ii) Below are top views of four identical objects moving to the right at 20 m/s. Various forces act on the objects in the horizontal plane, either parallel to the motion or at 45°, 90, or 135°.Rank the objects on the basis of their speed just after the forces are applied, from largest to smallest; e.g., enter ABCD 5N 10N 5.N 5N ON ?ON 5N D) A) SN B) N C) 5N Solution In case of A - Total force opposing the motion = 10 + 5 + 5 = 20 N In the case of B - Resultant force on the object is ZERO. Because, force in the left side = 10 N Total force on the right side = 5+5 = 10 N So, resultant force = 10 - 10 = 0 N So, speed of the object will be constant i.e, 20 m/s. In case of C - Total force opposing the motion = 10 - 2*5*cos45 = 2.93 N In case of D - Total force opposing the motion = 10 N So, the correct order of the speed of the object after application of the force is (from highest to lowest) - BCDA .

1. ii) Below are top views of four identical objects moving to the right at 20 m/s. Various forces act
on the objects in the horizontal plane, either parallel to the motion or at 45°, 90, or 135°.Rank
the objects on the basis of their speed just after the forces are applied, from largest to smallest;
e.g., enter ABCD 5N 10N 5.N 5N ON ?ON 5N D) A) SN B) N C) 5N
Solution
In case of A -
Total force opposing the motion = 10 + 5 + 5 = 20 N
In the case of B -
Resultant force on the object is ZERO.
Because, force in the left side = 10 N
Total force on the right side = 5+5 = 10 N
So, resultant force = 10 - 10 = 0 N
So, speed of the object will be constant i.e, 20 m/s.
In case of C -
Total force opposing the motion = 10 - 2*5*cos45 = 2.93 N
In case of D -
Total force opposing the motion = 10 N
So, the correct order of the speed of the object after application of the force is (from highest to
lowest) -
BCDA