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Forces in equilibrium
So this means

‱ There is no acceleration
‱ The sum of the forces = 0
‱ Further

     – The sum of force in the x-direction = 0
     – The sum of forces in the y-direction = 0   ΣFx = 0
                                                  ÎŁFy = 0
Example
A cafe sign with a mass of 65.5 kg is being held up by 2 cables as shown in
   the picture to the left. Calculate the tension in each of the ropes.
                                                    X Direction
                                                    T2 cos35 T1 cos19
                    T2    T1                        T1    0.866T2
    T2sin35                            T1sin19

              T2cos35    T1cos19
                                                 T2 sin 35 T1 sin 19 mg
              Catsup & Mustard                   0.574T2 0.326T1      642
                                    0.574T2 0.282T2      642
                                    0.856T2 642
                         mg         T2 750 N             T1 = 650 N
What if the object is not in
              equilibrium?
If it is not in equilibrium, then what’s going on
                 with its motion???
It is changing in some way!!
It can be
.stopping, slowing down, speeding
up, changing direction, beginning to move

                                    USE NEWTON’S
ACCELERATING!                       SECOND LAW!!
                                          
What if the object is not in
               equilibrium?

1. Draw a free body diagram
2. Break vectors into components if needed
3. Find the NET force by adding and subtracting forces
   that are on the same axis as the acceleration.
4. Set net force equal to “ma” this is called writing an
   EQUATION OF MOTION.
                             ÎŁFx = max     ÎŁFy = may
NOTE: To avoid negative numbers, always subtract the
   smaller forces from the larger one.
example
     A bucket attached to a rope is lifted from a well. The mass of
     the bucket and the water in the bucket are 10.0 kg, and the
     tension in the rope is 100 Newtons. What is the acceleration
1.   of the bucket? diagram
      Draw a free body
2.   Break vectors into components if
     needed
3.   Find the NET force by adding and
     subtracting forces that are on the same
     axis as the acceleration.
4.   Set net force equal to “ma” this is called
     writing an EQUATION OF MOTION.
                                                  a = 0.2 m/s2
Example
An elevator with a mass of 2000 kg rises with an
  acceleration of 1.0 m/s/s. What is the tension in the
  supporting cable?                      Equation of Motion
      T
                     FNET = ma
                     T - mg = ma
                     T = ma + mg
                     T = (2000)(1) + (2000)(9.8)
                     T=     21,600 N
       mg
elevators
    ‱ Maximum tension in ‱ Minimum tension
      elevator occurs
         T                        occurs when there is
                                               T
      when Tthere is an
              - mg = ma           a downward
                             mg - T = ma
      upward ma + mg
            T = acceleration      acceleration
                             T = ma - mg
a
                                           a




         mg
                                               mg
elevators
‱ There are typically 3 phases to an elevators motion:
   – At a constant speed
   – When it comes to a stop
   – When it starts moving
‱ As a result, the tension on the elevators rope WILL
  change, AND the weight you read on a scale will change

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Forces in Equilibrium Explained

  • 1. Forces in equilibrium So this means
 ‱ There is no acceleration ‱ The sum of the forces = 0 ‱ Further
 – The sum of force in the x-direction = 0 – The sum of forces in the y-direction = 0 ÎŁFx = 0 ÎŁFy = 0
  • 2. Example A cafe sign with a mass of 65.5 kg is being held up by 2 cables as shown in the picture to the left. Calculate the tension in each of the ropes. X Direction T2 cos35 T1 cos19 T2 T1 T1 0.866T2 T2sin35 T1sin19 T2cos35 T1cos19 T2 sin 35 T1 sin 19 mg Catsup & Mustard 0.574T2 0.326T1 642 0.574T2 0.282T2 642 0.856T2 642 mg T2 750 N T1 = 650 N
  • 3. What if the object is not in equilibrium? If it is not in equilibrium, then what’s going on with its motion??? It is changing in some way!! It can be
.stopping, slowing down, speeding up, changing direction, beginning to move
 USE NEWTON’S ACCELERATING! SECOND LAW!! 
  • 4. What if the object is not in equilibrium? 1. Draw a free body diagram 2. Break vectors into components if needed 3. Find the NET force by adding and subtracting forces that are on the same axis as the acceleration. 4. Set net force equal to “ma” this is called writing an EQUATION OF MOTION. ÎŁFx = max ÎŁFy = may NOTE: To avoid negative numbers, always subtract the smaller forces from the larger one.
  • 5. example A bucket attached to a rope is lifted from a well. The mass of the bucket and the water in the bucket are 10.0 kg, and the tension in the rope is 100 Newtons. What is the acceleration 1. of the bucket? diagram Draw a free body 2. Break vectors into components if needed 3. Find the NET force by adding and subtracting forces that are on the same axis as the acceleration. 4. Set net force equal to “ma” this is called writing an EQUATION OF MOTION. a = 0.2 m/s2
  • 6. Example An elevator with a mass of 2000 kg rises with an acceleration of 1.0 m/s/s. What is the tension in the supporting cable? Equation of Motion T FNET = ma T - mg = ma T = ma + mg T = (2000)(1) + (2000)(9.8) T= 21,600 N mg
  • 7. elevators ‱ Maximum tension in ‱ Minimum tension elevator occurs T occurs when there is T when Tthere is an - mg = ma a downward mg - T = ma upward ma + mg T = acceleration acceleration T = ma - mg a a mg mg
  • 8. elevators ‱ There are typically 3 phases to an elevators motion: – At a constant speed – When it comes to a stop – When it starts moving ‱ As a result, the tension on the elevators rope WILL change, AND the weight you read on a scale will change