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Legendre Functions Explained

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Solo Hermelin
Solo Hermelin

The document discusses Legendre functions, which are solutions to Legendre's differential equation. Legendre functions arise when solving Laplace's equation in spherical coordinates. Legendre polynomials were first introduced by Adrien-Marie Legendre in 1785 as coefficients in an expansion of Newtonian potential. The document covers topics such as Legendre polynomials, Rodrigues' formula, orthogonality of Legendre polynomials, and associated Legendre functions.

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Legendre Functions SOLO HERMELIN Updated: 20.02.13 1 http://www.solohermelin.com
Table of Content SOLO 2 Legendre Functions Introduction Legendre Polynomials History Second Order Linear Ordinary Differential Equation (ODE) Laplace’s Homogeneous Differential Equation Legendre Polynomials The Generating Function of Legendre Polynomials Rodrigues' Formula Series Solutions – Frobenius’ Method Recursive Relations for Legendre Polynomial Computation Orthogonality of Legendre Polynomials Expansion of Functions, Legendre Series Schlaefli Integral Laplace’s Integral Representation Neumann Integral
Table of Content (continue) SOLO 3 Legendre Functions Associate Lagrange Differential Equation Laplace Differential Equation in Spherical Coordinates Analysis of Associate Lagrange Differential Equation Associate Lagrange Differential Equation (2nd Way) Generating Function for Pn m (t) Recurrence Relations for Pn m (t) Orthogonality of Associated Legendre Functions Recurrence Relations for Θn m Functions Spherical Harmonics References Boundary Value Problems and Sturm–Liouville Theory
SOLO 4 Legendre Polynomials Adrien-Marie Legendre (1752 –1833( In mathematics, Legendre functions are solutions to Legendre's differential equation: ( ) ( ) ( ) ( ) 011 2 =++      − xPnnxP xd d x xd d nn They are named after Adrien-Marie Legendre. This ordinary differential equation is frequently encountered in physics and other technical fields. In particular, it occurs when solving Laplace's equation (and related partial differential equations) in spherical coordinates. The Legendre polynomials were first introduced in 1785 by Adrien-Marie Legendre, in “Recherches sur l’attraction des sphéroides homogènes”, as the coefficients in the expansion of the Newtonian potential ( )∑ ∞ =       =       −      + = −+ = − 0 222 cos '1 cos ' 2 ' 1 11 cos'2' 1 ' 1 n n n P r r r r r r rrrrrrrr γ γ γ  Return to Table of Content
Second Order Linear Ordinary Differential Equation (ODE) Consider a Second Order Linear Ordinary Differential Equation (ODE) define by the Operator SOLO ( ) ( ) ( ) ( ) ( )xuxp xd ud xp xd ud xpxu 212 2 0: ++=L defined in the interval a ≤ x ≤ b, with the coefficients p0 (x), p1 (x), p2 (x) real in this region and with the first 2 – i derivatives of pi (x) continuous . Also we require that p0 (x) is nonzero in the interval. Define the Quadratic Form of the Operator L as: ( ) ( ) ( ) dxuup xd ud p xd ud pdxxuxuxu b a b a ∫∫       ++== 212 2 0: LLu, ( ) ( ) ( ) ( ) ( ) ( ) ( )∫ ∫∫ ∫ ∫∫ ∫∫∫ +−++      −      = +−+−      = ++ b a b a b a b a b a b a b a b a b a b a b a b a b a b a xdupuxdup xd d uupudxup xd d uup xd d u xd ud up xdupuxdup xd d uupudx xd ud up xd d xd ud up xdupxdu xd ud pxdu xd ud p 21102 2 00 21100 2 212 2 0 5
SOLO ( ) ( ) ( ) dxuup xd ud p xd ud pdxxuxuxu b a b a ∫∫       ++== 212 2 0: LLu, ( ) ( ) ( ) ( ) b a b a b a b a b a xu xd pd pxu upu xd ud upu xd pd u xd ud upupuup xd d u xd ud up             −=       +−−=+      −      0 1 10 0 0100 Therefore: ( ) ( ) ( ) ( )∫       +−+            −= b a b a dxupup xd d up xd d uxu xd pd pxu 2102 2 0 1 Define the Adjoint Operator: ( ) ( ) ( ) upup xd d up xd d xu 2102 2 : +−=L 6 Second Order Linear Ordinary Differential Equation (ODE)
SOLO ( ) dx u up xd ud p xd ud puxu b a ∫       ++=    L Lu, 212 2 0 The two Integrals are equal if: ( ) ( ) ( ) ( )∫       +−+            −= b a b a dxupup xd d up xd d uxu xd pd pxu    uL 2102 2 0 1 or: ( ) ( ) ( ) ( ) ( ) ( )xuxq xd xud xp xd d xuxu +      == LL ( ) ( ) 02 1 01 2 0 2 2102 2 212 2 0 =      −+      −=       +−−      ++ xd ud p xd pd uu xd pd xd pd u upup xd d up xd d uup xd ud p xd ud pu ( ) ( ) xd xpd xp 0 1 = If this condition is satisfied, then the terms at the boundary x = a and x = b also vanish, and we have by defining p (x): = p0 (x) and q (x) := p2 (x) 7 Second Order Linear Ordinary Differential Equation (ODE)
SOLO ( ) ( ) ( ) ( ) ( ) ( )xuxq xd xud xp xd d xuxu +      == LL This Operator is called Self-Adjoint ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )      ++      =      ∫∫ xuxp xd ud xp xd ud xptd tp tp xp xutd tp tp xp xx 212 2 0 0 1 00 1 0 expexp 1 L 1 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )xutd tp tp xp xp xd ud td tp tp xd d xq x xp x            +                   = ∫∫ 0 1 0 2 0 1 expexp This is clearly Self-Adjoint. We can see that p0 (x) is in the denominator. This is the reason that we requested the p0 (x) to be nonzero in the interval a ≤ x ≤ b. p0 (x1) = 0 means that the Differential Equation is not Second Order at that point. We can always transform the Non-Self-Adjoint Operator to a Self-Adjoint one by multipling L by ( ) ( ) ( )       ∫x td tp tp xp 0 1 0 exp 1 8 Second Order Linear Ordinary Differential Equation (ODE)
Consider a Second Order Linear Ordinary Differential Equation (ODE) SOLO ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 2 210 :'':'0''': xd ud u xd ud uxuxpxuxpxuxpxu ===++=L If we know one Solution u1 (x) we can find a second u2 (x). Proof If we have two Solutions u1 (x) and u2 (x), then 0''' 0''' 222120 121110 =++ =++ upupup upupup Multiply first equation by u2 (x) and second by u1 (x) and subtract: ( ) ( ) 0'''''' 1221112210 =−+− uuuupuuuup The Wronskian W is defined as: 1221 21 21 '' '' : uuuu uu uu W −== 0' 10 =+ WpWp 9 Theorem: “Method of Reduction of Order” Second Order Linear Ordinary Differential Equation (ODE)
Consider a Second Order Linear Ordinary Differential Equation (ODE) SOLO ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 2 210 :'':'0''': xd ud u xd ud uxuxpxuxpxuxpxu ===++=L Theorem: “Method of Reduction of Order” If we know one Solution u1 (x) we can find a second u2 (x). Proof (continue -1) 0' 10 =+ WpWp xd p p W Wd 0 1 −= ( ) ( ) ( ) ( )         −= ∫ x x d p p xWxW 0 0 1 0 exp τ τ τ From: ( ) ( ) ( ) ( ) ( )xuxuxuxuxW 1221 '' −= q.e.d. Therefore: ( ) ( ) ( ) ( )∫= x x d u W xuxu 0 2 1 12 τ τ τ ( ) ( ) ( ) ( ) ( ) ( ) ( )       =−= 1 2 22 1 1 1 2 2 1 '' u u xd d xu xu xu xu xu xu xW Divide by u1 2 (x) x0 and W (x0) are given (or not). 10 Second Order Linear Ordinary Differential Equation (ODE)
If the Second Order Linear Ordinary Differential Equation (ODE) is in the Self-Adjoint Mode: SOLO Then: The Wronskian is given by ( ) ( ) ( ) ( ) ( ) ( ) 0=+      == xuxq xd xud xp xd d xuxu LL ( ) ( ) ( ) ( ) ( ) ( ) 0 1 0 2 2 =++ xuxq xd xud xd xpd xd xud xp p p  ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )xp xp xW p pd xWd p p xWxW x x x x 0 00 0 0 0 0 0 1 0 00 expexp =         −=         −= ∫∫ τ τ τ 11 Return to Table of Content Second Order Linear Ordinary Differential Equation (ODE)
12 SOLO The Laplace’s Homogeneous Differential Equation is: We want to find the Potential Φ at the point F (field) due to all the sources (S) in the volume V, including its boundaries . n i iSS 1= = iS nS  n i iSS 1= =dV dSn → 1 V Fr  Sr  F 0r SF rrr  −= iS nS dV dSn → 1 V Fr  Sr  F 0r SF rrr  −= F inside V F on the boundary of V Therefore is the vector from S to F.SF rrr  −= →→→ ++= zzyyxxr 111  →→→ ++= zzyyxxr SSSS 111  →→→ ++= zzyyxxr FFFF 111  Let define the operator that acts only on the source coordinate. →→→ ∂ ∂ + ∂ ∂ + ∂ ∂ =∇ z z y y x x SSS S 111 Sr  Laplace’s Homogeneous Differential Equation ( ) 02 =Φ∇ r Pierre-Simon, marquis de Laplace (1749 1827)
13 SOLO Laplace’s Homogeneous Differential Equation Laplace Differential Equation in Spherical Coordinates ( ) 02 =Φ∇ r Spherical Coordinates: θ ϕθ ϕθ cos sinsin cossin rz ry rx = = = A Solution in Spherical Coordinates is: ( ) 0 1 ≠=Φ r r r ( ) 0 111 22 ≠−=∇−=∇=Φ∇ r r r r r rr r  ( ) ( ) 00 33111 35333 2 ≠=−⋅=⋅∇−⋅      −∇=      ⋅−∇=Φ∇⋅∇=Φ∇ r r rr r r r r r r r rr  r r r z r y r x zyx zyx r zyxzyx  =++=++      ∂ ∂ + ∂ ∂ + ∂ ∂ =∇ 111111 222 ( ) 3111111 =++⋅      ∂ ∂ + ∂ ∂ + ∂ ∂ =⋅∇ zyx zyx r zyxzyx  2222 zyxr ++=
14 SOLO Laplace’s Homogeneous Differential Equation Laplace Differential Equation in Spherical Coordinates Spherical Coordinates: θ ϕθ ϕθ cos sinsin cossin rz ry rx = = = θcos= ∂ ∂ z r 2222 zyxr ++= 0 cos11 22 ≠−= ∂ ∂ −=      ∂ ∂ = ∂ Φ∂ r rz r rrzz θ 0 1cos3331 3 2 5 22 4332 2 ≠ − = − = ∂ ∂ +−=      − ∂ ∂ = ∂ Φ∂ r rr rz z r r z rr z zz θ 0 cos9cos159153 5 26 3 4 23 7 23 6 22 55 22 3 3 ≠ − = − −= ∂ ∂− − ∂ ∂ − =      − ∂ ∂ = ∂ Φ∂ r r r r rzz z r r rz r z r rz r rz zz θθ We note that ∂n Φ/∂zn is a n-degree polynomial in cos θ divided by rn+1 . ( ) ( ) ( ) ( ) ( ) ( )zyx zn hzyx z hzyx z hzyxhzyx n nn n ,, ! 1 ,, !2 1 ,,,,,, 2 2 2 ∂ Φ∂− ++ ∂ Φ∂ + ∂ Φ∂ −Φ=−Φ  Using Taylor’s Series development we obtain
15 SOLO Laplace’s Homogeneous Differential Equation Laplace Differential Equation in Spherical Coordinates Spherical Coordinates: θ ϕθ ϕθ cos sinsin cossin rz ry rx = = = 2222 zyxr ++= ( ) ( ) ( )       ∂ ∂− ++      ∂ ∂ +      ∂ ∂ −= −++ =−Φ rzn h rz h rz h rhzyx hzyx n nn n 1 ! 11 !2 1111 ,, 2 2 2 222  ( ) ∑ ∞ =       ∂ ∂− = +− 0 22 1 ! 1 cos2 1 n n nn n rzn h hhrr θ or: Let define: ( ) ( )       ∂ ∂− = + rzn rP n nn n n 1 ! 1 :cos 1 θ ( ) rhP r h rhhrr n n n ≤      = +− ∑ ∞ =0 22 cos 1 cos2 1 θ θ Therefore:
16 SOLO Laplace’s Homogeneous Differential Equation Laplace Differential Equation in Spherical Coordinates Spherical Coordinates: θ ϕθ ϕθ cos sinsin cossin rz ry rx = = = 2222 zyxr ++= Let define w:=Pn (cos θ) and substitute w/rn+1 in the Laplace Equations in Spherical Coordinates instead of Φ Therefore, since w:=Pn (cos θ) (Partial Derivative becomes Total Derivative): 0 sin 1 sin sin 11 0 12 2 22121 2 2 =      ∂ ∂ +            ∂ ∂ ∂ ∂ +            ∂ ∂ ∂ ∂ +++  nnn r w rr w rr w r r rr φθθ θ θθ 0sin sin 111 1 =      ∂ ∂ ∂ ∂ +    + − ∂ ∂ + θ θ θθ w rr n r w nn or: ( ) 0sin sin 1 1 =      ++ θ θ θθ d wd d d wnn Substitute t=cos θ (dt = - sinθ dθ):  ( ) ( )       −=         −−=           =      −− td wd t td d td wd t td d d td td wd d td d d d wd d d 2 sin 2 1sin 11 sin 1 sin sin 1 sin sin 1 2   θ θ θθθ θ θθθ θ θθ Finally we obtain: ( ) ( ) 1011 2 ≤=++      − twnn td wd t td d Return to Table of Content
17 SOLO This is the Legendre Differential Equation and Pn (t) the Legendre Polynomials are one of the two solutions of the ODE. ( ) ( ) ( ) ( ) 1011 2 ≤=++      − ttPnntP td d t td d nn ( )∑ ∞ =       =       +− 0 2 cos cos21 1 n n n P r h r h r h θ θ We found ( ) 1cos cos21 1 0 2 ≤= +− ∑ ∞ = uPu uu n n n θ θFor u:=h/r The left-hand side is called “The Generating Function of Legendre Polynomials” Legendre Polynomials The Generating Function of Legendre Polynomials
18 SOLO Let use Taylor expansion for the function: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )  +++++= n n x n f x f x f fxf ! 0 !2 0 1 0 0 2 21 ( ) ( ) 1, 21 1 0 2 ≤= −+ ∑ ∞ = tutPu tuu n n n ( ) ( ) ( ) 101 2 1 =−= − fxxf ( ) ( ) ( ) ( ) ( ) 2 1 01 2 1 1 2 3 1 =−= − fxxf ( ) ( ) ( ) ( ) ( ) 2 3 2 1 01 2 3 2 1 2 2 5 2 ⋅=−⋅= − fxxf ( ) ( ) ( ) ( ) ( ) ( ) ( ) !2 !2 !2 !2 2 1231 2 12 2 3 2 1 01 2 12 2 3 2 1 2 2 12 n n n nnn fx n xf nn n n n n n =⋅ −⋅ = − ⋅=− − ⋅= + −   Tacking x = 2 u t - u2 we obtain ( ) ( ) ( ) ( ) 12 !2 !2 21 1 0 2 222 ≤−= −− ∑ ∞ = uutu n n utu n n n Let prove that Pn (t) are indeed Polynomials. Legendre Polynomials The Generating Function of Legendre Polynomials
19 SOLO Using Taylor expansion we obtained: ( ) ( ) 1, 21 1 0 2 ≤= −+ ∑ ∞ = tutPu tuu n n n Take the binomial expansion of (2 u t - u2 )n we obtain ( ) ( ) ( ) ( ) 12 !2 !2 21 1 0 2 222 ≤−= −− ∑ ∞ = uutu n n utu n n n ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 12 !!!2 !2 12 !! ! 1 !2 !2 21 1 0 0 2 0 0 222 ≤ − −= − −= −− ∑∑∑ ∑ ∞ = = +− ∞ = = − uut knkn n ut knk n n n utu n n k knkn n k n n k kknk n Change Variables in the second sum from n+k to n ( ) ( ) ( ) ( ) ( ) ( ) [ ] ( )   − =      ≤ −− − −= −− ∑ ∑ ∞ = = − − evennifn oddnifnn uut knknk kn utu n n k nkn kn k 2/1 2/ 2 12 !2!!2 !22 1 21 1 0 2/ 0 2 222 Equating in the two power series the un coefficients, we obtain ( ) ( ) ( ) ( ) ( ) [ ] ∑= − ≤ −− − −= 2/ 0 2 1 !2!!2 !22 1 n k kn n k n tt knknk kn tP Polynomial of order n in t Return to Rodrtgues Formula Return to Frobenius Series We can see that for n odd the polynomial Pn (t) has only odd powers of t and for n even only even powers of t. Legendre Polynomials The Generating Function of Legendre Polynomials
20 SOLO Let use Taylor expansion for the function: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )  +++++= n n x n f x f x f fxf ! 0 !2 0 1 0 0 2 21 ( ) ( ) 1, 21 1 0 2 ≤= −+ ∑ ∞ = tutPu tuu n n n Tacking x = u2 -2 u t we obtain ( ) ( ) ( ) 101 2 1 =+= − fxxf ( ) ( ) ( ) ( ) ( ) 2 1 01 2 1 1 2 3 1 −=+−= − fxxf ( ) ( ) ( ) ( ) ( ) 2 3 2 1 01 2 3 2 1 2 2 5 2 ⋅=+⋅= − fxxf ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 12 2 3 2 1 101 2 12 2 3 2 1 1 2 12 − ⋅−=+ − ⋅−= + − n fx n xf nn n nn  ( ) ( ) ( ) ( ) ( ) ( )∑ ∞ = =      +− +      − +      − ++= −+−−−+−−= −+ 0 24 4 3 3 2 20 4232222 2 8 33035 2 35 2 13 1 2 128 35 2 16 5 2 8 3 2 1 1 21 1 n n n tPu tt u tt u t utuu tuutuutuutuu ttuu   Legendre Polynomials The Generating Function of Legendre Polynomials
SOLO 21 Legendre Polynomials The first few Legendre polynomials are: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 256/63346530030900901093954618910 128/31546201801825740121559 128/35126069301201264358 16/353156934297 16/51053152316 8/1570635 8/330354 2/353 2/132 1 10 246810 3579 2468 357 246 35 24 3 2 −+++− +−+− +−+− −+− −+− +− +− − − xxxxx xxxxx xxxx xxxx xxx xxx xx xx x x xPn n
22 SOLO ( ) 1, 21 1 0 2 ≤= +− ∑ ∞ = tutPu utu n n n Substitute u by – u in this equation: ( ) ( ) ( ) 11 21 1 00 2 ≤−=−= ++ ∑∑ ∞ = ∞ = utPutPu utu n n n n n nn which results in the following identity: ( ) ( ) ( )tPtP n n n 1−=− For t =1 we have ( ) 11 1 1 21 1 0 2 ≤= − = +− ∑ ∞ = uPu uuu n n n But 1 1 1 0 ≤= − ∑ ∞ = uu u n n By equalizing the coefficients of un in the two sums, we obtain: ( ) nPn ∀=11 and ( ) ( ) ( ) ( )n n n n PP 1111 −=−=− Legendre Polynomials The Generating Function of Legendre Polynomials
23 SOLO ( ) 1, 21 1 0 2 ≤= +− ∑ ∞ = tutPu utu n n n For t = 0 we obtain: Legendre Polynomials ( ) 10 1 1 0 2 ≤= + ∑ ∞ = uPu u n n n ( ) ( ) ( ) ( ) ( ) ( ) ( ){ } ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∑∑∑ ∞ = ∞ = ∞ = − −= ⋅−⋅⋅−⋅⋅ −= −⋅⋅ −= + −−−− ++ −− +      −+=+= + 0 22 2 0 1 2 0 2 22222/12 2 !2 !2 1 !2 222642 !2 12531 1 !2 12531 1 ! 2/123/12/1 !2 3/12/1 2 1 11 1 1 n n n n n nn n n n n n n n n un n nn n un n un t n n ttu u        Therefore we have: ( ) ( ) ( ) ( ) 10 !2 !2 1 1 1 00 22 2 2 ≤=−= + ∑∑ ∞ = ∞ = uPu n un u n n n n n n n By equating coefficients of un on both sides we obtain: ( ) ( ) ( ) ( ) ( ) 00 !2 !2 10 12 222 = −= +n n n n P n n P Return to Table of Content The Generating Function of Legendre Polynomials
Derivation of Legendre Polynomials via Rodrigues’ Formula SOLO 24 Legendre Polynomials Benjamin Olinde Rodrigues (1794-1851) In mathematics, Rodrigues' Formula (formerly called the Ivory– Jacobi formula) is a formula for Legendre polynomials independently introduced by Olinde Rodrigues (1816), Sir James Ivory (1824) and Carl Gustav Jacobi (1827). The name "Rodrigues’ formula" was introduced by Heine in 1878, after Hermite pointed out in 1865 that Rodrigues was the first to discover it, and is also used for generalizations to other orthogonal polynomials. Askey (2005) describes the history of the Rodrigues’ Formula in detail. Rodrigues stated his formula for Legendre polynomials Pn Carl Gustav Jacob Jacobi (1804 –1851) ( ) ( )[ ]n n n nn x xd d n xP 1 !2 1 2 −=
SOLO 25 Legendre Polynomials Olinde Rodrigues (1794-1851) Start from the function: ( ) .12 constkxky n =−= ( ) 12 12:' − −== n xxkn xd yd y ( ) ( ) ( ) 22212 2 2 11412:'' −− −−+−== nn xxnknxkn xd yd y Let compute: ( ) ( ) ( ) ( ) ( ) '12211412''1 12222 yxnynxxnknxknyx nn −+=−−+−=− − or: ( ) ( ) 02'12''12 =−−+− ynyxnyx Let differentiate the last equation n times with respect to x: ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) ''1''2''1 00''1 3 ''1 2 ''1 1 ''1''1 2 2 1 1 2 3 3 0 2 3 3 2 2 2 2 2 1 1 222 y xd d nny xd d xny xd d x y xd d x xd dn y xd d x xd dn y xd d x xd dn y xd d xyx xd d n n n n n n n n n n n n n n n n − − − − − − − − − − −++−= +−      +−      +−      +−=−   ( ) ( ) ( ) ( )       +−=            +−=− − − − − ''12' 1 '12'12 1 1 1 1 y xd d ny xd d xny xd d x xd dn y xd d xnyx xd d n n n n n n n n n n n Derivation of Legendre Polynomials via Rodrigues’ Formula
SOLO 26 Legendre Polynomials Olinde Rodrigues (1794-1851) Start from the function: ( ) .12 constkxky n =−= ( ) ( ) 02'12''12 =−−+− ynyxnyxDifferentiate n times with respect to x: ( ) ( ) ''1''2''1 2 2 1 1 2 y xd d nny xd d xny xd d x n n n n n n − − − − −++− ( ) 02''12 1 1 =−      +−+ − − y xd d ny xd d ny xd d xn n n n n n n Define: a Polynomial( ) ( )[ ]n n n n n x xd d k xd yd xw 1: 2 −== ( ) ( ) ( )[ ] 02'121'2''12 =−+−+−++− wnwnwxnwnnwxnwx ( ) ( ) ( ) ( )[ ] 02121'2''12 =−−+−+−++− wnnnnnwxnxxnwx ( ) ( ) 01'2''12 =+−+− wnnwxwx This is Legendre’s Differential Equation. We proved that one of the solutions are Polynomials. We can rewrite this equation in a Sturm-Liouville Form: ( ) ( ) 0112 =+−      − wnnw xd d x xd d Derivation of Legendre Polynomials via Rodrigues’ Formula
SOLO 27 Legendre Polynomials Olinde Rodrigues (1794-1851) Let find k such that: by using the fact that Pn (1) = 1 ( ) ( )[ ]n n n n n n x xd d k xd yd xP 12 −== ( ) ( )[ ] ( ) ( ) ( ) ( )       −+=         +−=−= ∑>0 22 1!2111 i inn v n u n n n n n n n xxaxnkxx xd d kxk xd d xP  !2 1 n k n = We recover the Rodrigues Formula: ( ) ( )[ ]n n n nn x xd d n xP 1 !2 1 2 −= Let use Leibnitz’s Rule (Binomial Expansion for the n Derivative of a Product - with u:=(x-1)n and v:=(x+1)n ): ( ) ( ) ( ) udvudvdnvddu nn vddunvdu vdud mnm n vud nnnnn n m mnmn +++ − ++= − =⋅ −−− = − ∑ 1221 0 !2 1 !! !  We have: ( )   ( )    1!2 !2 1 1 1!20 12 0 21 00 ==        +++ − ++== = −−− nkudvudvdnvddu nn vddunvdukxP n xn nnnnn n n  We can see from this Formula that Pn (x) is indeed a Polynomial of Order n in t. Derivation of Legendre Polynomials via Rodrigues’ Formula
SOLO 28 Legendre Polynomials Olinde Rodrigues (1794-1851) Let find an explicit expression for Pn (x) from Rodrigues’ Formula: ( ) ( )[ ]n n n nn n n x xd d nxd yd xP 1 !2 1 2 −== Start with: ( ) ( ) ( )∑= − − − =− n m mnmn x mnm n x 0 22 1 !! ! 1 ( ) ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )   + = −− − −= −− −= +−− − −=−= ∑ ∑ ∑ = − −= ≥ −− ≥ −− oddnn evennn p x knknk kn x nm m mnm xnmmm mnm n n x xd d n xP p k knk n knm n pm nmmn n n pm nmmn n n n n nn 2/12 2/ !2!! !22 1 2 1 !2 !2 !! 1 1 2 1 12122 !! ! 1 !2 1 1 !2 1 0 2 2 22  ( ) ( )    < ≥+−− = 2/0 2/121222 nm nmnmmm x xd d m n n  We recover the result obtained by the Generating Function of Legendre Polynomials Return to Frobenius Series Return to Table of Content Derivation of Legendre Polynomials via Rodrigues’ Formula
SOLO Series Solutions – Frobenius’ Method Ferdinand Georg Frobenius (1849 –1917) ( ) ( ) .0121 2 2 22 constrealryrr xd yd yx xd yd x =++−− Example: General Legendre Equation ∑ ∞ = + = 0λ λ λ k xay Let check the Frobenius’s expansion: We have: ( ) ( ) ( )∑∑ ∞ = −+ ∞ = −+ −++=+= 0 2 2 2 0 1 1& λ λ λ λ λ λ λλλ kk xkka xd yd xka xd yd Substitute in the General Legendre Equation: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ] 0111 121 00 2 000 2 =+++−++−++= +++−−−++ ∑∑ ∑∑∑ ∞ = + ∞ = −+ ∞ = + ∞ = + ∞ = +−+ λ λ λ λ λ λ λ λ λ λ λ λ λ λλ λ λλλλ λλλ kk kkkk xkkrraxkka xrraxkaxxkka 29 Legendre Polynomials
SOLO Example: Legendre Equation (continue – 1) ( ) ( ) ( ) ( ) ( )[ ] 0111 00 2 =+++−++−++ ∑∑ ∞ = + ∞ = −+ λ λ λ λ λ λ λλλλ kk xkkrraxkka Denote, in the first sum λ = j +2 and in the second sum λ = j, to obtain: ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ]{ } 01112 11 0 2 1 1 2 0 =+++−+++++++ ++− ∑ ∞ = + + −− j jk jj kk xjkjkrrajkjka xkkaxkka All the coefficients of xk+j must be zero, therefore ( ) 001 00 ≠=− akka ( ) 011 =+kka ( ) ( ) ( ) ( ) ( )[ ] 011122 =+++−+++++++ jkjkrrajkjka jj 30 Ferdinand Georg Frobenius 1849 - 1917 Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 2) ( ) ( ) ( ) ( ) ( ) ( )[ ] ( ) ( ) ( ) ,2,1,0 12 1 12 11 2 = ++++ ++++− −= ++++ +++−+ −=+ j jkjk jkrjkr a jkjk jkjkrr aa jjj ( ) 01 =−kk ( ) 011 =+kka ( ) ( ) ( ) ( ) ( )[ ] 011122 =+++−+++++++ jkjkrrajkjka jj 0&1.3 0&0.2 0&0.1 1 1 1 == ≠= == ak ak akThree possible solutions The equation that, k (k+1) = 0, comes from the coefficient of the lowest power of x, and is called Indicial Equation. It has two solutions for k k = 0 and k = 1 The equation gives the recursive relation 31 Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 3) ( ) 1001: ==⇒=− korkkkEquationIndicial 1. Using k = 0 and a1 = 0 we obtain a series of even powers of x ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ,2,1,0 21 1 21 11 2 = ++ ++− −= ++ +−+ −=+ j jj jrjr a jj jjrr aa jjj ( ) ( ) ( ) ( ) ( ) ( )       + ++− + + −== 42 0 !4 312 !2 1 1: x rrrr x rr axpxy reven ( ) 01231 ==== +naaa  The recurrence relation results in the following expression for the coefficients ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )   ,3,2,1 !2 123124222 1 02 = −+++⋅−+−+− −= ma m mrrrrrmrmr a m m 32 ( ) ( ) ( ) ( ) ( ) ( )[ ] ( ) ( ) ( ) ,2,1,0 12 1 12 11 2 = ++++ ++++− −= ++++ +++−+ −=+ j jkjk jkrjkr a jkjk jkjkrr aa jjj ( ) ∑ ∞ = = 0 2 2m m meven xaxy Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 4) ( ) 1001: ==⇒=− korkkkEquationIndicial 3. Using k = 1 and a1 = 0 we obtain a series of odd powers of x ( ) ( )( ) ( ) ( ) ( )( ) ( ) ( ) .2,1,0 32 21 32 211 2 = ++ ++−− −= ++ ++−+ −=+ j jj jrjr a jj jjrr aa jjj ( ) ( ) ( )( ) ( ) ( )( ) ( )       + ++−− + +− −== 53 0 !4 4213 !3 21 : x rrrr x rr xaxqxy rodd ( ) 01231 ==== +naaa  The recurrence relation results in the following expression for the coefficients ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )   ,3,2,1 !12 24213212 1 02 = + +++−+−+− −= ma m mrrrrmrmr a m m 33Since pr (x) and qr (x) are two linearly independent solutions of the 2nd Order Linear Lagrange ODE, the final solution is y = c1 pn (x) + c2 qn (x) ( ) ( ) ( ) ( ) ( ) ( )[ ] ( ) ( ) ( ) ,2,1,0 12 1 12 11 2 = ++++ ++++− −= ++++ +++−+ −=+ j jkjk jkrjkr a jkjk jkjkrr aa jjj ( ) ∑ ∞ = + = 0 12 2m m modd xaxy Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 5) Using d’Alembert – Cauchy test for convergence of an Infinite Series, we have Convergence Test: ( ) ( ) ( ) ( ) ( )     ≥≥ << = ++++ +++−+ = ∞→ + + ∞→ divergex convergex xx jkjk jkjkrr xa xa jj j j j j 11 11 12 11 limlim 22 2 2 The even series stops at j = n. The expansion is a Polynomial of order n (even). 1. If n is even, using k = 0 and a1 = 0 we obtain a series of even powers of x . ( ) ( ) ( ) ( ) ,..1,0 21 11 2 = ++ +−+ −=+ j jj jjnn aa jj For the case that r = n, a positive integer: ,...2,1,,02 ++==+ nnnjaj 3. If n is odd, using k = 1 and a1 = 0 we obtain a series of odd powers of x . ( ) ( )( ) ( ) ( ) ,..2,1 32 211 2 = ++ ++−+ −=+ j jj jjnn aa jj ,...2,1,,1,02 ++−==+ nnnnjaj The odd series stops at j = n-1. The expansion is a Polynomial of order n (odd).34 Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 6) 1. If n is even, using k = 0 and a1 = 0 we obtain a series of even powers of x ( ) ( ) ( )( ) ( )       + ++− + + −= 42 0 !4 312 !2 1 1 x nnnn x nn axyeven 3. If n is odd using k = 1 and a1 = 0 we obtain a series of odd powers of x ( ) ( )( ) ( ) ( )( ) ( )       + ++−− + +− −= 53 0 !4 4231 !3 21 x nnnn x nn xaxyodd ( ) ( ) ( ) ( )( ) ( )       +−=      ++− + + −== −=      + −== == 42 0 42 0 2 0 2 0 0 6 70 101 !4 3414244 !2 144 14 31 !2 122 12 0 xxaxxayn xaxayn ayn even even even ( )( )       −=      +− −== == 3 0 3 0 0 3 5 !3 2313 3 1 xxaxxayn xayn odd odd We obtain the Legendre Polynomials Solutions for a0 = 1. 35 Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 7) 1. The recurrence relation for even x powers results in the following expression for the coefficients ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2/,,3,2,1 !2 123124222 1 02 nma m mnnnnnmnmn a m m   = −+++⋅−+−+− −= ( ) ( ) ( ) ( ) ( ) ( ) ( )! ! 2121224222 11 2 mp p ppmpmpnnmnmn mm pn − =−+−+−=−+−+− −− =  ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( )( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( )!!22 !!22 212 1 !2 !22 242 242 1231 ! ! 1231 22 mpp pmp mpppp mp mnnn mnnn mnnn n n mnnn m pn m pn + + = +++ + = +++ +++ −+++=−+++ ==     ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2/,,3,2,1 !!!22 !221 !!!2!2 ! 2 !22 1 !!2!2 !!22 ! ! 2 1 1 0 0 2 2 02 nm snssn sn a snssnn n sn a mpmp pmp mp p a n sthatsucha choose s nmps m m = −− −− = −−             − −= + + − −= − − −= ( ) ( ) ( ) ( )∑= −− < −− − −= 2/ 0 2 1 !2!!2 !22 1 n s sn n s even xx snsns sn y 36 Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 8) 3. The recurrence relation for odd x powers results in the following expression for the coefficients ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 1 ,,3,2,1 !12 24213212 1 02 − = + +++−+−+− −= n ma m mnnnnmnmn a m m   ( ) ( ) ( ) ( )( ) ( ) ( )! ! 222242222213212 1 12 mp p ppmpmpnmnmn m pn − =−+−+−=−+−+− − +=  ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( )!!122 !!122 212 224222 1225232 !12 !12 242 1 1 12 mpp pmp mppp mppp mppp p p mnnn m m pn ++ ++ = +++ +++ ++++ + + =+++ − − +=   ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 1 ,,3,2,1 !2!1!! ! 2 1 !122 1 !12!!!12 !!122 1 0 2 0 2 2 − = −−−             − −− −= ++−+ ++ −= − −= n ma snsnsn n sn a mmpmpp pmp a sp mps m m  37 ( ) ( ) ( ) ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) 2 1 ,...,1,0 !2!!!2 ! 2 1 !22 1 !2!12!! ! 2 1 !12222 1 0 2 0 2 − = −−             − − −= −−−−             − −−− −= − −= − −= n sa snsnsn n sn a snsnsnsn n snsn sp mps sp mps Series Solutions – Frobenius’ Method Legendre Polynomials
Example: Legendre Equation (continue – 9) 3. The recurrence relation for odd x powers results in the following expression for the coefficients ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 1 ,...,1,0 !2!!2 !22 1 !2!! !22 ! 2 1 !2 1 1 0 0 2 2 1 2 − = −− − −= −− −             − −= −− − n s snsns sn a snsns snn n a n s thatsucha Choose s n m ( ) ( ) ( ) ( ) ( ) ( ) 1& !2!! !22 1 2 1 2/1 0 2 < −− − −= ∑ − = −− xoddnx snsns sn xy n s sns nodd We also found that the solution for k = 0 and a1 = 0 is ( ) ( ) ( ) ( ) ( ) 1& !2!!2 !22 1 2/ 0 2 < −− − −= ∑= −− xevennx snsns sn xy n s sn n s even We recover the result obtained by the Generating Function of Legendre Polynomials and by Rodrigues’ Formula 38 Therefore we can unify those two relations to obtain: ( ) ( ) ( ) ( ) ( ) [ ] 1 !2!!2 !22 1 2/ 0 2 < −− − −= ∑= −− xx snsns sn xP n s sn n s n Series Solutions – Frobenius’ Method SOLO Legendre Polynomials
SOLO Example: Legendre Equation (continue – 10) 2. Using k = 0 and a1 ≠ 0 we obtain an infinite series and not a polynomial. This is the Second Solution of the Legendre Differential Equation. The solution is the sum of the two infinite series, one with even powers of x and the other with odd powers of x. The series solution, in this case, diverges at x = ± 1. Those are Legendre Functions of the Second Kind. The Polynomial solutions are Legendre Functions of the First Kind. 39 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ,2,1,0 21 1 21 11 2 = ++ ++− −= ++ +−+ −=+ j jj jnjn a jj jjnn aa jjj In this case we have The recurrence relation results in the following expression for the coefficients ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )   ,3,2,1 !2 123124222 1 02 = −+++⋅−+−+− −= ma m mnnnnnmnmn a m m ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )   ,3,2,1 !12 123124222 1 112 = + −+++⋅−+−+− −=+ ma m mnnnnnmnmn a m m Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 11) 40 We want to find a series that converges for |x| > 1. Let return to the conditions to have a series solution for Legendre ODE For k = 0 and a0 = 0 By substituting j = m – 2 we obtain ( ) ( ) ( ) ( ) ,2,1,0 1 21 2 == ++− ++ −= + ja jnjn jj a jj ( ) ( ) ( ) mm a mnmn mm a 12 1 2 −++− − −=− ( ) ( ) .0121 2 2 22 constrealryrr xd yd yx xd yd x =++−− ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ,2,1,0 21 1 21 11 2 = ++ ++− −= ++ +−+ −=+ j jj jrjr a jj jjrr aa jjj We can make am+2, am+4, am+6,…. To vanish for m = r = n or m = -n – 1. If we start for am ≠ 0 we can obtain the following recursive formula Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 12) 41 ( ) ( ) ( ) mm a mnmn mm a 12 1 2 −++− − −=− Tacking m = n we obtain ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) nnn nn a nn nnnn a n nn a a n nn a 321242 321 324 32 122 1 24 2 −⋅−⋅⋅ −−− += − −− −= − − −= −− − The first solution can be written as ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )       + +−−⋅−⋅⋅ −−−− ++ −⋅−⋅⋅ −−− + − − −= −−−     innnn n x innni ininnn x nn nnnn x n nn xaxy 242 1 1223212242 1221 321242 321 122 1 Using d’Alembert – Cauchy test for convergence of an Infinite Series, we have ( )( ) ( )     ≤≥ >< = +− −−− = −− ∞→+− +− − − ∞→ divergex convergex xx ini inin xa xa iin in in in j 11 11 1222 122 limlim 22 22 22 2 2 Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 13) 42 ( ) ( ) ( ) mm a mnmn mm a 12 1 2 −++− − −=− Tacking m =- n - 1 we obtain ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) 135 13 523242 4321 524 43 322 21 −−−−−− −−−− +⋅+⋅⋅ ++++ += + ++ = + ++ += nnn nn a nn nnnn a n nn a a n nn a The second solution can be written as ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )       + +++⋅+⋅⋅ +−+++ ++ +⋅+⋅⋅ ++++ + + ++ += −−−−−−−−− −−     12531 12 1225232242 21221 523242 4321 322 21 innnn n x innni ininnn x nn nnnn x n nn xaxy Using d’Alembert – Cauchy test for convergence of an Infinite Series, we have ( ) ( ) ( )     ≤≥ >< = ++ +−+ = −− ∞→+− +− −− −−− ∞→ divergex convergex xx ini inin xa xa iin in in in j 11 11 1222 212 limlim 22 12 12 12 12 Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 14) 43 ( )( ) ! 1353212 n nn an ⋅⋅−− = By choosing we have ( ) ( ) ( )( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 1] 1223212242 1221 1 321242 321 122 1 [ ! 1353212 2 42 1 >+ +−−⋅−⋅⋅ −−−− −+ + −⋅−⋅⋅ −−− + − − − ⋅⋅−− == − −− xx innni ininnn x nn nnnn x n nn x n nn xyxP ini nnn n       Return to Table of Content Finally ( ) ( ) ( ) ( ) ( ) 1 !2!!2 !22 1 0 2 > −− − −= ∑ ∞ = − xx inini in xP i in n i n ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )!2!!2 !22 1 !2 !22 !2!2 1 1 !2!2 135122 1 1223212242 1221 1 ! 1353212 inini in in in iiniin in innni ininnn n nn n i ini i i i i −− − −= − − − −= − ⋅⋅−− −= +−−⋅−⋅⋅ −−−− − ⋅⋅−− −    Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 14) 44 ( )( ) 1351212 ! 1 ⋅⋅−+ == −− nn n aa nn By choosing we have ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 1] 1225232242 21221 523242 4321 322 21 [ 1351212 ! 12 531 2 >+ +++⋅+⋅⋅ +−+++ + + +⋅+⋅⋅ ++++ + + ++ + ⋅⋅−+ == −−− −−−−−− xx innni ininnn x nn nnnn x n nn x nn n xyxQ in nnn n       ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )!122! !2! ! !12 ! !2 !122 !12 ! !2 2 1 !122 2222!12 ! !2 !2 1 1225232242 21221 2 ++ +++ = + ++ ++ = ++ ++++ = +++⋅+⋅⋅ +−+++ ini inin n n n in in n n in in innn n in iinnni ininnn i i i    ( ) ( ) ( ) ( ) ( ) 1 !122! !2! 2 0 12 > ++ ++ = ∑ ∞ = ++− xx ini inin xQ i inn n Go to Neumann Integral ( )( ) ( )!12 !2 ! 1351212 ! + = ⋅⋅−+ n n n nn n n  Finally Series Solutions – Frobenius’ Method Legendre Polynomials
SOLO Example: Legendre Equation (continue – 15) 45 Summarize ( ) ( ) ( ) ( ) ( ) 1 !122! !2! 2 0 12 > ++ ++ = ∑ ∞ = ++− xx ini inin xQ i inn n Return to Table of Content ( ) ( ) ( ) ( ) ( ) 1 !2!! !22 1 2 1 0 2 > −− − −= ∑ ∞ = − xx inini in xP i ini nn ( ) ( ) ( ) ( ) ( ) [ ] 1 !2!! !22 1 2 1 2/ 0 2 < −− − −= ∑= −− xx inini in xP n i ini nn Return to Similar to Rodrigues Formula Using Frobenius’ Method we found that solutions of Legendre ODE are ( ) ( ) integerpositive0121 2 2 22 nynn xd yd yx xd yd x =++−− Series Solutions – Frobenius’ Method Legendre Polynomials ( ) 4,3,2,1 1 = > l xxPl ( ) 4,3,2,1 1 = > l xxQl
46 SOLO ( ) 1 21 1 0 2 ≤= +− ∑ ∞ = utPu utu n n n For u=0 we obtain ( ) 10 =tP For t = 1 we obtain ( ) ( ) 111 1 1 21 1 00 2 =⇒== − = +− ∑∑ ∞ = ∞ = n n n n n n PPuu uuu For t = -1 we obtain ( ) ( ) ( ) ( )n n n n n n nn PPuu uuu 1111 1 1 21 1 00 2 −=⇒=−= + = ++ ∑∑ ∞ = ∞ = Let find a Recursive Relation for Legendre Polynomial computation Start with: ( ) ( ) ( ) ( ) ( ) ( ) ( )       ∂ ∂ + − =      ∂ ∂− + − =      ∂ ∂ + − = ++ + + ++ + + 11 1 1 11 2 1 cos 1 11 ! 1 1 11 !1 1cos n n n nn n nn n n r P znrznnrznr P θθ ( ) ( ) ( ) ( ) ( )( ) ( )       ∂ ∂ + ∂ ∂+ − + − = +++ + zd Pd rz r r Pn nr P n nn n n n θ θ θθθ cos cos cos1cos1 1 1cos 122 1 Recursive Relations for Legendre Polynomial Computation First Recursive Relation Legendre Polynomials
47 SOLO Recursive Relations for Legendre Polynomial Computation ( ) ( ) ( ) ( ) ( )( ) ( )       ∂ ∂ + ∂ ∂+ − + − = +++ + zd Pd rz r r Pn nr P n nn n n n θ θ θθθ cos cos cos1cos1 1 1cos 122 1 θcosrz = θcos= ∂ ∂ z r  z r z r z z ∂ ∂ + ∂ ∂ = ∂ ∂ = θ θ θ cos cos1 cos rz θθ 2 cos1cos − = ∂ ∂ ( ) ( ) ( ) ( ) ( )( )       − + + − + − = +++ + rd Pd rr Pn nr P n nn n n n θ θ θ θ θθ 2 122 1 cos1 cos cos1 cos cos1 1 1cos ( ) ( ) ( )( ) θ θθ θθθ cos cos 1 cos1 coscoscos 2 1 d Pd n PP n nn + − −=+ Substituting t = cos θ we obtain ( ) ( ) ( ) td tPd n t tPttP n nn 1 1 2 1 + − −=+ First Recursive Relation (continue – 1) Legendre Polynomials
48 SOLO Recursive Relations for Legendre Polynomial Computation ( ) ( ) ( ) 0,1 1 1 2 1 ≥≤ + − −=+ nt td tPd n t tPttP n nn Use to start ( ) ( ) 01 0 0 =⇒= td tPd tP ( ) ( ) ( ) ( ) ( ) 8 157063 8 33035 2 35 2 13 35 5 24 4 3 3 2 2 1 ttt tP tt tP tt tP t tP ttP +− = +− = − = − = = First Recursive Relation (continue – 2) Legendre Polynomials
49 SOLO Recursive Relations for Legendre Polynomial Computation Start from ( ) ( ) 1 21 1 :, 0 2 ≤= +− = ∑ ∞ = utPu utu tug n n n Let differentiate both sides with respect to u and rearranging ( ) ( )∑ ∞ = − +−= +− − = ∂ ∂ 1 12 2 21 21 n n n tPunutu utu ut u g ( ) ( ) ( ) ( )∑∑ ∞ = − ∞ = +−=− 1 12 0 21 n n n n n n tPunututPuut ( ) ( ) ( ) ( )∑∑ ∞ = +− ∞ = + +−=− 1 11 0 1 2 n n nnn n n nn tPunutnuntPuut ( ) ( ) ( ) ( ) ( ) ( ) ( )∑∑∑∑∑ ∞ = − ∞ = ∞ = + ∞ = − ∞ = −+−+=− 2 1 10 1 1 1 0 121 n n n n n n n n n n n n n n n tPuntPutntPuntPutPut ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )     ≥+=−+ =−=− == +− 2112 122 0 11 1201 10 ntPuntPuntPutn ntPtutPutPutuPt ntPtPt n n n n n n We can see that the last relation agrees also with the previous relations, for n = 0 and n = 1. Second Recursive Relation Legendre Polynomials
50 SOLO Recursive Relations for Legendre Polynomial Computation We find the Recursive Relation: ( ) ( ) ( ) 1 11 12 11 ≥ + − + + = −+ ntP n n tPt n n tP nnn ( ) 10 =tP This is called the Bonnet’s Recursion Relation. It starts with: Examples: ( ) ( ) ( ) 2 3 1 01 2 tPtPt tPn − =→= ( ) 2 1 2 3 2 2 −= ttP ( ) ( ) ( )  tP tP ttttPn 1 2 3 2 2 1 2 3 3 5 2 2 3 −      −=→=  ( ) 2 35 3 3 tt tP − = ( ) ( ) ( )  tPtP tttttPn 23 2 1 2 3 4 3 2 3 2 5 4 7 3 23 4       −−      −=→= ( ) 8 33035 24 4 +− = tt tP ( ) ttP =1 Second Recursive Relation (continue) Legendre Polynomials
51 SOLO Recursive Relations for Legendre Polynomial Computation Start from ( ) ( ) 1 21 1 :, 0 2 ≤= +− = ∑ ∞ = utPu utu tug n n n Let differentiate both sides with respect to t and rearranging ( ) ( ) ∑ ∞ = = +− = ∂ ∂ 0 2/32 21 n nn td tPd u utu u t g ( ) ( ) ( ) ∑∑ ∞ = ∞ = +−= 0 2 0 21 n nn n n n td tPd uututPuuor Equaling coefficients of each power of u gives ( ) ( ) ( ) ( ) td tPd td tPd t td tPd tP nnn n 11 2 −+ +−= ( ) ( ) ( ) ( ) ( )tPntPntPtn nnn 11112 −+ ++=+ Differentiate the Second Recursive Relation with respect to t and rearranging ( ) ( ) ( ) ( ) ( ) ( ) ( ) td tPd n n td tPd n n td tPd ttP nnn n 11 1212 1 −+ + + + + =+ Third Recursive Relation Legendre Polynomials
52 SOLO Recursive Relations for Legendre Polynomial Computation We found ( ) ( ) ( ) ( ) td tPd ttP td tPd td tPd n n nn 211 +=+ −+ ( ) ( ) ( ) ( ) ( ) ( ) ( ) td tPd ttP td tPd n n td tPd n n n n nn += + + + + −+ 11 1212 1 Third Recursive Relation (continue) Let solve for and in terms of and( )tPn ( ) td tPd n( ) td tPd n 1+( ) td tPd n 1− ( ) ( ) ( ) td tPd ttPn td tPd n n n +−=−1 ( ) ( ) ( ) ( ) td tPd ttPn td tPd n n n ++=+ 11 Subtracting the first relation from the second gives the Third Recursive Relation ( ) ( ) ( ) ( ) td tPd td tPd tPn nn n 11 12 −+ −=+ Legendre Polynomials
53 SOLO Recursive Relations for Legendre Polynomial Computation ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ){ }yPxPyPxP yx n yPxPk tPtntPn td tPd t tPntPtn td tPd t tPn td tPd t td tPd tPn td tPd td tPd t tPn td tPd td tPd tPntPtntPn tP n n tP n n tPt tPin td tPd nnnn n k kk nn n nn n n nn n nn n nn nnn nnn l i in n 11 0 1 2 1 2 1 1 1 11 11 11 1 2 1 0 12 1 129 1118 17 6 5 124 01213 1212 1 2 1421 ++ = + − − − − −+ −+ −+       − = −− − − + =+ +−+=− −=− =− =− +=− =++−+ + + + + = −−= ∑ ∑ Recursive Relation between Legendre Polynomials and their Derivatives) Legendre Polynomials Return to Table of Content
54 SOLO Orthogonality of Legendre Polynomials Define ( ) ( )tPwtPv nm == :&: We use Legendre’s Differential Equations: ( ) ( ) 011 2 =++      − vmm td vd t td d ( ) ( ) 011 2 =++      − wnn td wd t td d Multiply first equation by w and integrate from t = -1 to t = +1. ( ) ( ) 011 1 1 1 1 2 =++      − ∫∫ + − + − dtwvmmdtw td vd t td d Integrate the first integral by parts we get ( ) ( ) ( ) 0111 1 1 1 1 2 0 1 1 2 =++−−− ∫∫ + − + − += −= dtwvmmdt td wd td vd tw td vd t t t    In the same way, multiply second equation by v and integrate from t = -1 to t = +1. ( ) ( ) 011 1 1 1 1 2 =++−− ∫∫ + − + − dtwvnndt td wd td vd t Legendre Polynomials
55 SOLO Orthogonality of Legendre Polynomials ( ) ( ) 011 1 1 1 1 2 =++−− ∫∫ + − + − dtwvmmdt td wd td vd t Subtracting those two equations we obtain ( ) ( ) 011 1 1 1 1 2 =++−− ∫∫ + − + − dtwvnndt td wd td vd t ( ) ( )[ ] ( ) ( )[ ] ( ) ( ) 01111 1 1 1 1 =+−+=+−+ ∫∫ + − + − dttPtPnnmmdtwvnnmm nm This gives the Orthogonality Condition for m ≠ n ( ) ( ) nmdttPtP nm ≠=∫ + − 0 1 1 To find let square the relation and integrate between t = -1 to t = +1. Due to orthogonality only the integrals of terms having Pn 2 (t) survive on the right-hand side. So we get ( )∫ + − 1 1 2 dttPn ( )∑ ∞ = = +− 0 2 21 1 n n n tPu utu ( )∑ ∫∫ ∞ = + − + − = +− 0 1 1 22 1 1 2 21 1 n n n dttPudt utu Legendre Polynomials
56 SOLO Orthogonality of Legendre Polynomials ( )∑ ∫∫ ∞ = + − + − = +− 0 1 1 22 1 1 2 21 1 n n n dttPudt utu ( ) ( ) ( ) 1 1 1 ln 1 1 1 ln 2 1 21ln 2 1 21 1 2 21 1 2 1 1 2 < − + = + − − =−+ − = −+ += −= + −∫ u u u uu u u tuu u dt tuu t t ( ) ( ) ( ) ( ) ( ) ( ) ( ) ∑∑∑ ∞ ++∞ +∞ + + −− −= + − −− + −=−−+ 0 11 0 1 0 1 1 1 1 1 1 1 1 1 1 1ln 1 1ln 1 n uu un u un u u u u u u nn n n n n n ( ) ( ) ( ) ( ) ( ) ( ) ( ) ∑∑∑∑ ∞∞ +∞ ++ + ∞ ++ + = + = + −− −+ + −− −= 0 2 0 12 0 0 1212 12 0 1212 2 12 2 12 1 2 12 1 1 12 1 1 n nnn n nn n u nn u un uu un uu u    Let compute first Therefore ( )∑ ∫∑∫ ∞ + − ∞+ − = + = +− 0 1 1 22 0 2 1 1 2 12 2 21 1 dttPuu n dt utu n nn Comparing the coefficients of u2n we get ( ) 12 21 1 2 + =∫ + − n dttPn Legendre Polynomials ( ) ( ) nmmn n dttPtP δ 12 21 1 + =∫ + − Hence
57 SOLO Using Rodrigues’ Formula let calculate ( ) ( ) ( ) ( )[ ]∫∫ + − + − − = 1 1 2 1 1 1 !2 1 dt td td tP n dttPtP n nn knnk Legendre Polynomials ( ) ( )[ ]n nn nn td td n tP 1 !2 1 2 − = Orthogonality of Legendre Polynomials (Second Method) Assume, without loss of generality, that n > k, and integrate by parts ( ) ( ) ( ) ( )[ ] ( ) ( )[ ] ( ) ( )[ ] ( ) ( ) ( ) ∫∫ ∫∫ + − + − − − + − − − + − + − −−== − − − = − = 1 1 2 1 1 1 21 0 1 1 1 21 1 1 2 1 1 1 !2 1 1 1 !2 11 !2 1 1 !2 1 dt td tPd t n dt td td td tPd ntd td tP n dt td td tP n dttPtP n k n n n n n nn k nn nn kn n nn knnk     Since Pk (t) is a Polynomial of Order k and we assume that n > k, we have ( ) 0=n k n td tPd Therefore ( ) ( ) nkdttPtP nk ≠=∫ + − 0 1 1
58 SOLO For k = n we have Legendre Polynomials Orthogonality of Legendre Polynomials (Second Method) (continue – 1) ( )[ ] ( ) ( ) ( ) ∫∫ + − + − −−= 1 1 2 1 1 2 1 !2 1 1 dt td tPd t n dttP n n n n n n n But we found that Pn (t) is given by: ( ) ( ) ( ) ( ) ( ) [ ] ∑= − −− − −= 2/ 0 2 !2!!2 !22 1 n k kn n k n t knknk kn tP Therefore to compute it is sufficient to consider only the highest power of t in the series, i.e. for k = 0, and we obtain ( ) n n n td tPd ( ) ( ) ( ) ( ) !2 !2 ! !2 !2 2 n n n n n td tPd nnn n n == ( )[ ] ( ) ( ) ( ) ( ) ( ) ( )∫∫∫ + − + − + − −=−−= 1 1 2 22 1 1 2 1 1 2 1 !2 !2 !2 !2 1 !2 1 1 dtt n n dt n n t n dttP n nn n n n n
SOLO Legendre Polynomials Orthogonality of Legendre Polynomials (Second Method) (continue – 2) ( )[ ] ( ) ( ) ( ) ( ) ( ) ( )∫∫∫ + − + − + − −=−−= 1 1 2 22 1 1 2 1 1 2 1 !2 !2 !2 !2 1 !2 1 1 dtt n n dt n n t n dttP n nn n n n n ( ) ∫∫∫ ++ =+ − =−=− π π θ θθθθ 0 12 0 12 cos1 1 2 sinsin1 dddtt nn tn Therefore ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )!12 !2 cos 2222 !2 11212 !2 sin 31212 2222 sin 12 2 sin 212 2 0 1 00 12 0 12 + = −⋅ ⋅ −⋅+ = −⋅+ −⋅ = + = + −+ ∫∫∫ n n nn n nn n d nn nn d n n d nnn nn       π πππ θθθθθθθ ( ) ( ) ( )∫∫∫∫ +−−+ −=+−== ππ π ππ θθθθθθθθθθθθ 0 1212 0 212 0 0 2 0 2 0 12 sinsin2cossin2cossincossinsin dndndd nnnnnn    ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) ( ) ,2,1,0 12 2 !12 !2 !2 !2 1 !2 !2 212 22 1 1 2 22 1 1 2 = + = + =−= + + − + − ∫∫ n nn n n n dtt n n dttP n n n nn Return to Table of Content 59
SOLO Legendre Polynomials Expansion of Functions, Legendre Series Using Sturm-Liouville Theory it can be seen that the Legendre Polynomials that are Solution of the Legendre ODE, form an orthogonal and “Complete” Set, meaning that we can expand any function f (t) , Piecewise Continuous in the interval -1 ≤ t ≤+1. Therefore we can define a series of Legendre Polynomials that converges in the mean to the function f (t) ( ) ( ) 11 0 ≤≤−= ∑ ∞ = ttPatf n nn The coefficients an can be defined using the Orthogonality Property of Legendre Polynomials ( ) ( ) ( ) ( ) m n m mnnm a m tdtPtPatdtPtf mn 12 2 0 2 12 1 1 1 1 + == ∑ ∫∫ ∞ = + + − + −    δ ( ) ( )∫ + − + = 1 1 2 12 tdtPtf m a mm ( ) ( ) ( ) ( ) 11 2 12 0 1 1 ≤≤−       + = ∑ ∫ ∞ = + − ttPtdtPtf n tf n nn 60
SOLO Legendre Polynomials Expansion of Functions, Legendre Series At any discontinuous point t0 ( f(t0- ) ≠ f(t0+) ) we have ( ) ( )[ ] ( ) ( ) ( ) 11 2 12 2 1 0 0 0 1 1 00 ≤≤−       + =+ ∑ ∫ ∞ = + − +− ttPtdtPtf n tftf n nn If f (t) is defined in the interval –a ≤ t ≤ +a then ( ) ( ) ataatPatf n nn ≤≤−= ∑ ∞ =0 / ( ) ( )∫ + − + = a a nn tdatPtf a n a / 2 12 61
SOLO Legendre Polynomials Expansion of Functions, Legendre Series If f (t) is an odd function ( f(-t ) =- f(t) ) we have ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )    =+−−= +== + ∫ ∫∫ ∫∫∫ + ++ −− + −→ − + − 1 0 1 0 1 0 1 1 0 0 1 1 1 2 0 12 2 oddndttPtf evenn dttPtfdttPtf dttPtfdttPtfdttPtfa n n n tP n tf n tt nnn n n     If f (t) is an even function ( f(-t ) = f(t) ) we have ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )     =+−−= +== + ∫∫∫ ∫∫∫ + ++ − + −→ − + − oddn evenndttPtf dttPtfdttPtf dttPtfdttPtfdttPtfa n n n tP n tf n tt nnn n n 0 2 12 2 1 0 1 0 1 0 1 1 0 0 1 1 1     62
SOLO Legendre Polynomials Expansion of Functions, Legendre Series Using Rodrigues’ Formula let calculate ( ) ( )[ ]n nn nn td td n tP 1 !2 1 2 − = ( ) ( ) ( )[ ] ( ) ( ) ( )[ ] ( )[ ] ( ) ( ) ( ) ( ) ∫∫ ∫∫ + − + − − − + − − − + − + − −−== − − − = − = 1 1 2 1 1 1 21 0 1 1 1 21 1 1 21 1 1 !2 1 1 1 !2 11 !2 1 1 !2 1 td td tfd t n td td tfd td td ntd td tf n tdtf td td n tdtftP n n n n n n nn nn nn n n nn nn     ( ) ( ) ( ) ( ) ( ) ( ) ( ) ∫∫∫ + − + − + − −=−−= 1 1 2 1 1 2 1 1 1 !2 1 1 !2 1 1 td td tfd t n td td tfd t n tdtPtf n n n nn n n n n n or 63
SOLO Legendre Polynomials Expansion of Functions, Legendre Series Example f (t) = tk ,|t| < 1 ( ) ( ) ( ) ( ) ( ) ( ) ( )     ≥−+−− + < =− + = + = ∫ ∫∫ + − − + + − + + − nktdttnkkk n n nk td td td t n n tdtPt n a nkn n n kn n nn k n 1 1 2 1 1 1 2 1 1 1 111 !2 12 0 1 !2 12 2 12  We have ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( )( ) ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∫ ∫ ∫ ∫∫ + − + −− + − −−−+ + − −−+ + − −−+ + − −−+= −= + − − − − − + = − +++ −−−−−−−− = =− ++ −−−− = − + −− +− + −=− −− 1 1 2 1 1 22222 1 1 422222 1 1 222122 0 1 1 122122 1 2 1 1 1 2222 1 !2 !22 !2 !2 1 2222122 12222322122 1 222122 322122 1 122 122 1 122 1 1 122 222 tdt nm nm mn n tdtt mnnn nmnmnmnm tdtt nn nmnm tdtt n nm tt n tdtt mn nmnm nmnmmn nmn nmnnmntu tdtdv nmn nm n        Take k = 2m and since t2m is even, they are only even coefficients nonzero so we take 2 n instead of n, and 2n ≤ 2m 64
SOLO Legendre Polynomials Expansion of Functions, Legendre Series Example f (t) = tk , |t| < 1 (continue – 1) ( ) ( ) ( ) ( ) ( )     ≥− − + < = ∫ + − − + nmtdtt nm m n n nm a nmn n n 1 1 2222 12 2 1 !22 !2 !22 14 0 We have for f (t) = t2m ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( )!122 !2 !2 !22 !2 !2 1 !2 !22 !2 !2 1 2122 1 1 2 1 1 2222 ++ + − − + = − − − + =− ++ −− + − + −− + − − ∫∫ nm mn nm nm mn n tdt nm nm mn n tdtt nm nmnm mn nmnm nmn ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( )!122! !!2142 !122 !2 !2 !22 !2 !2 !22 !2 !22 14 22122 122 ++− ++ = ++ + − − +− + = ++ −−+ nmnm nmmn nm nm nm nm nm n nm m n n a nnm nmnmnn ( ) ( ) ( )!12 !2 1 212 1 1 2 + =− + + −∫ n n dtt n n Where we used the previous result Therefore ( ) ( ) ( ) ( ) ( ) ( )∑= ++− ++ = m n n n m tP nmnm nmmn t 0 2 2 2 !122! !!2142 65
SOLO Legendre Polynomials Expansion of Functions, Legendre Series ( ) ( ) ( ) ( ) ( ) ( ) ( )     ≥−+−− + < =− + = + = ∫ ∫∫ + − − + + − + + − nktdttnkkk n n nk td td td t n n tdtPt n a nkn n n kn n nn k n 1 1 2 1 1 1 2 1 1 1 111 !2 12 0 1 !2 12 2 12  We have ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( )( ) ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( )∫ ∫ ∫ ∫∫ + − ++ ++ −− + − −−−++ + − −−+ + − −−+ + − −−+= −= + − −+ − ++ + − − ++ + = − ++++ −−−−−−−− = =− ++ −−−− = − + −− +− + −=− −− + 1 1 12 2122 1 1 222212 1 1 422322 1 1 222222 0 1 1 122222 1 2 1 1 1 22122 1 !122 !2 !2 !22 !12 !12 1 12322222 12222322122 1 322222 322122 1 222 122 1 222 1 1 122 2122 tdt nm mn nm nm mn n tdtt mnnn nmnmnmnm tdtt nn nmnm tdtt n nm tt n tdtt mn nm nmnm nmnmmn nmn nmnnmntu tdtdv nmn nm n        Take k = 2m+1 and since t2m+1 is odd, they are only odd coefficients nonzero so we take 2 n+1 instead of n, and 2n+1 ≤ 2m+1 66 Example f (t) = tk , |t| < 1 (continue – 2)
SOLO Legendre Polynomials Expansion of Functions, Legendre Series ( ) ( ) ( ) ( ) ( )     ≥− −+ + < = ∫ + − −+ + + nmtdtt nm m n n nm a nmn n n 1 1 22122 22 12 1 !22 !2 !122 34 0 We have for f (t) = t2m+1 ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( )!322 !12 !2 !22 !12 !12 1 !122 !2 !2 !22 !12 !12 1 2322 1 1 12 21221 1 22122 ++ ++ − − ++ + = − ++ + − − ++ + =− ++ −− + − ++ ++ −− + − −+ ∫∫ nm mn nm nm mn n tdt nm mn nm nm mn n tdtt nm nmnm mn nm nmnm nmn ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( )!322! !1!12342 !322 !12 !2 !22 !12 !12 !22 !2 !122 34 122322 2212 ++− ++++ = ++ ++ − − ++ + −+ + = +++ −−++ nmnm nmmn nm nm nm nm nm n nm m n n a nnm nmnmnn ( ) ( ) ( )!12 !2 1 212 1 1 2 + =− + + −∫ n n dtt n n Where we used the previous result Therefore ( ) ( ) ( ) ( ) ( ) ( )∑= + + + ++− ++++ = m n n n m tP nmnm nmmn t 0 12 12 12 !322! !1!12342 Return to Neumann Integral 67 Example f (t) = tk , |t| < 1 (continue – 3)
SOLO Legendre Polynomials Expansion of Functions, Legendre Series Neumann Integral 1 1 1 111 0 2 12 0 12 2 0 1 0 <+==      = − = − ∑∑∑∑ ∞ = −∞ = + ∞ = + ∞ = x t x t x t x t x t x x txtx m m m m m m m m m m m Start from Use ( ) ( ) ( ) ( ) ( ) ( )∑= + + + ++− ++++ = m n n n m tP nmnm nmmn t 0 12 12 12 !322! !1!12342 ( ) ( ) ( ) ( ) ( ) ( )∑= ++− ++ = m n n n m tP nmnm nmmn t 0 2 2 2 !122! !!2142 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∑ ∑∑ ∑ ∑ ∑∑ ∑ ∑ ∑∑ ∑ ∞ = ∞ = + − +∞ = ∞ = ++− += ∞ = ∞ = + − +∞ = ∞ = +− ∞ = = − + +∞ = +− = ++ +++++ + ++ +++ = ++− ++++ + ++− ++ = ++− ++++ + ++− ++ = − 0 0 12 2 12 0 0 2 212 2 0 12 2 12 0 2 12 2 0 0 2 12 12 0 12 0 2 2 !322! !12!122342 !124! !2!22142 !322! !1!12342 !122! !!2142 !322! !1!12342 !122! !!21421 n i n m n n i n in ninm n nm n m n n nm n m nOrder Summation Change m m n m n n m m m n n n tPx nmi ininn tPx ini ininn tPx nmnm nmmn tPx nmnm nmmn xtP nmnm nmmn xtP nmnm nmmn tx 68
SOLO Legendre Polynomials Expansion of Functions, Legendre Series Neumann Integral (continue – 1) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∑ ∑∑ ∑ ∞ = + ∞ = − +∞ = ∞ = ++−       ++ +++++ +      ++ +++ = − 0 12 0 2 12 0 2 0 212 2 !322! !12!122342 !124! !2!221421 n n i m n n n i in n tPx nmi ininn tPx ini ininn tx We found ( ) ( ) ( ) ( ) ( ) 1 !122! !2! 2 0 12 > ++ ++ = ∑ ∞ = ++− xx ini inin xQ i inn n Use the Frobenius Series development of Legendre Functions of the Second Kind Qn (x) We have ( ) ( ) ( ) ( ) ( ) ( )∑∑ ∞ = ++ ∞ = +++= − 0 1212 0 22 3414 1 n nn n nn tPxQntPxQn tx ( ) ( ) ( )∑ ∞ = <+= − 0 12 1 n nn xttPxQn tx Return to Qn Frobenius Series 69
SOLO Legendre Polynomials Expansion of Functions, Legendre Series Neumann Integral (continue – 2) We found ( ) ( ) ( )∑ ∞ = += − 0 12 1 n nn tPxQn tx Multiply both sides by Pm (t) and integrate between -1 to +1 ( ) ( ) ( ) ( ) ( ) ( )xQtdtPtPxQntd tx tP m n n mnn m nm 212 0 12 2 1 1 1 1 =+= − ∑ ∫∫ ∞ = + + − + −    δ We obtain ( ) ( ) ∫ + − − = 1 1 2 1 td tx tP xQ n n Franz Neumann's Integral of 1848 Franz Ernst Neumann (1798 –1895) Return to Table of Content 70
SOLO 71 Legendre Polynomials Schlaefli Integral Start with Using Rodrigues's Formula we obtain( ) ( )[ ]n n n nn x xd d n xP 1 !2 1 2 −= ( ) ( ) ∫ − = td zt tf j zf π2 1 Cauchy's Integral with ( ) ( )n zzf 12 −= ( ) ( ) ∫ − − =− td zt t j z n n 1 2 1 1 2 2 π Differentiate n times this equation with respect to z and multiply by 1/ (2n n!) ( ) ( ) ( )∫ + − − − =− td zt t j z zd d n n nn n n n n 1 2 2 1 2 2 1 !2 1 π with the contour enclosing the point t = z. Schlaefli Integral ( ) ( ) ( )∫ + − − − = td zt t j zP n nn n 1 2 1 2 2 π Return to Table of Content
SOLO 72 Legendre Polynomials Laplace’s Integral Representation Start with ( ) ( ) ( )[ ] ( )[ ] ( )[ ] ( ) [ ] [ ] ( ) ( ) 22 0 1 2 0 22 0 2 0 22 2/tan 0 22 2 0 2 2 0 121 2 1 1 tan 1 2 1 1 1 1 1 1 2 11 2 11 2 2/tan12/tan1 2/tan1 2/tan1 2/tan1 1 cos1 λ ππ λλ λ λ λ λ λ λ λ λλλφλφ φφ φ φ λ φ φλ φ φπππ − = − =        + − − =         + − + + − − = −++ = −++ = −++ + = + − + = + ∞ − ∞ ∞∞= ∫ ∫∫∫∫∫ t t td t td tt tdddd t ( ) ( ) ( ) ( ) ( ) { }[ ] ( ) { }∑ ∞ = −− − ±= −±−=−±−−= −±− − = − − ± = + 0 2 1 2 22 1 1 cos11cos111 cos11 1 cos 1 1 1 1 cos1 1 2 n n n xu xu xxuxuxxuxu xuxu xu xu xu φφ φ φ φλ λ Let write where we used ( ) ∑ ∞ = − =− 0 1 1 n n aa ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2222 2 22 1 1 2 21 1 11 1 1 1 1 1 1 1 2 uxu xu xuxu xu xu xu xu xu +− − = −−− − = − − − = − − − ±=λ λ ( ) { } ( ) { } ( ) 22 0 0 2 0 0 2 0 21 1 1 cos11cos11 cos1 uxu xu dxxuxudxxuxu d n n n n n n +− − = − =−±−=−±−= + ∑ ∫∫ ∑∫ ∞ = ∞ = π λ π φφφφ φλ φ πππ
SOLO 73 Legendre Polynomials Laplace’s Integral Representation (continue - 1) { } ( )∑∑ ∫ ∞ = ∞ = = +− =−± 0 2 0 0 2 21 cos1 n n n n n n xPu uxu dxxu π π φφ π We obtained Equating un coefficients we obtain : ( ) { }∫ −±= π φφ π 0 2 cos1 1 dxxxP n n ( ) ( ) 0112 =+−      − ynny xd d x xd d If we replace in the Legendre ODE n by –n – 1 the equation does not change. Therefore , and( ) ( )xPxP nn 1−−= ( ) { }∫ −− −±= π φφ π 0 1 2 cos1 1 dxxxP n n Substitute x = cosθ ( ) { }∫ ±= π φφθθ π θ 0 cossincos 1 cos djP n n Laplace’s First Integral Laplace’s Second Integral
SOLO 74 Legendre Polynomials Laplace’s Integral Representation (continue - 2) Use the Generating Function [ ] ( )∑ ∞ = = +− 0 2/12 21 1 n n n tPu uut Substitute t = cosθ and u = ejφ [ ] ( )∑ ∞ = = +− 0 2/12 cos cos21 1 n n nj jj Pe ee θ θ ϕ ϕϕ [ ] [ ] [ ] [ ] [ ] 2/12/12/12/12/12 coscos2cos2cos21 θϕθθ ϕϕϕϕϕϕ −=+−=+− − jjjjjj eeeeeeBut Therefore ( ) ( ) ( ) ( )       > − < − = − ∞ = ∑ θϕ θϕ θϕ θϕ θ πϕ ϕ ϕ 2/12/ 2/12/ 0 coscos2 1 coscos2 1 cos j j n n nj e e Pe Equating the real and imaginary parts, we obtain ( ) ( ) ( ) ( ) ( ) ( )       > − < − =∑ ∞ = θϕ θϕ ϕ θϕ θϕ ϕ θϕ 2/1 2/1 0 coscos2 2/sin2 coscos2 2/cos2 coscos n nPn ( ) ( ) ( ) ( ) ( ) ( )       > − < − − =∑ ∞ = θϕ θϕ ϕ θϕ θϕ ϕ θϕ 2/1 2/1 0 coscos2 2/cos2 coscos2 2/sin2 cossin n nPn
SOLO 75 Legendre Polynomials Laplace’s Integral Representation (continue - 3) Let multiply first relation by cos (nφ) and the second by sin (nφ) and integrate over φ on (0,π), we obtain two integrals ( ) ( ) ( ) ( ) ( ) ( )       > − < − =∑ ∞ = θϕ θϕ ϕ θϕ θϕ ϕ θϕ 2/1 2/1 0 coscos2 2/sin2 coscos2 2/cos2 coscos i iPi ( ) ( ) ( ) ( ) ( ) ( )       > − < − − =∑ ∞ = θϕ θϕ ϕ θϕ θϕ ϕ θϕ 2/1 2/1 0 coscos2 2/cos2 coscos2 2/sin2 cossin i iPi ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∫ ∫∑∫ − + − == ∞ = θ π θ δ π π ϕ θϕ ϕϕ ϕ θϕ ϕϕ θ π θϕϕϕ 0 2/12/1 0 2 0 coscos2 cos2/sin2 coscos2 cos2/cos2 cos 2 coscoscos d n d n PPdni n i i in    ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∫ ∫∑∫ − + − −== ∞ = θ π θ δ π π ϕ θϕ ϕϕ ϕ θϕ ϕϕ θ π θϕϕϕ 0 2/12/1 0 2 0 coscos2 sin2/cos2 coscos2 sin2/sin2 cos 2 cossinsin d n d n PPdni n i i in    ( ) ( ) ( ) ( ) ( ) ( ) ( )       − + − = ∫ ∫ θ π θ ϕ θϕ ϕϕ ϕ θϕ ϕϕ π θ 0 2/12/1 coscos cos2/sin coscos cos2/cos2 cos d n d n Pn ( ) ( ) ( ) ( ) ( ) ( ) ( )       − + − −= ∫ ∫ θ π θ ϕ θϕ ϕϕ ϕ θϕ ϕϕ π θ 0 2/12/1 coscos sin2/cos coscos sin2/sin2 cos d n d n Pn Dirichlet Integrals Johann Peter Gustav Lejeune Dirichlet (1805 –1859)
SOLO 76 Legendre Polynomials Add and subtract those two equations ( ) ( ) ( ) ( ) ( ) ( ) ( )       − + − = ∫ ∫ θ π θ ϕ θϕ ϕϕ ϕ θϕ ϕϕ π θ 0 2/12/1 coscos cos2/sin coscos cos2/cos2 cos d n d n Pn ( ) ( ) ( ) ( ) ( ) ( ) ( )       − + − −= ∫ ∫ θ π θ ϕ θϕ ϕϕ ϕ θϕ ϕϕ π θ 0 2/12/1 coscos sin2/cos coscos sin2/sin2 cos d n d n Pn Dirichlet Integrals ( ) ( )[ ] ( ) ( )[ ] ( )       − + + − + = ∫ ∫ θ π θ ϕ θϕ ϕ ϕ θϕ ϕ π θ 0 2/12/1 coscos 2/1sin coscos 2/1cos 2 1 cos d n d n Pn ( )[ ] ( ) ( )[ ] ( )∫ ∫ − − − − − = θ π θ ϕ θϕ ϕ ϕ θϕ ϕ 0 2/12/1 coscos 2/1sin coscos 2/1cos 0 d n d n Replace n by n + 1 in the last equation and substitute in the previous ( ) ( )[ ] ( ) ( )[ ] ( )∫ ∫ − + = − + = θ π θ ϕ θϕ ϕ π ϕ θϕ ϕ π θ 0 2/12/1 coscos 2/1sin2 coscos 2/1cos2 cos d n d n Pn Mehler Integrals Gustav Ferdinand Mehler (1835 - 1895) Return to Table of Content Laplace’s Integral Representation (continue - 4)
SOLO 77 Legendre Polynomials We found Return to Table of Content Integrals in terms of sin(iθ) and cos(iθ) ( ) ( ) mnnk n dttPtP δ 12 21 1 + =∫ + − ( ) ( ) mnnk n dPP δθθθθ π 12 2 sincoscos 0 + =∫ θcos=t ( ) ( ) ( ) ( ) ( )     ≥ ++− + < = + = − + − ∫ nm nmnm nmm nm a n tdtPt n nn m !122! !!22 0 14 2 12 2 1 1 2 2 ( ) ( ) ( ) ( ) ( )     ≥ ++− +++ < = + = + + + − + + ∫ nm nmnm nmm nm a n tdtPt n nn m !322! !1!122 0 34 2 22 12 1 1 12 12 ( ) ( ) ( ) ( ) ( )     ≥ ++− + < = − ∫ nm nmnm nmm nm dP n n m !122! !!22 0 sincoscos 12 0 2 2 π θθθθ ( ) ( ) ( ) ( ) ( )     ≥ ++− +++ < = + + + ∫ nm nmnm nmm nm dP n n m !322! !1!122 0 sincoscos 22 0 12 12 π θθθθ
Ordinary Differential EquationsSOLO Second Order Linear Ordinary Differential Equation (ODE) 78 Legendre Functions of the Second Kind Qn (x) ( ) [ ] ( ) ( )∑ ∫ ∞ = −− ∞ −− = − − +− −+= 0 2 12/12 0 1 2 1 cosh21 cosh1 n n n n n txQ x xt ttx dxxxQ θθ ( ) ( )n n n nn x xd d n xP 1 !2 1 2 −= ( ) ( ) 1<+= xxQBxPAy nn ( ) ( ) ( )xP xd d xxP nm m mm n 2/2 1−= ( ) ( ) ( )xQ xd d xxQ nm m mm n 2/2 1−= ( ) ( ) ( )xW x x xPxQ nnn 1 1 1 ln 2 1 −− − + = ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 3 2 2 5 2 3 1 1 1 ln 2 1 2 033 022 011 0 +−= −= −= − + = xxQxPxQ xxQxPxQ xQxPxQ x x xQ ( ) ( ) ( )∑= −−− = n m mnmn xPxP m xW 1 11 1 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) [ ] ( ) ( )   − − =    −       − − +− − − + = −+ −− − − + = ∑ ∑ = − =+       − = −− evennifn oddnifnn xP m nm mn x x xP xP rnr rn x x xPxQ n m mnn mr n r rnnn 2/2 2/1 2 1 2 1 122 1 1 ln 2 1 12 142 1 1 ln 2 1 1 12 2 1 0 12
Legendre Ordinary Differential EquationSOLO 79 Legendre Functions of the Second Kind Qn (x) ( ) ( ) ( )xPxuxy nnn = With Pn (x) being a solution of the Legendre Differential Equation we look for the second solution having the form ( ) ( ) 0121 2 2 2 =++−− wnn xd wd x xd wd x ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 2 2 2 2 2 2 xd xPd xu xd xPd xd xud xP xd xud xd xyd xd xPd xuxP xd xud xd xyd n n nn n nn n nn nn ++= += ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 01221121 2 2 22 2 2 2 =++−−−+−+− xPxunn xd xPd xuxxP xd xud x xd xPd xxu xd xPd xd xud xxP xd xud x nn n nn nn n nn n n Substituting in the Legendre ODE we obtain ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 01212121 0 2 2 22 2 2 2 =      ++−−+−−+− xuxPnn xd xPd x xd xPd xxP xd xud x xd xPd xd xud xxP xd xud x nn nn n nnn n n    or
SOLO 80 Legendre Functions of the Second Kind Qn (x) (continue – 1) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 02121 2 2 2 2 =−−+− xP xd xud x xd xPd xd xud xxP xd xud x n nnn n n Equivalent to ( ) ( ) ( ) ( ) 0 1 2/ 2 / / 2 22 = − −+ x x xP xdxPd xdxud xdxud n n n n ( ) ( ) ( ) 01lnln2ln 2 =−++ x xd d xP xd d xd xud xd d n n or Integrating we obtain ( ) ( )[ ] ( ) .1lnlnln 22 constxxP xd xud n n =−++ Therefore ( ) ( )[ ] ( ) AconstxxP xd xud n n ==−⋅⋅ .1 22 ( ) ( )[ ] ( )∫ −⋅ = 22 1 xxP xd Axu n n This means that the second solution has the form ( ) ( ) ( ) ( ) ( )[ ] ( )∫ −⋅ == 22 1 xxP xd xPxuxPxQ n nnnn Legendre Ordinary Differential Equation
SOLO 81 Legendre Functions of the Second Kind Qn (x) (continue – 2) We obtained ( ) ( ) ( ) ( ) ( )[ ] ( ) 1 1 22 < −⋅ == ∫ x xxP xd xPxuxPxQ n nnnn ( ) ( ) ( )[ ] ( ) ( ) ( )[ ] x x xxxd xxxxP xd xPxQ − + =++−−=      + + − = −⋅ = ∫∫ 1 1 ln 2 1 1ln1ln 2 1 1 1 1 1 2 1 1 2 1 2 01 00  Let calculate Q0 (x), Q1 (x) ( ) ( ) ( )[ ] ( ) ( ) 1 1 1 ln 2 1 1 2/1 1 2/1 1 1 1 22222 1 11 2 − − + =      + + + − = − = −⋅ = ∫∫∫ x xx xd xxx xxd xx x xxP xd xPxQ x x  Legendre Ordinary Differential Equation
SOLO 82 Legendre Functions of the Second Kind Qn (x) (continue – 2) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 3 2 2 5 1 1 ln 2 1 3 2 2 5 1 1 ln 4 35 2 3 1 1 ln 2 1 2 3 1 1 ln 4 43 1 1 1 ln 2 1 1 1 1 ln 2 1 1 ln 2 1 2 3 23 3 2 2 2 11 0 +−      − + =+−      − +− = −      − + =−      − +− = −      − + =−      − + =       − + = x x x xP x x xxx xQ x x x xP x x xx xQ x x xP x xx xQ x x xQ Legendre Ordinary Differential Equation
SOLO 83 Legendre Functions of the Second Kind Qn (x) (continue – 3) To obtain a general formula for Qn (x), start from the Polynomial Pn (x) that has n zeros αi, i=1,2,…,n ( ) ( ) ( ) ( )nnn xxxkxP ααα −−−= 21 ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∑=       − + − + + + − = +⋅−⋅−−− = −⋅ n i i i i i nnn x d x c x b x a xxxxxkxxP 1 2 00 22 2 2 1 222 11 11 1 1 1 αα ααα  ( ) ( )[ ] ( ) ( )[ ] ( )[ ] ( ) ( ) ( )∑=       − + − −⋅+−++= n i i i i i nnn x d x c xxPxPxbxPxa 1 2 222 0 2 0 1111 αα If we put x=1 and x = -1, and remembering that Pn (1) = 1 and Pn(-1)=(-1)n , we obtain 2/100 == ba Let prove that ( ) ( )[ ] ( ) 0 1 1 22 2 =               −⋅ −= = ixn ii xxP x xd d c α α Legendre Ordinary Differential Equation
SOLO 84 Legendre Functions of the Second Kind Qn (x) (continue – 4) Let prove that ( ) ( )[ ] ( ) 0 1 1 22 2 =               −⋅ −= = ixn ii xxP x xd d c α α Start with ( ) ( )[ ] ( ) ( ) ( ) ( ) ( ) i x iixi xatfinitexfprovided xd xfd xxfxxfx xd d i i αααα α α ==      −+−=− = = 02 22 The only terms that are not finite in at x = αi are the terms ci/(x-αi) and di/(x-αi)2 , therefore ( )[ ] ( ) ( ) ( )∑=       − + − + + + − = −⋅ n i i i i i n x d x c x b x a xxP 1 2 00 22 111 1 αα ( ) ( )[ ] ( ) ( ) ( ) ( ) ( )[ ] i x iii xi i i i i xn i cdxc xd d x d x c x xd d xxP x xd d iii =       +−=               − + − −=       −⋅ − === ααα α αα αα 2 2 22 2 1 1 Therefore if we write Pn (x) = (x-αi) Li (x), we have ( )[ ] ( ) ( )[ ] ( ) ( ) ( )[ ] ( ) ( ) ( ) ( ) ( )[ ] ( ) ( ) ( ) ( ) ( )[ ] ( )22 2 223 2 2322222 1 /1 2 1 /122 1 /2 1 2 1 1 iii iiiiii xi ii xi i ixi i L xdxLdL xxL xdxLdxxLx xxL xdxLd xxL x xxLxd d c iii αα αααα ααα −⋅ =−− =         −⋅ −⋅− =         −⋅ − −⋅ =               −⋅ = === Legendre Ordinary Differential Equation
SOLO 85 Legendre Functions of the Second Kind Qn (x) (continue – 5) We proved that ( ) ( )[ ] ( ) ixn ii xxP x xd d c α α =               −⋅ −= 22 2 1 1 ( ) ( ) ( ) ( )[ ] ( )22 2 1 /1 2 iii iiiiii i L xdxLdL c αα αααα −⋅ =−− =Therefore if we write Pn (x) = (x-αi) Li (x), we have Since Pn (x) = (x-αi) Li (x) satisfies the Legendre ODE, we have ( ) ( ) ( ){ } ( ) ( ){ } ( ) ( ) ( ){ } 0121 2 2 2 =−++−−−− xLxnnxLx xd d xxLx xd d x iiiiii ααα Performing the calculation and substituting x = αi, we have ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ] 01221 2 2 2 =       −++      +−−      +−− = ix iii i i ii i xLxnnxL xd xLd xx xd xLd xd xLd xx α ααα ( ) ( ) ( ) 0212 2 =− = − iii ii i L xd xLd αα α α Substituting in ci equation we get ( ) ( ) ( ) ( )[ ] ( ) 0 1 /1 2 22 2 = −⋅ =−− = iii iiiiii i L xdxLdL c αα αααα Therefore ( )[ ] ( ) ( )∑= − +      + + − = −⋅ n i i i n x d xxxxP 1 222 1 1 1 1 2 1 1 1 α Legendre Ordinary Differential Equation
SOLO 86 Legendre Functions of the Second Kind Qn (x) (continue – 6) We can prove that but the exact value is not important, as we shall see ( ) ( )[ ] ( ) ixn i i xxP x d α α =      −⋅ − = 22 2 1 Therefore ( )[ ] ( ) ( )∑= − +      + + − = −⋅ n i i i n x d xxxxP 1 222 1 1 1 1 2 1 1 1 α ( )[ ] ( ) ( ) ∑∑∫∫∫ == − − − + = − +      + + − = −⋅ n i i i n i i i n x d x x dx x d dx xxxxP dx 11 222 1 1 ln 2 1 1 1 1 1 2 1 1 αα ( ) ( ) ( ) ∑= − − − + = n i i n inn x xP d x x xPxQ 11 1 ln 2 1 α Since Pn (x)/(x-αi) is a polynomial of order (n-1) the sum above is also a polynomial of order (n-1), and we define it as ( ) ( ) ∑= − − = n i i n in x xP dxW 1 1 : α so ( ) ( ) ( ) 1 1 1 ln 2 1 1 <− − + = − xxW x x xPxQ nnn Legendre Ordinary Differential Equation
SOLO 87 Legendre Functions of the Second Kind Qn (x) (continue – 7) To find Wn-1 (x) let use the fact that Qn (x) is a solution of Legendre’s ODE or ( ) ( ) ( ) ( ) ( ) 0121 2 2 2 =++−− xQnn xd xQd x xd xQd x n nn ( ) ( ) ( ) ( ) xd xWd xP xx x xd xPd xd xQd n n nn 1 2 1 1 1 1 ln 2 1 − − − + − + = ( ) ( ) ( ) ( ) ( ) ( ) 2 1 2 2222 2 2 2 1 2 1 2 1 1 ln 2 1 xd xWd xP x x xd xPd xx x xd xPd xd xQd n n nnn − − − + − + − + = ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 0121 1 2 2 1 2 1 1 ln 2 1 121 1 1 2 1 2 2 22 0 2 2 2 =+−+−− − −+ − + − +       ++−− − −− xWnn xd xWd x xd xWd xxP x x xd xPd xP x x x x xPnn xd xPd x xd xPd x n nn n n n n nn    ( ) ( ) ( ) ( ) ( ) ( ) xd xPd xWnn xd xWd x xd xWd x n n nn 2121 1 1 2 1 2 2 =++−− − −− Legendre Ordinary Differential Equation ( ) ( ) ( ) 1 1 1 ln 2 1 1 <− − + = − xxW x x xPxQ nnn
SOLO 88 Legendre Functions of the Second Kind Qn (x) (continue – 8) Use the Recursive Formula ( ) ( ) ( ) ( ) ( ) xd xPd xWnn xd xWd x xd d n n n 211 1 12 =++       − − − ( ) ( ) ( ) ( ) ( ) ∑       − = −−−−= 1 2 1 0 121421 l i in n xPin xd xPd Since Wn-1(x) is a polynomial of order n – 1, let write ( ) ( ) ( ) ( ) ( ) ∑       − = −−−−− =++= 1 2 1 0 1231101 n i ininnn xPaxPaxPaxW  Substitute those two equation in the Wn-1(x) O.D.E. to obtain ( ) ( ){ } ( ) ( ) ( ) ( ) ( ) ( ) ( ) ∑∑∑       − = −−       − = −−       − = −− −−=++− 1 2 1 0 12 1 2 1 0 12 1 2 1 0 12 2 142211 l i in n i ini n i ini xPinxPannxPx xd d a But by Legendre O.D.E.: ( ) ( ){ } ( ) ( ) ( ) 02121 1212 2 =−−−+− −−−− xPininxPx xd d inin ( ) ( ) ( ){ } ( ) ( ) ( ) ( ) ( ) ∑∑       − = −−       − = −− −−=++−−−− 1 2 1 0 12 1 2 1 0 12 14221212 l i in n i ini xPinxPnninina Let solve Legendre Ordinary Differential Equation
SOLO 89 Legendre Functions of the Second Kind Qn (x) (continue – 9) The coefficients of the same polynomial in both sides must be equal ( ) ( ) ( ){ } ( ) ( ) ( ) ( ) ( ) ∑∑       − = −−       − = −− −−=++−−−− 1 2 1 0 12 1 2 1 0 12 14221212 l i in n i ini xPinxPnninina ( ) ( ) ( ){ } ( )14221212 −−=++−−−− innnininai ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( )12224244 1221212 222 2 +−=−+−=++−+−+−= ++−+−−=++−−−− iininininniniinn nnininnninin But which gives ( ) ( )12 142 +− −− = iin in ai ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) [ ][ ] ∑ ∑∑ = = −− =+       − = −−− +− +− =       − − +− = +− −− = n m n m mnmn mi n i inn xP mn mn m xP m n mn m xP iin in xW 1 1 12 1 2 1 0 121 12 12221 2 1 1221 12 142 and ( ) ( ) ( )∑= −−− = n m mnmn xPxP m xW 1 11 1 ????? Legendre Ordinary Differential Equation
SOLO 90 Legendre Functions of the Second Kind Qn (x) (continue -10) ( ) 3,2,1,0 10 = <≤ n xxQn Legendre Ordinary Differential Equation ( ) ( ) ( ) ( ) ( ) ( ) ( ) 3 2 2 5 1 1 ln 2 1 3 2 2 5 1 1 ln 4 35 2 3 1 1 ln 2 1 2 3 1 1 ln 4 43 1 1 1 ln 2 1 1 1 1 ln 2 1 1 ln 2 1 2 3 23 3 2 2 2 11 0 +−      − + =+−      − +− = −      − + =−      − +− = −      − + =−      − + =       − + = x x x xP x x xxx xQ x x x xP x x xx xQ x x xP x xx xQ x x xQ
SOLO 91 Legendre Functions of the Second Kind Qn (x) (continue -11) Similar to Rodrigues Formula for Legendre Functions of the Second Kind Qn (x) Start with ( ) ( ) ( )12 2212 1 1 1 1 +−− ++ −= − n nn x xx ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( )( )( ) ( ) ( ) ( ) ( ) ( )( ) ( )1 32211 11, ,121,11,1: ++− +−+−+− −++= −++=−+=−= ini nnn uinnuf unnufunufuuf   ( ) ( ) ( ) ( ) 1 !! ! !! !1 1 1 12 0 2 0 2212 > + = + = − ++− ∞ = − ∞ = ++ ∑∑ xx in in x in in xx in i i i nn ( ) ( ) ( ) ( )( ) ( ) 1 ! 21 ! 0 00 < +++ == ∑∑ ∞ = ∞ = uu i innn u i f uf i i i i i  Taylor expansion around u = 0 Use u = x-2 Legendre Ordinary Differential Equation
SOLO 92 Legendre Functions of the Second Kind Qn (x) (continue -12) Similar to Rodrigues Formula for Legendre Functions of the Second Kind Qn (x) Integrate relative to x ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ∑∑ ∫∑∫∑∫ ∞ = ++− ∞ = ∞ ++− ∞ ++− ∞ = ∞ ++− ∞ = ∞ + −+ + = ++ + = + = + = − 0 122 0 122 12 0 2 12 0 212 122!! ! 122!! ! ! ! ! ! 1 i in i xin x in ix in ix n x inni in inni in d n in d n ind η ηηηη η η Integrate this n more times ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ∑ ∑ ∑ ∫ ∫∫∫ ∫ ∞ = ++− ∞ = ++− ∞ = ∞ ∞ ++− ∞ ∞ ∞ + + ++ ++ = +++++++ + = ++ + = − 0 12 0 12 0 122 12 1 !122!! !2! 122222122!! ! 122!! ! 1 i in i in i x nin x n n x inni inin x ininininni in d inni ind   ηη η ηη η η Legendre Ordinary Differential Equation
SOLO 93 Legendre Functions of the Second Kind Qn (x) (continue -13) Similar to Rodrigues Formula for Legendre Functions of the Second Kind Qn (x) (continue) ( ) ( ) ( ) ( ) ( ) 1 !122! !2! ! 1 1 0 12 12 1 > ++ ++ = − ∑∫∫ ∫ ∞ = ++− ∞ ∞ ∞ + + xx ini inin n d i in x n n η η η η  We found, using Frobenius Series By comparing those two relations we obtain ( ) ( ) 1 1 !2 12 1 > − = ∫∫ ∫ ∞∞ ∞ + + x d nxQ x n n n n η η η η  Return to Frobenius Series ( ) ( ) ( ) ( ) ( ) 1 !122! !2! 2 0 12 > ++ ++ = ∑ ∞ = ++− xx ini inin xQ i inn n Legendre Ordinary Differential Equation
SOLO 94 Legendre Functions of the Second Kind Qn (x) (continue -14) Another Expression for Legendre Functions of the Second Kind Qn (x) Start with the following Differential Equation ( ) ( ) 02121 2 2 2 =+−+− un xd ud xn xd ud x One of the Solutions is . Check:( ) ( )n xxu 12 1 −= ( ) ( ) ( ) ( ) 22212 2 1 2 121 11412&12 −−− −−+−=−= nnn xxnnxn xd ud xxn xd ud ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 01211411412 2121 21221222 1 1 2 1 2 2 =−−−−+−−−−−= +−+− −− nnnn xnxnxnxxnnxn un xd ud xn xd ud x The Second Solution can be find using u1 (x) by finding a function v (x) that satisfies: ( ) ( ) ( )n xxvxu 12 2 −= Legendre Ordinary Differential Equation
SOLO 95 Legendre Functions of the Second Kind Qn (x) (continue -15) Another Expression for Legendre Functions of the Second Kind Qn (x) (continue – 1) ( ) ( ) ( ) ( ) ( ) ( ) 01221 21212121 112 2 1 12 0 1 1 2 1 2 2 2 2 2 2 2 2 =−+      +−+       +−+−=+−+− xd vd uxnu xd vd u xd vd xd ud x un xd ud xn xd ud xvun xd ud xn xd ud x    The Second Solution can be find using u1 (x) by finding a function v (x) that satisfies: ( ) ( ) ( )n xxvxu 12 2 −= 2 1 2 1 12 2 2 2 2 1 1 2 2& xd ud v xd ud xd vd u xd vd xd ud xd ud vu xd vd xd ud ++=+= ( ) ( ) ( ) ( ) ( ) ( ) ( )1 121 2 2 1 12 2 1 12 / / 2 1 2 1 2 1 1 1 2 1 22 − + −= − − − − = − − − − = x xn u x uxn x uxn u xd ud x uxn xdvd xdvd Legendre Ordinary Differential Equation
SOLO 96 Legendre Functions of the Second Kind Qn (x) (continue -16) Another Expression for Legendre Functions of the Second Kind Qn (x) (continue – 2) Therefore ( ) ( )1 12 / / 2 22 − + −= x xn xdvd xdvd ( ) ( ) ( ) ( ) ( )∫ ∞ ++ − =⇒ − =⇒−+−= x nn d xv xxd vd xn xd vd 1212 2 11 1 1ln1 η η ( ) ( ) ( ) ( ) ( )∫ ∞ + − −== x n n d xxuxvxu 12 2 12 1 1 η η Differentiate the Differential Equation ( ) ( ) 02121 2 2 2 =+−+− un xd ud xn xd ud x ( ) ( ) ( ) ( ) ( ) ( ) 0122221 2121221 2 2 3 3 2 2 2 2 2 2 =−+−+−= +−+−+−− xd ud n xd ud xn xd ud x xd ud n xd ud xd d xn xd ud n xd ud x xd ud xd d x Legendre Ordinary Differential Equation
SOLO 97 Legendre Functions of the Second Kind Qn (x) (continue -17) Another Expression for Legendre Functions of the Second Kind Qn (x) (continue – 3) Differentiate relative to x the Ordinary Differential Equation n times ( ) ( ) ( ) 0122221: 2 2 3 3 2 =−+−+− xd ud n xd ud xn xd ud xODE xd d ( ) ( ) ( ) 0223321: 2 2 4 4 2 2 2 =−+−+− xd ud n xd ud xn xd ud xODE xd d ( ) ( ) 02121: 2 2 2 =+−+− un xd ud xn xd ud xODE ( ) ( ) 0121: 1 1 2 2 2 =++−− + + + + n n n n n n n n xd ud nn xd ud x xd ud xODE xd d Derive ( ) ( )[ ] ( )( ) 021121: 1 1 2 2 2 =−+++−+− + + + + i i i i i i i i xd ud ini xd ud xin xd ud xODE xd d ( ) ( )[ ]{ } ( )[ ] ( )( ){ } ( ) ( )[ ] ( )( ) 0122221 21121221: 1 1 1 1 3 3 2 1 1 1 1 3 3 2 =−−+++−+− −+++−++−+−+− + + + + + + + + + + + + i i i i i i i i i i i i i i xd ud ini xd ud xin xd ud x xd ud iniin xd ud xin xd ud xODE xd d xd d Proof by Induction q.e.d. i = n i → i+1 Legendre Ordinary Differential Equation
SOLO 98 Legendre Functions of the Second Kind Qn (x) (continue -18) Another Expression for Legendre Functions of the Second Kind Qn (x) (continue – 4) This is the Legendre Ordinary Differential Equation for dn u/dxn , having the solution Pn (x) and Qn (x). Thus, the solution Pn (x) and Qn (x) can be written in the following form: ( ) ( ) 0121: 1 1 2 2 2 =++−− + + + + n n n n n n n n xd ud nn xd ud x xd ud xODE xd d We obtain ( ) ( )[ ]n n n nn n nn x xd d nxd ud n xP 1 !2 1 !2 1 21 −== ( ) ( ) ( ) ( ) ( ) ( ) ( ) 1 1 1 !2 !21 !2 !21 12 22 >         − − − = − = ∫ ∞ + x d x xd d n n xd ud n n xQ x n n n nnn n nnn n η η Rodrigues Formula An integral for Qn (x) valid in |x| < 1 can be obtained from the previous result ( ) ( ) ( ) ( ) ( ) 1 1 1 !2 !21 0 12 2 <         − − − = ∫ + x d x xd d n n xQ x n n n nnn n η η Return to Table of Content Legendre Ordinary Differential Equation
99 SOLO Laplace Differential Equation in Spherical Coordinates 0 sin 1 sin sin 11 2 2 222 2 2 2 = ∂ Φ∂ +      ∂ Φ∂ ∂ ∂ +      ∂ Φ∂ ∂ ∂ =Φ∇ φθθ θ θθ rrr r rr Let solve this equation by the method of Separation of Variables, by assuming a solution of the form : ( ) ( )ϕθ,SrR=Φ Spherical Coordinates: θ ϕθ ϕθ cos sinsin cossin rz ry rx = = = In Spherical Coordinates the Laplace equation becomes: Substituting in the Laplace Equation and dividing by Φ gives: 0sinsin sin 11 2 2 22 2 2 =      ∂ ∂ +      ∂ ∂ ∂ ∂ +      φθ θ θ θ θ SS Srrd Rd r rd d Rr The first term is a function of r only, and the second of angular coordinates. For the sum to be zero each must be a constant, therefore: λ φθ θ θ θ θ λ −=      ∂ ∂ +      ∂ ∂ ∂ ∂ =      2 2 2 2 sinsin sin 1 1 SS S rd Rd r rd d R Associate Legendre Differential Equation
100 SOLO λ φθ θ θ θ θ −=      ∂ ∂ +      ∂ ∂ ∂ ∂ 2 2 2 sinsin sin 1 SS S ( ) ( ) ( )φθφθ ,,, SrRr =Φ We obtain: Multiply this by S sin2 θ and put to get:( ) ( ) ( )φθφθ ΦΘ=,S 0 1 sinsinsin 1 2 2 2 = Φ Φ +      +      Θ ∂ ∂ Θ φ θλ θ θ θ θ d d d d Again, the first term, in the square bracket, and the last term must be equal and opposite constants, which we write m2 , -m2 . Thus: Φ−= Φ =Θ      −+      Θ 2 2 2 2 2 0 sin sin sin 1 m d d m d d d d φ θ λ θ θ θθ The Φ ( ) must be periodical in (a period of 2 π) and becauseϕ ϕ this we choose the constant m2 , with m an integer. Thus: ( ) φφφ mbma sincos +=Φ Laplace Differential Equation in Spherical Coordinates ( ) φφ φ mjmj ee +− =Φ ,or With m integer, we have the Orthogonality Condition 21 21 , 2 0 2 mm mjmj dee δπφ π φφ =⋅∫ +− Return to Table of Content Associate Legendre Differential Equation
101 SOLO ( ) ( ) ( )φθ ΦΘ=Φ rR We obtain: or: Θ−=Θ− Θ + Θ λ θθ θ θ 2 2 2 2 sin cot m d d d d 0 sin sin sin 1 2 2 =Θ      −+      Θ ∂ ∂ θ λ θ θ θθ m d d Analysis of Associate Lagrange Differential Equation Laplace Differential Equation in Spherical Coordinates Change of variables: t = cos θ θθ dtd sin−= td d d d Θ −= Θ θ θ sin  ( ) td d t td d t td d d d td d td d td d td d d d d d d d Θ − Θ −= Θ + Θ =      Θ −−=      Θ = Θ − 2 2 2 cossin/1 2 2 2 2 2 1 sin sinsinsinsin  θθ θ θθ θθθθ θθθ Θ      − −+ Θ − Θ − Θ =Θ      −+ Θ + Θ = = 2 2 2 2cos 2 2 2 2 1sin cot0 t m td d t td d t td dm d d d d t λ θ λ θ θ θ θ We obtain: 1cos 0 1 2 2 2 2 2 ≤⇒= =Θ      − −+ Θ − Θ tt t m td d t td d θ λ Associate Legendre Differential Equation
102 SOLO ( ) ( ) ( )ϕθ gfrR=Φ We obtain: or: ff m d fd d fd λ θθ θ θ −=−+ 2 2 2 2 sin cot Let try to factorize the left-hand side, second order differential equation into two first-order operators: 0 sin sin sin 1 2 2 =      −+      ∂ ∂ f m d fd θ λ θ θ θθ The two equations are identical if the coefficient are equal. This is obtained by choosing α and β as follows: ( ) integer1 1 2 ==− =+ mmαβ βα ( ) ( ) ( ) ff d fd d fd ff d fd d fd f d fd d d f d d d d βα θ αβ θ θβα θ θβα θ β θ θβα θ θβ θ θα θ θβ θ θα θ θ −−−++= +−++=       +      +=      +      + − 22 2 1 sin 1 2 22 2 sin 1 1cot cot sin cot cotcotcotcot 2  Laplace Differential Equation in Spherical Coordinates Analysis of Associate Lagrange Differential Equation (continue – 1) Associate Legendre Differential Equation
103 SOLO ( ) ( ) ( )ϕθ gfrR=Φ We obtain: and: ff m d fd d fd λ θθ θ θ −=−+ 2 2 2 2 sin cot We have two solutions for α and β as follows: 1.β1 = m, α1 = 1-m 2.β2 = -m, α2 = 1+m Since m is an integer α, β are also integers. ( ) integer1 1 2 ==− =+ mmαβ βα ( ) ( ) ( ) fff d fd d fd  λ βαλβα θ αβ θ θβα θ +−=−−−++ ' sin 1 1cot 22 2 βα −=1 integer22 == mmβ Let define the two operators: ( ) ( ) ( ) θ θ θ θ cot1 cot ++= −= − + m d d M m d d M m m Laplace Differential Equation in Spherical Coordinates Analysis of Associate Lagrange Differential Equation (continue – 2) Associate Legendre Differential Equation
104 SOLO ( ) ( ) ( )ϕθ gfrR=Φ We obtain: We have two solutions for α and β as follows: 1.β1 = m, α1 = 1-m 2.β2 = -m, α2 = 1+m Since m is an integer α, β are also integers. ( ) ( ) ( ) θ θ θ θ cot1 cot ++= −= − + m d d M m d d M m m ff d d d d λθβ θ θα θ −=      +      + cotcot ( )  ( )  ( )  ( ) ( )11 11 11 11 1 mmmm fmmfMM         −−−= − − − + − αβ βα λ We have: ( )  ( )  ( )  ( ) ( )22 22 22 1 mmmm fmmfMM         +−−= − +− αβ βα λ fm (1) – the solution for α1, β1 fm (2) – the solution for α2, β2 Laplace Differential Equation in Spherical Coordinates Analysis of Associate Lagrange Differential Equation (continue – 3) Associate Legendre Differential Equation
105 SOLO ( ) ( ) ( )ϕθ gfrR=Φ We obtain: ( ) ( ) ( ) ( )[ ] ( )11 11 1 mmmm fmmfMM −−−=− − + − λ ( ) ( ) ( ) ( )[ ] ( )22 1 mmmm fmmfMM +−−=+− λ Let operate on first of those equations with ( )− −1mM ( ) ( ) ( ) ( ) [ ] ( )[ ] ( ) ( ) [ ]1 1 1 111 1 mmmmmm fMmmfMMM − − − − + − − − −−−= λ In the Second Equation replace m by m-1 ( ) ( ) ( ) ( )[ ] ( )2 1 2 111 1 −− + − − − −−−= mmmm fmmfMM λ Let operate on second of those equations with ( )+ mM 1 2 ( ) ( ) ( ) ( ) [ ] ( )[ ] ( ) ( ) [ ]22 1 mmmmmm fMmmfMMM ++−+ +−−= λ In the First Equation replace m by m+1 ( ) ( ) ( ) ( )[ ] ( )1 1 1 1 1 ++ −+ +−−= mmmm fmmfMM λ ( ) ( ) ( )21 1 mmmm fpfM =+ − ( ) ( ) ( )1 1 2 + + = mmmm fqfM Laplace Differential Equation in Spherical Coordinates pm is a constant qm is a constant mm →−1 mm →−1 Analysis of Associate Lagrange Differential Equation (continue – 4) Associate Legendre Differential Equation
106 SOLO We obtained:( ) ( ) ( )21 1 mmmm fpfM =+ − ( ) ( ) ( )1 1 2 + + = mmmm fqfM Laplace Differential Equation in Spherical Coordinates ( ) ( ) ( ) θ θ θ θ cot cot1 m d d M m d d M m m −= ++= + − where: Theorem: ( ) ( ) ( ) ( ) ( ) ( )∫∫ +− −= ππ θθθθθθθθ 00 sinsin dgMfdfMg mm where f and g are arbitrary bounded function of θ. Proof: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( )∫∫ ∫ ∫∫ + − −=      −−=       +−−=       ++= ππ π π ππ θθθθθθθ θ θ θθ θ θθ θθθθθθ θ θθθθ θθθ θ θθθθθθ 00 0 0 0 00 sinsin sin cos sin cos1sinsin cot1sinsin dgMfdgfmg d d f dgfmg d d ffg dfm d d gdfMg m m    Those are Recursive Relations in m. Analysis of Associate Lagrange Differential Equation (continue – 5) Associate Legendre Differential Equation
107 SOLO Laplace Differential Equation in Spherical Coordinates ( ) ( ) ( )( ) ( ) ( ) ( )( )∫∫ +− −= ππ θθθθθθθθ 00 sinsin dgMfdfMg mm ( ) ( ) ( ) ( ) ( ) ( ) ( )∫∫ + −+ ++ − + − −= ππ θθθθ 0 11 0 11 sinsin dfMMfdfMfM mmmmmmmm ( ) ( ) ( ) ( ) ( ) ( ) ∫ ∫∫ = =+ − + − π ππ θθ θθθθ 0 22 00 11 sin sinsin dfp dfpfpdfMfM mm mmmmmmmm Choose f := fm+1 and g := Mm (-) fm+1: ( ) ( ) ( ) ( )[ ]{ } ( )[ ] ∫ ∫∫ + +++ −+ + +−= +−−−=− π ππ θθλ θλθθθ 0 2 1 0 11 0 11 sin1 1sinsin dfmm dfmmfdfMMf m mmmmmm Assuming: we have1sinsin 0 2 1 0 2 == ∫∫ + ππ θθθθ dfdf mm ( ) ( ) λλ ≤+→+−= 11 mmmmpm Analysis of Associate Lagrange Differential Equation (continue – 6) Associate Legendre Differential Equation
108 SOLO Laplace Differential Equation in Spherical Coordinates ( ) ( ) ( )( ) ( ) ( ) ( )( )∫∫ +− −= ππ θθθθθθθθ 00 sinsin dgMfdfMg mm Choose now f := Mm (+) fm and g := fm, to obtain as before We obtained ( ) ( ) λλ ≤+→+−= 11 mmmmqm ( ) ( ) λλ ≤+→+−= 11 mmmmpm We see that m, an integer, is bounded by λ, therefore we must choose λ as ( ) 0integer1 >=+= lllλ In this case we have mMAX = l, mmin = -(l+1), or ( ) integer0,integer1 =>=≤≤+− mllml Therefore ( ) ( ) ( ) lmlmmllqp mm ≤≤+−→+−+== 111 Analysis of Associate Lagrange Differential Equation (continue – 7) Associate Legendre Differential Equation
109 SOLO Laplace Differential Equation in Spherical Coordinates We obtained ( ) ( ) ( ) lmlmmllqp mm ≤≤+−→+−+== 111 ( ) ( ) ( ) θ θ θ θ cot cot1 m d d M m d d M m m −= ++= + − ( ) ( ) ( )21 1 mmmm fpfM =+ − ( ) ( ) ( )1 1 2 + + = mmmm fqfM ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) lml mmllfm d d fmmllfm d d m mm ≤≤+−        +−+=      − +−+=      ++ + 1 11cot 11cot1 2 21 1 θ θ θ θ Substituting m = - (l+1) in the First Equation and m = l in the Second we obtain: ( ) ( )        =      − =      − − 0cot 0cot 2 1 l l fl d d fl d d θ θ θ θ ( ) ( ) ( ) ( ) ( ) ( ) θ θ θ θ sin sin sin sin 2 2 1 1 d l f fd d l f fd l l l l = = + + − − ( ) ( ) θl lll Cff sin 21 == +− If we can find a Solution for a particular m, we can use the Recursive Relations above to find the others. Analysis of Associate Lagrange Differential Equation (continue – 8) Associate Legendre Differential Equation
110 SOLO Laplace Differential Equation in Spherical Coordinates We obtained ( ) ( ) θl lll Cff sin 21 == +− Cl must be chosen to normalize fi and f-l: 1sinsin 0 122 0 2 == ∫∫ + ± ππ θθθθ dCdf l ll ( ) ( )!12 !21 212 2 + = + n n C n l ( ) ( )212 !2 !12 n n C nl + + = ( ) ( ) ( )∫∫∫∫ +−−+ −=+−=−= ππ π ππ θθθθθθθθθθθθ 0 1212 0 212 0 0 2 0 2 0 12 sinsin2cossin2cossincossinsin dndndd nnnnnn    Therefore ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )!12 !2 cos 2222 !2 11212 !2 sin 31212 2222 sin 12 2 sin 212 2 0 1 00 12 0 12 + = −⋅ ⋅ −⋅+ = −⋅+ −⋅ = + = + −+ ∫∫∫ n n nn n nn n d nn nn d n n d nnn nn       π πππ θθθθθθθ Analysis of Associate Lagrange Differential Equation (continue – 9) Associate Legendre Differential Equation
111 SOLO Laplace Differential Equation in Spherical Coordinates The Normalized Solution for m = l is defined as ( ) ( ) θl n lm l lm l n n sin !2 !12 212 + −== + =Θ=Θ The Solutions for m < l can be found using the Recursive Relation: ( ) ( ) ( ) ( )1,,,0,,1,cot 11 11 1 1 1 +−−−=Θ      + −−+ =Θ=Θ − − − − llllmm d d mmll M p m l m lm m m l θ θ ( ) ( ) ( )21 1 mmmm fpfM =+ − From which the Normalized Solutions for m < l are given by Or we can find the Solutions for m >- l by using the Recursive Relation: ( ) ( ) ( )1 1 2 + + = mmmm fqfM ( ) ( ) ( ) llllmm d d mmll M q m l m lm m m l ,1,,0,,,1cot 11 111 −−−−=Θ      − +−+ =Θ=Θ ++ θ θ Analysis of Associate Lagrange Differential Equation (continue – 10) Associate Legendre Differential Equation
112 SOLO Laplace Differential Equation in Spherical Coordinates ( ) ( ) θl n lm l lm l n n sin !2 !12 212 + −== + =Θ=Θ ( ) ( ) ( ) ( )1,,,0,,1,cot 11 11 1 1 1 +−−−=Θ      + −−+ =Θ=Θ − − − − llllmm d d mmll M p m l m lm m m l θ θ Examples: ( ) ( ) ( ) llllmm d d mmll M q m l m lm m m l ,1,,0,,,1cot 11 111 −−−−=Θ      − +−+ =Θ=Θ ++ θ θ Analysis of Associate Lagrange Differential Equation (continue – 11) 2 cos 1 1 cos 0 1 2 cos 1 1 0 0 1 2 3 sin 2 3 2 3 cos 2 3 1 2 3 sin 2 3 1 2 1 0 x x xl l x x x −−=−=Θ ==Θ −==Θ= =Θ= = − = = θ θ θ θ θ θ ( ) ( ) ( ) ( )2 cos 22 2 2 cos 1 2 2 cos 20 2 2 cos 1 2 2 cos 22 2 1 4 15 sin 4 15 1 2 15 cossin 2 15 13 22 5 1cos3 22 5 1 2 15 cossin 2 15 1 4 15 sin 4 15 2 x xx x xx xl x x x x x −−=−=Θ −−=−=Θ −=−=Θ −==Θ −==Θ= = − = − = = = θ θ θ θ θ θ θθ θ θθ θ Return to Table of Content Associate Legendre Differential Equation
SOLO 113 Associated Legendre Functions Let Differentiate this equation m times with respect to t, and use Leibnitz Rule of Product Differentiation: ( ) ( )[ ] ( ) ( ) ( ) im im i im i m m td tgd td tsd imi m tgts td d − − = ∑ − =⋅ 0 !! ! Start with: ( ) ( ) ( ) ( ) 1011 2 ≤=++      − ttwnntw td d t td d nn or: ( ) ( ) ( ) ( ) ( ) 10121 2 2 2 ≤=++−− ttwnntw td d ttw td d t nnn ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )twmmtwtmtwttw td d t td d m n m n m nnm m 1211 122 2 2 2 −−−−=      − ++ ( ) ( ) ( ) ( ) ( )twmtwttw td d t td d m n m nnm m +=      +1 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )twnntwmtwttwmmtwtmtwt m n m n m n m n m n m n 122121 1122 ++−−−−−− +++ ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ] ( ) ( ) 011121 122 =+−+++−−= ++ twmmnntwtmtwt m n m n m n 2nd Way
SOLO 114 Associated Legendre Functions ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ] ( ) ( ) 011121 122 =+−+++−− ++ twmmnntwtmtwt m n m n m n Define: ( ) ( ) ( )twty m n=: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ] ( ) 011121 122 =+−+++−− tymmnntytmtyt Now define: ( ) ( ) ( )tyttu m 22 1: −= Let compute: ( ) ( ) ( )1221 22 11 ytyttm td ud mm −+−−= − ( ) ( ) ( ) ( )11 22222 111 ytyttm td ud t mm + −+−−=− ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )21 221221221 2222222 1121111 ytyttmyttmyttmytm td ud t td d mmmmm +− −+−+−−−−+−−=      − ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ]{ } ( ) ( ) y t tm mnnmmtymmnnytmytt mm       − +−+−+−++−+++−−−= 2 22 222 0 12222 1 11111211    We get: ( ) ( ) 0 1 11 2 2 2 =      − −++      − u t m nn td ud t td d 2nd Way
SOLO 115 Associated Legendre Functions Define: ( ) ( ) ( )tw td d ttu nm mm 22 1: −= We get: ( ) ( ) 0 1 11 2 2 2 =      − −++      − u t m nn td ud t td d Start with Legendre Differential Equation: ( ) ( ) ( ) ( ) 1011 2 ≤=++      − ttwnntw td d t td d nn Summarize But this is the Differential Equation of f (θ) obtained by solving Laplace’s Equation by Separation of Variables in Spherical Coordinates . 02 =Φ∇ ( ) ( ) ( ) ( )φθφθ ΦΘ=Φ rRr ,, The Solutions of this Differential Equation are called Associated Legendre Functions, because they are derived from the Legendre Polynomials, and Legendre Functions of the Second Kind Qn (x) and are denoted: ( ) ( ) ( )tP td d ttP nm mm m n 22 1: −= 2nd Way ( ) ( ) ( )tQ td d ttQ nm mm m n 22 1: −=
SOLO 116 Associated Legendre Functions Let use Rodrigues Formula for Pn (t): We see that we can define the Associated Legendre Function even for negative m (In the Differential equation m2 appears): ( ) ( ) ( )tP td d ttP nm mm m n 22 1: −= ( ) ( )[ ]n n n nn t td d n tP 1 !2 1 2 −= we obtain: Associated Legendre Functions ( ) ( ) ( )[ ]n mn mnm n m n t td d t n tP 11 !2 1 : 222 −−= + + From this equation we obtain: ( ) ( )tPtP nn = 0 2nd Way
Legendre Functions Explained
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Legendre Functions Explained

  • 1. Legendre Functions SOLO HERMELIN Updated: 20.02.13 1 http://www.solohermelin.com
  • 2. Table of Content SOLO 2 Legendre Functions Introduction Legendre Polynomials History Second Order Linear Ordinary Differential Equation (ODE) Laplace’s Homogeneous Differential Equation Legendre Polynomials The Generating Function of Legendre Polynomials Rodrigues' Formula Series Solutions – Frobenius’ Method Recursive Relations for Legendre Polynomial Computation Orthogonality of Legendre Polynomials Expansion of Functions, Legendre Series Schlaefli Integral Laplace’s Integral Representation Neumann Integral
  • 3. Table of Content (continue) SOLO 3 Legendre Functions Associate Lagrange Differential Equation Laplace Differential Equation in Spherical Coordinates Analysis of Associate Lagrange Differential Equation Associate Lagrange Differential Equation (2nd Way) Generating Function for Pn m (t) Recurrence Relations for Pn m (t) Orthogonality of Associated Legendre Functions Recurrence Relations for Θn m Functions Spherical Harmonics References Boundary Value Problems and Sturm–Liouville Theory
  • 4. SOLO 4 Legendre Polynomials Adrien-Marie Legendre (1752 –1833( In mathematics, Legendre functions are solutions to Legendre's differential equation: ( ) ( ) ( ) ( ) 011 2 =++      − xPnnxP xd d x xd d nn They are named after Adrien-Marie Legendre. This ordinary differential equation is frequently encountered in physics and other technical fields. In particular, it occurs when solving Laplace's equation (and related partial differential equations) in spherical coordinates. The Legendre polynomials were first introduced in 1785 by Adrien-Marie Legendre, in “Recherches sur l’attraction des sphéroides homogènes”, as the coefficients in the expansion of the Newtonian potential ( )∑ ∞ =       =       −      + = −+ = − 0 222 cos '1 cos ' 2 ' 1 11 cos'2' 1 ' 1 n n n P r r r r r r rrrrrrrr γ γ γ  Return to Table of Content
  • 5. Second Order Linear Ordinary Differential Equation (ODE) Consider a Second Order Linear Ordinary Differential Equation (ODE) define by the Operator SOLO ( ) ( ) ( ) ( ) ( )xuxp xd ud xp xd ud xpxu 212 2 0: ++=L defined in the interval a ≤ x ≤ b, with the coefficients p0 (x), p1 (x), p2 (x) real in this region and with the first 2 – i derivatives of pi (x) continuous . Also we require that p0 (x) is nonzero in the interval. Define the Quadratic Form of the Operator L as: ( ) ( ) ( ) dxuup xd ud p xd ud pdxxuxuxu b a b a ∫∫       ++== 212 2 0: LLu, ( ) ( ) ( ) ( ) ( ) ( ) ( )∫ ∫∫ ∫ ∫∫ ∫∫∫ +−++      −      = +−+−      = ++ b a b a b a b a b a b a b a b a b a b a b a b a b a b a xdupuxdup xd d uupudxup xd d uup xd d u xd ud up xdupuxdup xd d uupudx xd ud up xd d xd ud up xdupxdu xd ud pxdu xd ud p 21102 2 00 21100 2 212 2 0 5
  • 6. SOLO ( ) ( ) ( ) dxuup xd ud p xd ud pdxxuxuxu b a b a ∫∫       ++== 212 2 0: LLu, ( ) ( ) ( ) ( ) b a b a b a b a b a xu xd pd pxu upu xd ud upu xd pd u xd ud upupuup xd d u xd ud up             −=       +−−=+      −      0 1 10 0 0100 Therefore: ( ) ( ) ( ) ( )∫       +−+            −= b a b a dxupup xd d up xd d uxu xd pd pxu 2102 2 0 1 Define the Adjoint Operator: ( ) ( ) ( ) upup xd d up xd d xu 2102 2 : +−=L 6 Second Order Linear Ordinary Differential Equation (ODE)
  • 7. SOLO ( ) dx u up xd ud p xd ud puxu b a ∫       ++=    L Lu, 212 2 0 The two Integrals are equal if: ( ) ( ) ( ) ( )∫       +−+            −= b a b a dxupup xd d up xd d uxu xd pd pxu    uL 2102 2 0 1 or: ( ) ( ) ( ) ( ) ( ) ( )xuxq xd xud xp xd d xuxu +      == LL ( ) ( ) 02 1 01 2 0 2 2102 2 212 2 0 =      −+      −=       +−−      ++ xd ud p xd pd uu xd pd xd pd u upup xd d up xd d uup xd ud p xd ud pu ( ) ( ) xd xpd xp 0 1 = If this condition is satisfied, then the terms at the boundary x = a and x = b also vanish, and we have by defining p (x): = p0 (x) and q (x) := p2 (x) 7 Second Order Linear Ordinary Differential Equation (ODE)
  • 8. SOLO ( ) ( ) ( ) ( ) ( ) ( )xuxq xd xud xp xd d xuxu +      == LL This Operator is called Self-Adjoint ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )      ++      =      ∫∫ xuxp xd ud xp xd ud xptd tp tp xp xutd tp tp xp xx 212 2 0 0 1 00 1 0 expexp 1 L 1 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )xutd tp tp xp xp xd ud td tp tp xd d xq x xp x            +                   = ∫∫ 0 1 0 2 0 1 expexp This is clearly Self-Adjoint. We can see that p0 (x) is in the denominator. This is the reason that we requested the p0 (x) to be nonzero in the interval a ≤ x ≤ b. p0 (x1) = 0 means that the Differential Equation is not Second Order at that point. We can always transform the Non-Self-Adjoint Operator to a Self-Adjoint one by multipling L by ( ) ( ) ( )       ∫x td tp tp xp 0 1 0 exp 1 8 Second Order Linear Ordinary Differential Equation (ODE)
  • 9. Consider a Second Order Linear Ordinary Differential Equation (ODE) SOLO ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 2 210 :'':'0''': xd ud u xd ud uxuxpxuxpxuxpxu ===++=L If we know one Solution u1 (x) we can find a second u2 (x). Proof If we have two Solutions u1 (x) and u2 (x), then 0''' 0''' 222120 121110 =++ =++ upupup upupup Multiply first equation by u2 (x) and second by u1 (x) and subtract: ( ) ( ) 0'''''' 1221112210 =−+− uuuupuuuup The Wronskian W is defined as: 1221 21 21 '' '' : uuuu uu uu W −== 0' 10 =+ WpWp 9 Theorem: “Method of Reduction of Order” Second Order Linear Ordinary Differential Equation (ODE)
  • 10. Consider a Second Order Linear Ordinary Differential Equation (ODE) SOLO ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 2 210 :'':'0''': xd ud u xd ud uxuxpxuxpxuxpxu ===++=L Theorem: “Method of Reduction of Order” If we know one Solution u1 (x) we can find a second u2 (x). Proof (continue -1) 0' 10 =+ WpWp xd p p W Wd 0 1 −= ( ) ( ) ( ) ( )         −= ∫ x x d p p xWxW 0 0 1 0 exp τ τ τ From: ( ) ( ) ( ) ( ) ( )xuxuxuxuxW 1221 '' −= q.e.d. Therefore: ( ) ( ) ( ) ( )∫= x x d u W xuxu 0 2 1 12 τ τ τ ( ) ( ) ( ) ( ) ( ) ( ) ( )       =−= 1 2 22 1 1 1 2 2 1 '' u u xd d xu xu xu xu xu xu xW Divide by u1 2 (x) x0 and W (x0) are given (or not). 10 Second Order Linear Ordinary Differential Equation (ODE)
  • 11. If the Second Order Linear Ordinary Differential Equation (ODE) is in the Self-Adjoint Mode: SOLO Then: The Wronskian is given by ( ) ( ) ( ) ( ) ( ) ( ) 0=+      == xuxq xd xud xp xd d xuxu LL ( ) ( ) ( ) ( ) ( ) ( ) 0 1 0 2 2 =++ xuxq xd xud xd xpd xd xud xp p p  ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )xp xp xW p pd xWd p p xWxW x x x x 0 00 0 0 0 0 0 1 0 00 expexp =         −=         −= ∫∫ τ τ τ 11 Return to Table of Content Second Order Linear Ordinary Differential Equation (ODE)
  • 12. 12 SOLO The Laplace’s Homogeneous Differential Equation is: We want to find the Potential Φ at the point F (field) due to all the sources (S) in the volume V, including its boundaries . n i iSS 1= = iS nS  n i iSS 1= =dV dSn → 1 V Fr  Sr  F 0r SF rrr  −= iS nS dV dSn → 1 V Fr  Sr  F 0r SF rrr  −= F inside V F on the boundary of V Therefore is the vector from S to F.SF rrr  −= →→→ ++= zzyyxxr 111  →→→ ++= zzyyxxr SSSS 111  →→→ ++= zzyyxxr FFFF 111  Let define the operator that acts only on the source coordinate. →→→ ∂ ∂ + ∂ ∂ + ∂ ∂ =∇ z z y y x x SSS S 111 Sr  Laplace’s Homogeneous Differential Equation ( ) 02 =Φ∇ r Pierre-Simon, marquis de Laplace (1749 1827)
  • 13. 13 SOLO Laplace’s Homogeneous Differential Equation Laplace Differential Equation in Spherical Coordinates ( ) 02 =Φ∇ r Spherical Coordinates: θ ϕθ ϕθ cos sinsin cossin rz ry rx = = = A Solution in Spherical Coordinates is: ( ) 0 1 ≠=Φ r r r ( ) 0 111 22 ≠−=∇−=∇=Φ∇ r r r r r rr r  ( ) ( ) 00 33111 35333 2 ≠=−⋅=⋅∇−⋅      −∇=      ⋅−∇=Φ∇⋅∇=Φ∇ r r rr r r r r r r r rr  r r r z r y r x zyx zyx r zyxzyx  =++=++      ∂ ∂ + ∂ ∂ + ∂ ∂ =∇ 111111 222 ( ) 3111111 =++⋅      ∂ ∂ + ∂ ∂ + ∂ ∂ =⋅∇ zyx zyx r zyxzyx  2222 zyxr ++=
  • 14. 14 SOLO Laplace’s Homogeneous Differential Equation Laplace Differential Equation in Spherical Coordinates Spherical Coordinates: θ ϕθ ϕθ cos sinsin cossin rz ry rx = = = θcos= ∂ ∂ z r 2222 zyxr ++= 0 cos11 22 ≠−= ∂ ∂ −=      ∂ ∂ = ∂ Φ∂ r rz r rrzz θ 0 1cos3331 3 2 5 22 4332 2 ≠ − = − = ∂ ∂ +−=      − ∂ ∂ = ∂ Φ∂ r rr rz z r r z rr z zz θ 0 cos9cos159153 5 26 3 4 23 7 23 6 22 55 22 3 3 ≠ − = − −= ∂ ∂− − ∂ ∂ − =      − ∂ ∂ = ∂ Φ∂ r r r r rzz z r r rz r z r rz r rz zz θθ We note that ∂n Φ/∂zn is a n-degree polynomial in cos θ divided by rn+1 . ( ) ( ) ( ) ( ) ( ) ( )zyx zn hzyx z hzyx z hzyxhzyx n nn n ,, ! 1 ,, !2 1 ,,,,,, 2 2 2 ∂ Φ∂− ++ ∂ Φ∂ + ∂ Φ∂ −Φ=−Φ  Using Taylor’s Series development we obtain
  • 15. 15 SOLO Laplace’s Homogeneous Differential Equation Laplace Differential Equation in Spherical Coordinates Spherical Coordinates: θ ϕθ ϕθ cos sinsin cossin rz ry rx = = = 2222 zyxr ++= ( ) ( ) ( )       ∂ ∂− ++      ∂ ∂ +      ∂ ∂ −= −++ =−Φ rzn h rz h rz h rhzyx hzyx n nn n 1 ! 11 !2 1111 ,, 2 2 2 222  ( ) ∑ ∞ =       ∂ ∂− = +− 0 22 1 ! 1 cos2 1 n n nn n rzn h hhrr θ or: Let define: ( ) ( )       ∂ ∂− = + rzn rP n nn n n 1 ! 1 :cos 1 θ ( ) rhP r h rhhrr n n n ≤      = +− ∑ ∞ =0 22 cos 1 cos2 1 θ θ Therefore:
  • 16. 16 SOLO Laplace’s Homogeneous Differential Equation Laplace Differential Equation in Spherical Coordinates Spherical Coordinates: θ ϕθ ϕθ cos sinsin cossin rz ry rx = = = 2222 zyxr ++= Let define w:=Pn (cos θ) and substitute w/rn+1 in the Laplace Equations in Spherical Coordinates instead of Φ Therefore, since w:=Pn (cos θ) (Partial Derivative becomes Total Derivative): 0 sin 1 sin sin 11 0 12 2 22121 2 2 =      ∂ ∂ +            ∂ ∂ ∂ ∂ +            ∂ ∂ ∂ ∂ +++  nnn r w rr w rr w r r rr φθθ θ θθ 0sin sin 111 1 =      ∂ ∂ ∂ ∂ +    + − ∂ ∂ + θ θ θθ w rr n r w nn or: ( ) 0sin sin 1 1 =      ++ θ θ θθ d wd d d wnn Substitute t=cos θ (dt = - sinθ dθ):  ( ) ( )       −=         −−=           =      −− td wd t td d td wd t td d d td td wd d td d d d wd d d 2 sin 2 1sin 11 sin 1 sin sin 1 sin sin 1 2   θ θ θθθ θ θθθ θ θθ Finally we obtain: ( ) ( ) 1011 2 ≤=++      − twnn td wd t td d Return to Table of Content
  • 17. 17 SOLO This is the Legendre Differential Equation and Pn (t) the Legendre Polynomials are one of the two solutions of the ODE. ( ) ( ) ( ) ( ) 1011 2 ≤=++      − ttPnntP td d t td d nn ( )∑ ∞ =       =       +− 0 2 cos cos21 1 n n n P r h r h r h θ θ We found ( ) 1cos cos21 1 0 2 ≤= +− ∑ ∞ = uPu uu n n n θ θFor u:=h/r The left-hand side is called “The Generating Function of Legendre Polynomials” Legendre Polynomials The Generating Function of Legendre Polynomials
  • 18. 18 SOLO Let use Taylor expansion for the function: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )  +++++= n n x n f x f x f fxf ! 0 !2 0 1 0 0 2 21 ( ) ( ) 1, 21 1 0 2 ≤= −+ ∑ ∞ = tutPu tuu n n n ( ) ( ) ( ) 101 2 1 =−= − fxxf ( ) ( ) ( ) ( ) ( ) 2 1 01 2 1 1 2 3 1 =−= − fxxf ( ) ( ) ( ) ( ) ( ) 2 3 2 1 01 2 3 2 1 2 2 5 2 ⋅=−⋅= − fxxf ( ) ( ) ( ) ( ) ( ) ( ) ( ) !2 !2 !2 !2 2 1231 2 12 2 3 2 1 01 2 12 2 3 2 1 2 2 12 n n n nnn fx n xf nn n n n n n =⋅ −⋅ = − ⋅=− − ⋅= + −   Tacking x = 2 u t - u2 we obtain ( ) ( ) ( ) ( ) 12 !2 !2 21 1 0 2 222 ≤−= −− ∑ ∞ = uutu n n utu n n n Let prove that Pn (t) are indeed Polynomials. Legendre Polynomials The Generating Function of Legendre Polynomials
  • 19. 19 SOLO Using Taylor expansion we obtained: ( ) ( ) 1, 21 1 0 2 ≤= −+ ∑ ∞ = tutPu tuu n n n Take the binomial expansion of (2 u t - u2 )n we obtain ( ) ( ) ( ) ( ) 12 !2 !2 21 1 0 2 222 ≤−= −− ∑ ∞ = uutu n n utu n n n ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 12 !!!2 !2 12 !! ! 1 !2 !2 21 1 0 0 2 0 0 222 ≤ − −= − −= −− ∑∑∑ ∑ ∞ = = +− ∞ = = − uut knkn n ut knk n n n utu n n k knkn n k n n k kknk n Change Variables in the second sum from n+k to n ( ) ( ) ( ) ( ) ( ) ( ) [ ] ( )   − =      ≤ −− − −= −− ∑ ∑ ∞ = = − − evennifn oddnifnn uut knknk kn utu n n k nkn kn k 2/1 2/ 2 12 !2!!2 !22 1 21 1 0 2/ 0 2 222 Equating in the two power series the un coefficients, we obtain ( ) ( ) ( ) ( ) ( ) [ ] ∑= − ≤ −− − −= 2/ 0 2 1 !2!!2 !22 1 n k kn n k n tt knknk kn tP Polynomial of order n in t Return to Rodrtgues Formula Return to Frobenius Series We can see that for n odd the polynomial Pn (t) has only odd powers of t and for n even only even powers of t. Legendre Polynomials The Generating Function of Legendre Polynomials
  • 20. 20 SOLO Let use Taylor expansion for the function: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )  +++++= n n x n f x f x f fxf ! 0 !2 0 1 0 0 2 21 ( ) ( ) 1, 21 1 0 2 ≤= −+ ∑ ∞ = tutPu tuu n n n Tacking x = u2 -2 u t we obtain ( ) ( ) ( ) 101 2 1 =+= − fxxf ( ) ( ) ( ) ( ) ( ) 2 1 01 2 1 1 2 3 1 −=+−= − fxxf ( ) ( ) ( ) ( ) ( ) 2 3 2 1 01 2 3 2 1 2 2 5 2 ⋅=+⋅= − fxxf ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 12 2 3 2 1 101 2 12 2 3 2 1 1 2 12 − ⋅−=+ − ⋅−= + − n fx n xf nn n nn  ( ) ( ) ( ) ( ) ( ) ( )∑ ∞ = =      +− +      − +      − ++= −+−−−+−−= −+ 0 24 4 3 3 2 20 4232222 2 8 33035 2 35 2 13 1 2 128 35 2 16 5 2 8 3 2 1 1 21 1 n n n tPu tt u tt u t utuu tuutuutuutuu ttuu   Legendre Polynomials The Generating Function of Legendre Polynomials
  • 21. SOLO 21 Legendre Polynomials The first few Legendre polynomials are: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 256/63346530030900901093954618910 128/31546201801825740121559 128/35126069301201264358 16/353156934297 16/51053152316 8/1570635 8/330354 2/353 2/132 1 10 246810 3579 2468 357 246 35 24 3 2 −+++− +−+− +−+− −+− −+− +− +− − − xxxxx xxxxx xxxx xxxx xxx xxx xx xx x x xPn n
  • 22. 22 SOLO ( ) 1, 21 1 0 2 ≤= +− ∑ ∞ = tutPu utu n n n Substitute u by – u in this equation: ( ) ( ) ( ) 11 21 1 00 2 ≤−=−= ++ ∑∑ ∞ = ∞ = utPutPu utu n n n n n nn which results in the following identity: ( ) ( ) ( )tPtP n n n 1−=− For t =1 we have ( ) 11 1 1 21 1 0 2 ≤= − = +− ∑ ∞ = uPu uuu n n n But 1 1 1 0 ≤= − ∑ ∞ = uu u n n By equalizing the coefficients of un in the two sums, we obtain: ( ) nPn ∀=11 and ( ) ( ) ( ) ( )n n n n PP 1111 −=−=− Legendre Polynomials The Generating Function of Legendre Polynomials
  • 23. 23 SOLO ( ) 1, 21 1 0 2 ≤= +− ∑ ∞ = tutPu utu n n n For t = 0 we obtain: Legendre Polynomials ( ) 10 1 1 0 2 ≤= + ∑ ∞ = uPu u n n n ( ) ( ) ( ) ( ) ( ) ( ) ( ){ } ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∑∑∑ ∞ = ∞ = ∞ = − −= ⋅−⋅⋅−⋅⋅ −= −⋅⋅ −= + −−−− ++ −− +      −+=+= + 0 22 2 0 1 2 0 2 22222/12 2 !2 !2 1 !2 222642 !2 12531 1 !2 12531 1 ! 2/123/12/1 !2 3/12/1 2 1 11 1 1 n n n n n nn n n n n n n n n un n nn n un n un t n n ttu u        Therefore we have: ( ) ( ) ( ) ( ) 10 !2 !2 1 1 1 00 22 2 2 ≤=−= + ∑∑ ∞ = ∞ = uPu n un u n n n n n n n By equating coefficients of un on both sides we obtain: ( ) ( ) ( ) ( ) ( ) 00 !2 !2 10 12 222 = −= +n n n n P n n P Return to Table of Content The Generating Function of Legendre Polynomials
  • 24. Derivation of Legendre Polynomials via Rodrigues’ Formula SOLO 24 Legendre Polynomials Benjamin Olinde Rodrigues (1794-1851) In mathematics, Rodrigues' Formula (formerly called the Ivory– Jacobi formula) is a formula for Legendre polynomials independently introduced by Olinde Rodrigues (1816), Sir James Ivory (1824) and Carl Gustav Jacobi (1827). The name "Rodrigues’ formula" was introduced by Heine in 1878, after Hermite pointed out in 1865 that Rodrigues was the first to discover it, and is also used for generalizations to other orthogonal polynomials. Askey (2005) describes the history of the Rodrigues’ Formula in detail. Rodrigues stated his formula for Legendre polynomials Pn Carl Gustav Jacob Jacobi (1804 –1851) ( ) ( )[ ]n n n nn x xd d n xP 1 !2 1 2 −=
  • 25. SOLO 25 Legendre Polynomials Olinde Rodrigues (1794-1851) Start from the function: ( ) .12 constkxky n =−= ( ) 12 12:' − −== n xxkn xd yd y ( ) ( ) ( ) 22212 2 2 11412:'' −− −−+−== nn xxnknxkn xd yd y Let compute: ( ) ( ) ( ) ( ) ( ) '12211412''1 12222 yxnynxxnknxknyx nn −+=−−+−=− − or: ( ) ( ) 02'12''12 =−−+− ynyxnyx Let differentiate the last equation n times with respect to x: ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) ''1''2''1 00''1 3 ''1 2 ''1 1 ''1''1 2 2 1 1 2 3 3 0 2 3 3 2 2 2 2 2 1 1 222 y xd d nny xd d xny xd d x y xd d x xd dn y xd d x xd dn y xd d x xd dn y xd d xyx xd d n n n n n n n n n n n n n n n n − − − − − − − − − − −++−= +−      +−      +−      +−=−   ( ) ( ) ( ) ( )       +−=            +−=− − − − − ''12' 1 '12'12 1 1 1 1 y xd d ny xd d xny xd d x xd dn y xd d xnyx xd d n n n n n n n n n n n Derivation of Legendre Polynomials via Rodrigues’ Formula
  • 26. SOLO 26 Legendre Polynomials Olinde Rodrigues (1794-1851) Start from the function: ( ) .12 constkxky n =−= ( ) ( ) 02'12''12 =−−+− ynyxnyxDifferentiate n times with respect to x: ( ) ( ) ''1''2''1 2 2 1 1 2 y xd d nny xd d xny xd d x n n n n n n − − − − −++− ( ) 02''12 1 1 =−      +−+ − − y xd d ny xd d ny xd d xn n n n n n n Define: a Polynomial( ) ( )[ ]n n n n n x xd d k xd yd xw 1: 2 −== ( ) ( ) ( )[ ] 02'121'2''12 =−+−+−++− wnwnwxnwnnwxnwx ( ) ( ) ( ) ( )[ ] 02121'2''12 =−−+−+−++− wnnnnnwxnxxnwx ( ) ( ) 01'2''12 =+−+− wnnwxwx This is Legendre’s Differential Equation. We proved that one of the solutions are Polynomials. We can rewrite this equation in a Sturm-Liouville Form: ( ) ( ) 0112 =+−      − wnnw xd d x xd d Derivation of Legendre Polynomials via Rodrigues’ Formula
  • 27. SOLO 27 Legendre Polynomials Olinde Rodrigues (1794-1851) Let find k such that: by using the fact that Pn (1) = 1 ( ) ( )[ ]n n n n n n x xd d k xd yd xP 12 −== ( ) ( )[ ] ( ) ( ) ( ) ( )       −+=         +−=−= ∑>0 22 1!2111 i inn v n u n n n n n n n xxaxnkxx xd d kxk xd d xP  !2 1 n k n = We recover the Rodrigues Formula: ( ) ( )[ ]n n n nn x xd d n xP 1 !2 1 2 −= Let use Leibnitz’s Rule (Binomial Expansion for the n Derivative of a Product - with u:=(x-1)n and v:=(x+1)n ): ( ) ( ) ( ) udvudvdnvddu nn vddunvdu vdud mnm n vud nnnnn n m mnmn +++ − ++= − =⋅ −−− = − ∑ 1221 0 !2 1 !! !  We have: ( )   ( )    1!2 !2 1 1 1!20 12 0 21 00 ==        +++ − ++== = −−− nkudvudvdnvddu nn vddunvdukxP n xn nnnnn n n  We can see from this Formula that Pn (x) is indeed a Polynomial of Order n in t. Derivation of Legendre Polynomials via Rodrigues’ Formula
  • 28. SOLO 28 Legendre Polynomials Olinde Rodrigues (1794-1851) Let find an explicit expression for Pn (x) from Rodrigues’ Formula: ( ) ( )[ ]n n n nn n n x xd d nxd yd xP 1 !2 1 2 −== Start with: ( ) ( ) ( )∑= − − − =− n m mnmn x mnm n x 0 22 1 !! ! 1 ( ) ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )   + = −− − −= −− −= +−− − −=−= ∑ ∑ ∑ = − −= ≥ −− ≥ −− oddnn evennn p x knknk kn x nm m mnm xnmmm mnm n n x xd d n xP p k knk n knm n pm nmmn n n pm nmmn n n n n nn 2/12 2/ !2!! !22 1 2 1 !2 !2 !! 1 1 2 1 12122 !! ! 1 !2 1 1 !2 1 0 2 2 22  ( ) ( )    < ≥+−− = 2/0 2/121222 nm nmnmmm x xd d m n n  We recover the result obtained by the Generating Function of Legendre Polynomials Return to Frobenius Series Return to Table of Content Derivation of Legendre Polynomials via Rodrigues’ Formula
  • 29. SOLO Series Solutions – Frobenius’ Method Ferdinand Georg Frobenius (1849 –1917) ( ) ( ) .0121 2 2 22 constrealryrr xd yd yx xd yd x =++−− Example: General Legendre Equation ∑ ∞ = + = 0λ λ λ k xay Let check the Frobenius’s expansion: We have: ( ) ( ) ( )∑∑ ∞ = −+ ∞ = −+ −++=+= 0 2 2 2 0 1 1& λ λ λ λ λ λ λλλ kk xkka xd yd xka xd yd Substitute in the General Legendre Equation: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ] 0111 121 00 2 000 2 =+++−++−++= +++−−−++ ∑∑ ∑∑∑ ∞ = + ∞ = −+ ∞ = + ∞ = + ∞ = +−+ λ λ λ λ λ λ λ λ λ λ λ λ λ λλ λ λλλλ λλλ kk kkkk xkkrraxkka xrraxkaxxkka 29 Legendre Polynomials
  • 30. SOLO Example: Legendre Equation (continue – 1) ( ) ( ) ( ) ( ) ( )[ ] 0111 00 2 =+++−++−++ ∑∑ ∞ = + ∞ = −+ λ λ λ λ λ λ λλλλ kk xkkrraxkka Denote, in the first sum λ = j +2 and in the second sum λ = j, to obtain: ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ]{ } 01112 11 0 2 1 1 2 0 =+++−+++++++ ++− ∑ ∞ = + + −− j jk jj kk xjkjkrrajkjka xkkaxkka All the coefficients of xk+j must be zero, therefore ( ) 001 00 ≠=− akka ( ) 011 =+kka ( ) ( ) ( ) ( ) ( )[ ] 011122 =+++−+++++++ jkjkrrajkjka jj 30 Ferdinand Georg Frobenius 1849 - 1917 Series Solutions – Frobenius’ Method Legendre Polynomials
  • 31. SOLO Example: Legendre Equation (continue – 2) ( ) ( ) ( ) ( ) ( ) ( )[ ] ( ) ( ) ( ) ,2,1,0 12 1 12 11 2 = ++++ ++++− −= ++++ +++−+ −=+ j jkjk jkrjkr a jkjk jkjkrr aa jjj ( ) 01 =−kk ( ) 011 =+kka ( ) ( ) ( ) ( ) ( )[ ] 011122 =+++−+++++++ jkjkrrajkjka jj 0&1.3 0&0.2 0&0.1 1 1 1 == ≠= == ak ak akThree possible solutions The equation that, k (k+1) = 0, comes from the coefficient of the lowest power of x, and is called Indicial Equation. It has two solutions for k k = 0 and k = 1 The equation gives the recursive relation 31 Series Solutions – Frobenius’ Method Legendre Polynomials
  • 32. SOLO Example: Legendre Equation (continue – 3) ( ) 1001: ==⇒=− korkkkEquationIndicial 1. Using k = 0 and a1 = 0 we obtain a series of even powers of x ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ,2,1,0 21 1 21 11 2 = ++ ++− −= ++ +−+ −=+ j jj jrjr a jj jjrr aa jjj ( ) ( ) ( ) ( ) ( ) ( )       + ++− + + −== 42 0 !4 312 !2 1 1: x rrrr x rr axpxy reven ( ) 01231 ==== +naaa  The recurrence relation results in the following expression for the coefficients ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )   ,3,2,1 !2 123124222 1 02 = −+++⋅−+−+− −= ma m mrrrrrmrmr a m m 32 ( ) ( ) ( ) ( ) ( ) ( )[ ] ( ) ( ) ( ) ,2,1,0 12 1 12 11 2 = ++++ ++++− −= ++++ +++−+ −=+ j jkjk jkrjkr a jkjk jkjkrr aa jjj ( ) ∑ ∞ = = 0 2 2m m meven xaxy Series Solutions – Frobenius’ Method Legendre Polynomials
  • 33. SOLO Example: Legendre Equation (continue – 4) ( ) 1001: ==⇒=− korkkkEquationIndicial 3. Using k = 1 and a1 = 0 we obtain a series of odd powers of x ( ) ( )( ) ( ) ( ) ( )( ) ( ) ( ) .2,1,0 32 21 32 211 2 = ++ ++−− −= ++ ++−+ −=+ j jj jrjr a jj jjrr aa jjj ( ) ( ) ( )( ) ( ) ( )( ) ( )       + ++−− + +− −== 53 0 !4 4213 !3 21 : x rrrr x rr xaxqxy rodd ( ) 01231 ==== +naaa  The recurrence relation results in the following expression for the coefficients ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )   ,3,2,1 !12 24213212 1 02 = + +++−+−+− −= ma m mrrrrmrmr a m m 33Since pr (x) and qr (x) are two linearly independent solutions of the 2nd Order Linear Lagrange ODE, the final solution is y = c1 pn (x) + c2 qn (x) ( ) ( ) ( ) ( ) ( ) ( )[ ] ( ) ( ) ( ) ,2,1,0 12 1 12 11 2 = ++++ ++++− −= ++++ +++−+ −=+ j jkjk jkrjkr a jkjk jkjkrr aa jjj ( ) ∑ ∞ = + = 0 12 2m m modd xaxy Series Solutions – Frobenius’ Method Legendre Polynomials
  • 34. SOLO Example: Legendre Equation (continue – 5) Using d’Alembert – Cauchy test for convergence of an Infinite Series, we have Convergence Test: ( ) ( ) ( ) ( ) ( )     ≥≥ << = ++++ +++−+ = ∞→ + + ∞→ divergex convergex xx jkjk jkjkrr xa xa jj j j j j 11 11 12 11 limlim 22 2 2 The even series stops at j = n. The expansion is a Polynomial of order n (even). 1. If n is even, using k = 0 and a1 = 0 we obtain a series of even powers of x . ( ) ( ) ( ) ( ) ,..1,0 21 11 2 = ++ +−+ −=+ j jj jjnn aa jj For the case that r = n, a positive integer: ,...2,1,,02 ++==+ nnnjaj 3. If n is odd, using k = 1 and a1 = 0 we obtain a series of odd powers of x . ( ) ( )( ) ( ) ( ) ,..2,1 32 211 2 = ++ ++−+ −=+ j jj jjnn aa jj ,...2,1,,1,02 ++−==+ nnnnjaj The odd series stops at j = n-1. The expansion is a Polynomial of order n (odd).34 Series Solutions – Frobenius’ Method Legendre Polynomials
  • 35. SOLO Example: Legendre Equation (continue – 6) 1. If n is even, using k = 0 and a1 = 0 we obtain a series of even powers of x ( ) ( ) ( )( ) ( )       + ++− + + −= 42 0 !4 312 !2 1 1 x nnnn x nn axyeven 3. If n is odd using k = 1 and a1 = 0 we obtain a series of odd powers of x ( ) ( )( ) ( ) ( )( ) ( )       + ++−− + +− −= 53 0 !4 4231 !3 21 x nnnn x nn xaxyodd ( ) ( ) ( ) ( )( ) ( )       +−=      ++− + + −== −=      + −== == 42 0 42 0 2 0 2 0 0 6 70 101 !4 3414244 !2 144 14 31 !2 122 12 0 xxaxxayn xaxayn ayn even even even ( )( )       −=      +− −== == 3 0 3 0 0 3 5 !3 2313 3 1 xxaxxayn xayn odd odd We obtain the Legendre Polynomials Solutions for a0 = 1. 35 Series Solutions – Frobenius’ Method Legendre Polynomials
  • 36. SOLO Example: Legendre Equation (continue – 7) 1. The recurrence relation for even x powers results in the following expression for the coefficients ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2/,,3,2,1 !2 123124222 1 02 nma m mnnnnnmnmn a m m   = −+++⋅−+−+− −= ( ) ( ) ( ) ( ) ( ) ( ) ( )! ! 2121224222 11 2 mp p ppmpmpnnmnmn mm pn − =−+−+−=−+−+− −− =  ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( )( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( )!!22 !!22 212 1 !2 !22 242 242 1231 ! ! 1231 22 mpp pmp mpppp mp mnnn mnnn mnnn n n mnnn m pn m pn + + = +++ + = +++ +++ −+++=−+++ ==     ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2/,,3,2,1 !!!22 !221 !!!2!2 ! 2 !22 1 !!2!2 !!22 ! ! 2 1 1 0 0 2 2 02 nm snssn sn a snssnn n sn a mpmp pmp mp p a n sthatsucha choose s nmps m m = −− −− = −−             − −= + + − −= − − −= ( ) ( ) ( ) ( )∑= −− < −− − −= 2/ 0 2 1 !2!!2 !22 1 n s sn n s even xx snsns sn y 36 Series Solutions – Frobenius’ Method Legendre Polynomials
  • 37. SOLO Example: Legendre Equation (continue – 8) 3. The recurrence relation for odd x powers results in the following expression for the coefficients ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 1 ,,3,2,1 !12 24213212 1 02 − = + +++−+−+− −= n ma m mnnnnmnmn a m m   ( ) ( ) ( ) ( )( ) ( ) ( )! ! 222242222213212 1 12 mp p ppmpmpnmnmn m pn − =−+−+−=−+−+− − +=  ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( )!!122 !!122 212 224222 1225232 !12 !12 242 1 1 12 mpp pmp mppp mppp mppp p p mnnn m m pn ++ ++ = +++ +++ ++++ + + =+++ − − +=   ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 1 ,,3,2,1 !2!1!! ! 2 1 !122 1 !12!!!12 !!122 1 0 2 0 2 2 − = −−−             − −− −= ++−+ ++ −= − −= n ma snsnsn n sn a mmpmpp pmp a sp mps m m  37 ( ) ( ) ( ) ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) 2 1 ,...,1,0 !2!!!2 ! 2 1 !22 1 !2!12!! ! 2 1 !12222 1 0 2 0 2 − = −−             − − −= −−−−             − −−− −= − −= − −= n sa snsnsn n sn a snsnsnsn n snsn sp mps sp mps Series Solutions – Frobenius’ Method Legendre Polynomials
  • 38. Example: Legendre Equation (continue – 9) 3. The recurrence relation for odd x powers results in the following expression for the coefficients ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 1 ,...,1,0 !2!!2 !22 1 !2!! !22 ! 2 1 !2 1 1 0 0 2 2 1 2 − = −− − −= −− −             − −= −− − n s snsns sn a snsns snn n a n s thatsucha Choose s n m ( ) ( ) ( ) ( ) ( ) ( ) 1& !2!! !22 1 2 1 2/1 0 2 < −− − −= ∑ − = −− xoddnx snsns sn xy n s sns nodd We also found that the solution for k = 0 and a1 = 0 is ( ) ( ) ( ) ( ) ( ) 1& !2!!2 !22 1 2/ 0 2 < −− − −= ∑= −− xevennx snsns sn xy n s sn n s even We recover the result obtained by the Generating Function of Legendre Polynomials and by Rodrigues’ Formula 38 Therefore we can unify those two relations to obtain: ( ) ( ) ( ) ( ) ( ) [ ] 1 !2!!2 !22 1 2/ 0 2 < −− − −= ∑= −− xx snsns sn xP n s sn n s n Series Solutions – Frobenius’ Method SOLO Legendre Polynomials
  • 39. SOLO Example: Legendre Equation (continue – 10) 2. Using k = 0 and a1 ≠ 0 we obtain an infinite series and not a polynomial. This is the Second Solution of the Legendre Differential Equation. The solution is the sum of the two infinite series, one with even powers of x and the other with odd powers of x. The series solution, in this case, diverges at x = ± 1. Those are Legendre Functions of the Second Kind. The Polynomial solutions are Legendre Functions of the First Kind. 39 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ,2,1,0 21 1 21 11 2 = ++ ++− −= ++ +−+ −=+ j jj jnjn a jj jjnn aa jjj In this case we have The recurrence relation results in the following expression for the coefficients ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )   ,3,2,1 !2 123124222 1 02 = −+++⋅−+−+− −= ma m mnnnnnmnmn a m m ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )   ,3,2,1 !12 123124222 1 112 = + −+++⋅−+−+− −=+ ma m mnnnnnmnmn a m m Series Solutions – Frobenius’ Method Legendre Polynomials
  • 40. SOLO Example: Legendre Equation (continue – 11) 40 We want to find a series that converges for |x| > 1. Let return to the conditions to have a series solution for Legendre ODE For k = 0 and a0 = 0 By substituting j = m – 2 we obtain ( ) ( ) ( ) ( ) ,2,1,0 1 21 2 == ++− ++ −= + ja jnjn jj a jj ( ) ( ) ( ) mm a mnmn mm a 12 1 2 −++− − −=− ( ) ( ) .0121 2 2 22 constrealryrr xd yd yx xd yd x =++−− ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ,2,1,0 21 1 21 11 2 = ++ ++− −= ++ +−+ −=+ j jj jrjr a jj jjrr aa jjj We can make am+2, am+4, am+6,…. To vanish for m = r = n or m = -n – 1. If we start for am ≠ 0 we can obtain the following recursive formula Series Solutions – Frobenius’ Method Legendre Polynomials
  • 41. SOLO Example: Legendre Equation (continue – 12) 41 ( ) ( ) ( ) mm a mnmn mm a 12 1 2 −++− − −=− Tacking m = n we obtain ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) nnn nn a nn nnnn a n nn a a n nn a 321242 321 324 32 122 1 24 2 −⋅−⋅⋅ −−− += − −− −= − − −= −− − The first solution can be written as ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )       + +−−⋅−⋅⋅ −−−− ++ −⋅−⋅⋅ −−− + − − −= −−−     innnn n x innni ininnn x nn nnnn x n nn xaxy 242 1 1223212242 1221 321242 321 122 1 Using d’Alembert – Cauchy test for convergence of an Infinite Series, we have ( )( ) ( )     ≤≥ >< = +− −−− = −− ∞→+− +− − − ∞→ divergex convergex xx ini inin xa xa iin in in in j 11 11 1222 122 limlim 22 22 22 2 2 Series Solutions – Frobenius’ Method Legendre Polynomials
  • 42. SOLO Example: Legendre Equation (continue – 13) 42 ( ) ( ) ( ) mm a mnmn mm a 12 1 2 −++− − −=− Tacking m =- n - 1 we obtain ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) 135 13 523242 4321 524 43 322 21 −−−−−− −−−− +⋅+⋅⋅ ++++ += + ++ = + ++ += nnn nn a nn nnnn a n nn a a n nn a The second solution can be written as ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )       + +++⋅+⋅⋅ +−+++ ++ +⋅+⋅⋅ ++++ + + ++ += −−−−−−−−− −−     12531 12 1225232242 21221 523242 4321 322 21 innnn n x innni ininnn x nn nnnn x n nn xaxy Using d’Alembert – Cauchy test for convergence of an Infinite Series, we have ( ) ( ) ( )     ≤≥ >< = ++ +−+ = −− ∞→+− +− −− −−− ∞→ divergex convergex xx ini inin xa xa iin in in in j 11 11 1222 212 limlim 22 12 12 12 12 Series Solutions – Frobenius’ Method Legendre Polynomials
  • 43. SOLO Example: Legendre Equation (continue – 14) 43 ( )( ) ! 1353212 n nn an ⋅⋅−− = By choosing we have ( ) ( ) ( )( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 1] 1223212242 1221 1 321242 321 122 1 [ ! 1353212 2 42 1 >+ +−−⋅−⋅⋅ −−−− −+ + −⋅−⋅⋅ −−− + − − − ⋅⋅−− == − −− xx innni ininnn x nn nnnn x n nn x n nn xyxP ini nnn n       Return to Table of Content Finally ( ) ( ) ( ) ( ) ( ) 1 !2!!2 !22 1 0 2 > −− − −= ∑ ∞ = − xx inini in xP i in n i n ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )!2!!2 !22 1 !2 !22 !2!2 1 1 !2!2 135122 1 1223212242 1221 1 ! 1353212 inini in in in iiniin in innni ininnn n nn n i ini i i i i −− − −= − − − −= − ⋅⋅−− −= +−−⋅−⋅⋅ −−−− − ⋅⋅−− −    Series Solutions – Frobenius’ Method Legendre Polynomials
  • 44. SOLO Example: Legendre Equation (continue – 14) 44 ( )( ) 1351212 ! 1 ⋅⋅−+ == −− nn n aa nn By choosing we have ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 1] 1225232242 21221 523242 4321 322 21 [ 1351212 ! 12 531 2 >+ +++⋅+⋅⋅ +−+++ + + +⋅+⋅⋅ ++++ + + ++ + ⋅⋅−+ == −−− −−−−−− xx innni ininnn x nn nnnn x n nn x nn n xyxQ in nnn n       ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )!122! !2! ! !12 ! !2 !122 !12 ! !2 2 1 !122 2222!12 ! !2 !2 1 1225232242 21221 2 ++ +++ = + ++ ++ = ++ ++++ = +++⋅+⋅⋅ +−+++ ini inin n n n in in n n in in innn n in iinnni ininnn i i i    ( ) ( ) ( ) ( ) ( ) 1 !122! !2! 2 0 12 > ++ ++ = ∑ ∞ = ++− xx ini inin xQ i inn n Go to Neumann Integral ( )( ) ( )!12 !2 ! 1351212 ! + = ⋅⋅−+ n n n nn n n  Finally Series Solutions – Frobenius’ Method Legendre Polynomials
  • 45. SOLO Example: Legendre Equation (continue – 15) 45 Summarize ( ) ( ) ( ) ( ) ( ) 1 !122! !2! 2 0 12 > ++ ++ = ∑ ∞ = ++− xx ini inin xQ i inn n Return to Table of Content ( ) ( ) ( ) ( ) ( ) 1 !2!! !22 1 2 1 0 2 > −− − −= ∑ ∞ = − xx inini in xP i ini nn ( ) ( ) ( ) ( ) ( ) [ ] 1 !2!! !22 1 2 1 2/ 0 2 < −− − −= ∑= −− xx inini in xP n i ini nn Return to Similar to Rodrigues Formula Using Frobenius’ Method we found that solutions of Legendre ODE are ( ) ( ) integerpositive0121 2 2 22 nynn xd yd yx xd yd x =++−− Series Solutions – Frobenius’ Method Legendre Polynomials ( ) 4,3,2,1 1 = > l xxPl ( ) 4,3,2,1 1 = > l xxQl
  • 46. 46 SOLO ( ) 1 21 1 0 2 ≤= +− ∑ ∞ = utPu utu n n n For u=0 we obtain ( ) 10 =tP For t = 1 we obtain ( ) ( ) 111 1 1 21 1 00 2 =⇒== − = +− ∑∑ ∞ = ∞ = n n n n n n PPuu uuu For t = -1 we obtain ( ) ( ) ( ) ( )n n n n n n nn PPuu uuu 1111 1 1 21 1 00 2 −=⇒=−= + = ++ ∑∑ ∞ = ∞ = Let find a Recursive Relation for Legendre Polynomial computation Start with: ( ) ( ) ( ) ( ) ( ) ( ) ( )       ∂ ∂ + − =      ∂ ∂− + − =      ∂ ∂ + − = ++ + + ++ + + 11 1 1 11 2 1 cos 1 11 ! 1 1 11 !1 1cos n n n nn n nn n n r P znrznnrznr P θθ ( ) ( ) ( ) ( ) ( )( ) ( )       ∂ ∂ + ∂ ∂+ − + − = +++ + zd Pd rz r r Pn nr P n nn n n n θ θ θθθ cos cos cos1cos1 1 1cos 122 1 Recursive Relations for Legendre Polynomial Computation First Recursive Relation Legendre Polynomials
  • 47. 47 SOLO Recursive Relations for Legendre Polynomial Computation ( ) ( ) ( ) ( ) ( )( ) ( )       ∂ ∂ + ∂ ∂+ − + − = +++ + zd Pd rz r r Pn nr P n nn n n n θ θ θθθ cos cos cos1cos1 1 1cos 122 1 θcosrz = θcos= ∂ ∂ z r  z r z r z z ∂ ∂ + ∂ ∂ = ∂ ∂ = θ θ θ cos cos1 cos rz θθ 2 cos1cos − = ∂ ∂ ( ) ( ) ( ) ( ) ( )( )       − + + − + − = +++ + rd Pd rr Pn nr P n nn n n n θ θ θ θ θθ 2 122 1 cos1 cos cos1 cos cos1 1 1cos ( ) ( ) ( )( ) θ θθ θθθ cos cos 1 cos1 coscoscos 2 1 d Pd n PP n nn + − −=+ Substituting t = cos θ we obtain ( ) ( ) ( ) td tPd n t tPttP n nn 1 1 2 1 + − −=+ First Recursive Relation (continue – 1) Legendre Polynomials
  • 48. 48 SOLO Recursive Relations for Legendre Polynomial Computation ( ) ( ) ( ) 0,1 1 1 2 1 ≥≤ + − −=+ nt td tPd n t tPttP n nn Use to start ( ) ( ) 01 0 0 =⇒= td tPd tP ( ) ( ) ( ) ( ) ( ) 8 157063 8 33035 2 35 2 13 35 5 24 4 3 3 2 2 1 ttt tP tt tP tt tP t tP ttP +− = +− = − = − = = First Recursive Relation (continue – 2) Legendre Polynomials
  • 49. 49 SOLO Recursive Relations for Legendre Polynomial Computation Start from ( ) ( ) 1 21 1 :, 0 2 ≤= +− = ∑ ∞ = utPu utu tug n n n Let differentiate both sides with respect to u and rearranging ( ) ( )∑ ∞ = − +−= +− − = ∂ ∂ 1 12 2 21 21 n n n tPunutu utu ut u g ( ) ( ) ( ) ( )∑∑ ∞ = − ∞ = +−=− 1 12 0 21 n n n n n n tPunututPuut ( ) ( ) ( ) ( )∑∑ ∞ = +− ∞ = + +−=− 1 11 0 1 2 n n nnn n n nn tPunutnuntPuut ( ) ( ) ( ) ( ) ( ) ( ) ( )∑∑∑∑∑ ∞ = − ∞ = ∞ = + ∞ = − ∞ = −+−+=− 2 1 10 1 1 1 0 121 n n n n n n n n n n n n n n n tPuntPutntPuntPutPut ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )     ≥+=−+ =−=− == +− 2112 122 0 11 1201 10 ntPuntPuntPutn ntPtutPutPutuPt ntPtPt n n n n n n We can see that the last relation agrees also with the previous relations, for n = 0 and n = 1. Second Recursive Relation Legendre Polynomials
  • 50. 50 SOLO Recursive Relations for Legendre Polynomial Computation We find the Recursive Relation: ( ) ( ) ( ) 1 11 12 11 ≥ + − + + = −+ ntP n n tPt n n tP nnn ( ) 10 =tP This is called the Bonnet’s Recursion Relation. It starts with: Examples: ( ) ( ) ( ) 2 3 1 01 2 tPtPt tPn − =→= ( ) 2 1 2 3 2 2 −= ttP ( ) ( ) ( )  tP tP ttttPn 1 2 3 2 2 1 2 3 3 5 2 2 3 −      −=→=  ( ) 2 35 3 3 tt tP − = ( ) ( ) ( )  tPtP tttttPn 23 2 1 2 3 4 3 2 3 2 5 4 7 3 23 4       −−      −=→= ( ) 8 33035 24 4 +− = tt tP ( ) ttP =1 Second Recursive Relation (continue) Legendre Polynomials
  • 51. 51 SOLO Recursive Relations for Legendre Polynomial Computation Start from ( ) ( ) 1 21 1 :, 0 2 ≤= +− = ∑ ∞ = utPu utu tug n n n Let differentiate both sides with respect to t and rearranging ( ) ( ) ∑ ∞ = = +− = ∂ ∂ 0 2/32 21 n nn td tPd u utu u t g ( ) ( ) ( ) ∑∑ ∞ = ∞ = +−= 0 2 0 21 n nn n n n td tPd uututPuuor Equaling coefficients of each power of u gives ( ) ( ) ( ) ( ) td tPd td tPd t td tPd tP nnn n 11 2 −+ +−= ( ) ( ) ( ) ( ) ( )tPntPntPtn nnn 11112 −+ ++=+ Differentiate the Second Recursive Relation with respect to t and rearranging ( ) ( ) ( ) ( ) ( ) ( ) ( ) td tPd n n td tPd n n td tPd ttP nnn n 11 1212 1 −+ + + + + =+ Third Recursive Relation Legendre Polynomials
  • 52. 52 SOLO Recursive Relations for Legendre Polynomial Computation We found ( ) ( ) ( ) ( ) td tPd ttP td tPd td tPd n n nn 211 +=+ −+ ( ) ( ) ( ) ( ) ( ) ( ) ( ) td tPd ttP td tPd n n td tPd n n n n nn += + + + + −+ 11 1212 1 Third Recursive Relation (continue) Let solve for and in terms of and( )tPn ( ) td tPd n( ) td tPd n 1+( ) td tPd n 1− ( ) ( ) ( ) td tPd ttPn td tPd n n n +−=−1 ( ) ( ) ( ) ( ) td tPd ttPn td tPd n n n ++=+ 11 Subtracting the first relation from the second gives the Third Recursive Relation ( ) ( ) ( ) ( ) td tPd td tPd tPn nn n 11 12 −+ −=+ Legendre Polynomials
  • 53. 53 SOLO Recursive Relations for Legendre Polynomial Computation ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ){ }yPxPyPxP yx n yPxPk tPtntPn td tPd t tPntPtn td tPd t tPn td tPd t td tPd tPn td tPd td tPd t tPn td tPd td tPd tPntPtntPn tP n n tP n n tPt tPin td tPd nnnn n k kk nn n nn n n nn n nn n nn nnn nnn l i in n 11 0 1 2 1 2 1 1 1 11 11 11 1 2 1 0 12 1 129 1118 17 6 5 124 01213 1212 1 2 1421 ++ = + − − − − −+ −+ −+       − = −− − − + =+ +−+=− −=− =− =− +=− =++−+ + + + + = −−= ∑ ∑ Recursive Relation between Legendre Polynomials and their Derivatives) Legendre Polynomials Return to Table of Content
  • 54. 54 SOLO Orthogonality of Legendre Polynomials Define ( ) ( )tPwtPv nm == :&: We use Legendre’s Differential Equations: ( ) ( ) 011 2 =++      − vmm td vd t td d ( ) ( ) 011 2 =++      − wnn td wd t td d Multiply first equation by w and integrate from t = -1 to t = +1. ( ) ( ) 011 1 1 1 1 2 =++      − ∫∫ + − + − dtwvmmdtw td vd t td d Integrate the first integral by parts we get ( ) ( ) ( ) 0111 1 1 1 1 2 0 1 1 2 =++−−− ∫∫ + − + − += −= dtwvmmdt td wd td vd tw td vd t t t    In the same way, multiply second equation by v and integrate from t = -1 to t = +1. ( ) ( ) 011 1 1 1 1 2 =++−− ∫∫ + − + − dtwvnndt td wd td vd t Legendre Polynomials
  • 55. 55 SOLO Orthogonality of Legendre Polynomials ( ) ( ) 011 1 1 1 1 2 =++−− ∫∫ + − + − dtwvmmdt td wd td vd t Subtracting those two equations we obtain ( ) ( ) 011 1 1 1 1 2 =++−− ∫∫ + − + − dtwvnndt td wd td vd t ( ) ( )[ ] ( ) ( )[ ] ( ) ( ) 01111 1 1 1 1 =+−+=+−+ ∫∫ + − + − dttPtPnnmmdtwvnnmm nm This gives the Orthogonality Condition for m ≠ n ( ) ( ) nmdttPtP nm ≠=∫ + − 0 1 1 To find let square the relation and integrate between t = -1 to t = +1. Due to orthogonality only the integrals of terms having Pn 2 (t) survive on the right-hand side. So we get ( )∫ + − 1 1 2 dttPn ( )∑ ∞ = = +− 0 2 21 1 n n n tPu utu ( )∑ ∫∫ ∞ = + − + − = +− 0 1 1 22 1 1 2 21 1 n n n dttPudt utu Legendre Polynomials
  • 56. 56 SOLO Orthogonality of Legendre Polynomials ( )∑ ∫∫ ∞ = + − + − = +− 0 1 1 22 1 1 2 21 1 n n n dttPudt utu ( ) ( ) ( ) 1 1 1 ln 1 1 1 ln 2 1 21ln 2 1 21 1 2 21 1 2 1 1 2 < − + = + − − =−+ − = −+ += −= + −∫ u u u uu u u tuu u dt tuu t t ( ) ( ) ( ) ( ) ( ) ( ) ( ) ∑∑∑ ∞ ++∞ +∞ + + −− −= + − −− + −=−−+ 0 11 0 1 0 1 1 1 1 1 1 1 1 1 1 1ln 1 1ln 1 n uu un u un u u u u u u nn n n n n n ( ) ( ) ( ) ( ) ( ) ( ) ( ) ∑∑∑∑ ∞∞ +∞ ++ + ∞ ++ + = + = + −− −+ + −− −= 0 2 0 12 0 0 1212 12 0 1212 2 12 2 12 1 2 12 1 1 12 1 1 n nnn n nn n u nn u un uu un uu u    Let compute first Therefore ( )∑ ∫∑∫ ∞ + − ∞+ − = + = +− 0 1 1 22 0 2 1 1 2 12 2 21 1 dttPuu n dt utu n nn Comparing the coefficients of u2n we get ( ) 12 21 1 2 + =∫ + − n dttPn Legendre Polynomials ( ) ( ) nmmn n dttPtP δ 12 21 1 + =∫ + − Hence
  • 57. 57 SOLO Using Rodrigues’ Formula let calculate ( ) ( ) ( ) ( )[ ]∫∫ + − + − − = 1 1 2 1 1 1 !2 1 dt td td tP n dttPtP n nn knnk Legendre Polynomials ( ) ( )[ ]n nn nn td td n tP 1 !2 1 2 − = Orthogonality of Legendre Polynomials (Second Method) Assume, without loss of generality, that n > k, and integrate by parts ( ) ( ) ( ) ( )[ ] ( ) ( )[ ] ( ) ( )[ ] ( ) ( ) ( ) ∫∫ ∫∫ + − + − − − + − − − + − + − −−== − − − = − = 1 1 2 1 1 1 21 0 1 1 1 21 1 1 2 1 1 1 !2 1 1 1 !2 11 !2 1 1 !2 1 dt td tPd t n dt td td td tPd ntd td tP n dt td td tP n dttPtP n k n n n n n nn k nn nn kn n nn knnk     Since Pk (t) is a Polynomial of Order k and we assume that n > k, we have ( ) 0=n k n td tPd Therefore ( ) ( ) nkdttPtP nk ≠=∫ + − 0 1 1
  • 58. 58 SOLO For k = n we have Legendre Polynomials Orthogonality of Legendre Polynomials (Second Method) (continue – 1) ( )[ ] ( ) ( ) ( ) ∫∫ + − + − −−= 1 1 2 1 1 2 1 !2 1 1 dt td tPd t n dttP n n n n n n n But we found that Pn (t) is given by: ( ) ( ) ( ) ( ) ( ) [ ] ∑= − −− − −= 2/ 0 2 !2!!2 !22 1 n k kn n k n t knknk kn tP Therefore to compute it is sufficient to consider only the highest power of t in the series, i.e. for k = 0, and we obtain ( ) n n n td tPd ( ) ( ) ( ) ( ) !2 !2 ! !2 !2 2 n n n n n td tPd nnn n n == ( )[ ] ( ) ( ) ( ) ( ) ( ) ( )∫∫∫ + − + − + − −=−−= 1 1 2 22 1 1 2 1 1 2 1 !2 !2 !2 !2 1 !2 1 1 dtt n n dt n n t n dttP n nn n n n n
  • 59. SOLO Legendre Polynomials Orthogonality of Legendre Polynomials (Second Method) (continue – 2) ( )[ ] ( ) ( ) ( ) ( ) ( ) ( )∫∫∫ + − + − + − −=−−= 1 1 2 22 1 1 2 1 1 2 1 !2 !2 !2 !2 1 !2 1 1 dtt n n dt n n t n dttP n nn n n n n ( ) ∫∫∫ ++ =+ − =−=− π π θ θθθθ 0 12 0 12 cos1 1 2 sinsin1 dddtt nn tn Therefore ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )!12 !2 cos 2222 !2 11212 !2 sin 31212 2222 sin 12 2 sin 212 2 0 1 00 12 0 12 + = −⋅ ⋅ −⋅+ = −⋅+ −⋅ = + = + −+ ∫∫∫ n n nn n nn n d nn nn d n n d nnn nn       π πππ θθθθθθθ ( ) ( ) ( )∫∫∫∫ +−−+ −=+−== ππ π ππ θθθθθθθθθθθθ 0 1212 0 212 0 0 2 0 2 0 12 sinsin2cossin2cossincossinsin dndndd nnnnnn    ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) ( ) ,2,1,0 12 2 !12 !2 !2 !2 1 !2 !2 212 22 1 1 2 22 1 1 2 = + = + =−= + + − + − ∫∫ n nn n n n dtt n n dttP n n n nn Return to Table of Content 59
  • 60. SOLO Legendre Polynomials Expansion of Functions, Legendre Series Using Sturm-Liouville Theory it can be seen that the Legendre Polynomials that are Solution of the Legendre ODE, form an orthogonal and “Complete” Set, meaning that we can expand any function f (t) , Piecewise Continuous in the interval -1 ≤ t ≤+1. Therefore we can define a series of Legendre Polynomials that converges in the mean to the function f (t) ( ) ( ) 11 0 ≤≤−= ∑ ∞ = ttPatf n nn The coefficients an can be defined using the Orthogonality Property of Legendre Polynomials ( ) ( ) ( ) ( ) m n m mnnm a m tdtPtPatdtPtf mn 12 2 0 2 12 1 1 1 1 + == ∑ ∫∫ ∞ = + + − + −    δ ( ) ( )∫ + − + = 1 1 2 12 tdtPtf m a mm ( ) ( ) ( ) ( ) 11 2 12 0 1 1 ≤≤−       + = ∑ ∫ ∞ = + − ttPtdtPtf n tf n nn 60
  • 61. SOLO Legendre Polynomials Expansion of Functions, Legendre Series At any discontinuous point t0 ( f(t0- ) ≠ f(t0+) ) we have ( ) ( )[ ] ( ) ( ) ( ) 11 2 12 2 1 0 0 0 1 1 00 ≤≤−       + =+ ∑ ∫ ∞ = + − +− ttPtdtPtf n tftf n nn If f (t) is defined in the interval –a ≤ t ≤ +a then ( ) ( ) ataatPatf n nn ≤≤−= ∑ ∞ =0 / ( ) ( )∫ + − + = a a nn tdatPtf a n a / 2 12 61
  • 62. SOLO Legendre Polynomials Expansion of Functions, Legendre Series If f (t) is an odd function ( f(-t ) =- f(t) ) we have ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )    =+−−= +== + ∫ ∫∫ ∫∫∫ + ++ −− + −→ − + − 1 0 1 0 1 0 1 1 0 0 1 1 1 2 0 12 2 oddndttPtf evenn dttPtfdttPtf dttPtfdttPtfdttPtfa n n n tP n tf n tt nnn n n     If f (t) is an even function ( f(-t ) = f(t) ) we have ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )     =+−−= +== + ∫∫∫ ∫∫∫ + ++ − + −→ − + − oddn evenndttPtf dttPtfdttPtf dttPtfdttPtfdttPtfa n n n tP n tf n tt nnn n n 0 2 12 2 1 0 1 0 1 0 1 1 0 0 1 1 1     62
  • 63. SOLO Legendre Polynomials Expansion of Functions, Legendre Series Using Rodrigues’ Formula let calculate ( ) ( )[ ]n nn nn td td n tP 1 !2 1 2 − = ( ) ( ) ( )[ ] ( ) ( ) ( )[ ] ( )[ ] ( ) ( ) ( ) ( ) ∫∫ ∫∫ + − + − − − + − − − + − + − −−== − − − = − = 1 1 2 1 1 1 21 0 1 1 1 21 1 1 21 1 1 !2 1 1 1 !2 11 !2 1 1 !2 1 td td tfd t n td td tfd td td ntd td tf n tdtf td td n tdtftP n n n n n n nn nn nn n n nn nn     ( ) ( ) ( ) ( ) ( ) ( ) ( ) ∫∫∫ + − + − + − −=−−= 1 1 2 1 1 2 1 1 1 !2 1 1 !2 1 1 td td tfd t n td td tfd t n tdtPtf n n n nn n n n n n or 63
  • 64. SOLO Legendre Polynomials Expansion of Functions, Legendre Series Example f (t) = tk ,|t| < 1 ( ) ( ) ( ) ( ) ( ) ( ) ( )     ≥−+−− + < =− + = + = ∫ ∫∫ + − − + + − + + − nktdttnkkk n n nk td td td t n n tdtPt n a nkn n n kn n nn k n 1 1 2 1 1 1 2 1 1 1 111 !2 12 0 1 !2 12 2 12  We have ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( )( ) ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∫ ∫ ∫ ∫∫ + − + −− + − −−−+ + − −−+ + − −−+ + − −−+= −= + − − − − − + = − +++ −−−−−−−− = =− ++ −−−− = − + −− +− + −=− −− 1 1 2 1 1 22222 1 1 422222 1 1 222122 0 1 1 122122 1 2 1 1 1 2222 1 !2 !22 !2 !2 1 2222122 12222322122 1 222122 322122 1 122 122 1 122 1 1 122 222 tdt nm nm mn n tdtt mnnn nmnmnmnm tdtt nn nmnm tdtt n nm tt n tdtt mn nmnm nmnmmn nmn nmnnmntu tdtdv nmn nm n        Take k = 2m and since t2m is even, they are only even coefficients nonzero so we take 2 n instead of n, and 2n ≤ 2m 64
  • 65. SOLO Legendre Polynomials Expansion of Functions, Legendre Series Example f (t) = tk , |t| < 1 (continue – 1) ( ) ( ) ( ) ( ) ( )     ≥− − + < = ∫ + − − + nmtdtt nm m n n nm a nmn n n 1 1 2222 12 2 1 !22 !2 !22 14 0 We have for f (t) = t2m ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( )!122 !2 !2 !22 !2 !2 1 !2 !22 !2 !2 1 2122 1 1 2 1 1 2222 ++ + − − + = − − − + =− ++ −− + − + −− + − − ∫∫ nm mn nm nm mn n tdt nm nm mn n tdtt nm nmnm mn nmnm nmn ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( )!122! !!2142 !122 !2 !2 !22 !2 !2 !22 !2 !22 14 22122 122 ++− ++ = ++ + − − +− + = ++ −−+ nmnm nmmn nm nm nm nm nm n nm m n n a nnm nmnmnn ( ) ( ) ( )!12 !2 1 212 1 1 2 + =− + + −∫ n n dtt n n Where we used the previous result Therefore ( ) ( ) ( ) ( ) ( ) ( )∑= ++− ++ = m n n n m tP nmnm nmmn t 0 2 2 2 !122! !!2142 65
  • 66. SOLO Legendre Polynomials Expansion of Functions, Legendre Series ( ) ( ) ( ) ( ) ( ) ( ) ( )     ≥−+−− + < =− + = + = ∫ ∫∫ + − − + + − + + − nktdttnkkk n n nk td td td t n n tdtPt n a nkn n n kn n nn k n 1 1 2 1 1 1 2 1 1 1 111 !2 12 0 1 !2 12 2 12  We have ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( )( ) ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( )∫ ∫ ∫ ∫∫ + − ++ ++ −− + − −−−++ + − −−+ + − −−+ + − −−+= −= + − −+ − ++ + − − ++ + = − ++++ −−−−−−−− = =− ++ −−−− = − + −− +− + −=− −− + 1 1 12 2122 1 1 222212 1 1 422322 1 1 222222 0 1 1 122222 1 2 1 1 1 22122 1 !122 !2 !2 !22 !12 !12 1 12322222 12222322122 1 322222 322122 1 222 122 1 222 1 1 122 2122 tdt nm mn nm nm mn n tdtt mnnn nmnmnmnm tdtt nn nmnm tdtt n nm tt n tdtt mn nm nmnm nmnmmn nmn nmnnmntu tdtdv nmn nm n        Take k = 2m+1 and since t2m+1 is odd, they are only odd coefficients nonzero so we take 2 n+1 instead of n, and 2n+1 ≤ 2m+1 66 Example f (t) = tk , |t| < 1 (continue – 2)
  • 67. SOLO Legendre Polynomials Expansion of Functions, Legendre Series ( ) ( ) ( ) ( ) ( )     ≥− −+ + < = ∫ + − −+ + + nmtdtt nm m n n nm a nmn n n 1 1 22122 22 12 1 !22 !2 !122 34 0 We have for f (t) = t2m+1 ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( )!322 !12 !2 !22 !12 !12 1 !122 !2 !2 !22 !12 !12 1 2322 1 1 12 21221 1 22122 ++ ++ − − ++ + = − ++ + − − ++ + =− ++ −− + − ++ ++ −− + − −+ ∫∫ nm mn nm nm mn n tdt nm mn nm nm mn n tdtt nm nmnm mn nm nmnm nmn ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( )!322! !1!12342 !322 !12 !2 !22 !12 !12 !22 !2 !122 34 122322 2212 ++− ++++ = ++ ++ − − ++ + −+ + = +++ −−++ nmnm nmmn nm nm nm nm nm n nm m n n a nnm nmnmnn ( ) ( ) ( )!12 !2 1 212 1 1 2 + =− + + −∫ n n dtt n n Where we used the previous result Therefore ( ) ( ) ( ) ( ) ( ) ( )∑= + + + ++− ++++ = m n n n m tP nmnm nmmn t 0 12 12 12 !322! !1!12342 Return to Neumann Integral 67 Example f (t) = tk , |t| < 1 (continue – 3)
  • 68. SOLO Legendre Polynomials Expansion of Functions, Legendre Series Neumann Integral 1 1 1 111 0 2 12 0 12 2 0 1 0 <+==      = − = − ∑∑∑∑ ∞ = −∞ = + ∞ = + ∞ = x t x t x t x t x t x x txtx m m m m m m m m m m m Start from Use ( ) ( ) ( ) ( ) ( ) ( )∑= + + + ++− ++++ = m n n n m tP nmnm nmmn t 0 12 12 12 !322! !1!12342 ( ) ( ) ( ) ( ) ( ) ( )∑= ++− ++ = m n n n m tP nmnm nmmn t 0 2 2 2 !122! !!2142 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∑ ∑∑ ∑ ∑ ∑∑ ∑ ∑ ∑∑ ∑ ∞ = ∞ = + − +∞ = ∞ = ++− += ∞ = ∞ = + − +∞ = ∞ = +− ∞ = = − + +∞ = +− = ++ +++++ + ++ +++ = ++− ++++ + ++− ++ = ++− ++++ + ++− ++ = − 0 0 12 2 12 0 0 2 212 2 0 12 2 12 0 2 12 2 0 0 2 12 12 0 12 0 2 2 !322! !12!122342 !124! !2!22142 !322! !1!12342 !122! !!2142 !322! !1!12342 !122! !!21421 n i n m n n i n in ninm n nm n m n n nm n m nOrder Summation Change m m n m n n m m m n n n tPx nmi ininn tPx ini ininn tPx nmnm nmmn tPx nmnm nmmn xtP nmnm nmmn xtP nmnm nmmn tx 68
  • 69. SOLO Legendre Polynomials Expansion of Functions, Legendre Series Neumann Integral (continue – 1) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∑ ∑∑ ∑ ∞ = + ∞ = − +∞ = ∞ = ++−       ++ +++++ +      ++ +++ = − 0 12 0 2 12 0 2 0 212 2 !322! !12!122342 !124! !2!221421 n n i m n n n i in n tPx nmi ininn tPx ini ininn tx We found ( ) ( ) ( ) ( ) ( ) 1 !122! !2! 2 0 12 > ++ ++ = ∑ ∞ = ++− xx ini inin xQ i inn n Use the Frobenius Series development of Legendre Functions of the Second Kind Qn (x) We have ( ) ( ) ( ) ( ) ( ) ( )∑∑ ∞ = ++ ∞ = +++= − 0 1212 0 22 3414 1 n nn n nn tPxQntPxQn tx ( ) ( ) ( )∑ ∞ = <+= − 0 12 1 n nn xttPxQn tx Return to Qn Frobenius Series 69
  • 70. SOLO Legendre Polynomials Expansion of Functions, Legendre Series Neumann Integral (continue – 2) We found ( ) ( ) ( )∑ ∞ = += − 0 12 1 n nn tPxQn tx Multiply both sides by Pm (t) and integrate between -1 to +1 ( ) ( ) ( ) ( ) ( ) ( )xQtdtPtPxQntd tx tP m n n mnn m nm 212 0 12 2 1 1 1 1 =+= − ∑ ∫∫ ∞ = + + − + −    δ We obtain ( ) ( ) ∫ + − − = 1 1 2 1 td tx tP xQ n n Franz Neumann's Integral of 1848 Franz Ernst Neumann (1798 –1895) Return to Table of Content 70
  • 71. SOLO 71 Legendre Polynomials Schlaefli Integral Start with Using Rodrigues's Formula we obtain( ) ( )[ ]n n n nn x xd d n xP 1 !2 1 2 −= ( ) ( ) ∫ − = td zt tf j zf π2 1 Cauchy's Integral with ( ) ( )n zzf 12 −= ( ) ( ) ∫ − − =− td zt t j z n n 1 2 1 1 2 2 π Differentiate n times this equation with respect to z and multiply by 1/ (2n n!) ( ) ( ) ( )∫ + − − − =− td zt t j z zd d n n nn n n n n 1 2 2 1 2 2 1 !2 1 π with the contour enclosing the point t = z. Schlaefli Integral ( ) ( ) ( )∫ + − − − = td zt t j zP n nn n 1 2 1 2 2 π Return to Table of Content
  • 72. SOLO 72 Legendre Polynomials Laplace’s Integral Representation Start with ( ) ( ) ( )[ ] ( )[ ] ( )[ ] ( ) [ ] [ ] ( ) ( ) 22 0 1 2 0 22 0 2 0 22 2/tan 0 22 2 0 2 2 0 121 2 1 1 tan 1 2 1 1 1 1 1 1 2 11 2 11 2 2/tan12/tan1 2/tan1 2/tan1 2/tan1 1 cos1 λ ππ λλ λ λ λ λ λ λ λ λλλφλφ φφ φ φ λ φ φλ φ φπππ − = − =        + − − =         + − + + − − = −++ = −++ = −++ + = + − + = + ∞ − ∞ ∞∞= ∫ ∫∫∫∫∫ t t td t td tt tdddd t ( ) ( ) ( ) ( ) ( ) { }[ ] ( ) { }∑ ∞ = −− − ±= −±−=−±−−= −±− − = − − ± = + 0 2 1 2 22 1 1 cos11cos111 cos11 1 cos 1 1 1 1 cos1 1 2 n n n xu xu xxuxuxxuxu xuxu xu xu xu φφ φ φ φλ λ Let write where we used ( ) ∑ ∞ = − =− 0 1 1 n n aa ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2222 2 22 1 1 2 21 1 11 1 1 1 1 1 1 1 2 uxu xu xuxu xu xu xu xu xu +− − = −−− − = − − − = − − − ±=λ λ ( ) { } ( ) { } ( ) 22 0 0 2 0 0 2 0 21 1 1 cos11cos11 cos1 uxu xu dxxuxudxxuxu d n n n n n n +− − = − =−±−=−±−= + ∑ ∫∫ ∑∫ ∞ = ∞ = π λ π φφφφ φλ φ πππ
  • 73. SOLO 73 Legendre Polynomials Laplace’s Integral Representation (continue - 1) { } ( )∑∑ ∫ ∞ = ∞ = = +− =−± 0 2 0 0 2 21 cos1 n n n n n n xPu uxu dxxu π π φφ π We obtained Equating un coefficients we obtain : ( ) { }∫ −±= π φφ π 0 2 cos1 1 dxxxP n n ( ) ( ) 0112 =+−      − ynny xd d x xd d If we replace in the Legendre ODE n by –n – 1 the equation does not change. Therefore , and( ) ( )xPxP nn 1−−= ( ) { }∫ −− −±= π φφ π 0 1 2 cos1 1 dxxxP n n Substitute x = cosθ ( ) { }∫ ±= π φφθθ π θ 0 cossincos 1 cos djP n n Laplace’s First Integral Laplace’s Second Integral
  • 74. SOLO 74 Legendre Polynomials Laplace’s Integral Representation (continue - 2) Use the Generating Function [ ] ( )∑ ∞ = = +− 0 2/12 21 1 n n n tPu uut Substitute t = cosθ and u = ejφ [ ] ( )∑ ∞ = = +− 0 2/12 cos cos21 1 n n nj jj Pe ee θ θ ϕ ϕϕ [ ] [ ] [ ] [ ] [ ] 2/12/12/12/12/12 coscos2cos2cos21 θϕθθ ϕϕϕϕϕϕ −=+−=+− − jjjjjj eeeeeeBut Therefore ( ) ( ) ( ) ( )       > − < − = − ∞ = ∑ θϕ θϕ θϕ θϕ θ πϕ ϕ ϕ 2/12/ 2/12/ 0 coscos2 1 coscos2 1 cos j j n n nj e e Pe Equating the real and imaginary parts, we obtain ( ) ( ) ( ) ( ) ( ) ( )       > − < − =∑ ∞ = θϕ θϕ ϕ θϕ θϕ ϕ θϕ 2/1 2/1 0 coscos2 2/sin2 coscos2 2/cos2 coscos n nPn ( ) ( ) ( ) ( ) ( ) ( )       > − < − − =∑ ∞ = θϕ θϕ ϕ θϕ θϕ ϕ θϕ 2/1 2/1 0 coscos2 2/cos2 coscos2 2/sin2 cossin n nPn
  • 75. SOLO 75 Legendre Polynomials Laplace’s Integral Representation (continue - 3) Let multiply first relation by cos (nφ) and the second by sin (nφ) and integrate over φ on (0,π), we obtain two integrals ( ) ( ) ( ) ( ) ( ) ( )       > − < − =∑ ∞ = θϕ θϕ ϕ θϕ θϕ ϕ θϕ 2/1 2/1 0 coscos2 2/sin2 coscos2 2/cos2 coscos i iPi ( ) ( ) ( ) ( ) ( ) ( )       > − < − − =∑ ∞ = θϕ θϕ ϕ θϕ θϕ ϕ θϕ 2/1 2/1 0 coscos2 2/cos2 coscos2 2/sin2 cossin i iPi ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∫ ∫∑∫ − + − == ∞ = θ π θ δ π π ϕ θϕ ϕϕ ϕ θϕ ϕϕ θ π θϕϕϕ 0 2/12/1 0 2 0 coscos2 cos2/sin2 coscos2 cos2/cos2 cos 2 coscoscos d n d n PPdni n i i in    ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∫ ∫∑∫ − + − −== ∞ = θ π θ δ π π ϕ θϕ ϕϕ ϕ θϕ ϕϕ θ π θϕϕϕ 0 2/12/1 0 2 0 coscos2 sin2/cos2 coscos2 sin2/sin2 cos 2 cossinsin d n d n PPdni n i i in    ( ) ( ) ( ) ( ) ( ) ( ) ( )       − + − = ∫ ∫ θ π θ ϕ θϕ ϕϕ ϕ θϕ ϕϕ π θ 0 2/12/1 coscos cos2/sin coscos cos2/cos2 cos d n d n Pn ( ) ( ) ( ) ( ) ( ) ( ) ( )       − + − −= ∫ ∫ θ π θ ϕ θϕ ϕϕ ϕ θϕ ϕϕ π θ 0 2/12/1 coscos sin2/cos coscos sin2/sin2 cos d n d n Pn Dirichlet Integrals Johann Peter Gustav Lejeune Dirichlet (1805 –1859)
  • 76. SOLO 76 Legendre Polynomials Add and subtract those two equations ( ) ( ) ( ) ( ) ( ) ( ) ( )       − + − = ∫ ∫ θ π θ ϕ θϕ ϕϕ ϕ θϕ ϕϕ π θ 0 2/12/1 coscos cos2/sin coscos cos2/cos2 cos d n d n Pn ( ) ( ) ( ) ( ) ( ) ( ) ( )       − + − −= ∫ ∫ θ π θ ϕ θϕ ϕϕ ϕ θϕ ϕϕ π θ 0 2/12/1 coscos sin2/cos coscos sin2/sin2 cos d n d n Pn Dirichlet Integrals ( ) ( )[ ] ( ) ( )[ ] ( )       − + + − + = ∫ ∫ θ π θ ϕ θϕ ϕ ϕ θϕ ϕ π θ 0 2/12/1 coscos 2/1sin coscos 2/1cos 2 1 cos d n d n Pn ( )[ ] ( ) ( )[ ] ( )∫ ∫ − − − − − = θ π θ ϕ θϕ ϕ ϕ θϕ ϕ 0 2/12/1 coscos 2/1sin coscos 2/1cos 0 d n d n Replace n by n + 1 in the last equation and substitute in the previous ( ) ( )[ ] ( ) ( )[ ] ( )∫ ∫ − + = − + = θ π θ ϕ θϕ ϕ π ϕ θϕ ϕ π θ 0 2/12/1 coscos 2/1sin2 coscos 2/1cos2 cos d n d n Pn Mehler Integrals Gustav Ferdinand Mehler (1835 - 1895) Return to Table of Content Laplace’s Integral Representation (continue - 4)
  • 77. SOLO 77 Legendre Polynomials We found Return to Table of Content Integrals in terms of sin(iθ) and cos(iθ) ( ) ( ) mnnk n dttPtP δ 12 21 1 + =∫ + − ( ) ( ) mnnk n dPP δθθθθ π 12 2 sincoscos 0 + =∫ θcos=t ( ) ( ) ( ) ( ) ( )     ≥ ++− + < = + = − + − ∫ nm nmnm nmm nm a n tdtPt n nn m !122! !!22 0 14 2 12 2 1 1 2 2 ( ) ( ) ( ) ( ) ( )     ≥ ++− +++ < = + = + + + − + + ∫ nm nmnm nmm nm a n tdtPt n nn m !322! !1!122 0 34 2 22 12 1 1 12 12 ( ) ( ) ( ) ( ) ( )     ≥ ++− + < = − ∫ nm nmnm nmm nm dP n n m !122! !!22 0 sincoscos 12 0 2 2 π θθθθ ( ) ( ) ( ) ( ) ( )     ≥ ++− +++ < = + + + ∫ nm nmnm nmm nm dP n n m !322! !1!122 0 sincoscos 22 0 12 12 π θθθθ
  • 78. Ordinary Differential EquationsSOLO Second Order Linear Ordinary Differential Equation (ODE) 78 Legendre Functions of the Second Kind Qn (x) ( ) [ ] ( ) ( )∑ ∫ ∞ = −− ∞ −− = − − +− −+= 0 2 12/12 0 1 2 1 cosh21 cosh1 n n n n n txQ x xt ttx dxxxQ θθ ( ) ( )n n n nn x xd d n xP 1 !2 1 2 −= ( ) ( ) 1<+= xxQBxPAy nn ( ) ( ) ( )xP xd d xxP nm m mm n 2/2 1−= ( ) ( ) ( )xQ xd d xxQ nm m mm n 2/2 1−= ( ) ( ) ( )xW x x xPxQ nnn 1 1 1 ln 2 1 −− − + = ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 3 2 2 5 2 3 1 1 1 ln 2 1 2 033 022 011 0 +−= −= −= − + = xxQxPxQ xxQxPxQ xQxPxQ x x xQ ( ) ( ) ( )∑= −−− = n m mnmn xPxP m xW 1 11 1 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) [ ] ( ) ( )   − − =    −       − − +− − − + = −+ −− − − + = ∑ ∑ = − =+       − = −− evennifn oddnifnn xP m nm mn x x xP xP rnr rn x x xPxQ n m mnn mr n r rnnn 2/2 2/1 2 1 2 1 122 1 1 ln 2 1 12 142 1 1 ln 2 1 1 12 2 1 0 12
  • 79. Legendre Ordinary Differential EquationSOLO 79 Legendre Functions of the Second Kind Qn (x) ( ) ( ) ( )xPxuxy nnn = With Pn (x) being a solution of the Legendre Differential Equation we look for the second solution having the form ( ) ( ) 0121 2 2 2 =++−− wnn xd wd x xd wd x ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 2 2 2 2 2 2 2 xd xPd xu xd xPd xd xud xP xd xud xd xyd xd xPd xuxP xd xud xd xyd n n nn n nn n nn nn ++= += ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 01221121 2 2 22 2 2 2 =++−−−+−+− xPxunn xd xPd xuxxP xd xud x xd xPd xxu xd xPd xd xud xxP xd xud x nn n nn nn n nn n n Substituting in the Legendre ODE we obtain ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 01212121 0 2 2 22 2 2 2 =      ++−−+−−+− xuxPnn xd xPd x xd xPd xxP xd xud x xd xPd xd xud xxP xd xud x nn nn n nnn n n    or
  • 80. SOLO 80 Legendre Functions of the Second Kind Qn (x) (continue – 1) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 02121 2 2 2 2 =−−+− xP xd xud x xd xPd xd xud xxP xd xud x n nnn n n Equivalent to ( ) ( ) ( ) ( ) 0 1 2/ 2 / / 2 22 = − −+ x x xP xdxPd xdxud xdxud n n n n ( ) ( ) ( ) 01lnln2ln 2 =−++ x xd d xP xd d xd xud xd d n n or Integrating we obtain ( ) ( )[ ] ( ) .1lnlnln 22 constxxP xd xud n n =−++ Therefore ( ) ( )[ ] ( ) AconstxxP xd xud n n ==−⋅⋅ .1 22 ( ) ( )[ ] ( )∫ −⋅ = 22 1 xxP xd Axu n n This means that the second solution has the form ( ) ( ) ( ) ( ) ( )[ ] ( )∫ −⋅ == 22 1 xxP xd xPxuxPxQ n nnnn Legendre Ordinary Differential Equation
  • 81. SOLO 81 Legendre Functions of the Second Kind Qn (x) (continue – 2) We obtained ( ) ( ) ( ) ( ) ( )[ ] ( ) 1 1 22 < −⋅ == ∫ x xxP xd xPxuxPxQ n nnnn ( ) ( ) ( )[ ] ( ) ( ) ( )[ ] x x xxxd xxxxP xd xPxQ − + =++−−=      + + − = −⋅ = ∫∫ 1 1 ln 2 1 1ln1ln 2 1 1 1 1 1 2 1 1 2 1 2 01 00  Let calculate Q0 (x), Q1 (x) ( ) ( ) ( )[ ] ( ) ( ) 1 1 1 ln 2 1 1 2/1 1 2/1 1 1 1 22222 1 11 2 − − + =      + + + − = − = −⋅ = ∫∫∫ x xx xd xxx xxd xx x xxP xd xPxQ x x  Legendre Ordinary Differential Equation
  • 82. SOLO 82 Legendre Functions of the Second Kind Qn (x) (continue – 2) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 3 2 2 5 1 1 ln 2 1 3 2 2 5 1 1 ln 4 35 2 3 1 1 ln 2 1 2 3 1 1 ln 4 43 1 1 1 ln 2 1 1 1 1 ln 2 1 1 ln 2 1 2 3 23 3 2 2 2 11 0 +−      − + =+−      − +− = −      − + =−      − +− = −      − + =−      − + =       − + = x x x xP x x xxx xQ x x x xP x x xx xQ x x xP x xx xQ x x xQ Legendre Ordinary Differential Equation
  • 83. SOLO 83 Legendre Functions of the Second Kind Qn (x) (continue – 3) To obtain a general formula for Qn (x), start from the Polynomial Pn (x) that has n zeros αi, i=1,2,…,n ( ) ( ) ( ) ( )nnn xxxkxP ααα −−−= 21 ( )[ ] ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )∑=       − + − + + + − = +⋅−⋅−−− = −⋅ n i i i i i nnn x d x c x b x a xxxxxkxxP 1 2 00 22 2 2 1 222 11 11 1 1 1 αα ααα  ( ) ( )[ ] ( ) ( )[ ] ( )[ ] ( ) ( ) ( )∑=       − + − −⋅+−++= n i i i i i nnn x d x c xxPxPxbxPxa 1 2 222 0 2 0 1111 αα If we put x=1 and x = -1, and remembering that Pn (1) = 1 and Pn(-1)=(-1)n , we obtain 2/100 == ba Let prove that ( ) ( )[ ] ( ) 0 1 1 22 2 =               −⋅ −= = ixn ii xxP x xd d c α α Legendre Ordinary Differential Equation
  • 84. SOLO 84 Legendre Functions of the Second Kind Qn (x) (continue – 4) Let prove that ( ) ( )[ ] ( ) 0 1 1 22 2 =               −⋅ −= = ixn ii xxP x xd d c α α Start with ( ) ( )[ ] ( ) ( ) ( ) ( ) ( ) i x iixi xatfinitexfprovided xd xfd xxfxxfx xd d i i αααα α α ==      −+−=− = = 02 22 The only terms that are not finite in at x = αi are the terms ci/(x-αi) and di/(x-αi)2 , therefore ( )[ ] ( ) ( ) ( )∑=       − + − + + + − = −⋅ n i i i i i n x d x c x b x a xxP 1 2 00 22 111 1 αα ( ) ( )[ ] ( ) ( ) ( ) ( ) ( )[ ] i x iii xi i i i i xn i cdxc xd d x d x c x xd d xxP x xd d iii =       +−=               − + − −=       −⋅ − === ααα α αα αα 2 2 22 2 1 1 Therefore if we write Pn (x) = (x-αi) Li (x), we have ( )[ ] ( ) ( )[ ] ( ) ( ) ( )[ ] ( ) ( ) ( ) ( ) ( )[ ] ( ) ( ) ( ) ( ) ( )[ ] ( )22 2 223 2 2322222 1 /1 2 1 /122 1 /2 1 2 1 1 iii iiiiii xi ii xi i ixi i L xdxLdL xxL xdxLdxxLx xxL xdxLd xxL x xxLxd d c iii αα αααα ααα −⋅ =−− =         −⋅ −⋅− =         −⋅ − −⋅ =               −⋅ = === Legendre Ordinary Differential Equation
  • 85. SOLO 85 Legendre Functions of the Second Kind Qn (x) (continue – 5) We proved that ( ) ( )[ ] ( ) ixn ii xxP x xd d c α α =               −⋅ −= 22 2 1 1 ( ) ( ) ( ) ( )[ ] ( )22 2 1 /1 2 iii iiiiii i L xdxLdL c αα αααα −⋅ =−− =Therefore if we write Pn (x) = (x-αi) Li (x), we have Since Pn (x) = (x-αi) Li (x) satisfies the Legendre ODE, we have ( ) ( ) ( ){ } ( ) ( ){ } ( ) ( ) ( ){ } 0121 2 2 2 =−++−−−− xLxnnxLx xd d xxLx xd d x iiiiii ααα Performing the calculation and substituting x = αi, we have ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ] 01221 2 2 2 =       −++      +−−      +−− = ix iii i i ii i xLxnnxL xd xLd xx xd xLd xd xLd xx α ααα ( ) ( ) ( ) 0212 2 =− = − iii ii i L xd xLd αα α α Substituting in ci equation we get ( ) ( ) ( ) ( )[ ] ( ) 0 1 /1 2 22 2 = −⋅ =−− = iii iiiiii i L xdxLdL c αα αααα Therefore ( )[ ] ( ) ( )∑= − +      + + − = −⋅ n i i i n x d xxxxP 1 222 1 1 1 1 2 1 1 1 α Legendre Ordinary Differential Equation
  • 86. SOLO 86 Legendre Functions of the Second Kind Qn (x) (continue – 6) We can prove that but the exact value is not important, as we shall see ( ) ( )[ ] ( ) ixn i i xxP x d α α =      −⋅ − = 22 2 1 Therefore ( )[ ] ( ) ( )∑= − +      + + − = −⋅ n i i i n x d xxxxP 1 222 1 1 1 1 2 1 1 1 α ( )[ ] ( ) ( ) ∑∑∫∫∫ == − − − + = − +      + + − = −⋅ n i i i n i i i n x d x x dx x d dx xxxxP dx 11 222 1 1 ln 2 1 1 1 1 1 2 1 1 αα ( ) ( ) ( ) ∑= − − − + = n i i n inn x xP d x x xPxQ 11 1 ln 2 1 α Since Pn (x)/(x-αi) is a polynomial of order (n-1) the sum above is also a polynomial of order (n-1), and we define it as ( ) ( ) ∑= − − = n i i n in x xP dxW 1 1 : α so ( ) ( ) ( ) 1 1 1 ln 2 1 1 <− − + = − xxW x x xPxQ nnn Legendre Ordinary Differential Equation
  • 87. SOLO 87 Legendre Functions of the Second Kind Qn (x) (continue – 7) To find Wn-1 (x) let use the fact that Qn (x) is a solution of Legendre’s ODE or ( ) ( ) ( ) ( ) ( ) 0121 2 2 2 =++−− xQnn xd xQd x xd xQd x n nn ( ) ( ) ( ) ( ) xd xWd xP xx x xd xPd xd xQd n n nn 1 2 1 1 1 1 ln 2 1 − − − + − + = ( ) ( ) ( ) ( ) ( ) ( ) 2 1 2 2222 2 2 2 1 2 1 2 1 1 ln 2 1 xd xWd xP x x xd xPd xx x xd xPd xd xQd n n nnn − − − + − + − + = ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 0121 1 2 2 1 2 1 1 ln 2 1 121 1 1 2 1 2 2 22 0 2 2 2 =+−+−− − −+ − + − +       ++−− − −− xWnn xd xWd x xd xWd xxP x x xd xPd xP x x x x xPnn xd xPd x xd xPd x n nn n n n n nn    ( ) ( ) ( ) ( ) ( ) ( ) xd xPd xWnn xd xWd x xd xWd x n n nn 2121 1 1 2 1 2 2 =++−− − −− Legendre Ordinary Differential Equation ( ) ( ) ( ) 1 1 1 ln 2 1 1 <− − + = − xxW x x xPxQ nnn
  • 88. SOLO 88 Legendre Functions of the Second Kind Qn (x) (continue – 8) Use the Recursive Formula ( ) ( ) ( ) ( ) ( ) xd xPd xWnn xd xWd x xd d n n n 211 1 12 =++       − − − ( ) ( ) ( ) ( ) ( ) ∑       − = −−−−= 1 2 1 0 121421 l i in n xPin xd xPd Since Wn-1(x) is a polynomial of order n – 1, let write ( ) ( ) ( ) ( ) ( ) ∑       − = −−−−− =++= 1 2 1 0 1231101 n i ininnn xPaxPaxPaxW  Substitute those two equation in the Wn-1(x) O.D.E. to obtain ( ) ( ){ } ( ) ( ) ( ) ( ) ( ) ( ) ( ) ∑∑∑       − = −−       − = −−       − = −− −−=++− 1 2 1 0 12 1 2 1 0 12 1 2 1 0 12 2 142211 l i in n i ini n i ini xPinxPannxPx xd d a But by Legendre O.D.E.: ( ) ( ){ } ( ) ( ) ( ) 02121 1212 2 =−−−+− −−−− xPininxPx xd d inin ( ) ( ) ( ){ } ( ) ( ) ( ) ( ) ( ) ∑∑       − = −−       − = −− −−=++−−−− 1 2 1 0 12 1 2 1 0 12 14221212 l i in n i ini xPinxPnninina Let solve Legendre Ordinary Differential Equation
  • 89. SOLO 89 Legendre Functions of the Second Kind Qn (x) (continue – 9) The coefficients of the same polynomial in both sides must be equal ( ) ( ) ( ){ } ( ) ( ) ( ) ( ) ( ) ∑∑       − = −−       − = −− −−=++−−−− 1 2 1 0 12 1 2 1 0 12 14221212 l i in n i ini xPinxPnninina ( ) ( ) ( ){ } ( )14221212 −−=++−−−− innnininai ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( )12224244 1221212 222 2 +−=−+−=++−+−+−= ++−+−−=++−−−− iininininniniinn nnininnninin But which gives ( ) ( )12 142 +− −− = iin in ai ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) [ ][ ] ∑ ∑∑ = = −− =+       − = −−− +− +− =       − − +− = +− −− = n m n m mnmn mi n i inn xP mn mn m xP m n mn m xP iin in xW 1 1 12 1 2 1 0 121 12 12221 2 1 1221 12 142 and ( ) ( ) ( )∑= −−− = n m mnmn xPxP m xW 1 11 1 ????? Legendre Ordinary Differential Equation
  • 90. SOLO 90 Legendre Functions of the Second Kind Qn (x) (continue -10) ( ) 3,2,1,0 10 = <≤ n xxQn Legendre Ordinary Differential Equation ( ) ( ) ( ) ( ) ( ) ( ) ( ) 3 2 2 5 1 1 ln 2 1 3 2 2 5 1 1 ln 4 35 2 3 1 1 ln 2 1 2 3 1 1 ln 4 43 1 1 1 ln 2 1 1 1 1 ln 2 1 1 ln 2 1 2 3 23 3 2 2 2 11 0 +−      − + =+−      − +− = −      − + =−      − +− = −      − + =−      − + =       − + = x x x xP x x xxx xQ x x x xP x x xx xQ x x xP x xx xQ x x xQ
  • 91. SOLO 91 Legendre Functions of the Second Kind Qn (x) (continue -11) Similar to Rodrigues Formula for Legendre Functions of the Second Kind Qn (x) Start with ( ) ( ) ( )12 2212 1 1 1 1 +−− ++ −= − n nn x xx ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( )( )( ) ( ) ( ) ( ) ( ) ( )( ) ( )1 32211 11, ,121,11,1: ++− +−+−+− −++= −++=−+=−= ini nnn uinnuf unnufunufuuf   ( ) ( ) ( ) ( ) 1 !! ! !! !1 1 1 12 0 2 0 2212 > + = + = − ++− ∞ = − ∞ = ++ ∑∑ xx in in x in in xx in i i i nn ( ) ( ) ( ) ( )( ) ( ) 1 ! 21 ! 0 00 < +++ == ∑∑ ∞ = ∞ = uu i innn u i f uf i i i i i  Taylor expansion around u = 0 Use u = x-2 Legendre Ordinary Differential Equation
  • 92. SOLO 92 Legendre Functions of the Second Kind Qn (x) (continue -12) Similar to Rodrigues Formula for Legendre Functions of the Second Kind Qn (x) Integrate relative to x ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ∑∑ ∫∑∫∑∫ ∞ = ++− ∞ = ∞ ++− ∞ ++− ∞ = ∞ ++− ∞ = ∞ + −+ + = ++ + = + = + = − 0 122 0 122 12 0 2 12 0 212 122!! ! 122!! ! ! ! ! ! 1 i in i xin x in ix in ix n x inni in inni in d n in d n ind η ηηηη η η Integrate this n more times ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ∑ ∑ ∑ ∫ ∫∫∫ ∫ ∞ = ++− ∞ = ++− ∞ = ∞ ∞ ++− ∞ ∞ ∞ + + ++ ++ = +++++++ + = ++ + = − 0 12 0 12 0 122 12 1 !122!! !2! 122222122!! ! 122!! ! 1 i in i in i x nin x n n x inni inin x ininininni in d inni ind   ηη η ηη η η Legendre Ordinary Differential Equation
  • 93. SOLO 93 Legendre Functions of the Second Kind Qn (x) (continue -13) Similar to Rodrigues Formula for Legendre Functions of the Second Kind Qn (x) (continue) ( ) ( ) ( ) ( ) ( ) 1 !122! !2! ! 1 1 0 12 12 1 > ++ ++ = − ∑∫∫ ∫ ∞ = ++− ∞ ∞ ∞ + + xx ini inin n d i in x n n η η η η  We found, using Frobenius Series By comparing those two relations we obtain ( ) ( ) 1 1 !2 12 1 > − = ∫∫ ∫ ∞∞ ∞ + + x d nxQ x n n n n η η η η  Return to Frobenius Series ( ) ( ) ( ) ( ) ( ) 1 !122! !2! 2 0 12 > ++ ++ = ∑ ∞ = ++− xx ini inin xQ i inn n Legendre Ordinary Differential Equation
  • 94. SOLO 94 Legendre Functions of the Second Kind Qn (x) (continue -14) Another Expression for Legendre Functions of the Second Kind Qn (x) Start with the following Differential Equation ( ) ( ) 02121 2 2 2 =+−+− un xd ud xn xd ud x One of the Solutions is . Check:( ) ( )n xxu 12 1 −= ( ) ( ) ( ) ( ) 22212 2 1 2 121 11412&12 −−− −−+−=−= nnn xxnnxn xd ud xxn xd ud ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 01211411412 2121 21221222 1 1 2 1 2 2 =−−−−+−−−−−= +−+− −− nnnn xnxnxnxxnnxn un xd ud xn xd ud x The Second Solution can be find using u1 (x) by finding a function v (x) that satisfies: ( ) ( ) ( )n xxvxu 12 2 −= Legendre Ordinary Differential Equation
  • 95. SOLO 95 Legendre Functions of the Second Kind Qn (x) (continue -15) Another Expression for Legendre Functions of the Second Kind Qn (x) (continue – 1) ( ) ( ) ( ) ( ) ( ) ( ) 01221 21212121 112 2 1 12 0 1 1 2 1 2 2 2 2 2 2 2 2 =−+      +−+       +−+−=+−+− xd vd uxnu xd vd u xd vd xd ud x un xd ud xn xd ud xvun xd ud xn xd ud x    The Second Solution can be find using u1 (x) by finding a function v (x) that satisfies: ( ) ( ) ( )n xxvxu 12 2 −= 2 1 2 1 12 2 2 2 2 1 1 2 2& xd ud v xd ud xd vd u xd vd xd ud xd ud vu xd vd xd ud ++=+= ( ) ( ) ( ) ( ) ( ) ( ) ( )1 121 2 2 1 12 2 1 12 / / 2 1 2 1 2 1 1 1 2 1 22 − + −= − − − − = − − − − = x xn u x uxn x uxn u xd ud x uxn xdvd xdvd Legendre Ordinary Differential Equation
  • 96. SOLO 96 Legendre Functions of the Second Kind Qn (x) (continue -16) Another Expression for Legendre Functions of the Second Kind Qn (x) (continue – 2) Therefore ( ) ( )1 12 / / 2 22 − + −= x xn xdvd xdvd ( ) ( ) ( ) ( ) ( )∫ ∞ ++ − =⇒ − =⇒−+−= x nn d xv xxd vd xn xd vd 1212 2 11 1 1ln1 η η ( ) ( ) ( ) ( ) ( )∫ ∞ + − −== x n n d xxuxvxu 12 2 12 1 1 η η Differentiate the Differential Equation ( ) ( ) 02121 2 2 2 =+−+− un xd ud xn xd ud x ( ) ( ) ( ) ( ) ( ) ( ) 0122221 2121221 2 2 3 3 2 2 2 2 2 2 =−+−+−= +−+−+−− xd ud n xd ud xn xd ud x xd ud n xd ud xd d xn xd ud n xd ud x xd ud xd d x Legendre Ordinary Differential Equation
  • 97. SOLO 97 Legendre Functions of the Second Kind Qn (x) (continue -17) Another Expression for Legendre Functions of the Second Kind Qn (x) (continue – 3) Differentiate relative to x the Ordinary Differential Equation n times ( ) ( ) ( ) 0122221: 2 2 3 3 2 =−+−+− xd ud n xd ud xn xd ud xODE xd d ( ) ( ) ( ) 0223321: 2 2 4 4 2 2 2 =−+−+− xd ud n xd ud xn xd ud xODE xd d ( ) ( ) 02121: 2 2 2 =+−+− un xd ud xn xd ud xODE ( ) ( ) 0121: 1 1 2 2 2 =++−− + + + + n n n n n n n n xd ud nn xd ud x xd ud xODE xd d Derive ( ) ( )[ ] ( )( ) 021121: 1 1 2 2 2 =−+++−+− + + + + i i i i i i i i xd ud ini xd ud xin xd ud xODE xd d ( ) ( )[ ]{ } ( )[ ] ( )( ){ } ( ) ( )[ ] ( )( ) 0122221 21121221: 1 1 1 1 3 3 2 1 1 1 1 3 3 2 =−−+++−+− −+++−++−+−+− + + + + + + + + + + + + i i i i i i i i i i i i i i xd ud ini xd ud xin xd ud x xd ud iniin xd ud xin xd ud xODE xd d xd d Proof by Induction q.e.d. i = n i → i+1 Legendre Ordinary Differential Equation
  • 98. SOLO 98 Legendre Functions of the Second Kind Qn (x) (continue -18) Another Expression for Legendre Functions of the Second Kind Qn (x) (continue – 4) This is the Legendre Ordinary Differential Equation for dn u/dxn , having the solution Pn (x) and Qn (x). Thus, the solution Pn (x) and Qn (x) can be written in the following form: ( ) ( ) 0121: 1 1 2 2 2 =++−− + + + + n n n n n n n n xd ud nn xd ud x xd ud xODE xd d We obtain ( ) ( )[ ]n n n nn n nn x xd d nxd ud n xP 1 !2 1 !2 1 21 −== ( ) ( ) ( ) ( ) ( ) ( ) ( ) 1 1 1 !2 !21 !2 !21 12 22 >         − − − = − = ∫ ∞ + x d x xd d n n xd ud n n xQ x n n n nnn n nnn n η η Rodrigues Formula An integral for Qn (x) valid in |x| < 1 can be obtained from the previous result ( ) ( ) ( ) ( ) ( ) 1 1 1 !2 !21 0 12 2 <         − − − = ∫ + x d x xd d n n xQ x n n n nnn n η η Return to Table of Content Legendre Ordinary Differential Equation
  • 99. 99 SOLO Laplace Differential Equation in Spherical Coordinates 0 sin 1 sin sin 11 2 2 222 2 2 2 = ∂ Φ∂ +      ∂ Φ∂ ∂ ∂ +      ∂ Φ∂ ∂ ∂ =Φ∇ φθθ θ θθ rrr r rr Let solve this equation by the method of Separation of Variables, by assuming a solution of the form : ( ) ( )ϕθ,SrR=Φ Spherical Coordinates: θ ϕθ ϕθ cos sinsin cossin rz ry rx = = = In Spherical Coordinates the Laplace equation becomes: Substituting in the Laplace Equation and dividing by Φ gives: 0sinsin sin 11 2 2 22 2 2 =      ∂ ∂ +      ∂ ∂ ∂ ∂ +      φθ θ θ θ θ SS Srrd Rd r rd d Rr The first term is a function of r only, and the second of angular coordinates. For the sum to be zero each must be a constant, therefore: λ φθ θ θ θ θ λ −=      ∂ ∂ +      ∂ ∂ ∂ ∂ =      2 2 2 2 sinsin sin 1 1 SS S rd Rd r rd d R Associate Legendre Differential Equation
  • 100. 100 SOLO λ φθ θ θ θ θ −=      ∂ ∂ +      ∂ ∂ ∂ ∂ 2 2 2 sinsin sin 1 SS S ( ) ( ) ( )φθφθ ,,, SrRr =Φ We obtain: Multiply this by S sin2 θ and put to get:( ) ( ) ( )φθφθ ΦΘ=,S 0 1 sinsinsin 1 2 2 2 = Φ Φ +      +      Θ ∂ ∂ Θ φ θλ θ θ θ θ d d d d Again, the first term, in the square bracket, and the last term must be equal and opposite constants, which we write m2 , -m2 . Thus: Φ−= Φ =Θ      −+      Θ 2 2 2 2 2 0 sin sin sin 1 m d d m d d d d φ θ λ θ θ θθ The Φ ( ) must be periodical in (a period of 2 π) and becauseϕ ϕ this we choose the constant m2 , with m an integer. Thus: ( ) φφφ mbma sincos +=Φ Laplace Differential Equation in Spherical Coordinates ( ) φφ φ mjmj ee +− =Φ ,or With m integer, we have the Orthogonality Condition 21 21 , 2 0 2 mm mjmj dee δπφ π φφ =⋅∫ +− Return to Table of Content Associate Legendre Differential Equation
  • 101. 101 SOLO ( ) ( ) ( )φθ ΦΘ=Φ rR We obtain: or: Θ−=Θ− Θ + Θ λ θθ θ θ 2 2 2 2 sin cot m d d d d 0 sin sin sin 1 2 2 =Θ      −+      Θ ∂ ∂ θ λ θ θ θθ m d d Analysis of Associate Lagrange Differential Equation Laplace Differential Equation in Spherical Coordinates Change of variables: t = cos θ θθ dtd sin−= td d d d Θ −= Θ θ θ sin  ( ) td d t td d t td d d d td d td d td d td d d d d d d d Θ − Θ −= Θ + Θ =      Θ −−=      Θ = Θ − 2 2 2 cossin/1 2 2 2 2 2 1 sin sinsinsinsin  θθ θ θθ θθθθ θθθ Θ      − −+ Θ − Θ − Θ =Θ      −+ Θ + Θ = = 2 2 2 2cos 2 2 2 2 1sin cot0 t m td d t td d t td dm d d d d t λ θ λ θ θ θ θ We obtain: 1cos 0 1 2 2 2 2 2 ≤⇒= =Θ      − −+ Θ − Θ tt t m td d t td d θ λ Associate Legendre Differential Equation
  • 102. 102 SOLO ( ) ( ) ( )ϕθ gfrR=Φ We obtain: or: ff m d fd d fd λ θθ θ θ −=−+ 2 2 2 2 sin cot Let try to factorize the left-hand side, second order differential equation into two first-order operators: 0 sin sin sin 1 2 2 =      −+      ∂ ∂ f m d fd θ λ θ θ θθ The two equations are identical if the coefficient are equal. This is obtained by choosing α and β as follows: ( ) integer1 1 2 ==− =+ mmαβ βα ( ) ( ) ( ) ff d fd d fd ff d fd d fd f d fd d d f d d d d βα θ αβ θ θβα θ θβα θ β θ θβα θ θβ θ θα θ θβ θ θα θ θ −−−++= +−++=       +      +=      +      + − 22 2 1 sin 1 2 22 2 sin 1 1cot cot sin cot cotcotcotcot 2  Laplace Differential Equation in Spherical Coordinates Analysis of Associate Lagrange Differential Equation (continue – 1) Associate Legendre Differential Equation
  • 103. 103 SOLO ( ) ( ) ( )ϕθ gfrR=Φ We obtain: and: ff m d fd d fd λ θθ θ θ −=−+ 2 2 2 2 sin cot We have two solutions for α and β as follows: 1.β1 = m, α1 = 1-m 2.β2 = -m, α2 = 1+m Since m is an integer α, β are also integers. ( ) integer1 1 2 ==− =+ mmαβ βα ( ) ( ) ( ) fff d fd d fd  λ βαλβα θ αβ θ θβα θ +−=−−−++ ' sin 1 1cot 22 2 βα −=1 integer22 == mmβ Let define the two operators: ( ) ( ) ( ) θ θ θ θ cot1 cot ++= −= − + m d d M m d d M m m Laplace Differential Equation in Spherical Coordinates Analysis of Associate Lagrange Differential Equation (continue – 2) Associate Legendre Differential Equation
  • 104. 104 SOLO ( ) ( ) ( )ϕθ gfrR=Φ We obtain: We have two solutions for α and β as follows: 1.β1 = m, α1 = 1-m 2.β2 = -m, α2 = 1+m Since m is an integer α, β are also integers. ( ) ( ) ( ) θ θ θ θ cot1 cot ++= −= − + m d d M m d d M m m ff d d d d λθβ θ θα θ −=      +      + cotcot ( )  ( )  ( )  ( ) ( )11 11 11 11 1 mmmm fmmfMM         −−−= − − − + − αβ βα λ We have: ( )  ( )  ( )  ( ) ( )22 22 22 1 mmmm fmmfMM         +−−= − +− αβ βα λ fm (1) – the solution for α1, β1 fm (2) – the solution for α2, β2 Laplace Differential Equation in Spherical Coordinates Analysis of Associate Lagrange Differential Equation (continue – 3) Associate Legendre Differential Equation
  • 105. 105 SOLO ( ) ( ) ( )ϕθ gfrR=Φ We obtain: ( ) ( ) ( ) ( )[ ] ( )11 11 1 mmmm fmmfMM −−−=− − + − λ ( ) ( ) ( ) ( )[ ] ( )22 1 mmmm fmmfMM +−−=+− λ Let operate on first of those equations with ( )− −1mM ( ) ( ) ( ) ( ) [ ] ( )[ ] ( ) ( ) [ ]1 1 1 111 1 mmmmmm fMmmfMMM − − − − + − − − −−−= λ In the Second Equation replace m by m-1 ( ) ( ) ( ) ( )[ ] ( )2 1 2 111 1 −− + − − − −−−= mmmm fmmfMM λ Let operate on second of those equations with ( )+ mM 1 2 ( ) ( ) ( ) ( ) [ ] ( )[ ] ( ) ( ) [ ]22 1 mmmmmm fMmmfMMM ++−+ +−−= λ In the First Equation replace m by m+1 ( ) ( ) ( ) ( )[ ] ( )1 1 1 1 1 ++ −+ +−−= mmmm fmmfMM λ ( ) ( ) ( )21 1 mmmm fpfM =+ − ( ) ( ) ( )1 1 2 + + = mmmm fqfM Laplace Differential Equation in Spherical Coordinates pm is a constant qm is a constant mm →−1 mm →−1 Analysis of Associate Lagrange Differential Equation (continue – 4) Associate Legendre Differential Equation
  • 106. 106 SOLO We obtained:( ) ( ) ( )21 1 mmmm fpfM =+ − ( ) ( ) ( )1 1 2 + + = mmmm fqfM Laplace Differential Equation in Spherical Coordinates ( ) ( ) ( ) θ θ θ θ cot cot1 m d d M m d d M m m −= ++= + − where: Theorem: ( ) ( ) ( ) ( ) ( ) ( )∫∫ +− −= ππ θθθθθθθθ 00 sinsin dgMfdfMg mm where f and g are arbitrary bounded function of θ. Proof: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( )∫∫ ∫ ∫∫ + − −=      −−=       +−−=       ++= ππ π π ππ θθθθθθθ θ θ θθ θ θθ θθθθθθ θ θθθθ θθθ θ θθθθθθ 00 0 0 0 00 sinsin sin cos sin cos1sinsin cot1sinsin dgMfdgfmg d d f dgfmg d d ffg dfm d d gdfMg m m    Those are Recursive Relations in m. Analysis of Associate Lagrange Differential Equation (continue – 5) Associate Legendre Differential Equation
  • 107. 107 SOLO Laplace Differential Equation in Spherical Coordinates ( ) ( ) ( )( ) ( ) ( ) ( )( )∫∫ +− −= ππ θθθθθθθθ 00 sinsin dgMfdfMg mm ( ) ( ) ( ) ( ) ( ) ( ) ( )∫∫ + −+ ++ − + − −= ππ θθθθ 0 11 0 11 sinsin dfMMfdfMfM mmmmmmmm ( ) ( ) ( ) ( ) ( ) ( ) ∫ ∫∫ = =+ − + − π ππ θθ θθθθ 0 22 00 11 sin sinsin dfp dfpfpdfMfM mm mmmmmmmm Choose f := fm+1 and g := Mm (-) fm+1: ( ) ( ) ( ) ( )[ ]{ } ( )[ ] ∫ ∫∫ + +++ −+ + +−= +−−−=− π ππ θθλ θλθθθ 0 2 1 0 11 0 11 sin1 1sinsin dfmm dfmmfdfMMf m mmmmmm Assuming: we have1sinsin 0 2 1 0 2 == ∫∫ + ππ θθθθ dfdf mm ( ) ( ) λλ ≤+→+−= 11 mmmmpm Analysis of Associate Lagrange Differential Equation (continue – 6) Associate Legendre Differential Equation
  • 108. 108 SOLO Laplace Differential Equation in Spherical Coordinates ( ) ( ) ( )( ) ( ) ( ) ( )( )∫∫ +− −= ππ θθθθθθθθ 00 sinsin dgMfdfMg mm Choose now f := Mm (+) fm and g := fm, to obtain as before We obtained ( ) ( ) λλ ≤+→+−= 11 mmmmqm ( ) ( ) λλ ≤+→+−= 11 mmmmpm We see that m, an integer, is bounded by λ, therefore we must choose λ as ( ) 0integer1 >=+= lllλ In this case we have mMAX = l, mmin = -(l+1), or ( ) integer0,integer1 =>=≤≤+− mllml Therefore ( ) ( ) ( ) lmlmmllqp mm ≤≤+−→+−+== 111 Analysis of Associate Lagrange Differential Equation (continue – 7) Associate Legendre Differential Equation
  • 109. 109 SOLO Laplace Differential Equation in Spherical Coordinates We obtained ( ) ( ) ( ) lmlmmllqp mm ≤≤+−→+−+== 111 ( ) ( ) ( ) θ θ θ θ cot cot1 m d d M m d d M m m −= ++= + − ( ) ( ) ( )21 1 mmmm fpfM =+ − ( ) ( ) ( )1 1 2 + + = mmmm fqfM ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) lml mmllfm d d fmmllfm d d m mm ≤≤+−        +−+=      − +−+=      ++ + 1 11cot 11cot1 2 21 1 θ θ θ θ Substituting m = - (l+1) in the First Equation and m = l in the Second we obtain: ( ) ( )        =      − =      − − 0cot 0cot 2 1 l l fl d d fl d d θ θ θ θ ( ) ( ) ( ) ( ) ( ) ( ) θ θ θ θ sin sin sin sin 2 2 1 1 d l f fd d l f fd l l l l = = + + − − ( ) ( ) θl lll Cff sin 21 == +− If we can find a Solution for a particular m, we can use the Recursive Relations above to find the others. Analysis of Associate Lagrange Differential Equation (continue – 8) Associate Legendre Differential Equation
  • 110. 110 SOLO Laplace Differential Equation in Spherical Coordinates We obtained ( ) ( ) θl lll Cff sin 21 == +− Cl must be chosen to normalize fi and f-l: 1sinsin 0 122 0 2 == ∫∫ + ± ππ θθθθ dCdf l ll ( ) ( )!12 !21 212 2 + = + n n C n l ( ) ( )212 !2 !12 n n C nl + + = ( ) ( ) ( )∫∫∫∫ +−−+ −=+−=−= ππ π ππ θθθθθθθθθθθθ 0 1212 0 212 0 0 2 0 2 0 12 sinsin2cossin2cossincossinsin dndndd nnnnnn    Therefore ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )!12 !2 cos 2222 !2 11212 !2 sin 31212 2222 sin 12 2 sin 212 2 0 1 00 12 0 12 + = −⋅ ⋅ −⋅+ = −⋅+ −⋅ = + = + −+ ∫∫∫ n n nn n nn n d nn nn d n n d nnn nn       π πππ θθθθθθθ Analysis of Associate Lagrange Differential Equation (continue – 9) Associate Legendre Differential Equation
  • 111. 111 SOLO Laplace Differential Equation in Spherical Coordinates The Normalized Solution for m = l is defined as ( ) ( ) θl n lm l lm l n n sin !2 !12 212 + −== + =Θ=Θ The Solutions for m < l can be found using the Recursive Relation: ( ) ( ) ( ) ( )1,,,0,,1,cot 11 11 1 1 1 +−−−=Θ      + −−+ =Θ=Θ − − − − llllmm d d mmll M p m l m lm m m l θ θ ( ) ( ) ( )21 1 mmmm fpfM =+ − From which the Normalized Solutions for m < l are given by Or we can find the Solutions for m >- l by using the Recursive Relation: ( ) ( ) ( )1 1 2 + + = mmmm fqfM ( ) ( ) ( ) llllmm d d mmll M q m l m lm m m l ,1,,0,,,1cot 11 111 −−−−=Θ      − +−+ =Θ=Θ ++ θ θ Analysis of Associate Lagrange Differential Equation (continue – 10) Associate Legendre Differential Equation
  • 112. 112 SOLO Laplace Differential Equation in Spherical Coordinates ( ) ( ) θl n lm l lm l n n sin !2 !12 212 + −== + =Θ=Θ ( ) ( ) ( ) ( )1,,,0,,1,cot 11 11 1 1 1 +−−−=Θ      + −−+ =Θ=Θ − − − − llllmm d d mmll M p m l m lm m m l θ θ Examples: ( ) ( ) ( ) llllmm d d mmll M q m l m lm m m l ,1,,0,,,1cot 11 111 −−−−=Θ      − +−+ =Θ=Θ ++ θ θ Analysis of Associate Lagrange Differential Equation (continue – 11) 2 cos 1 1 cos 0 1 2 cos 1 1 0 0 1 2 3 sin 2 3 2 3 cos 2 3 1 2 3 sin 2 3 1 2 1 0 x x xl l x x x −−=−=Θ ==Θ −==Θ= =Θ= = − = = θ θ θ θ θ θ ( ) ( ) ( ) ( )2 cos 22 2 2 cos 1 2 2 cos 20 2 2 cos 1 2 2 cos 22 2 1 4 15 sin 4 15 1 2 15 cossin 2 15 13 22 5 1cos3 22 5 1 2 15 cossin 2 15 1 4 15 sin 4 15 2 x xx x xx xl x x x x x −−=−=Θ −−=−=Θ −=−=Θ −==Θ −==Θ= = − = − = = = θ θ θ θ θ θ θθ θ θθ θ Return to Table of Content Associate Legendre Differential Equation
  • 113. SOLO 113 Associated Legendre Functions Let Differentiate this equation m times with respect to t, and use Leibnitz Rule of Product Differentiation: ( ) ( )[ ] ( ) ( ) ( ) im im i im i m m td tgd td tsd imi m tgts td d − − = ∑ − =⋅ 0 !! ! Start with: ( ) ( ) ( ) ( ) 1011 2 ≤=++      − ttwnntw td d t td d nn or: ( ) ( ) ( ) ( ) ( ) 10121 2 2 2 ≤=++−− ttwnntw td d ttw td d t nnn ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )twmmtwtmtwttw td d t td d m n m n m nnm m 1211 122 2 2 2 −−−−=      − ++ ( ) ( ) ( ) ( ) ( )twmtwttw td d t td d m n m nnm m +=      +1 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )twnntwmtwttwmmtwtmtwt m n m n m n m n m n m n 122121 1122 ++−−−−−− +++ ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ] ( ) ( ) 011121 122 =+−+++−−= ++ twmmnntwtmtwt m n m n m n 2nd Way
  • 114. SOLO 114 Associated Legendre Functions ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ] ( ) ( ) 011121 122 =+−+++−− ++ twmmnntwtmtwt m n m n m n Define: ( ) ( ) ( )twty m n=: ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ] ( ) 011121 122 =+−+++−− tymmnntytmtyt Now define: ( ) ( ) ( )tyttu m 22 1: −= Let compute: ( ) ( ) ( )1221 22 11 ytyttm td ud mm −+−−= − ( ) ( ) ( ) ( )11 22222 111 ytyttm td ud t mm + −+−−=− ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )21 221221221 2222222 1121111 ytyttmyttmyttmytm td ud t td d mmmmm +− −+−+−−−−+−−=      − ( ) ( ) ( ) ( ) ( ) ( ) ( )[ ]{ } ( ) ( ) y t tm mnnmmtymmnnytmytt mm       − +−+−+−++−+++−−−= 2 22 222 0 12222 1 11111211    We get: ( ) ( ) 0 1 11 2 2 2 =      − −++      − u t m nn td ud t td d 2nd Way
  • 115. SOLO 115 Associated Legendre Functions Define: ( ) ( ) ( )tw td d ttu nm mm 22 1: −= We get: ( ) ( ) 0 1 11 2 2 2 =      − −++      − u t m nn td ud t td d Start with Legendre Differential Equation: ( ) ( ) ( ) ( ) 1011 2 ≤=++      − ttwnntw td d t td d nn Summarize But this is the Differential Equation of f (θ) obtained by solving Laplace’s Equation by Separation of Variables in Spherical Coordinates . 02 =Φ∇ ( ) ( ) ( ) ( )φθφθ ΦΘ=Φ rRr ,, The Solutions of this Differential Equation are called Associated Legendre Functions, because they are derived from the Legendre Polynomials, and Legendre Functions of the Second Kind Qn (x) and are denoted: ( ) ( ) ( )tP td d ttP nm mm m n 22 1: −= 2nd Way ( ) ( ) ( )tQ td d ttQ nm mm m n 22 1: −=
  • 116. SOLO 116 Associated Legendre Functions Let use Rodrigues Formula for Pn (t): We see that we can define the Associated Legendre Function even for negative m (In the Differential equation m2 appears): ( ) ( ) ( )tP td d ttP nm mm m n 22 1: −= ( ) ( )[ ]n n n nn t td d n tP 1 !2 1 2 −= we obtain: Associated Legendre Functions ( ) ( ) ( )[ ]n mn mnm n m n t td d t n tP 11 !2 1 : 222 −−= + + From this equation we obtain: ( ) ( )tPtP nn = 0 2nd Way

Hinweis der Redaktion

  1. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  2. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  3. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  4. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  5. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  6. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  7. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  8. http://en.wikipedia.org/wiki/Legendre_polynomials
  9. W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  10. http://en.wikipedia.org/wiki/Rodrigues%27_formula http://books.google.co.il/books?id=oTyJYUx8Jr4C&amp;pg=PA105&amp;redir_esc=y#v=onepage&amp;q&amp;f=false http://www-history.mcs.st-andrews.ac.uk/Biographies/Rodrigues.html
  11. http://en.wikipedia.org/wiki/Rodrigues%27_formula
  12. http://en.wikipedia.org/wiki/Rodrigues%27_formula
  13. http://en.wikipedia.org/wiki/Rodrigues%27_formula
  14. http://en.wikipedia.org/wiki/Rodrigues%27_formula
  15. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 K.T. Tang, “Mathematical Methods for Engineers and Scientists”, Vol 3, Springer-Verlag, 2007 http://en.wikipedia.org/wiki/Ferdinand_Georg_Frobenius
  16. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 K.T. Tang, “Mathematical Methods for Engineers and Scientists”, Vol 3, Springer-Verlag, 2007 http://en.wikipedia.org/wiki/Ferdinand_Georg_Frobenius
  17. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 K.T. Tang, “Mathematical Methods for Engineers and Scientists”, Vol 3, Springer-Verlag, 2007 http://en.wikipedia.org/wiki/Ferdinand_Georg_Frobenius
  18. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 K.T. Tang, “Mathematical Methods for Engineers and Scientists”, Vol 3, Springer-Verlag, 2007 http://en.wikipedia.org/wiki/Ferdinand_Georg_Frobenius
  19. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 K.T. Tang, “Mathematical Methods for Engineers and Scientists”, Vol 3, Springer-Verlag, 2007 http://en.wikipedia.org/wiki/Ferdinand_Georg_Frobenius
  20. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 K.T. Tang, “Mathematical Methods for Engineers and Scientists”, Vol 3, Springer-Verlag, 2007 http://en.wikipedia.org/wiki/Ferdinand_Georg_Frobenius
  21. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 K.T. Tang, “Mathematical Methods for Engineers and Scientists”, Vol 3, Springer-Verlag, 2007 http://en.wikipedia.org/wiki/Ferdinand_Georg_Frobenius
  22. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 K.T. Tang, “Mathematical Methods for Engineers and Scientists”, Vol 3, Springer-Verlag, 2007 http://en.wikipedia.org/wiki/Ferdinand_Georg_Frobenius
  23. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 K.T. Tang, “Mathematical Methods for Engineers and Scientists”, Vol 3, Springer-Verlag, 2007 http://en.wikipedia.org/wiki/Ferdinand_Georg_Frobenius
  24. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 K.T. Tang, “Mathematical Methods for Engineers and Scientists”, Vol 3, Springer-Verlag, 2007 http://en.wikipedia.org/wiki/Ferdinand_Georg_Frobenius
  25. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 K.T. Tang, “Mathematical Methods for Engineers and Scientists”, Vol 3, Springer-Verlag, 2007 http://en.wikipedia.org/wiki/Ferdinand_Georg_Frobenius
  26. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  27. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  28. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  29. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  30. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  31. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001 W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  32. http://www.serc.iisc.ernet.in/~amohanty/SE288/l.pdf
  33. Wallace, P.R., “Mathematical Analysis of Physical Problems”, Dover 1972, 1984
  34. Wallace, P.R., “Mathematical Analysis of Physical Problems”, Dover 1972, 1984
  35. W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  36. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  37. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  38. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  39. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  40. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  41. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  42. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  43. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  44. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  45. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  46. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  47. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  48. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  49. L.C. Andrews, “Special Functions for Engineers and Applied Mathematics”, MacMillan Publishing Companie, 1985 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001 http://en.wikipedia.org/wiki/Franz_Ernst_Neumann http://journals.cambridge.org/action/displayAbstract;jsessionid=4BE79E68247E19A6FFC459F00AAFE923.journals?fromPage=online&amp;aid=2061924 S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  50. http://en.wikipedia.org/wiki/Legendre_polynomials
  51. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  52. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  53. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  54. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  55. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  56. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  57. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 “Handbook of Mathematical Functions with Formulas, Graphs, and Mathematical Tables”, M. Abramowitz, I. Stegun
  58. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  59. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  60. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  61. http://mathworld.wolfram.com/LegendreFunctionoftheSecondKind.html
  62. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  63. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  64. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  65. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  66. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  67. W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  68. W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  69. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 “Handbook of Mathematical Functions with Formulas, Graphs, and Mathematical Tables”, M. Abramowitz, I. Stegun
  70. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  71. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  72. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  73. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  74. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  75. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  76. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  77. S.I. Hayek, “Advanced Mathematical Methods in Science and Engineering”, Marcel Dekker Inc., 2001
  78. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  79. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  80. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  81. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  82. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  83. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  84. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  85. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  86. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  87. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  88. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  89. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  90. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  91. Wallace, P.R., “Mathematical Analysis of PhysicaL Problems”, Dover 1972, 1984
  92. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  93. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  94. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  95. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  96. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  97. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  98. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  99. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  100. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  101. http://en.wikipedia.org/wiki/
  102. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  103. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  104. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  105. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  106. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  107. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  108. W. W. Bell, “Special Functions for Scientists and Engineers”, D. van Nostrand Company ltd., 1968
  109. Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001
  110. Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001
  111. Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001
  112. Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001
  113. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  114. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  115. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  116. http://en.wikipedia.org/wiki/Spherical_Harmonics
  117. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin
  118. G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin Wallace, P.R., “Mathematical Analysis of Physical Problems”, Dover 1972, 1984 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001
  119. http://en.wikipedia.org/wiki/Spherical_Harmonics G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin Wallace, P.R., “Mathematical Analysis of Physical Problems”, Dover 1972, 1984 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001
  120. http://en.wikipedia.org/wiki/Spherical_Harmonics G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin Wallace, P.R., “Mathematical Analysis of Physical Problems”, Dover 1972, 1984 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001
  121. http://en.wikipedia.org/wiki/Spherical_Harmonics G.M. Wysin, “Associated Legendre Functions and Dipole Transition Matrix Elements”, http://www.phys.ksu.edu/personal/wysin Wallace, P.R., “Mathematical Analysis of Physical Problems”, Dover 1972, 1984 Afken, Weber, “Mathematical Methods for Physicists”, Harcourt Academic Press, 5th Ed., 2001
  122. http://en.wikipedia.org/wiki/Spherical_Harmonics
  123. http://en.wikipedia.org/wiki/Spherical_Harmonics
  124. Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  125. Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  126. Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations” http://en.wikipedia.org/wiki/Lagrange’s_identity_(boundary_value_problem)
  127. Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations” http://en.wikipedia.org/wiki/Lagrange’s_identity_(boundary_value_problem)
  128. Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations” http://en.wikipedia.org/wiki/Lagrange’s_identity_(boundary_value_problem)
  129. Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations” http://en.wikipedia.org/wiki/Lagrange’s_identity_(boundary_value_problem)
  130. Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  131. Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  132. Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  133. Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  134. Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  135. Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  136. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001”
  137. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”
  138. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001
  139. Arfken, Weber, “Mathematical Methods for the Physicists”, 5 Ed., Harcourt – Academic Press, 2001 Nagle, Saff, Snider, “Fundamentals of Differential Equations and Boundary Value Problems“, 4th Ed., Pearson/Addison Wesley, 2004, Ch. 11, “Eigenvalue Problems and Sturm-Liouville Equations”