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L4-1
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Ideal CSTR
Design Eq
with XA:
Review: Design Eq & Conversion
D
a
d
C
a
c
B
a
b
A 



fed
A
moles
reacted
A
moles
XA 
BATCH
SYSTEM: A
0
A
j
0
j
j X
N
N
N 

  











j
A
0
A
j
j
0
T
j
T X
N
N
N
N 
FLOW
SYSTEM: A
0
A
j
0
j
j X
F
F
F 

  











j
A
0
A
j
j
0
T
j
T X
F
F
F
F 
r
X
F
V
A
A
0
A


V
r
dt
dX
N A
A
0
A 

Ideal Batch Reactor
Design Eq with XA:



A
X
0 A
A
0
A
V
r
dX
N
t
A
A
0
A r
dV
dX
F 

Ideal SS PFR
Design Eq with XA:



A
X
0 A
A
0
A
r
dX
F
V
'
r
dW
dX
F A
A
0
A 

Ideal SS PBR
Design Eq with XA:



A
X
0 A
A
0
A
'
r
dX
F
W
j≡ stoichiometric coefficient;
positive for products, negative
for reactants
L4-2
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Review: Sizing CSTRs
We can determine the volume of the CSTR required to achieve a specific
conversion if we know how the reaction rate rj depends on the conversion Xj
A
A
0
A
CSTR
A
A
0
A
CSTR X
r
F
V
r
X
F
V 












Ideal SS
CSTR
design eq.
Volume is
product of FA0/-rA
and XA
• Plot FA0/-rA vs XA (Levenspiel plot)
• VCSTR is the rectangle with a base of XA,exit and a height of FA0/-rA at XA,exit

FA 0
rA
X
Area = Volume of CSTR
X1
V 
FA 0
rA



X1
 X1
L4-3
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
FA 0
rA
Area = Volume of PFR
V  0
X1

FA 0
rA






dX
X1
Area = VPFR or Wcatalyst, PBR
dX
'
r
F
W
1
X
0 A
0
A
 









Review: Sizing PFRs & PBRs
We can determine the volume (catalyst weight) of a PFR (PBR) required to
achieve a specific Xj if we know how the reaction rate rj depends on Xj
A
exit
,
A
X
0 A
0
A
PFR
exit
,
A
X
0 A
A
0
A
PFR dX
r
F
V
r
dX
F
V  













Ideal PFR
design eq.
• Plot FA0/-rA vs XA (Experimentally determined numerical values)
• VPFR (WPBR) is the area under the curve FA0/-rA vs XA,exit
A
exit
,
A
X
0 A
0
A
PBR
exit
,
A
X
0 A
A
0
A
PBR dX
r
F
W
r
dX
F
W  













Ideal PBR
design eq.
dX
r
F
V
1
X
0 A
0
A
 









L4-4
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Numerical Evaluation of Integrals (A.4)
Simpson’s one-third rule (3-point):
       
 
2
1
0
2
X
0
X
f
X
f
4
X
f
3
h
dx
x
f 



h
X
X
2
X
X
h 0
1
0
2 



Trapezoidal rule (2-point):
     
 
1
0
1
X
0
X
f
X
f
2
h
dx
x
f 


0
1 X
X
h 

Simpson’s three-eights rule (4-point):
         
 
3
2
1
0
3
X
0
X
f
X
f
3
X
f
3
X
f
h
8
3
dx
x
f 




3
X
X
h 0
3 

h
2
X
X
h
X
X 0
2
0
1 



Simpson’s five-point quadrature :
           
 
4
3
2
1
0
4
X
0
X
f
X
f
4
X
f
2
X
f
4
X
f
3
h
dx
x
f 





4
X
X
h 0
4 

L4-5
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Review: Reactors in Series
2 CSTRs 2 PFRs
CSTR→PFR
VCSTR1 VPFR2
VPFR2
VCSTR1
VCSTR2
VPFR1
VPFR1
VCSTR2
VCSTR1 + VPFR2
≠
VPFR1 + CCSTR2
PFR→CSTR
A
A0
r
-
F
 


i j
CSTR
PFR
PFR V
V
V
If is monotonically
increasing then:
CSTR
i j
CSTR
PFR V
V
V
  

L4-6
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
L4: Rate Laws & Stoichiometry
• Reaction Rates (–rA )
1. Concentration
2. Temperature
3. Reversible reactions
• How to derive an equation for –rA [–rA = f(XA)]
1. Relate all rj to Cj
2. Relate all Cj to V or u
3. Relate V or u to XA
4. Put together
A
A
X
A
A0
0
dX
r
t N
V

 
A
A
A0
F X
V
r


A
X
A
A0
0 A
r
dX
V F

 
A
A
X
A
A0
0
dX
r
W
'
F

 
L4-7
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Concentration and Temperature
• Molecular collision frequency  concentration
• Rate of reaction  concentration
   
A A A B
-r k T f C ,C ,...
  
 
Reaction rate is a function of temperature and concentration
CA : Concentration of A CB : Concentration of B
• As temperature increases, collision frequency increases
• Rate of reaction = f [( CA, CB, ……), (T)]
• At constant temperature : r = f(CA, CB, …….)
Specific rate of reaction, or rate constant,
for species A is a function of temperature
L4-8
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Elementary Reactions & Rate Laws
• Dependence of reaction rate –rA on concentration of chemical species in the
reaction is experimentally determined
• Elementary reaction: involves 1 step (only)
• Stoichiometric coefficients in an elementary reaction are identical to the
powers in the rate law:
C
B
A 

 
 

B
A
A
A C
C
k
r 

Reaction order:
•  order with respect to A
•  order with respect to B
• Overall reaction order n = 
Zero order: -rA = kA k is in units mol/(volume∙time)
1st order: -rA = kACA k is in units time-1
2nd order: -rA = kACA
2 k is in units volume/(mol∙time)
3rd order: -rA = kACA
3 k is in units volume2/(mol2∙time)
L4-9
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Examples:
• This reaction is not elementary, but under some conditions it
follows an elementary rate law
• Forward reaction is 2nd order with respect to NO and 1st order
with respect to O2 (3nd order overall)
Overall Stoichiometric Equations
• Overall equations describe the overall reaction stoichiometry
• Reaction order cannot be deduced from overall equations
Compare the above reaction with the nonelementary reaction
between CO and Cl2
2 2
2NO O 2NO
 
2
NO NO NO O2
r k C C
 
2 2
CO Cl COCl
 
3 2
CO CO Cl2
r kC C
 
Forward reaction is 1st order with respect to CO and 3/2 order with
respect to Cl2 (5/2 order overall)
L4-10
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
L4-11
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Specific Rate Constant, kA
kA is strongly dependent on temperature
Where :
A = Pre-exponential factor or frequency factor (1/time)
E = Activation energy, J/mol or cal/mol
R = Gas constant, 8.314 J/mol K (or 1.987 cal/mol K)
T = Absolute temperature, K
Arrhenius Equation
  E RT
A
k T Ae

To determine activation energy E, run
the reaction at several temperatures,
and plot ln k vs 1/T. Slope is –E/R
Taking ln of
both sides:
E 1
lnk lnA
R T
 
   
 
1/T
ln k -E/R
L4-12
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Reversible Reactions
kA
k A
aA b B c C d D

 
KC: concentration equilibrium constant (capital K)
a b a b
fA A A B fA A A B
r k C C r k C C
    
At equilibrium, the reaction rate is zero, rA=0
Rate of disappearance of A (forward rxn):
c d
bA A C D
r k C C


Rate of generation of A (reverse reaction):
A,net A fA bA
r r r r
  
a b c d
A A A B A C D
r 0 k C C k C C

   
c d
C D
A
C
a b
A A B
C C
k
K
k C C

  
Thermodynamic equilibrium relationship
RX
C C 1
1
H 1 1
K (T) K (T )exp
R T T
 
 

 
 
 
 
 
KC is temperature dependent
(no change in moles or CP):
HRX: heat of reaction
If KC is known for temperature T1, KC for temperature T can be calculated
a b c d
A A A B A C D
r k C C k C C

   
a b c d
A A B A C D
k C C k C C

 
L4-13
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
L4: Rate Laws & Stoichiometry
• Reaction Rates (–rA ) 
1. Concentration 
2. Temperature 
3. Reversible reactions 
• How to derive an equation for –rA [–rA = f(XA)]
1. Relate all rj to Cj
2. Relate all Cj to V or u
3. Relate V or u to XA (Wednesday)
4. Put together (Wednesday)
A
A
X
A
A0
0
dX
r
t N
V

 
A
A
A0
F X
V
r


A
X
A
A0
0 A
r
dX
V F

 
A
A
X
A
A0
0
dX
r
W
'
F

 
L4-14
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
1. Relate all rj to Cj
• rA as a function of Cj is given by the rate law
• The rate relative to other species (rj) is determined by stoichiometry
D
a
d
C
a
c
B
a
b
A 


 “A” is the limiting reagent
     
a
d
r
a
c
r
a
b
r
r D
C
B
A 



 rj is negative for reactants,
positive for products
In general:
j
A
j
r
r
 

j≡ stoichiometric coefficient
positive for products, negative for reactants
a
d
a
c
1
a
b
d
c
A
B 




 



L4-15
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
For the reaction the rate of O2
disappearance is 2 mol/dm3•s (-rO2= 2 mol/dm3•s).
What is the rate of formation of NO2?
2 2
2NO O 2NO
 
j
A
j
r
Hint: r
 

 
2
2
NO
O
r
r
2 1
   
2 2
O NO
2 r r
  
2 2
NO NO
3 3
mol mol
2 2 r 4 r
dm s dm s
 
   
 
 
 
rNO2 = 4 mol/dm3•s
L4-16
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
2a. Relate all Cj to V (Batch System)


B
A
A
A C
C
k
r 

Reaction rate is a function of Cj:
How is Cj related to V and XA? Batch:
j
j
N mol
C
V L
 
D
a
d
C
a
c
B
a
b
A 



 
B0 A0 A
B
B
b
N N X
N a
C
V V
 
  
 
 
 
C0 A0 A
C
C
c
N N X
N a
C
V V
 
  
 
 
A
A
N
C
V

 
A0 A0 A
A
N N X
C
V


Put NA in
terms of XA:
 
D0 A0 A
D
D
d
N N X
N a
C
V V
 
  
 
 
Do the same for
species B, C, and D:
Cj is in terms of XA and V. But what if V varies with XA? That’s step 3a!
A
0
A
j
0
j
j X
N
N
N 


L4-17
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
2a. Additional Variables Used in
Textbook
 
 
  
 
 
B0 A0 A
B
B
b
N X
N a
C
N
V V
Book uses
term Θi:
  
A0
0
0
i
A
i
0 i
C
C
N
N
So species Ni0 can be removed from the equation for Ci
 
 
 
  
 
 
 
 
A0
A0 A
A
B0
A
0
0
B
N
b
X
N
N N
1 a
C
N
V
Multiply numerator by NA0/NA0:
 

 
 
 
   



 
 
A
B
B
B
A
A
A0
0
B
V
b
X
X
C
b
a
C
a
N
C
D
a
d
C
a
c
B
a
b
A 



L4-18
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
T
0 0 0 T0 0
ZN RT
PV
P V Z N RT

3a. Relate V to XA (Batch System)
Volume is constant (V = V0) for:
• Most liquid phase reactions
• Gas phase reactions if moles reactants = moles products
       
2 2 2
CO g H O g CO g H g
 
If the volume varies with time, assume the equation of state for the gas phase:
At time t: PV = ZNTRT and at t=0: P0V0 = Z0NT0RT0
P: total pressure, atm Z: compressibility factor
NT: total moles T: temperature, K
R: ideal gas constant, 0.08206 dm3∙atm/mol∙K
d c b change in total # moles
where = 1
a a a Moles A reacted
 
 
    
 
 
Want V in terms of XA. First find and expression for V at time t:
NT at time t is:
0 T
0
0 0 T0
P N
T Z
V V
P T Z N
   
 
     
 
    
T j T0 A0 A
j
d c b
N N N 1 N X
a a a
 
     
  
 
T T0 A0 A
N N N X

  
What is
NT at t?
L4-19
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
  
T
A
T0
N
1 X
N

3a. Relate V to XA (continued)
T T0 A0 A
N N N X

 
d c b change in total # moles
where = 1
a a a Moles A reacted
 
 
    
 
 
0 T
0
0 0 T0
P N
T Z
V V
P T Z N
   
 
    
 
    
Can we use the eq. for NT above to
find an expression for NT/NT0?
A0
A0
T0
= =mole fraction of A ini
S t
ubstitut ially pr
e:
N
y
N
esent
 
A0
S e
ubsti xpans
tute ion
: r
y facto


T T
0
0
0
A
T 0
0 T0
P T Z
Plug : into
N N
V V
P T
1 X
N N
Z

   
 
 
   
 
    
 
 
  
 
    
 
   

0
0
0
A
0
P T Z
V V
P T
1
Z
X

 
T0
T
A
T0 T0
A0
T0
N
N
N
N
X
N N

  
T
A
T0
A0
N
1 y X
N

L4-20
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.

 
T T0
A
T0
N N
X
N

What is the meaning of ε?
When conversion is
complete (XA=1):
Tf T0 A
T0
N N Change in total # moles at X 1
N total moles fed

 
 
The expansion factor,, is the fraction of change in V per mol A reacted
that is caused by a change in the total number of moles in the system
A0
A0
T0
N
d c b
expansion factor: y 1
a a a N
 
 
    
 
 
T
A
T0
N
1 X
N

 
If we put the following
equation in terms of ε:
  
T
A
T0
N
1 X
N


 
T T0
T0 A
N N
N X

 
  
 
   
 
   


0
0 A
0 0
P T Z
V V
Z
1
P T
X
 where
L4-21
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
4a. Put it all together (batch reactor)
Batch:
 
  
 
 

  
 
  

 
0
j j0 j
j
A0 A
0 A
0 0
V P T
N N N X
Z
V 1
P T
C
X
Z


   
   
   
 


j A0 0 0
A 0
0 A
j
j T Z
P
1 X P T Z
C
C
X
C 

For a given XA, we can calculate Cj and plug the Cj into –rA=kCj
n

j
j
C
N
V


j0 A A
j
j 0
C
N
V
N X

j j j A A
N N N X
 
 0 0
 
  
 

  
 
   


0
0 A
0 0
P T Z
V V 1 X
P T Z


0
0
i0
i
V
N
C
What about flow systems?
L4-22
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
2b. Relate all Cj to u (Flow System)
How is Cj related to uand Xj?
Flow:
j
j
F mol s mol
C
L s L
u
  


B
A
A
A C
C
k
r 

Reaction rate is a
function of Cj:
D
a
d
C
a
c
B
a
b
A 



 
B0 A0 A
B
B
b
F F X
F a
C
u u
 
  
 
 
 
C0 A0 A
C
C
c
F F X
F a
C
u u
 
  
 
 
A
A
F
C
u

 
A0 A0 A
A
F F X
C
u


Put FA in
terms of XA:
 
D0 A0 A
D
D
d
F F X
F a
C
u u
 
  
 
 
Do the same for
species B, C, and D:
We have Cj in terms of XA and u, but what if u varies with XA? That’s step 3b!
A
0
A
j
0
j
j X
F
F
F 


L4-23
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
3b. Relate u to XA (Flow System)
Start with the equation of
state for the gas phase:
T
T
N
P
C
ZRT V
  
What is CT0 at the
entrance of the reactor?
T0 0
T0
0 0 0
F P
C
Z RT
u
 
 
 
T
T0 0 0 0 0
F ZRT 1 P
F Z RT 1 P
u
u

T
PV ZN RT

Rearrange to put in terms
of CT, where CT = NT/V:
T
T
F
C
u

Can we relate
CT to u? T
1
F ZRT
P
u
 
 
 
 
0
T
0
T0 0 0
P
F Z T
F Z T P
u u
    
      
 
   
Rearrange to put
in terms of u:
Put in terms of u0: T0 0 0 0
0
1
F Z RT
P
u
 
 
 
 
Use these 2 equations to
put uin terms of known or
measurable quantities
T
F P
ZRT
u
 
L4-24
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
3b. Relate u to XA (continued)
 
T T0 A0 A
subst F F F X
: and simplify
itute in 
    
     
 
  

 
0
0
T0 0
T0 A0
0
A P
Z T
F Z T P
F F X

u u
When conversion is
complete (XA=1):
Tf T0 A
T0
N N Change in total # moles at X =1
N total moles fed


 
    
     
 
   
0
0
T0
T
0 0
P
Z T
F Z T P
F
u u

A0
substitute y
:  
 
   
     
 
  
A0
0
0 A
0 0
P
Z T
y
1 X
Z T P
u 
u
    
  
    
 
   
A 0
0
0
A
T 0
0
0
X P
Z T
1
Z T
F
F P

u u
 
 
 
   
 
 
A0 0
A0 A0 A0
A0 A0
T0 T0 T0 0 T0
Simplify wit
N V
F N F
y y
F N N V F
Because
:
h
u
u
 
   
      
 
  
0
0 A
0 0
P
Z T
1 X
Z T P
u u 
L4-25
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
4b. Put it all together (flow reactor)
Flow:
 
  
 

  
 


 

  
0
j j0 j
0 A
0 0
0 A
j
A
P T Z
1 X
P
C
F
T
F F X
Z
u
u 

   
   
   
 


j A0 0 0
A 0
0 A
j
j T Z
P
1 X P T Z
C
C
X
C 

For a given XA, we can calculate Cj and plug the Cj into –rA=kCj
n

j
j
C
F
u


j0 A A
j
j 0
C
F
V
F X

j j j A A
F F F X
 
 0 0
 
  
 

  
 
   


0
0 A
0 0
P T Z
1 X
P T Z
u u 

0
0
i0
i
F
C
u
This is the same equation as that for the batch reactor!
L4-26
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
4. Summary: Cj in terms of Xj
Batch:
 

 
  
 

  
 
   
j j0 j A0 A
j
0
0 A
0 0
N N N X
C
V P T Z
V 1 X
P T Z


j0 j A0 A 0 0
j
A 0
C C X T Z
P
C
1 X P T Z


    
     
   
 
j0
j0
0
N
C
V

Flow:
 

 
  
 
   
 
   
j j0 j A0 A
j
0
0 A
0 0
F F F X
C
P T Z
1 X
P T Z

u
u 
j0
j0
0
F
C
u

j0 j A0 A 0 0
j
A 0
C C X T Z
P
C
1 X P T Z


    
     
   
 
This is the same equation as that for the batch reactor!
For a given XA, we can calculate Cj and plug the Cj into –rA=kCj
n

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L4 Rate laws and stoichiometry.pptx

  • 1. L4-1 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Ideal CSTR Design Eq with XA: Review: Design Eq & Conversion D a d C a c B a b A     fed A moles reacted A moles XA  BATCH SYSTEM: A 0 A j 0 j j X N N N                 j A 0 A j j 0 T j T X N N N N  FLOW SYSTEM: A 0 A j 0 j j X F F F                 j A 0 A j j 0 T j T X F F F F  r X F V A A 0 A   V r dt dX N A A 0 A   Ideal Batch Reactor Design Eq with XA:    A X 0 A A 0 A V r dX N t A A 0 A r dV dX F   Ideal SS PFR Design Eq with XA:    A X 0 A A 0 A r dX F V ' r dW dX F A A 0 A   Ideal SS PBR Design Eq with XA:    A X 0 A A 0 A ' r dX F W j≡ stoichiometric coefficient; positive for products, negative for reactants
  • 2. L4-2 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Review: Sizing CSTRs We can determine the volume of the CSTR required to achieve a specific conversion if we know how the reaction rate rj depends on the conversion Xj A A 0 A CSTR A A 0 A CSTR X r F V r X F V              Ideal SS CSTR design eq. Volume is product of FA0/-rA and XA • Plot FA0/-rA vs XA (Levenspiel plot) • VCSTR is the rectangle with a base of XA,exit and a height of FA0/-rA at XA,exit  FA 0 rA X Area = Volume of CSTR X1 V  FA 0 rA    X1  X1
  • 3. L4-3 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. FA 0 rA Area = Volume of PFR V  0 X1  FA 0 rA       dX X1 Area = VPFR or Wcatalyst, PBR dX ' r F W 1 X 0 A 0 A            Review: Sizing PFRs & PBRs We can determine the volume (catalyst weight) of a PFR (PBR) required to achieve a specific Xj if we know how the reaction rate rj depends on Xj A exit , A X 0 A 0 A PFR exit , A X 0 A A 0 A PFR dX r F V r dX F V                Ideal PFR design eq. • Plot FA0/-rA vs XA (Experimentally determined numerical values) • VPFR (WPBR) is the area under the curve FA0/-rA vs XA,exit A exit , A X 0 A 0 A PBR exit , A X 0 A A 0 A PBR dX r F W r dX F W                Ideal PBR design eq. dX r F V 1 X 0 A 0 A           
  • 4. L4-4 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Numerical Evaluation of Integrals (A.4) Simpson’s one-third rule (3-point):           2 1 0 2 X 0 X f X f 4 X f 3 h dx x f     h X X 2 X X h 0 1 0 2     Trapezoidal rule (2-point):         1 0 1 X 0 X f X f 2 h dx x f    0 1 X X h   Simpson’s three-eights rule (4-point):             3 2 1 0 3 X 0 X f X f 3 X f 3 X f h 8 3 dx x f      3 X X h 0 3   h 2 X X h X X 0 2 0 1     Simpson’s five-point quadrature :               4 3 2 1 0 4 X 0 X f X f 4 X f 2 X f 4 X f 3 h dx x f       4 X X h 0 4  
  • 5. L4-5 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Review: Reactors in Series 2 CSTRs 2 PFRs CSTR→PFR VCSTR1 VPFR2 VPFR2 VCSTR1 VCSTR2 VPFR1 VPFR1 VCSTR2 VCSTR1 + VPFR2 ≠ VPFR1 + CCSTR2 PFR→CSTR A A0 r - F     i j CSTR PFR PFR V V V If is monotonically increasing then: CSTR i j CSTR PFR V V V    
  • 6. L4-6 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. L4: Rate Laws & Stoichiometry • Reaction Rates (–rA ) 1. Concentration 2. Temperature 3. Reversible reactions • How to derive an equation for –rA [–rA = f(XA)] 1. Relate all rj to Cj 2. Relate all Cj to V or u 3. Relate V or u to XA 4. Put together A A X A A0 0 dX r t N V    A A A0 F X V r   A X A A0 0 A r dX V F    A A X A A0 0 dX r W ' F   
  • 7. L4-7 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Concentration and Temperature • Molecular collision frequency  concentration • Rate of reaction  concentration     A A A B -r k T f C ,C ,...      Reaction rate is a function of temperature and concentration CA : Concentration of A CB : Concentration of B • As temperature increases, collision frequency increases • Rate of reaction = f [( CA, CB, ……), (T)] • At constant temperature : r = f(CA, CB, …….) Specific rate of reaction, or rate constant, for species A is a function of temperature
  • 8. L4-8 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Elementary Reactions & Rate Laws • Dependence of reaction rate –rA on concentration of chemical species in the reaction is experimentally determined • Elementary reaction: involves 1 step (only) • Stoichiometric coefficients in an elementary reaction are identical to the powers in the rate law: C B A        B A A A C C k r   Reaction order: •  order with respect to A •  order with respect to B • Overall reaction order n =  Zero order: -rA = kA k is in units mol/(volume∙time) 1st order: -rA = kACA k is in units time-1 2nd order: -rA = kACA 2 k is in units volume/(mol∙time) 3rd order: -rA = kACA 3 k is in units volume2/(mol2∙time)
  • 9. L4-9 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Examples: • This reaction is not elementary, but under some conditions it follows an elementary rate law • Forward reaction is 2nd order with respect to NO and 1st order with respect to O2 (3nd order overall) Overall Stoichiometric Equations • Overall equations describe the overall reaction stoichiometry • Reaction order cannot be deduced from overall equations Compare the above reaction with the nonelementary reaction between CO and Cl2 2 2 2NO O 2NO   2 NO NO NO O2 r k C C   2 2 CO Cl COCl   3 2 CO CO Cl2 r kC C   Forward reaction is 1st order with respect to CO and 3/2 order with respect to Cl2 (5/2 order overall)
  • 10. L4-10 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
  • 11. L4-11 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Specific Rate Constant, kA kA is strongly dependent on temperature Where : A = Pre-exponential factor or frequency factor (1/time) E = Activation energy, J/mol or cal/mol R = Gas constant, 8.314 J/mol K (or 1.987 cal/mol K) T = Absolute temperature, K Arrhenius Equation   E RT A k T Ae  To determine activation energy E, run the reaction at several temperatures, and plot ln k vs 1/T. Slope is –E/R Taking ln of both sides: E 1 lnk lnA R T         1/T ln k -E/R
  • 12. L4-12 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Reversible Reactions kA k A aA b B c C d D    KC: concentration equilibrium constant (capital K) a b a b fA A A B fA A A B r k C C r k C C      At equilibrium, the reaction rate is zero, rA=0 Rate of disappearance of A (forward rxn): c d bA A C D r k C C   Rate of generation of A (reverse reaction): A,net A fA bA r r r r    a b c d A A A B A C D r 0 k C C k C C      c d C D A C a b A A B C C k K k C C     Thermodynamic equilibrium relationship RX C C 1 1 H 1 1 K (T) K (T )exp R T T                KC is temperature dependent (no change in moles or CP): HRX: heat of reaction If KC is known for temperature T1, KC for temperature T can be calculated a b c d A A A B A C D r k C C k C C      a b c d A A B A C D k C C k C C   
  • 13. L4-13 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. L4: Rate Laws & Stoichiometry • Reaction Rates (–rA )  1. Concentration  2. Temperature  3. Reversible reactions  • How to derive an equation for –rA [–rA = f(XA)] 1. Relate all rj to Cj 2. Relate all Cj to V or u 3. Relate V or u to XA (Wednesday) 4. Put together (Wednesday) A A X A A0 0 dX r t N V    A A A0 F X V r   A X A A0 0 A r dX V F    A A X A A0 0 dX r W ' F   
  • 14. L4-14 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. 1. Relate all rj to Cj • rA as a function of Cj is given by the rate law • The rate relative to other species (rj) is determined by stoichiometry D a d C a c B a b A     “A” is the limiting reagent       a d r a c r a b r r D C B A      rj is negative for reactants, positive for products In general: j A j r r    j≡ stoichiometric coefficient positive for products, negative for reactants a d a c 1 a b d c A B          
  • 15. L4-15 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. For the reaction the rate of O2 disappearance is 2 mol/dm3•s (-rO2= 2 mol/dm3•s). What is the rate of formation of NO2? 2 2 2NO O 2NO   j A j r Hint: r      2 2 NO O r r 2 1     2 2 O NO 2 r r    2 2 NO NO 3 3 mol mol 2 2 r 4 r dm s dm s             rNO2 = 4 mol/dm3•s
  • 16. L4-16 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. 2a. Relate all Cj to V (Batch System)   B A A A C C k r   Reaction rate is a function of Cj: How is Cj related to V and XA? Batch: j j N mol C V L   D a d C a c B a b A       B0 A0 A B B b N N X N a C V V            C0 A0 A C C c N N X N a C V V          A A N C V    A0 A0 A A N N X C V   Put NA in terms of XA:   D0 A0 A D D d N N X N a C V V          Do the same for species B, C, and D: Cj is in terms of XA and V. But what if V varies with XA? That’s step 3a! A 0 A j 0 j j X N N N   
  • 17. L4-17 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. 2a. Additional Variables Used in Textbook            B0 A0 A B B b N X N a C N V V Book uses term Θi:    A0 0 0 i A i 0 i C C N N So species Ni0 can be removed from the equation for Ci                  A0 A0 A A B0 A 0 0 B N b X N N N 1 a C N V Multiply numerator by NA0/NA0:                     A B B B A A A0 0 B V b X X C b a C a N C D a d C a c B a b A    
  • 18. L4-18 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. T 0 0 0 T0 0 ZN RT PV P V Z N RT  3a. Relate V to XA (Batch System) Volume is constant (V = V0) for: • Most liquid phase reactions • Gas phase reactions if moles reactants = moles products         2 2 2 CO g H O g CO g H g   If the volume varies with time, assume the equation of state for the gas phase: At time t: PV = ZNTRT and at t=0: P0V0 = Z0NT0RT0 P: total pressure, atm Z: compressibility factor NT: total moles T: temperature, K R: ideal gas constant, 0.08206 dm3∙atm/mol∙K d c b change in total # moles where = 1 a a a Moles A reacted              Want V in terms of XA. First find and expression for V at time t: NT at time t is: 0 T 0 0 0 T0 P N T Z V V P T Z N                    T j T0 A0 A j d c b N N N 1 N X a a a              T T0 A0 A N N N X     What is NT at t?
  • 19. L4-19 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.    T A T0 N 1 X N  3a. Relate V to XA (continued) T T0 A0 A N N N X    d c b change in total # moles where = 1 a a a Moles A reacted              0 T 0 0 0 T0 P N T Z V V P T Z N                   Can we use the eq. for NT above to find an expression for NT/NT0? A0 A0 T0 = =mole fraction of A ini S t ubstitut ially pr e: N y N esent   A0 S e ubsti xpans tute ion : r y facto   T T 0 0 0 A T 0 0 T0 P T Z Plug : into N N V V P T 1 X N N Z                                          0 0 0 A 0 P T Z V V P T 1 Z X    T0 T A T0 T0 A0 T0 N N N N X N N     T A T0 A0 N 1 y X N 
  • 20. L4-20 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.    T T0 A T0 N N X N  What is the meaning of ε? When conversion is complete (XA=1): Tf T0 A T0 N N Change in total # moles at X 1 N total moles fed      The expansion factor,, is the fraction of change in V per mol A reacted that is caused by a change in the total number of moles in the system A0 A0 T0 N d c b expansion factor: y 1 a a a N              T A T0 N 1 X N    If we put the following equation in terms of ε:    T A T0 N 1 X N     T T0 T0 A N N N X                     0 0 A 0 0 P T Z V V Z 1 P T X  where
  • 21. L4-21 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. 4a. Put it all together (batch reactor) Batch:                      0 j j0 j j A0 A 0 A 0 0 V P T N N N X Z V 1 P T C X Z                   j A0 0 0 A 0 0 A j j T Z P 1 X P T Z C C X C   For a given XA, we can calculate Cj and plug the Cj into –rA=kCj n  j j C N V   j0 A A j j 0 C N V N X  j j j A A N N N X    0 0                    0 0 A 0 0 P T Z V V 1 X P T Z   0 0 i0 i V N C What about flow systems?
  • 22. L4-22 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. 2b. Relate all Cj to u (Flow System) How is Cj related to uand Xj? Flow: j j F mol s mol C L s L u      B A A A C C k r   Reaction rate is a function of Cj: D a d C a c B a b A       B0 A0 A B B b F F X F a C u u            C0 A0 A C C c F F X F a C u u          A A F C u    A0 A0 A A F F X C u   Put FA in terms of XA:   D0 A0 A D D d F F X F a C u u          Do the same for species B, C, and D: We have Cj in terms of XA and u, but what if u varies with XA? That’s step 3b! A 0 A j 0 j j X F F F   
  • 23. L4-23 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. 3b. Relate u to XA (Flow System) Start with the equation of state for the gas phase: T T N P C ZRT V    What is CT0 at the entrance of the reactor? T0 0 T0 0 0 0 F P C Z RT u       T T0 0 0 0 0 F ZRT 1 P F Z RT 1 P u u  T PV ZN RT  Rearrange to put in terms of CT, where CT = NT/V: T T F C u  Can we relate CT to u? T 1 F ZRT P u         0 T 0 T0 0 0 P F Z T F Z T P u u                   Rearrange to put in terms of u: Put in terms of u0: T0 0 0 0 0 1 F Z RT P u         Use these 2 equations to put uin terms of known or measurable quantities T F P ZRT u  
  • 24. L4-24 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. 3b. Relate u to XA (continued)   T T0 A0 A subst F F F X : and simplify itute in                     0 0 T0 0 T0 A0 0 A P Z T F Z T P F F X  u u When conversion is complete (XA=1): Tf T0 A T0 N N Change in total # moles at X =1 N total moles fed                      0 0 T0 T 0 0 P Z T F Z T P F u u  A0 substitute y :                    A0 0 0 A 0 0 P Z T y 1 X Z T P u  u                    A 0 0 0 A T 0 0 0 X P Z T 1 Z T F F P  u u               A0 0 A0 A0 A0 A0 A0 T0 T0 T0 0 T0 Simplify wit N V F N F y y F N N V F Because : h u u                   0 0 A 0 0 P Z T 1 X Z T P u u 
  • 25. L4-25 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. 4b. Put it all together (flow reactor) Flow:                      0 j j0 j 0 A 0 0 0 A j A P T Z 1 X P C F T F F X Z u u                   j A0 0 0 A 0 0 A j j T Z P 1 X P T Z C C X C   For a given XA, we can calculate Cj and plug the Cj into –rA=kCj n  j j C F u   j0 A A j j 0 C F V F X  j j j A A F F F X    0 0                    0 0 A 0 0 P T Z 1 X P T Z u u   0 0 i0 i F C u This is the same equation as that for the batch reactor!
  • 26. L4-26 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. 4. Summary: Cj in terms of Xj Batch:                     j j0 j A0 A j 0 0 A 0 0 N N N X C V P T Z V 1 X P T Z   j0 j A0 A 0 0 j A 0 C C X T Z P C 1 X P T Z                    j0 j0 0 N C V  Flow:                     j j0 j A0 A j 0 0 A 0 0 F F F X C P T Z 1 X P T Z  u u  j0 j0 0 F C u  j0 j A0 A 0 0 j A 0 C C X T Z P C 1 X P T Z                    This is the same equation as that for the batch reactor! For a given XA, we can calculate Cj and plug the Cj into –rA=kCj n