find the vertex and all the intercepts of the parabola. sketch the graph then determine all appropriate window values f(x)=-4x^2+4x-1 Solution The vertex is found by -b/2a so a is the first number (-4) and bis the second number(4) so this is -4/2(-4) so when x=1/2 is the vertex(1/2,0). You then have y intrcepts when x=0 so f(0)=-4(0)^2+4(0)-1 so y intecept is (0,-1). You have x intecepts when the function =0 so you can do this by factoring the function so x intercept is (1/2,0) to graph the function just plug values into the function and plot points. for example in your case pick -2,-1,0,1,2 these are the x values and when you put them into the function and simplify that will be your y value.You should get (-2,-25),(-1,-9),(0,-1),(1,-1),(2,-9) also plot the vertex (1/2,0) then just connect the points and the graph is finished. Hope this helps. .

1. find the vertex and all the intercepts of the parabola. sketch the graph then determine all
appropriate window values
f(x)=-4x^2+4x-1
Solution
The vertex is found by -b/2a so a is the first number (-4) and bis the second number(4) so this is -
4/2(-4) so when x=1/2 is the vertex(1/2,0). You then have y intrcepts when x=0 so f(0)=-
4(0)^2+4(0)-1 so y intecept is (0,-1). You have x intecepts when the function =0 so you can do
this by factoring the function so x intercept is (1/2,0) to graph the function just plug values into
the function and plot points. for example in your case pick -2,-1,0,1,2 these are the x values and
when you put them into the function and simplify that will be your y value.You should get (-2,-
25),(-1,-9),(0,-1),(1,-1),(2,-9) also plot the vertex (1/2,0) then just connect the points and the
graph is finished. Hope this helps.