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Solve and Graph Quadratic
Equation
Algebra II
What Shape is the Golden Gate Bridge?
•What is a quadratic function?
Y = AX^2 + BX + C
•What is a
Parabola?
•How to know if it’s a function?
Use vertical line test.
How to find X-intercepts?
X-intercepts: also known as roots, are
the locations where the graph
intersects with the X-axis.
Example: Y = 2X^2 – 8X + 6
Let Y = 0, solve for X:
2X^2 – 8X + 6 = 0
X^2 – 4X + 3 = 0 (simplify)
(X-1)(X-3) = 0 (factor it)
X=1, or X=3
How to find Y-intercepts?
Y-intercept: the location where the
graph intersects with the Y-axis.
Example: Y = 2X^2 – 8X + 6
Let 0 = 0, solve for Y:
Y = 2(0)^2 – 8(0) + 6
Y = 0 – 0 + 6 (simplify)
Y=6 (simplify)
How to find vertex?
Vertex: the lowest or highest point of the graph.
Example: Y = 2X^2 – 8X + 6, (a=2, b=-8, c=6)
Formula for vertex X= -b/(2a)
X = -(-8)/(2*2)
X = 8/4 = 2 (simplify)
When X=2, Y=2(2)^2-8(2)+6 =8-16+6 =-2
So vertex is (2, -2)
How to determine the direction of a
parabola’s opening?
When a>0, parabola opens up
When a<0, parabola opens down
Example: Y = 2X^2 – 8X + 6, (a=2)
Because 2>0, the parabola opens up
Graph the Equation:
Domain (x-range): X are all real numbers
Range (Y-range): Y are >= -2

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Parabola Lesson Powerpoint Presentation

  • 1. Solve and Graph Quadratic Equation Algebra II
  • 2. What Shape is the Golden Gate Bridge?
  • 3. •What is a quadratic function? Y = AX^2 + BX + C •What is a Parabola? •How to know if it’s a function? Use vertical line test.
  • 4. How to find X-intercepts? X-intercepts: also known as roots, are the locations where the graph intersects with the X-axis. Example: Y = 2X^2 – 8X + 6 Let Y = 0, solve for X: 2X^2 – 8X + 6 = 0 X^2 – 4X + 3 = 0 (simplify) (X-1)(X-3) = 0 (factor it) X=1, or X=3
  • 5. How to find Y-intercepts? Y-intercept: the location where the graph intersects with the Y-axis. Example: Y = 2X^2 – 8X + 6 Let 0 = 0, solve for Y: Y = 2(0)^2 – 8(0) + 6 Y = 0 – 0 + 6 (simplify) Y=6 (simplify)
  • 6. How to find vertex? Vertex: the lowest or highest point of the graph. Example: Y = 2X^2 – 8X + 6, (a=2, b=-8, c=6) Formula for vertex X= -b/(2a) X = -(-8)/(2*2) X = 8/4 = 2 (simplify) When X=2, Y=2(2)^2-8(2)+6 =8-16+6 =-2 So vertex is (2, -2)
  • 7. How to determine the direction of a parabola’s opening? When a>0, parabola opens up When a<0, parabola opens down Example: Y = 2X^2 – 8X + 6, (a=2) Because 2>0, the parabola opens up
  • 8. Graph the Equation: Domain (x-range): X are all real numbers Range (Y-range): Y are >= -2