1. Capacitor VAR (reactive power of
capacitor Qc)
Qc = 2880 - 1338.64
Qc = 1541.35 VAR

2. IC
=
Qc
Vc
IC
=
1541.35
240
IC
=
6.422 A

3. XC
=
Vc
Ic
XC
=
240
6.422
Xc
=
37.37 Ω

4. If Xc =
1 .
2π f C
Then
C =
1 .
2π f Xc
so
C
=
1 .
2 x π x 50 x 37.37
C
=
85µF approximately
Answer: the value of the capacitor for a 0.8
power factor is 85µF