(20 points) Kinematic of particle motioos A particle movs along a durin straight line during 15 seconds with velocity V and acceloeration a sivw veloelty V(0)-10 m/s at moment b (s) and av-i m/s\" during irst 5 secouds 0x0 m/ during next 5 seconds 4 -2 m/s during last 5 seconds a) Plot N) Fiad the particle velosity V wita respect to the tine t (o points) b) Find total displacement of the particle during 15 seconds (10 points) 15 the E 10 15 10 time, s Solution a) The plotted graph of V vs t is already correct. b) The total displacement during the 15 sec, is the area under the graph of V vs t from t=0 to t=15 Area from t=0 to t=5 is (5*10) + (5*5/2) = 62.5 Area from t=5 to t=10 is (5*15) = 75 Area from t=10 to t=15 is (5*5) + (5*10/2) = 50 Total area under V vs t graph from t=0 to t=15 is 62.5 + 75 + 50 = 187.5 So the total displacement during the 15 sec is 187.5 m .