Answer is Highlighted in Red. I don\'t understand why it is the answer so can you ste by step explain what each part of the code is doing? Solution #include<iostream> #include<string> using namespace std; public bool isPermutation(String str1,String str2) { if(str1.size()!= str2.size()) return false; else continue; int i,counts[10]; for(i =0;i<str1.size();i++) counts[str1[i] –‘0’] ++;   //Increment the least significant bit for(i=0;i<str2.size();i++) counts[str2[i] – ‘0’]--;  // decrement the least significant bit for(i=0;i<10;i++) { if(counts[i]!=0) return false;  // if any count is different ,it is not a permutation else return true;  // counts are identical, was a permutation } } int main() { String s1,String s2; cout << “enter string1â€; cin>>s1; cout<<end1; cout << “Enter string2â€; cin>>s2; cout<<end1; isPermutation(s1,s2); if(isPermutation(s1,s2)) { cout<<â€Strings are permutations†<<end1; else cout <<â€Strings are not Permutations†<< end1; } return 0; } .