The hypothetical reaction, A +BC, has the rate law Rate-HA)\" [B] when [A] is doubled and IB) is held constan values of z and y? doubles. But the rate increases fourfold when (B] is doubled and [A] is held constant. What are the Solution rate = k [A]^x [B]^y case 1: when [A] doubles and [B] is constant, rate doubles So, rate2 / rate1 = ([A]2/[A]1)^x * ([B]2/[B]1)^y 2 = (2)^x * 1^y 2 = (2)^x * 1 2 = 2^x x = 1 case 2: when [A] is constant and [B] is doubles, rate becomes 4 times So, rate2 / rate1 = ([A]2/[A]1)^x * ([B]2/[B]1)^y 4 = (1)^x * (2)^y 4 = 1 * (2)^y 4 = (2)^y y = 2 Answer: x = 1 y = 2 .