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Fluid mechanics
Lecture 4
Dr. Ahmed Adel Saleh
Contents
• Pressure Variation in a Static Fluid
• Pressure Measurement
• Hydrostatic Force on a Plane Surface
• Hydrostatic Force on a Curved Surface
What are Hydrostatic Forces ?
• Force due to the pressure of a fluid at rest
• Ex:
• Force exerted on the wall of storage tanks, dams, and ships)
Why study Hydrostatic Forces ?
Previously, we learned
• Pressure affects perpendicular to the surface upon which it acts.
• Pressure increases linearly dependent only to the vertical depth
• Pressure on horizontal surfaces (i.e., at the bottom of tanks) is uniform
• Pressure depends on specific weight of the fluid
Hydrostatic Forces on
Plane Surfaces
newindianexpress.com
Total force acts on vertical straight surface
F1
F2
h1 = 4 m2 m
F1 = γ h1 Agate
F1 = 9.8 * 4 * (2*2) = 156.8 KN
h2 = 2 m
F2 = 0.5* γ h2 Agate
F2 = 0.5*9.8 * 2 * (2*2) = 39.2 KN
FR = F1 + F2
FR = 196 kN
(special case)
In-class exercise
h1
h2
h3
Square gate
Assume heights [h1(1:4), h2 (1:3)]
γwater = 9.8 kN/m3
Find force needed to start drain (i.e., open the gate)
The Hydrostatic Pressure Distribution
(General case)
x
y
z
x
y
Θ
Force Caused by a Hydrostatic Pressure Distribution
Force Caused by a
Hydrostatic Pressure
Distribution
Magnitude of
resultant hydrostatic
force
Location of affect of
the resultant
hydrostatic force
Force Caused by a Hydrostatic Pressure Distribution 2
1st moment of area
pressure at centroid of A
Magnitude of resultant hydrostatic force on plane surface is
product of pressure at centroid of area and area of surface.
F = γ hc A
The Center of Pressure for a Hydrostatic Pressure Distribution
by taking moments about horizontal axis 0-0
2nd moment of area about 0-0
= moment of inertia
about 0-0 about centroidal axis
The Center of Pressure for a Hydrostatic Pressure Distribution
The Center of Pressure is always below centroid
The Center of Pressure for a Hydrostatic Pressure Distribution
Determine xcp by taking moment about y axis
For symmetry surfaces
In-class exercise 2
(General case)
Square gate (2m)
γwater = 9.8 kN/m3
Find force needed to raise the gate (neglect gate weight
and coefficient of friction)
Θ = 30°
4.0 m
1. Find depth of centroid (hc)
2. Find Hz forces (F = γ hc A)
Special cases
F = γ h A
Hydrostatic Forces on Curved
Surfaces
• For the case of a curved surface, all elements do not lie in the same
plane. So the hydrostatic forces (although perpendicular to their
respective elements) do not form a system of parallel forces.
• To get the hydrostatic force on a submerged curved surface, both
horizontal and vertical components are calculated first. Then, their
resultant will be the required force.
• Pressure at a point in a fluid
• Proof that pressure acts equally in all directions
slideplayer.com
Hydrostatic Force on a Plane Surface
• How much is the resultant force on inclined submerged surface ?
• Where that resultant force act ?
This section explains how to represent hydrostatic pressure
distributions on one face of a panel with a resultant
force that passes through a point called the center of pressure.
This information is relevant to applications such
as dams and water towers.
• The force on an elemental plane lamina equals the pressure at the
depth of the element multiplied by its area,
www.engineersedge.com
Success at solving problems of
fluid mechanics
• https://www.youtube.com/watch?v=2ssodW8tVSA

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Hydrostatic force distribution on curved surfaces

  • 1. Fluid mechanics Lecture 4 Dr. Ahmed Adel Saleh
  • 2. Contents • Pressure Variation in a Static Fluid • Pressure Measurement • Hydrostatic Force on a Plane Surface • Hydrostatic Force on a Curved Surface
  • 3. What are Hydrostatic Forces ? • Force due to the pressure of a fluid at rest • Ex: • Force exerted on the wall of storage tanks, dams, and ships)
  • 5. Previously, we learned • Pressure affects perpendicular to the surface upon which it acts. • Pressure increases linearly dependent only to the vertical depth • Pressure on horizontal surfaces (i.e., at the bottom of tanks) is uniform • Pressure depends on specific weight of the fluid
  • 8.
  • 9. Total force acts on vertical straight surface F1 F2 h1 = 4 m2 m F1 = γ h1 Agate F1 = 9.8 * 4 * (2*2) = 156.8 KN h2 = 2 m F2 = 0.5* γ h2 Agate F2 = 0.5*9.8 * 2 * (2*2) = 39.2 KN FR = F1 + F2 FR = 196 kN (special case)
  • 10. In-class exercise h1 h2 h3 Square gate Assume heights [h1(1:4), h2 (1:3)] γwater = 9.8 kN/m3 Find force needed to start drain (i.e., open the gate)
  • 11. The Hydrostatic Pressure Distribution (General case) x y z x y Θ
  • 12. Force Caused by a Hydrostatic Pressure Distribution Force Caused by a Hydrostatic Pressure Distribution Magnitude of resultant hydrostatic force Location of affect of the resultant hydrostatic force
  • 13. Force Caused by a Hydrostatic Pressure Distribution 2 1st moment of area pressure at centroid of A Magnitude of resultant hydrostatic force on plane surface is product of pressure at centroid of area and area of surface. F = γ hc A
  • 14. The Center of Pressure for a Hydrostatic Pressure Distribution by taking moments about horizontal axis 0-0 2nd moment of area about 0-0 = moment of inertia about 0-0 about centroidal axis
  • 15. The Center of Pressure for a Hydrostatic Pressure Distribution The Center of Pressure is always below centroid
  • 16. The Center of Pressure for a Hydrostatic Pressure Distribution Determine xcp by taking moment about y axis For symmetry surfaces
  • 17. In-class exercise 2 (General case) Square gate (2m) γwater = 9.8 kN/m3 Find force needed to raise the gate (neglect gate weight and coefficient of friction) Θ = 30° 4.0 m 1. Find depth of centroid (hc) 2. Find Hz forces (F = γ hc A)
  • 19. Hydrostatic Forces on Curved Surfaces
  • 20. • For the case of a curved surface, all elements do not lie in the same plane. So the hydrostatic forces (although perpendicular to their respective elements) do not form a system of parallel forces. • To get the hydrostatic force on a submerged curved surface, both horizontal and vertical components are calculated first. Then, their resultant will be the required force.
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  • 23. • Pressure at a point in a fluid • Proof that pressure acts equally in all directions slideplayer.com
  • 24. Hydrostatic Force on a Plane Surface • How much is the resultant force on inclined submerged surface ? • Where that resultant force act ? This section explains how to represent hydrostatic pressure distributions on one face of a panel with a resultant force that passes through a point called the center of pressure. This information is relevant to applications such as dams and water towers.
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  • 26. • The force on an elemental plane lamina equals the pressure at the depth of the element multiplied by its area, www.engineersedge.com
  • 27. Success at solving problems of fluid mechanics