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Question:
Research supports a 79% finding; however, of a sample of 300 businesses, what is the
propability that Fewer that 65% agree with the finding:
P= .79, P-hat= .65, and n=300
Z= .65-.79/(sqrt of .79 *(1-.79)/300= -5.9534
I know this answer is not right, where did I mess-up?
Solution
z= (0.65-0.79)/sqrt(0.79*0.21/300) = -5.953
propability that Fewer that 65% agree with the finding = P(z<-5.953) = 0

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QuestionResearch supports a 79 finding; however, of a sample of .pdf

  • 1. Question: Research supports a 79% finding; however, of a sample of 300 businesses, what is the propability that Fewer that 65% agree with the finding: P= .79, P-hat= .65, and n=300 Z= .65-.79/(sqrt of .79 *(1-.79)/300= -5.9534 I know this answer is not right, where did I mess-up? Solution z= (0.65-0.79)/sqrt(0.79*0.21/300) = -5.953 propability that Fewer that 65% agree with the finding = P(z<-5.953) = 0