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Projectile Motion
Background 
• An object launched into space without motive 
power of its own is called a projectile. Neglect 
air resistance, and only gravity causes a 
projectile to deviate from a straight line. 
• Without motive power, the projectile has a 
constant horizontal velocity. 
• Under these conditions, the motion of a 
projectile can be calculated in 2 dimensions.
Horizontal Projection + Free Fall 
Note vertical 
velocity and 
position increase 
with time as a free-falling 
body. 
Horizontal distance 
increases linearly 
with time, indicating 
a constant 
horizontal velocity.
Projectile Motion at an Angle 
Note: 
• Vertical velocity (Vy) = 0 at Ymax 
• Ө = angle of projection 
• Vyo = Vo sin (Ө) 
• Vxo = Vo cos (Ө)
Objectives 
Following this exercise, you should: 
• know how to treat motion with constant velocity in 
two dimensions. 
• know how to treat motion with constant acceleration 
in two dimensions. 
• be able to apply the equations for two-dimensional 
motion to a projectile. 
• be able to calculate positions, velocities, and times for 
various types of projectile motion.
Projectile Motion Equations 
Topic Equation Explanation 
constant velocity X = X0 + V0xt 
Each direction obeys the constant Y = Y velocity equation independently. 0 + Y0xt 
constant acceleration: horizontal component 
V= V+ at 
x ox xV2 = Vx 
ox 
2+2ax(X-X0) 
X = X0 + 1/2(Vox + Vx)t 
X = X0 + Voxt + 1/2axt2 
constant acceleration: vertical component 
V= V+ at 
y oy yV2 = Vy 
oy 
2+2ay(Y-Y0) 
Y = Y0 + 1/2(Voy + Vy)t 
Y = Y0 + Voyt + 1/2ayt2 
range of a projectile S = (2Vo2/ay)sin 2ᶿ 
Horizontal distance (S) traveled if the initial height (Yo) equals the final height 
(Y).ᶿ equals the angle between the initial projectile direction and horizontal. 
flight time of projectile t = (2Vo/ay)sin 2ᶿ 
Total time in the air if the initial height equals the final height. ᶿ equals the 
angle between the initial projectile direction and horizontal.
Questions 
• Do we have to know the mass of the object? 
– NO. Gravity acts on large and small objects 
equally.
Questions 
• Do we have to know either the distance 
traveled, time traveled or the velocity of the 
projectile to calculate other parameters? 
– YES. The only constant available is gravity 
(g or –ay).
Example – Horizontal Projection 
Vo = ? 
Ymax = 100 cm 
Xmax = 500 cm
Example – Horizontal Projection 
• Known: 
– Vyo = 0 
– g = -ay = 9.81 m/sec 
– Ymax = 100 cm = 1 m 
– Xmax = 500 cm = 5 m
Example – Horizontal Projection 
• Key point: velocity = distance/time 
– Horizontal distance is known (5 m) 
– Horizontal travel time = “free fall” time 
– Y = Voy t + ½ a t2 
– Initial vertical velocity (Voy) = 0
Example – Horizontal Projection 
• Calculation 
– Y = 1 m = ½ 9.81 m/sec2 t2 
– t = [1 m (2)/9.8 m/sec2]1/2 = 0.45 sec 
– Vox = Xmax/t = 5 m/0.45 sec 
– Vox = 11.1 m/sec
Practical Application 
In 1957, Homer (Sony) Hickam and 5 other 
teenagers in Coalwood, West Virginia were 
designing and building miniature rockets. The 
boys were accused by authorities of starting a 
forest fire as a result of an errant rocket launch. 
The boys were suspended from school until 
Homer was able to make his case to the Principal 
of the High School using his understanding of 
projectile motion… 
http://movieclips.com/u6Kx-october-sky-movie-homer-proves-his-innocence/#. 
TqsNdRK2N0U.email

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David Bausmith - Teaching introduction to projectile motion

  • 2. Background • An object launched into space without motive power of its own is called a projectile. Neglect air resistance, and only gravity causes a projectile to deviate from a straight line. • Without motive power, the projectile has a constant horizontal velocity. • Under these conditions, the motion of a projectile can be calculated in 2 dimensions.
  • 3. Horizontal Projection + Free Fall Note vertical velocity and position increase with time as a free-falling body. Horizontal distance increases linearly with time, indicating a constant horizontal velocity.
  • 4. Projectile Motion at an Angle Note: • Vertical velocity (Vy) = 0 at Ymax • Ө = angle of projection • Vyo = Vo sin (Ө) • Vxo = Vo cos (Ө)
  • 5. Objectives Following this exercise, you should: • know how to treat motion with constant velocity in two dimensions. • know how to treat motion with constant acceleration in two dimensions. • be able to apply the equations for two-dimensional motion to a projectile. • be able to calculate positions, velocities, and times for various types of projectile motion.
  • 6. Projectile Motion Equations Topic Equation Explanation constant velocity X = X0 + V0xt Each direction obeys the constant Y = Y velocity equation independently. 0 + Y0xt constant acceleration: horizontal component V= V+ at x ox xV2 = Vx ox 2+2ax(X-X0) X = X0 + 1/2(Vox + Vx)t X = X0 + Voxt + 1/2axt2 constant acceleration: vertical component V= V+ at y oy yV2 = Vy oy 2+2ay(Y-Y0) Y = Y0 + 1/2(Voy + Vy)t Y = Y0 + Voyt + 1/2ayt2 range of a projectile S = (2Vo2/ay)sin 2ᶿ Horizontal distance (S) traveled if the initial height (Yo) equals the final height (Y).ᶿ equals the angle between the initial projectile direction and horizontal. flight time of projectile t = (2Vo/ay)sin 2ᶿ Total time in the air if the initial height equals the final height. ᶿ equals the angle between the initial projectile direction and horizontal.
  • 7. Questions • Do we have to know the mass of the object? – NO. Gravity acts on large and small objects equally.
  • 8. Questions • Do we have to know either the distance traveled, time traveled or the velocity of the projectile to calculate other parameters? – YES. The only constant available is gravity (g or –ay).
  • 9. Example – Horizontal Projection Vo = ? Ymax = 100 cm Xmax = 500 cm
  • 10. Example – Horizontal Projection • Known: – Vyo = 0 – g = -ay = 9.81 m/sec – Ymax = 100 cm = 1 m – Xmax = 500 cm = 5 m
  • 11. Example – Horizontal Projection • Key point: velocity = distance/time – Horizontal distance is known (5 m) – Horizontal travel time = “free fall” time – Y = Voy t + ½ a t2 – Initial vertical velocity (Voy) = 0
  • 12. Example – Horizontal Projection • Calculation – Y = 1 m = ½ 9.81 m/sec2 t2 – t = [1 m (2)/9.8 m/sec2]1/2 = 0.45 sec – Vox = Xmax/t = 5 m/0.45 sec – Vox = 11.1 m/sec
  • 13. Practical Application In 1957, Homer (Sony) Hickam and 5 other teenagers in Coalwood, West Virginia were designing and building miniature rockets. The boys were accused by authorities of starting a forest fire as a result of an errant rocket launch. The boys were suspended from school until Homer was able to make his case to the Principal of the High School using his understanding of projectile motion… http://movieclips.com/u6Kx-october-sky-movie-homer-proves-his-innocence/#. TqsNdRK2N0U.email