point of incidence. The normal is perpendicular to the tangent and goes through the center, C. Here, i = r = β. By alt. int. angles the angle at C is also β, and α = 2 β. s is the arc length from the principle axis to the pt. of incidence. Now imagine a sphere centered at F with radius f. If the incident tan ge ray is close to the principle axis, β ntl the arc length of the new sphere β s ine is about the same as s. From β α s = r θ, we have s = r β and • C • f F s ≈ f α = 2 f β. Thus, r β ≈ 2 f β, and r = 2 f. r
  • 40. Focusing Light with Concave Mirrors Light rays parallel to the principal axis will be reflected through the focus (disregarding spherical aberration, explained on next slide.) In reverse, light rays passing through the focus will be reflected parallel to the principal axis, as in a flood light. Concave mirrors can form both real and virtual images, depending on where the object is located, as will be shown in upcoming slides.
  • 41. Spherical Aberration F • F • C • C • Spherical Mirror Parabolic Mirror Only parallel rays close to the principal axis of a spherical mirror will converge at the focal point. Rays farther away will converge at a point closer to the mirror. The image formed by a large spherical mirror will be a disk, not a point. This is known as spherical aberration. Parabolic mirrors don’t have spherical aberration. They are used to focus rays from stars in a telescope. They can also be used in flashlights and headlights since a light source placed at their focal point will reflect light in parallel beams. However, perfectly parabolic mirrors are hard to make and slight errors could lead to spherical aberration. Continued…
  • 42. Spherical vs. Parabolic Mirrors Parallel rays converge at the Parabolic mirrors have no focal point of a spherical spherical aberration. The mirror only if they are close to mirror focuses all parallel rays the principal axis. The image at the focal point. That is why formed in a large spherical they are used in telescopes and mirror is a disk, not a point light beams like flashlights and (spherical aberration). car headlights.
  • 43. Concave Mirrors: Object beyond C object The image formed when an object is placed beyond C is • C • F located between C and F. It is a real, inverted image image that is smaller in size than the object. Animation 1 Animation 2
  • 44. Concave Mirrors: Object between C and F The image formed object when an object is placed between C and F • C • F is located beyond C. It is a real, inverted image image that is larger in size than the object. Animation 1 Animation 2
  • 45. Concave Mirrors: Object in front of F The image formed when an object is placed in front of F is object located behind the image mirror. It is a virtual, • C • F upright image that is larger in size than the object. It is virtual since it is formed only Animation where light rays seem to be diverging from.
  • 46. Concave Mirrors: Object at C or F What happens when an object is placed at C? The image will be formed at C also, but it will be inverted. It will be real and the same size as the object. Animation What happens when an object is placed at F? No image will be formed. All rays will reflect parallel to the principal axis and will never converge. The image is “at infinity.”
  • 47. Convex Mirrors • A convex mirror has the same basic properties as a light rays concave mirror but its focus and center are located behind the mirror. • This means a convex mirror has a negative focal length • Rays parallel to the principal (used later in the mirror axis will reflect as if coming equation). from the focus behind the mirror. • Light rays reflected from convex mirrors always • Rays approaching the mirror diverge, so only virtual on a path toward F will reflect images will be formed. parallel to the principal axis.
  • 48. Convex Mirror Diagram The image formed by a convex mirror no matter where the object object is placed will image be virtual, upright, • F • C and smaller than the object. As the object is moved closer to the mirror, the image will approach the size of the object.
  • 49. Mirror/Lens Equation Derivation From ∆PCO, β = θ + α, so 2β = 2θ + 2α. From ∆PCO, γ = 2θ + α , so -γ = -2θ - α. P Adding equations yields 2β - γ = α. θ object From s = r θ, we have s θ γ s = r β, s ≈ di α, and β α T • C O s ≈ di α (for rays image close to the principle axis). Thus: s α≈ s β= r d o di γ≈ s do di (cont.)
  • 50. Mirror/Lens Equation Derivation (cont.) From the last slide, β = s / r, α ≈ s / d0 , γ ≈ s / di , and 2 β - γ = α. Substituting into the last equation yields: P 2s s s s θ θ object r -d = d i o γ β α 2 1 1 T • C O r = di + do image 2 1 1 = d +d 2f i o di 1 1 1 = d +d f i o do The last equation applies to convex and concave mirrors, as well as to lenses, provided a sign convention is adhered to.
  • 51. Mirror Sign Convention f = focal length 1 1 1 di = image distance f = d i + do do = object distance + for real image di - for virtual image + for concave mirrors f - for convex mirrors
  • 52. Magnification hi By definition, m = ho m = magnification hi = image height (negative means inverted) ho = object height Magnification is simply the ratio of image height to object height. A positive magnification means an upright image.
  • 53. hi -di Magnification Identity: m = = ho do To derive this let’s look at two rays. One hits the mirror on the axis. The incident and reflected rays each make angle θ relative to the axis. A second ray is drawn through the center and is reflected back on top of itself (since a radius is always perpendicular to an tangent line of a circle). The intersection of the reflected rays object determines the location of θ ho the tip of the image. Our • C result follows image, from similar triangles, with the negative sign a height = hi consequence of our sign convention. (In this picture di do hi is negative and di is positive.)
  • 54. Mirror Equation Sample Problem Suppose AllStar, who is 3 and a half feet tall, stands 27 feet in front of a concave mirror with a radius of curvature of • C • F 20 feet. Where will his image be reflected and what will its size be? di = 15.88 feet hi = -2.06 feet
  • 55. Mirror Equation Sample Problem 2 Casey decides to join in the fun and she finds a convex mirror to stand in front of. She sees her image reflected 7 feet behind the mirror which • F • C has a focal length of 11 feet. Her image is 1 foot tall. Where is she standing and how tall is she? d =19.25 feet o ho = 2.75 feet
  • 56. Lenses Lenses are made of transparent Convex (Converging) materials, like glass or plastic, that Lens typically have an index of refraction greater than that of air. Each of a lens’ two faces is part of a sphere and can be convex or concave (or one face may be flat). If a lens is thicker at the center than the edges, it is a convex, or Concave (Diverging) converging, lens since parallel rays will Lens be converged to meet at the focus. A lens which is thinner in the center than the edges is a concave, or diverging, lens since rays going through it will be spread out.
  • 57. Lenses: Focal Length • Like mirrors, lenses have a principal axis perpendicular to their surface and passing through their midpoint. • Lenses also have a vertical axis, or principal plane, through their middle. • They have a focal point, F, and the focal length is the distance from the vertical axis to F. • There is no real center of curvature, so 2F is used to denote twice the focal length.
  • 58. Ray Diagrams For Lenses When light rays travel through a lens, they refract at both surfaces of the lens, upon entering and upon leaving the lens. At each interface the bends toward the normal. (Imagine the wheels and axle.) To simplify ray diagrams, we often pretend that all refraction occurs at the vertical axis. This simplification works well for thin lenses and provides the same results as refracting the light rays twice. • • 2F F • 2F F • • • 2F F • 2F F • Reality Approximation
  • 59. Convex Lenses Rays traveling parallel to the principal axis of a convex lens will refract toward • • 2F F • 2F F • the focus. Rays traveling from the focus will • F 2F • • 2F F • refract parallel to the principal axis. Rays traveling directly through the center of a convex lens will leave the • • 2F F • 2F F • lens traveling in the exact same direction.
  • 60. Convex Lens: Object Beyond 2F The image formed when an object is object placed beyond 2F is located behind • • • • the lens between F 2F F F 2F and 2F. It is a real, image inverted image which is smaller than the object Experiment with this diagram itself.
  • 61. Convex Lens: Object Between 2F and F The image formed object when an object is placed between 2F and F is • 2F • F • F • 2F located beyond 2F behind the lens. It is a real, image inverted image, larger than the object.
  • 62. Convex Lens: Object within F The image formed when an object is placed in front of F is located somewhere image beyond F on the same side of the lens as the object. It is a virtual, upright image • 2F • F • F • 2F which is larger than the object object. This is how a magnifying glass works. When the object is brought close to the lens, it will be convex lens used magnified greatly. as a magnifier
  • 63. Concave Lenses Rays traveling parallel to the principal axis of a concave lens will • 2 • F • F • 2 refract as if coming from the focus. F F Rays traveling toward the 2F • • F • 2 F • focus will refract parallel to the principal axis. F Rays traveling directly through the 2F • • F • 2 F • center of a concave lens will leave the lens traveling in the exact same F direction, just as with a convex lens.
  • 64. Concave Lens Diagram No matter where the object is placed, the object image will be on the same side as the • 2F • F • F • 2F object. The image is image virtual, upright, and smaller than the object with a concave lens. Experiment with this diagram
  • 65. Lens Sign Convention f = focal length 1 1 1 f = d +d di = image distance i o do = object distance + for real image di - for virtual image + for convex lenses f - for concave lenses
  • 66. Lens / Mirror Sign Convention The general rule for lenses and mirrors is this: + for real image di - for virtual image and if the lens or mirror has the ability to converge light, f is positive. Otherwise, f must be treated as negative for the mirror/lens equation to work correctly.
  • 67. Lens Sample Problem Tooter, who stands 4 feet tall (counting his snorkel), finds himself 24 feet in front of a convex lens and he sees his image reflected 35 feet • 2F • F • F • 2F behind the lens. What is the focal length of the lens and how tall is his image? f = 14.24 feet hi = -5.83 feet
  • 68. Lens and Mirror Applet This application shows where images will be formed with concave and convex mirrors and lenses. You can change between lenses and mirrors at the top. Changing the focal length to negative will change between concave and convex lenses and mirrors. You can also move the object or the lens/mirror by clicking and dragging on them. If you click with the right mouse button, the object will move with the mirror/lens. The focal length can be changed by clicking and dragging at the top or bottom of the lens/mirror. Object distance, image distance, focal length, and magnification can also be changed by typing in values at the top. Lens and Mirror Diagrams
  • 69. Convex Lens in Water Glass Glass H2O Air Because glass has a higher index of refraction that water the convex lens at the left will still converge light, but it will converge at a greater distance from the lens that it normally would in air. This is due to the fact that the difference in index of refraction between water and glass is small compared to that of air and glass. A large difference in index of refraction means a greater change in speed of light at the interface and, hence, a more dramatic change of direction.
  • 70. Convex Lens Made of Water Glass Since water has a higher index of refraction than air, a convex lens made of water will converge light just as a glass lens of the same shape. However, the Air glass lens will have a smaller focal length n = 1.5 than the water lens (provided the lenses are of same shape) because glass has an index of refraction greater than that of water. Since there is a bigger difference H2O in refractive index at the air-glass interface than at the air-water interface, the glass lens will bend light more than the water lens. Air n = 1.33
  • 71. Air & Water Lenses On the left is depicted a concave lens filled with water, and light rays entering it from an air-filled environment. Water has a higher index than air, so the rays diverge just like Air they do with a glass lens. Concave lens made of H2O To the right is an air-filled convex lens submerged in water. Instead of converging the light, the rays diverge because air has a lower index than water. H2O Convex lens made of Air What would be the situation with a concave lens made of air submerged in water?
  • 72. Chromatic Aberration As in a raindrop or a prism, different wave- lengths of light are refracted at different angles (higher frequency ↔ greater bending). The light passing through a lens is slightly dispersed, so objects viewed through lenses will be ringed with color. This is known as chromatic aberration and it will always be present when a single lens Chromatic Aberration is used. Chromatic aberration can be greatly reduced when a convex lens is combined with a concave lens with a different index of refraction. The dispersion caused by the convex lens will be almost canceled by the dispersion caused by the concave lens. Lenses such as this are called achromatic lenses and are Achromatic Lens used in all precision optical instruments. Examples
  • 73. Human eye The human eye is a fluid-filled object that focuses images of objects on the retina. The cornea, with an index of refraction of about 1.38, is where most of the refraction occurs. Some of this light will then passes through the pupil opening into the lens, with an index of refraction of about 1.44. The lens is flexi- Human eye w/rays ble and the ciliary muscles contract or relax to change its shape and focal length. When the muscles relax, the lens flattens and the focal length becomes longer so that distant objects can be focused on the retina. When the muscles contract, the lens is pushed into a more convex shape and the focal length is shortened so that close objects can be focused on the retina. The retina contains rods and cones to detect the intensity and frequency of the light and send impulses to the brain along the optic nerve.
  • 74. Hyperopia The first eye shown suffers from farsightedness, which is also known as hyperopia. This is due to a focal length that is too long, causing the image to be focused behind the retina, making it difficult for the person to see close up things. Formation of image behind The second eye is being helped with a the retina in a hyperopic eye. convex lens. The convex lens helps the eye refract the light and decrease the image distance so it is once again focused on the retina. Hyperopia usually occurs among adults due to weakened ciliary Convex lens correction muscles or decreased lens flexibility. for hyperopic eye. Farsighted means “can see far” and the rays focus too far from the lens.
  • 75. The first eye suffers from Myopia nearsightedness, or myopia. This is a result of a focal length that is too short, causing the images of distant objects to be focused in front of the retina. The second eye’s vision is being Formation of image in front corrected with a concave lens. The of the retina in a myopic eye. concave lens diverges the light rays, increasing the image distance so that it is focused on the retina. Nearsightedness is common among young people, sometimes the result of a bulging cornea (which will Concave lens correction refract light more than normal) or an for myopic eye. elongated eyeball. Nearsighted means “can see near” and the rays focus too near the lens.
  • 76. Refracting Telescopes Refracting telescopes are comprised of two convex lenses. The objective lens collects light from a distant source, converging it to a focus and forming a real, inverted image inside the telescope. The objective lens needs to be fairly large in order to have enough light-gathering power so that the final image is bright enough to see. An eyepiece lens is situated beyond this focal point by a distance equal to its own focal length. Thus, each lens has a focal point at F. The rays exiting the eyepiece are nearly parallel, resulting in a magnified, inverted, virtual image. Besides magnification, a good telescope also needs resolving power, which is its ability to distinguish objects with very small angular separations. F
  • 77. Reflecting Telescopes Galileo was the first to use a refracting telescope for astronomy. It is difficult to make large refracting telescopes, though, because the objective lens becomes so heavy that it is distorted by its own weight. In 1668 Newton invented a reflecting telescope. Instead of an objective lens, it uses a concave objective mirror, which focuses incoming parallel rays. A small plane mirror is placed at this focal point to shoot the light up to an eyepiece lens (perpendicular to incoming rays) on the side of the telescope. The mirror serves to gather as much light as possible, while the eyepiece lens, as in the refracting scope, is responsible for the magnification.
  • 78. Huygens’ Principle Christiaan Huygens, a contemporary of Newton, was an advocate of the wave theory of light. (Newton favored the particle view.) Huygens’ principle states that a wave crest can be thought of as a series of equally-spaced point sources that produce wavelets that travel at the same speed as the original wave. These wavelets superimpose with one another. Constructive interference occurs along a line parallel to the original wave at a distance of one wavelength from it. This principle explains diffraction well: When light passes through a very small slit, it is as if only one of these point sources is allowed through. Christiaan Since there are no other sources to interfere with it, Huygens circular wavefronts radiate outwards in all directions. Applet showing reflect • • • • •
  • 79. screen P Diffraction: Single Slit Light enters an opening of width a and is diffracted onto a distant screen. All points at the opening act as individual point sources of light. These point sources interfere with each other, both constructively and destructively, at different points on the screen, producing alternating bands of light and dark. To find the first dark spot, let’s consider two point sources: one at the left edge, and one in the middle of the slit. Light from the left point source must travel a greater distance to point P on the screen than light from the middle point source. If this extra distance Extra is a half a wavelength, λ/2, distance destructive interference will occur at P and there will be a dark spot there. a/2 applet a Continued…
  • 80. Single Slit (cont.) Let’s zoom in on the small triangle in the last slide. Since a / 2 is extremely small compared to the distanced to the screen, the two arrows pointing to P are essentially parallel. The extra distance is found by drawing segment AC perpendicular to BC. This means that angle A in the triangle is also θ. Since AB is the hypotenuse of a right triangle, the extra distance is given by (a / 2) sinθ. Thus, using (a / 2) sinθ = λ/2, or equivalently, P a sinθ = λ, we can locate the first dark i nt po C spot on the screen. Other dark spots can To be located by dividing the slit further. e c an P ist θ θ int ad po tr θ Ex To B a/2 A
  • 81. screen P Diffraction: Double Slit Light passes through two openings, each of which acts as a point source. Here a is the distance between the openings rather than the width of a particular opening. As before, if d1 - d2 = n λ (a multiple of the wavelength), light from the two sources will be in phase and there will a bright d1 spot at P for that wavelength. By the d2 Pythagorean theorem, the exact difference L in distance is d1 - d2 = [ L2 + (x + a / 2)2 ] ½ - [ L2 + (x - a / 2)2 ] ½ Approximation on next slide. Link 1 Link 2 a x
  • 82. Double Slit (cont.) screen P In practice, L is far greater than a, meaning that segments measuring d1 and d2 are virtually parallel. Thus, both rays make an angle θ relative to the vertical, and the bottom right angle of the triangle is also θ (just like in the single slit case). This means the extra distance traveled is given by a sinθ. d1 Therefore, the required condition for a bright d2 spot at P is that there exists a natural number, L n, such that: a sinθ = n λ θ θ If white light is shone at the slits, different colors will be in phase at different angles. Electron diffraction a
  • 83. Diffraction Gratings A different grating has numerous tiny slits, equally spaced. It separates white light into its component colors just as a double slit would. When a sinθ = n λ, light of wavelength λ will be reinforced at an angle of θ. Since different colors have different wavelengths, different colors will be reinforced at different angles, and a prism-like spectrum can be produced. Note, though, that prisms separate light via refraction rather than diffraction. The pic on the left shows red light shone through a grating. The CD acts as a diffraction grating since the tracks are very close together (about 625/mm).
  • 84. Credits Snork pics: http://www.geocities.com/EnchantedForest/Cottage/7352/indosnor.html Snorks icons: http://www.iconarchive.com/icon/cartoon/snorks_by_pino/ Snork seahorse pic: http://members.aol.com/discopanth/private/snork.jpg Mirror, Lens, and Eye pics: http://www.physicsclassroom.com/ Refracting Telescope pic: http://csep10.phys.utk.edu/astr162/lect/light/refracting.html Reflecting Telescope pic: http://csep10.phys.utk.edu/astr162/lect/light/reflecting.html Fiber Optics: http://www.howstuffworks.com/fiber-optic.htm Willebrord Snell and Christiaan Huygens pics: http://micro.magnet.fsu.edu/optics/timeline/people/snell.html Chromatic Aberrations: http://www.dpreview.com/learn/Glossary/Optical/Chromatic_Aberrations_01.htm Mirage Diagrams: http://www.islandnet.com/~see/weather/elements/mirage1.htm Sir David Brewster pic: http://www.brewstersociety.com/brewster_bio.html Mirage pics: http://www.polarimage.fi/ http://www.greatestplaces.org/mirage/desert1.html http://www.ac-grenoble.fr/college.ugine/physique/les%20mirages.html Diffuse reflection: http://www.glenbrook.k12.il.us/gbssci/phys/Class/refln/u13l1d.html Diffraction: http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/grating.html