SlideShare ist ein Scribd-Unternehmen logo
1 von 25
Lecture 5 – Rigid bodies: Moment 3D
What you will learn for today?
1. Moment of a force about a point in 3D
2. Moment of a force about an axis in 3D
• Angle between two vectors
• Nearest distance between two vectors
3. Example and exercise
By: Ts. Dr. Muhammad Hanif Ramlee
Credit to: Prof. Dato’ Ir. Dr. Mohammed Rafiq Abdul Kadir
Moment of a force about a point (3D)
Vector identity:
Cross Product (×)
Q

P
P
Q
Q
P
PQ
P
Q
PQ
Q
P










sin
sin
RIGHT HAND RULE
{ + k }
{ - k }
Moment of a force about a point (3D)
Definition of Moment about a point
F
r
M 
 where r = position vector
Start – the point where moment is taken
End – the point where the force acts
k
F
j
F
i
F
F
k
r
j
r
i
r
r
z
y
x
z
y
x






   
k
F
j
F
i
F
k
r
j
r
i
r
M z
y
x
z
y
x 





Moment of a force about a point (3D)
In 3D analysis, r and F are resolved into x, y, and z components.
sin  = 0 or 1
j
k
i
k
j
i
i
i






 0
i
k
j
j
j
k
i
j







0
0







k
k
i
j
k
j
i
k
           
     k
F
r
F
r
j
F
r
F
r
i
F
r
F
r
M
i
F
r
j
F
r
i
F
r
k
F
r
j
F
r
k
F
r
M
x
y
y
x
z
x
x
z
y
z
z
y
y
z
x
z
z
y
x
y
z
x
y
x












Moment of a force about a point (3D)
The equation can also be solved using determinant
x
x
F
r
i
y
y
F
r
j
z
z
F
r
k
           
     k
F
r
F
r
j
F
r
F
r
i
F
r
F
r
M
j
F
r
i
F
r
k
F
r
k
F
r
j
F
r
i
F
r
M
x
y
y
x
z
x
x
z
y
z
z
y
z
x
y
z
x
y
y
x
x
z
z
y












x
x
F
r
i
y
y
F
r
j
Example 1
b) Determine the shortest distance between point A and line of action of the force
a) Determine the moment of force F = 3000N about a point A.
x
y
z
D
2.2m
2.0m
0.4m
O
C
A
1.2m
Example 1
Nk
Nj
Ni
F
k
j
i
F
k
d
d
j
d
d
i
d
d
F
F
F
F
CD
CD
z
y
x
CD
CD
CD
CD
CD
2200
2000
400
3
2
.
2
3
0
.
2
3
4
.
0
3000


























 
Solutions for (a)
x
y
z
D
2.2m
2.0m
0.4m
O
C
A
1.2m
CD
AD
CD
AC
A F
r
F
r
M 



Example 1
   
       
       
Nmk
Nmj
Nmi
M
Nmi
Nmj
Nmi
Nmk
M
i
N
m
j
N
m
i
N
m
k
N
m
M
Nk
Nj
Ni
mk
mj
M
F
r
M
A
A
A
A
CD
AC
A
800
480
6800
2400
480
4400
800
2000
2
.
1
400
2
.
1
2200
0
.
2
400
0
.
2
2200
2000
400
2
.
1
0
.
2























r can be chosen from either rAC or rAD.
mk
mi
r
mk
mj
r
AD
AC
4
.
3
4
.
0
2
.
1
0
.
2





lets choose rAC
Example 1
 
m
F
M
d
Nm
M
M
M
M
M
M
F
M
d
d
F
M
A
A
A
z
y
x
A
A
A
288
.
2
3000
7
.
6863
7
.
6863
800
480
6800 2
2
2
2
2
2















Solutions for (b)
Moment of a force about a point (3D)
Vector identity:
Dot Product (·), is a scalar.
Q

P
P
Q
Q
P
PQ
P
Q
PQ
Q
P










cos
cos
Direction
not
associated
Moment of a force about a point (3D)
In 3D analysis, vectors are resolved into x, y, and z components.
cos  = 1 or 0
0
0
1






k
i
j
i
i
i
0
1
0






k
j
j
j
i
j
1
0
0






k
k
j
k
i
k
Moment of a force about a point (3D)
The dot product is used to determine:
The angle between two vectors
The moment of a force about an axis
The perpendicular / 90° / nearest distance between two
vectors (the line of action)
The angle between two vectors
    
cos
PQ
k
Q
j
Q
i
Q
k
P
j
P
i
P z
y
x
z
y
x 






cos
PQ
Q
P 

k
Q
j
Q
i
Q
Q
k
P
j
P
i
P
P
z
y
x
z
y
x






Q

P
2
2
2
z
y
x P
P
P
P 


2
2
2
z
y
x Q
Q
Q
Q 


  
cos
PQ
Q
P
Q
P
Q
P z
z
y
y
x
x 


 
PQ
Q
P
Q
P
Q
P z
z
y
y
x
x 


 
cos
Example 2
Determine the angle between vectors P = 6i +6j – 7k and Q = -6i +33j -30k
 
PQ
Q
P
Q
P
Q
P z
z
y
y
x
x 



cos
         372
30
7
33
6
6
6 







 z
z
y
y
x
x Q
P
Q
P
Q
P
  11
7
6
6
2
2
2
2
2
2







 z
y
x P
P
P
P
    45
30
33
6
2
2
2
2
2
2








 z
y
x Q
Q
Q
Q
  

38
.
41
7515
.
0
45
11
372
cos





Moment of a force about an axis
B
AB
AB
A
AB
AB
M
M
or
M
M






int
po
axis
axis M
M 
 
definition
application
where
MAB = moment of force F about axis AB
AB = unit vector from A to B
MA or MB = moment of force F about point A or point B
Example 3
Determine the moment of force F = 3000N about the axis AB.
x
y
z
2.2m
2.0m
0.4m
2.4m
2.4m
1.2m
C
D
A
B
Example 3
A
AB
AB M
M 
  B
AB
AB M
M 
 
int
po
axis
axis M
M 
 
Solution
       
CD
BD
AB
CD
BC
AB
CD
AD
AB
CD
AC
AB
AB F
r
F
r
F
r
F
r
M 










 



Observe that AB and FCD are common to all equations, the difference lies in the
position vector, r. Unless otherwise stated, it is advisable to choose the ‘simplest’ r.
Example 3
Solution
k
j
i
k
j
i
k
d
d
j
d
d
i
d
d
k
j
i
Z
Y
X
ABz
ABy
ABx
AB

































 














3
1
3
2
3
2
6
.
3
2
.
1
6
.
3
4
.
2
6
.
3
4
.
2




Example 3
Solution
Nk
Nj
Ni
F
k
j
i
F
k
d
d
j
d
d
i
d
d
F
F
F
F
Z
Y
X
CD
CD
CD
2200
2000
400
3
2
.
2
3
0
.
2
3
4
.
0
3000






















 






 










 
Example 3
Solution
mk
mj
mi
r
mj
mi
r
mk
mi
r
mk
mj
r
BD
BC
AD
AC
2
.
2
4
.
2
8
.
2
4
.
4
4
.
2
4
.
3
4
.
0
2
.
1
0
.
2












Example 3
 
CD
AC
axis
axis F
r
M 

 
Solution
   
 
   
   
   
   
 
 
Nm
Nmk
Nmj
Nmi
k
j
i
Nmi
Nmj
Nmi
Nmk
k
j
i
i
N
m
j
N
m
i
N
m
k
N
m
k
j
i
Nk
Nj
Ni
mk
mj
k
j
i
5120
3
800
3
960
3
13600
800
480
6800
3
1
3
2
3
2
2400
480
4400
800
3
1
3
2
3
2
2000
2
.
1
400
2
.
1
2200
0
.
2
400
0
.
2
3
1
3
2
3
2
2200
2000
400
2
.
1
0
.
2
3
1
3
2
3
2


















































































Nearest distance between two vectors
2
2
parallel
lar
Perpendicu F
F
F 

d
F
M lar
Perpendicu
axis 
F
F AB
parallel 
 
The component of a vector (F) that is parallel to an axis (AB) is given by
The perpendicular component of the vector is
From the definition of moment about an axis
Where d = perpendicular distance
lar
Perpendicu
axis
F
M
d 

Example 4
Determine the shortest distance between the line of action of force
F = -400Ni – 2000Nj +2200Nk and the line AB.
x
y
z
2.2m
2.0m
0.4m
2.4m
2.4m
1.2m
C
D
A
B
Example 4
Nm
M
M AB
axis 5120


 
     
m
F
M
d
N
F
N
N
N
N
Nk
Nj
Ni
k
j
i
F
F
F
F
F
lar
perpendicu
axis
lar
perpendicu
AB
parallel
parallel
lar
Perpendicu
133
.
2
2400
5120
2400
3
5400
3000
3
5400
2200
3
1
2000
3
2
400
3
2
2200
2000
400
3
1
3
2
3
2
2
2
2
2










































Solution
N
F 3000

Exercise 1
x
y
z
0.15m
0.25m
0.1m
A
B
O
F=150N
0.3m
C
Determine the moment of the F = 150N force about the diagonal BA.
Answer:
MAB = 14.52 Nm

Weitere ähnliche Inhalte

Ähnlich wie dynamics and static for the advanced Moments 3D.ppt

Pure-bending of curved bar
Pure-bending of curved barPure-bending of curved bar
Pure-bending of curved bar
Pratish Sardar
 
Pure bending of curved bar (polar coordinate)
 Pure bending of curved bar (polar coordinate) Pure bending of curved bar (polar coordinate)
Pure bending of curved bar (polar coordinate)
Pratish Sardar
 
Mekanikateknik 140330175907-phpapp01
Mekanikateknik 140330175907-phpapp01Mekanikateknik 140330175907-phpapp01
Mekanikateknik 140330175907-phpapp01
frans2014
 

Ähnlich wie dynamics and static for the advanced Moments 3D.ppt (20)

ME 245_ 2.pptx
ME 245_ 2.pptxME 245_ 2.pptx
ME 245_ 2.pptx
 
Aakash JEE Advance Solution Paper2
Aakash JEE Advance Solution Paper2Aakash JEE Advance Solution Paper2
Aakash JEE Advance Solution Paper2
 
Good physics equations sheet
Good physics equations sheetGood physics equations sheet
Good physics equations sheet
 
Pure-bending of curved bar
Pure-bending of curved barPure-bending of curved bar
Pure-bending of curved bar
 
Lecture Notes For Section 4.5
Lecture  Notes For  Section 4.5Lecture  Notes For  Section 4.5
Lecture Notes For Section 4.5
 
Ch27 ssm
Ch27 ssmCh27 ssm
Ch27 ssm
 
Physics Formula list (3)
Physics Formula list (3)Physics Formula list (3)
Physics Formula list (3)
 
Pure bending of curved bar (polar coordinate)
 Pure bending of curved bar (polar coordinate) Pure bending of curved bar (polar coordinate)
Pure bending of curved bar (polar coordinate)
 
Solution i ph o 26
Solution i ph o 26Solution i ph o 26
Solution i ph o 26
 
Solution 3 i ph o 35
Solution 3 i ph o 35Solution 3 i ph o 35
Solution 3 i ph o 35
 
Physics formulas
Physics formulasPhysics formulas
Physics formulas
 
Ch 3_rajib1.pptx
Ch 3_rajib1.pptxCh 3_rajib1.pptx
Ch 3_rajib1.pptx
 
Ks
KsKs
Ks
 
Formul me-3074683 Erdi Karaçal Mechanical Engineer University of Gaziantep
Formul me-3074683 Erdi Karaçal Mechanical Engineer University of GaziantepFormul me-3074683 Erdi Karaçal Mechanical Engineer University of Gaziantep
Formul me-3074683 Erdi Karaçal Mechanical Engineer University of Gaziantep
 
Me307 machine elements formula sheet Erdi Karaçal Mechanical Engineer Univers...
Me307 machine elements formula sheet Erdi Karaçal Mechanical Engineer Univers...Me307 machine elements formula sheet Erdi Karaçal Mechanical Engineer Univers...
Me307 machine elements formula sheet Erdi Karaçal Mechanical Engineer Univers...
 
RCC BMD
RCC BMDRCC BMD
RCC BMD
 
Mekanikateknik 140330175907-phpapp01
Mekanikateknik 140330175907-phpapp01Mekanikateknik 140330175907-phpapp01
Mekanikateknik 140330175907-phpapp01
 
Mekanika teknik
Mekanika teknikMekanika teknik
Mekanika teknik
 
10-design of singly reinforced beams
10-design of singly reinforced beams10-design of singly reinforced beams
10-design of singly reinforced beams
 
Shear Force and Bending Moment Diagram
Shear Force and Bending Moment DiagramShear Force and Bending Moment Diagram
Shear Force and Bending Moment Diagram
 

Kürzlich hochgeladen

Presentation on 3D Printing.pptx presentation
Presentation on 3D Printing.pptx presentationPresentation on 3D Printing.pptx presentation
Presentation on 3D Printing.pptx presentation
ajroy0196
 
一比一原版格林威治大学毕业证成绩单如何办理
一比一原版格林威治大学毕业证成绩单如何办理一比一原版格林威治大学毕业证成绩单如何办理
一比一原版格林威治大学毕业证成绩单如何办理
cyebo
 
在线购买田纳西大学毕业证(utk毕业证)硕士学历证书留信网认证原版一模一样
在线购买田纳西大学毕业证(utk毕业证)硕士学历证书留信网认证原版一模一样在线购买田纳西大学毕业证(utk毕业证)硕士学历证书留信网认证原版一模一样
在线购买田纳西大学毕业证(utk毕业证)硕士学历证书留信网认证原版一模一样
ykucop
 
NO1 Best Vashikaran Specialist in Uk Black Magic Specialist in Uk Black Magic...
NO1 Best Vashikaran Specialist in Uk Black Magic Specialist in Uk Black Magic...NO1 Best Vashikaran Specialist in Uk Black Magic Specialist in Uk Black Magic...
NO1 Best Vashikaran Specialist in Uk Black Magic Specialist in Uk Black Magic...
Amil baba
 
Week 11 Mini-Tasks.pptxjjjjjjjjjjjjjjjjjjjj
Week 11 Mini-Tasks.pptxjjjjjjjjjjjjjjjjjjjjWeek 11 Mini-Tasks.pptxjjjjjjjjjjjjjjjjjjjj
Week 11 Mini-Tasks.pptxjjjjjjjjjjjjjjjjjjjj
joshuaclack73
 
如何办理(RUG毕业证书)格罗宁根大学毕业证成绩单本科硕士学位证留信学历认证
如何办理(RUG毕业证书)格罗宁根大学毕业证成绩单本科硕士学位证留信学历认证如何办理(RUG毕业证书)格罗宁根大学毕业证成绩单本科硕士学位证留信学历认证
如何办理(RUG毕业证书)格罗宁根大学毕业证成绩单本科硕士学位证留信学历认证
ugzga
 
100^%)( MAYIBUYE))(*((+27838792658))*))௹ )Abortion Pills for Sale in Soweto, ...
100^%)( MAYIBUYE))(*((+27838792658))*))௹ )Abortion Pills for Sale in Soweto, ...100^%)( MAYIBUYE))(*((+27838792658))*))௹ )Abortion Pills for Sale in Soweto, ...
100^%)( MAYIBUYE))(*((+27838792658))*))௹ )Abortion Pills for Sale in Soweto, ...
drjose256
 
NO1 Best Best Amil In Rawalpindi Bangali Baba In Rawalpindi jadu tona karne w...
NO1 Best Best Amil In Rawalpindi Bangali Baba In Rawalpindi jadu tona karne w...NO1 Best Best Amil In Rawalpindi Bangali Baba In Rawalpindi jadu tona karne w...
NO1 Best Best Amil In Rawalpindi Bangali Baba In Rawalpindi jadu tona karne w...
Amil baba
 
挂科办理天主教大学毕业证成绩单一模一样品质
挂科办理天主教大学毕业证成绩单一模一样品质挂科办理天主教大学毕业证成绩单一模一样品质
挂科办理天主教大学毕业证成绩单一模一样品质
yzeoq
 
Knowing, Understanding and Planning Cities- Role and Relevance Physical Plan...
Knowing, Understanding and Planning Cities- Role and Relevance  Physical Plan...Knowing, Understanding and Planning Cities- Role and Relevance  Physical Plan...
Knowing, Understanding and Planning Cities- Role and Relevance Physical Plan...
JIT KUMAR GUPTA
 

Kürzlich hochgeladen (20)

Presentation on 3D Printing.pptx presentation
Presentation on 3D Printing.pptx presentationPresentation on 3D Printing.pptx presentation
Presentation on 3D Printing.pptx presentation
 
一比一原版格林威治大学毕业证成绩单如何办理
一比一原版格林威治大学毕业证成绩单如何办理一比一原版格林威治大学毕业证成绩单如何办理
一比一原版格林威治大学毕业证成绩单如何办理
 
Avoid these common UI/UX design mistakes
 Avoid these common UI/UX design mistakes Avoid these common UI/UX design mistakes
Avoid these common UI/UX design mistakes
 
在线购买田纳西大学毕业证(utk毕业证)硕士学历证书留信网认证原版一模一样
在线购买田纳西大学毕业证(utk毕业证)硕士学历证书留信网认证原版一模一样在线购买田纳西大学毕业证(utk毕业证)硕士学历证书留信网认证原版一模一样
在线购买田纳西大学毕业证(utk毕业证)硕士学历证书留信网认证原版一模一样
 
The Journey of Fashion Designer Sketches - From Concept to Catwalk
The Journey of Fashion Designer Sketches - From Concept to CatwalkThe Journey of Fashion Designer Sketches - From Concept to Catwalk
The Journey of Fashion Designer Sketches - From Concept to Catwalk
 
Real Smart Art Infographics by Slidesgo.pptx
Real Smart Art Infographics by Slidesgo.pptxReal Smart Art Infographics by Slidesgo.pptx
Real Smart Art Infographics by Slidesgo.pptx
 
Explaining the Hidden Treasures of Modern Bathroom Design — freixadesign.pdf
Explaining the Hidden Treasures of Modern Bathroom Design — freixadesign.pdfExplaining the Hidden Treasures of Modern Bathroom Design — freixadesign.pdf
Explaining the Hidden Treasures of Modern Bathroom Design — freixadesign.pdf
 
BIT Khushi gandhi project.pdf graphic design
BIT Khushi gandhi project.pdf graphic designBIT Khushi gandhi project.pdf graphic design
BIT Khushi gandhi project.pdf graphic design
 
NO1 Best Vashikaran Specialist in Uk Black Magic Specialist in Uk Black Magic...
NO1 Best Vashikaran Specialist in Uk Black Magic Specialist in Uk Black Magic...NO1 Best Vashikaran Specialist in Uk Black Magic Specialist in Uk Black Magic...
NO1 Best Vashikaran Specialist in Uk Black Magic Specialist in Uk Black Magic...
 
The Impact of Artificial Intelligence on Modern Healthcare.pptx
The Impact of Artificial Intelligence on Modern Healthcare.pptxThe Impact of Artificial Intelligence on Modern Healthcare.pptx
The Impact of Artificial Intelligence on Modern Healthcare.pptx
 
Week of Action 2022_EIT Climate-KIC_Headers
Week of Action 2022_EIT Climate-KIC_HeadersWeek of Action 2022_EIT Climate-KIC_Headers
Week of Action 2022_EIT Climate-KIC_Headers
 
Week 11 Mini-Tasks.pptxjjjjjjjjjjjjjjjjjjjj
Week 11 Mini-Tasks.pptxjjjjjjjjjjjjjjjjjjjjWeek 11 Mini-Tasks.pptxjjjjjjjjjjjjjjjjjjjj
Week 11 Mini-Tasks.pptxjjjjjjjjjjjjjjjjjjjj
 
如何办理(RUG毕业证书)格罗宁根大学毕业证成绩单本科硕士学位证留信学历认证
如何办理(RUG毕业证书)格罗宁根大学毕业证成绩单本科硕士学位证留信学历认证如何办理(RUG毕业证书)格罗宁根大学毕业证成绩单本科硕士学位证留信学历认证
如何办理(RUG毕业证书)格罗宁根大学毕业证成绩单本科硕士学位证留信学历认证
 
100^%)( MAYIBUYE))(*((+27838792658))*))௹ )Abortion Pills for Sale in Soweto, ...
100^%)( MAYIBUYE))(*((+27838792658))*))௹ )Abortion Pills for Sale in Soweto, ...100^%)( MAYIBUYE))(*((+27838792658))*))௹ )Abortion Pills for Sale in Soweto, ...
100^%)( MAYIBUYE))(*((+27838792658))*))௹ )Abortion Pills for Sale in Soweto, ...
 
Design Portofolios - Licensed Architect / BIM Specialist
Design Portofolios - Licensed Architect / BIM SpecialistDesign Portofolios - Licensed Architect / BIM Specialist
Design Portofolios - Licensed Architect / BIM Specialist
 
Recycled Modular Low Cost Construction .pdf
Recycled Modular Low Cost Construction .pdfRecycled Modular Low Cost Construction .pdf
Recycled Modular Low Cost Construction .pdf
 
Cascading Style Sheet(CSS) PDF Notes by Apna College
Cascading Style Sheet(CSS) PDF Notes by Apna CollegeCascading Style Sheet(CSS) PDF Notes by Apna College
Cascading Style Sheet(CSS) PDF Notes by Apna College
 
NO1 Best Best Amil In Rawalpindi Bangali Baba In Rawalpindi jadu tona karne w...
NO1 Best Best Amil In Rawalpindi Bangali Baba In Rawalpindi jadu tona karne w...NO1 Best Best Amil In Rawalpindi Bangali Baba In Rawalpindi jadu tona karne w...
NO1 Best Best Amil In Rawalpindi Bangali Baba In Rawalpindi jadu tona karne w...
 
挂科办理天主教大学毕业证成绩单一模一样品质
挂科办理天主教大学毕业证成绩单一模一样品质挂科办理天主教大学毕业证成绩单一模一样品质
挂科办理天主教大学毕业证成绩单一模一样品质
 
Knowing, Understanding and Planning Cities- Role and Relevance Physical Plan...
Knowing, Understanding and Planning Cities- Role and Relevance  Physical Plan...Knowing, Understanding and Planning Cities- Role and Relevance  Physical Plan...
Knowing, Understanding and Planning Cities- Role and Relevance Physical Plan...
 

dynamics and static for the advanced Moments 3D.ppt

  • 1. Lecture 5 – Rigid bodies: Moment 3D What you will learn for today? 1. Moment of a force about a point in 3D 2. Moment of a force about an axis in 3D • Angle between two vectors • Nearest distance between two vectors 3. Example and exercise By: Ts. Dr. Muhammad Hanif Ramlee Credit to: Prof. Dato’ Ir. Dr. Mohammed Rafiq Abdul Kadir
  • 2. Moment of a force about a point (3D) Vector identity: Cross Product (×) Q  P P Q Q P PQ P Q PQ Q P           sin sin RIGHT HAND RULE { + k } { - k }
  • 3. Moment of a force about a point (3D) Definition of Moment about a point F r M   where r = position vector Start – the point where moment is taken End – the point where the force acts k F j F i F F k r j r i r r z y x z y x           k F j F i F k r j r i r M z y x z y x      
  • 4. Moment of a force about a point (3D) In 3D analysis, r and F are resolved into x, y, and z components. sin  = 0 or 1 j k i k j i i i        0 i k j j j k i j        0 0        k k i j k j i k                  k F r F r j F r F r i F r F r M i F r j F r i F r k F r j F r k F r M x y y x z x x z y z z y y z x z z y x y z x y x            
  • 5. Moment of a force about a point (3D) The equation can also be solved using determinant x x F r i y y F r j z z F r k                  k F r F r j F r F r i F r F r M j F r i F r k F r k F r j F r i F r M x y y x z x x z y z z y z x y z x y y x x z z y             x x F r i y y F r j
  • 6. Example 1 b) Determine the shortest distance between point A and line of action of the force a) Determine the moment of force F = 3000N about a point A. x y z D 2.2m 2.0m 0.4m O C A 1.2m
  • 8. Example 1                     Nmk Nmj Nmi M Nmi Nmj Nmi Nmk M i N m j N m i N m k N m M Nk Nj Ni mk mj M F r M A A A A CD AC A 800 480 6800 2400 480 4400 800 2000 2 . 1 400 2 . 1 2200 0 . 2 400 0 . 2 2200 2000 400 2 . 1 0 . 2                        r can be chosen from either rAC or rAD. mk mi r mk mj r AD AC 4 . 3 4 . 0 2 . 1 0 . 2      lets choose rAC
  • 9. Example 1   m F M d Nm M M M M M M F M d d F M A A A z y x A A A 288 . 2 3000 7 . 6863 7 . 6863 800 480 6800 2 2 2 2 2 2                Solutions for (b)
  • 10. Moment of a force about a point (3D) Vector identity: Dot Product (·), is a scalar. Q  P P Q Q P PQ P Q PQ Q P           cos cos Direction not associated
  • 11. Moment of a force about a point (3D) In 3D analysis, vectors are resolved into x, y, and z components. cos  = 1 or 0 0 0 1       k i j i i i 0 1 0       k j j j i j 1 0 0       k k j k i k
  • 12. Moment of a force about a point (3D) The dot product is used to determine: The angle between two vectors The moment of a force about an axis The perpendicular / 90° / nearest distance between two vectors (the line of action)
  • 13. The angle between two vectors      cos PQ k Q j Q i Q k P j P i P z y x z y x        cos PQ Q P   k Q j Q i Q Q k P j P i P P z y x z y x       Q  P 2 2 2 z y x P P P P    2 2 2 z y x Q Q Q Q       cos PQ Q P Q P Q P z z y y x x      PQ Q P Q P Q P z z y y x x      cos
  • 14. Example 2 Determine the angle between vectors P = 6i +6j – 7k and Q = -6i +33j -30k   PQ Q P Q P Q P z z y y x x     cos          372 30 7 33 6 6 6          z z y y x x Q P Q P Q P   11 7 6 6 2 2 2 2 2 2         z y x P P P P     45 30 33 6 2 2 2 2 2 2          z y x Q Q Q Q     38 . 41 7515 . 0 45 11 372 cos     
  • 15. Moment of a force about an axis B AB AB A AB AB M M or M M       int po axis axis M M    definition application where MAB = moment of force F about axis AB AB = unit vector from A to B MA or MB = moment of force F about point A or point B
  • 16. Example 3 Determine the moment of force F = 3000N about the axis AB. x y z 2.2m 2.0m 0.4m 2.4m 2.4m 1.2m C D A B
  • 17. Example 3 A AB AB M M    B AB AB M M    int po axis axis M M    Solution         CD BD AB CD BC AB CD AD AB CD AC AB AB F r F r F r F r M                 Observe that AB and FCD are common to all equations, the difference lies in the position vector, r. Unless otherwise stated, it is advisable to choose the ‘simplest’ r.
  • 21. Example 3   CD AC axis axis F r M     Solution                           Nm Nmk Nmj Nmi k j i Nmi Nmj Nmi Nmk k j i i N m j N m i N m k N m k j i Nk Nj Ni mk mj k j i 5120 3 800 3 960 3 13600 800 480 6800 3 1 3 2 3 2 2400 480 4400 800 3 1 3 2 3 2 2000 2 . 1 400 2 . 1 2200 0 . 2 400 0 . 2 3 1 3 2 3 2 2200 2000 400 2 . 1 0 . 2 3 1 3 2 3 2                                                                                  
  • 22. Nearest distance between two vectors 2 2 parallel lar Perpendicu F F F   d F M lar Perpendicu axis  F F AB parallel    The component of a vector (F) that is parallel to an axis (AB) is given by The perpendicular component of the vector is From the definition of moment about an axis Where d = perpendicular distance lar Perpendicu axis F M d  
  • 23. Example 4 Determine the shortest distance between the line of action of force F = -400Ni – 2000Nj +2200Nk and the line AB. x y z 2.2m 2.0m 0.4m 2.4m 2.4m 1.2m C D A B
  • 24. Example 4 Nm M M AB axis 5120           m F M d N F N N N N Nk Nj Ni k j i F F F F F lar perpendicu axis lar perpendicu AB parallel parallel lar Perpendicu 133 . 2 2400 5120 2400 3 5400 3000 3 5400 2200 3 1 2000 3 2 400 3 2 2200 2000 400 3 1 3 2 3 2 2 2 2 2                                           Solution N F 3000 
  • 25. Exercise 1 x y z 0.15m 0.25m 0.1m A B O F=150N 0.3m C Determine the moment of the F = 150N force about the diagonal BA. Answer: MAB = 14.52 Nm