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Chrome File Edit View History Bookmarks People Window Help https://elear x https://elear x https://elear x https://elear x Representati X y Causal syster x wherext an x my MyUni MyU × Review Test S × : Picture 4.png x https://elearning Sydney.edu.au/webapps/assessment/review/review a h sp?attempt d -7239085 1&course; id - 54098 1&content;_id -2857557_1&return; content Question 2 0 out of 2 points The graph shows operating curves for a BJT. Please click on the saturation region of operation. Selected Answer: 223, 300 Student Response 3.0 mA ig-100 uA 1,-80 A IB = 60 A ig-40 HA in = 20 A 2.0 mA 1.0 mA 0.0 mA 1.0 mA IMG 0165.JPG IMG_0164JPG IMG 0162.JPG IMG 0160JPG IMG_0158JPG 11998468-89535271 jpg Show All 6 Solution the given is a o/p characteristics of CE amplifier Ic vs Vce at variation in Ib saturation region : it can be used as \'on\' switch in sat region.

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College students often make up a substantial portion of the population of college cities and towns. State College, Pennsylvania, ranks first with 71.1% of its population made up of college students. What is the probability that in a random sample of 150 people from State College, more than 50 are not college students? Solution Given p=1-0.711=0.289 By using Normal approximation, X~Normal(mean=n*p=150*0.289=43.35, s=n*p*(1-p)=sqrt(150*0.289*0.711)=5.55) The probability is P(X>50)=P((X-mean)/s >(50-43.35)/5.55) =P(Z> 1.2) =0.1151 (check standard normal table).

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$Consider the following function Reduce all fractions to lowest terms..pdf$ $Consider the following function Reduce all fractions to lowest terms..pdf$

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Consider the annual maximum series for the US Geological survey gating station on Clear Creek near Pearland, TX The statistics of the transformed flows are for given average of log of values (y-bar), standard deviation of log values (Sy), skewness (Gs), and sample site (n), Using the Pearson Type III distribution compare the discharges for given recurrence interval with and without the US Water Resource Council recommendation on s coefficients. The map skew (Gm) is given. Solution Frequency Factors K for Gamma and log-Pearson Type III Distributions Recurrence Interval In Years 1.0101 2 5 10 25 50 100 200 SKEW COEFFICIENT Cs Percent Chance (>=) = 1-F 99 50 20 10 4 2 1 0.5 3 -0.667 -0.396 0.420 1.180 2.278 3.152 4.051 4.970 2.9 -0.690 -0.390 0.440 1.195 2.277 3.134 4.013 4.904 2.8 -0.714 -0.384 0.460 1.210 2.275 3.114 3.973 4.847 2.7 -0.740 -0.376 0.479 1.224 2.272 3.093 3.932 4.783 2.6 -0.769 -0.368 0.499 1.238 2.267 3.071 3.889 4.718 2.5 -0.799 -0.360 0.518 1.250 2.262 3.048 3.845 4.652 2.4 -0.832 -0.351 0.537 1.262 2.256 3.023 3.800 4.584 2.3 -0.867 -0.341 0.555 1.274 2.248 2.997 3.753 4.515 2.2 -0.905 -0.330 0.574 1.284 2.240 2.970 3.705 4.444 2.1 -0.946 -0.319 0.592 1.294 2.230 2.942 3.656 4.372 2 -0.990 -0.307 0.609 1.302 2.219 2.912 3.605 4.298 1.9 -1.037 -0.294 0.627 1.310 2.207 2.881 3.553 4.223 1.8 -1.087 -0.282 0.643 1.318 2.193 2.848 3.499 4.147 1.7 -1.140 -0.268 0.660 1.324 2.179 2.815 3.444 4.069 1.6 -1.197 -0.254 0.675 1.329 2.163 2.780 3.388 3.990 1.5 -1.256 -0.240 0.690 1.333 2.146 2.743 3.330 3.910 1.4 -1.318 -0.225 0.705 1.337 2.128 2.706 3.271 3.828 1.3 -1.383 -0.210 0.719 1.339 2.108 2.666 3.211 3.745 1.2 -1.449 -0.195 0.732 1.340 2.087 2.626 3.149 3.661 1.1 -1.518 -0.180 0.745 1.341 2.066 2.585 3.087 3.575 1 -1.588 -0.164 0.758 1.340 2.043 2.542 3.022 3.489 0.9 -1.660 -0.148 0.769 1.339 2.018 2.498 2.957 3.401 0.8 -1.733 -0.132 0.780 1.336 1.993 2.453 2.891 3.312 0.7 -1.806 -0.116 0.790 1.333 1.967 2.407 2.824 3.223 0.6 -1.880 -0.099 0.800 1.328 1.939 2.359 2.755 3.132 0.5 -1.955 -0.083 0.808 1.323 1.910 2.311 2.686 3.041 0.4 -2.029 -0.066 0.816 1.317 1.880 2.261 2.615 2.949 0.3 -2.104 -0.050 0.824 1.309 1.849 2.211 2.544 2.856 0.2 -2.178 -0.033 0.830 1.301 1.818 2.159 2.472 2.763 0.1 -2.252 -0.017 0.836 1.292 1.785 2.107 2.400 2.67 0 -2.326 0.000 0.842 1.282 1.751 2.054 2.326 2.576 -0.1 -2.4 0.017 0.846 1.27 1.716 2.000 2.252 2.482 -0.2 -2.472 0.033 0.850 1.258 1.680 1.945 2.178 2.388 -0.3 -2.544 0.050 0.853 1.245 1.643 1.890 2.104 2.294 -0.4 -2.615 0.066 0.855 1.231 1.606 1.834 2.029 2.201 -0.5 -2.686 0.083 0.856 1.216 1.567 1.777 1.955 2.108 -0.6 -2.755 0.099 0.857 1.200 1.528 1.720 1.880 2.016 -0.7 -2.824 0.116 0.857 1.183 1.488 1.663 1.806 1.926 -0.8 -2.891 0.132 0.856 1.166 1.448 1.606 1.733 1.837 -0.9 -2.957 0.148 0.854 1.147 1.407 1.549 1.660 1.749 -1 -3.022 0.164 0.852 1.128 1.366 1.492 1.588 1.664 -1.1 -3.087 0.180 0.848 1.107 1.324 1.435 1.518 1.581 -1.2 -3.149 0.195 0.844 1.086 1.282 1.379 1.449 1.501 -1.3 -3.2.

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Christy Reed has been depositing $2,000 in her savings account every December since 2001. Her account earns 7 percent compounded annually. Solution 1) Future Value = PMT(P/A,7%,12) FV = $2000 x 7.943 = $15,886 2) Nper calculated in excel Double Amount in year = NPER (Rate, pmt, pv,fv) = NPER(10%,0,1,-2) = 7.2 years Triple Amount in years = NPER(10%,0,1,-3) = 11.5 years Using F/P table @10% we can find NPER year 1 F/P = 1.1 Year 7 F/P = 1.949 (its approx double the number) = NPER = 7 Year = 12 F/P = 3.138 (its approx triple the number = NPER = 12.

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Compute the correlation of X and Y. Compute the covariance of X and Y. (Refer to the Homework 14 solutions for the marginal PDFs.) Compute E(5X(1 + Y)+3Y( l - X)) from your work in part (b) (i.e., don\'t do any new integration). Compute the correlation coefficient rho of X and Y. Are X and Y uncorrelated? Justify your answer. Solution correlation of X willbe 3x/2+1/4 correlation of Y will be 3/4(y^2+1).

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