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Work and Energy
Chapter 9
Pg.144-
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Work
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         What do you think?
 List   five examples of things you have done in the
    last year that you would consider work.
 Based     on these examples, how do you define
    work?
+
    Work

     Inphysics, work is the magnitude of the force (F)
     times the magnitude of the displacement (d) in
     the same direction as the force.
    W     = Fd
     What    are the SI units for work?
      Force units (N) distance units    (m)
      N•m are also called joules (J).

     How     much work is 1 joule?
      Liftan apple weighing about 1 N from the floor to
       the desk, a distance of about 1 m.
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    Work


     Ifwe lift two loads, we do twice as much
      work as lifting one load the same
      distance, because the force needed is
      twice as great.
     Ifwe lift one load twice as far, we do twice
      as much work because the distance is
      twice as great.
+
    Work


     Work  is done in lifting
     the barbell. If the barbell
     could be lifted twice as
     high, the weight lifter
     would have to do twice
     as much work.
+
    Work

     Whilethe weight lifter is holding a barbell
     over his head, he may get really tired, but
     he does no work on the barbell.
     Work may be done on the muscles by
     stretching and squeezing them, but this
     work is not done on the barbell.
     When  the weight lifter raises the barbell,
     he is doing work on it.
+
    Classroom Practice Problem

     A 20.0kg suitcase is raised 3.0 m above a
     platform. How much work is done on the
     suitcase?
      Answer:   600 J
     Suppose  that you apply a 60-N horizontal
     force to a 32-kg package, which pushes it
     4 meters across a mailroom floor. How
     much work do you do on the package?
     W   = Fd = 60 N × 4 m = 240 J
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    Work is a Scalar

                        Work  can be
                        positive or
                        negative but does
                        not have a
                        direction.
+
    Sign of Work is Important
 Work    is positive
     Force   is in the same direction as the displacement
 Work    is negative
     Forceis in a different direction as the
     displacement
 Sing   of the net work lets you know if the object
    is speeding up or down
    +   for speeding up and work is being on object
     - for slowing down and work is done by object
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Energy
+
    Kinetic Energy


    Energy     associated with an object in
     motion              Wnet = Fd = mad
    Since     v2f = v2i + 2ad
                                                              v2
                                                               f       vi2
    Then
                             2       2            Wnet   m(                  )
                         v   f       v
                                     i                             2
                ad
                                 2
    Finally                     1 2      1 2
                  Wnet             mv f     mvi
                                 2        2
+
    Kinetic Energy
    Kinetic   energy depends on speed and
     mass
    The net work done on a body equals its
     change in kinetic energy
    SI   units for KE
      kg•m2/s2   or N•m or Joule (J)
+
    Example

 A 7.0    Kg bowling ball moves at 3.0 m/s. How
    fast must a 2.45g ping pong ball move in order
    to have the same kinetic energy as the bowling
    ball? Is the speed reasonable for the ping
    pong ball?
 Given:

 Bowling   ball: m- 7.0 kg   v= 3.0m/s
 Ping   pong: m= 2.45 g (this= 0.00245kg)   v-??
+
    Example

                                           2KE
     KE=   ½   mv2                   v
                                            m
     KE=   ½ (7)(32)
     KE=   31.5 J                        2(31.5)
                                  v
                                          0.00245
     Rearrange   Equation
     to get v by itself      v   = 160.36 m/s
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    Classroom Practice Problems


     A 6.00
           kg cat runs after a mouse at 10.0
     m/s. What is the cat’s kinetic energy?
      Answer:   3.00 x 102 J or 300 J
     Suppose  the above cat accelerated to a
     speed of 12.0 m/s while chasing the
     mouse. How much work was done on the
     cat to produce this change in speed?
      Answer:   1.32 x 102 J or 132 J
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    Work and Kinetic Energy

     KEis the work an object can do if the speed
     changes.
     Wnet
         is positive if the speed increases, and
     negative is speeds decrease
     You must include all the forces that do work
     on the object in calculating the net work done
+
    Potential Energy

     Energyassociated with an object’s potential
     to move due to an interaction with its
     environment basically its stored energy
      A book held above the desk
      An arrow ready to be released from the bow

     Some   types of PE are listed below.
      Gravitational
      Elastic
      Electromagnetic
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    Gravitational Potential Energy

     Energy associated with an object due to the
     object’s position relative to a gravitational
     source
     SI   unit is still a Joule
     Theheight (h) depends on the “zero level”
     chosen where PEg= 0.
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    Elastic Potential Energy

     Theenergy available for use in deformed elastic
     objects
        Rubber bands, springs in trampolines, pole-vault poles,
         muscles

     For    springs, the distance compressed or stretched =
         x
+
    Elastic Potential Energy

    The   spring constant (k) depends on the
     stiffness of the spring.
      Stiffer
            springs have higher k values.
      Measured in N/m
       Force in newtons needed to stretch a spring 1.0
        meters
+
    Example


     A 70.0kg  stuntman is attached to a bungee
     cord with an unstretched length of 15m. He
     jumps off a bridge from a height of 50m.
     When he finally stops the cord has a
     stretched length of 44m. Assuming the spring
     constant is 71.8 N/m, what is the total PE
     relative to the water when the man stops
     falling?
+
    Example
     Given:

     m=   70kg          k= 71.8 N/mg= 10m/s2
     h=   50m – 44m= 6m
     x=   44m – 15m= 29m
     PEg=   mgh
     PEelastic   = ½ k x2
     PEtotal=    PEg + PEelastic
+
    Example

     PEg=   mgh                    PEelastic   = ½ k x2
     PEg=   (70)(10)(6)            PEelastic=   ½ (71.8)(292)
     PEg=   4200 J                 PEelastic=   30191.9J


     PEtotal=   PEg + PEelastic
     PEtotal=   4200 + 30191.9
     PEtotal=   34391.9J
+
    Classroom Practice Problems

     When  a 2.00 kg mass is attached to a
     vertical spring, the spring is stretched 10.0
     cm such that the mass is 50.0 cm above the
     table.
      What  is the gravitational potential energy
       associated with the mass relative to the table?
        Answer: 9.81 J
      What is the spring’s elastic potential energy if
       the spring constant is 400.0 N/m?
        Answer: 2.00 J
+




5.3 Conservation of Energy
Pg. 173-178
+
    Mechanical Energy (ME)


     ME   = KE + PEg + PEelastic
      Doesnot include the many other types of
      energy, such as thermal energy, chemical
      potential energy, and others
     ME   is not a new form of energy.
      Just   a combination of KE and PE
+
    Conservation of Mechanical Energy

     The    sum of KE and PE remains constant.
     One type of energy changes into another
     type.
      For  the falling book, the PE of the book changed
       into KE as it fell.
      As a ball rolls up a hill, KE is changed into PE.
+
    Example


     Starting from rest, a child zooms down a
     frictionless slide from an initial height of
     3.0m. What is her speed at the bottom of
     the slide? Her mass is 25kg.
     Given:

     vi=   0m/s       hi= 3m   m=25kg
     vf=   ??     hf=0m
+
    Example
       *Choose your equations
     PE=    mgh            KE=    ½ mv2
     PEf=   (25)(10)(0)    KEf=   ½ (25)v2
     PEf=   0J             KEf=   ??
     PEi=   (25)(10)(3)    KEi=   ½ (25)(02)
     PEi=   750J           KEi=   0J
+
    Example
       *Put together
     PEi+    KEi= PEf+ KEf
     750    + 0 = 0 + ½ (25)vf2
     750=    12.5 vf2
     vf2   = √60
     vf=   7.75m/s
+
    Classroom Practice Problems

 Suppose    a 1.00 kg book is dropped from a height
    of 2.00 m. Assume no air resistance.
     Calculate the PE and the KE at the instant the book
      is released.
       Answer: PE = 19.6 J, KE = 0 J
     Calculate the KE and PE when the book has fallen
      1.0 m. (Hint: you will need an equation from Chapter
      2.)
       Answer: PE = 9.81 J, KE = 9.81 J
     Calculate the PE and the KE just as the book
      reaches the floor.
       Answer: PE = 0 J, KE = 19.6 J
+
    Table of Values for the Falling Book

     h (m)   PE(J)    KE(J)   ME(J)

     0       19.6     0       19.6

     0.5     14.7     4.9     19.6

     1.0     9.8      9.8     19.6

     1.5     4.9      14.7    19.6

     2.0     0        19.6    19.6
+
    Conservation of Energy
     Acceleration   does not have to be constant.
     ME   is not conserved if friction is present.
      If friction is negligible, conservation of ME is reasonably
       accurate.
        A pendulum as it swings back and forth a few times

     Consider a child going down a slide with friction.
      What happens to the ME as he slides down?
        Answer: It is not conserved but, instead, becomes less
         and less.
      The “lost” energy? is converted into nonmechanical
       energy (thermal energy).
+
    Classroom Practice Problems

     A small 10.0 g ball is held to a slingshot that
     is stretched 6.0 cm. The spring constant is
     2.0 102 N/m.
      What   is the elastic potential energy of the
       slingshot before release?
      What is the kinetic energy of the ball right after
       the slingshot is released?
      What is the ball’s speed at the instant it leaves
       the slingshot?
      How high does the ball rise if it is shot directly
       upward?
+




Power
+
            What do you think?

     Twocars are identical with one exception.
     One of the cars has a more powerful engine.
     How does having more power make the car
     behave differently?
      What does power mean?
      What units are used to measure power?
+
    Power


    Therate at which work is done or
    energy is transferred
     Energy    used or work done per second




     If   we substitute W for Fd then         Fd
                                         P
                                                t
+
    Power


     The unit of power is the joule per second,
     also known as the watt.
       One watt (W) of power is expended when
        one joule of work is done in one second.
       One kilowatt (kW) equals 1000 watts.
       One megawatt (MW) equals one million
        watts.
+
    Power

     SI   units for power are J/s.
      Calledwatts (W)
      Equivalent to kg•m2/s3

     Horsepower (hp) is a unit used in the
     Avoirdupois system.
      1.00   hp = 746 W
+
    Watts


     These  bulbs all consume
     different amounts of power.
     A 100watt bulb consumes
     100 joules of energy every
     second.
+
    Example


     A 193kg  curtain need to be raised 7.5m, at a
     constant speed, in as close to 5 sec as
     possible. Unsure which motor would be the
     best 3 motors were bought. Power ratings are
     1.0kW, 3.5kW, and 5.5kW. Which motor is
     best for the job?
     Given:

     m=   193kg    d= 7.5m   t= 5 sec   P=??
+
    Example




     P=2895   W or 2.895kW
     So
       the best motor would be the 3.5kW
     motor
+
    Classroom Practice Problems


     Two horses pull a cart. Each exerts a
     force of 250.0 N at a speed of 2.0 m/s for
     10.0 min.
      Calculate   the power delivered by the
       horses.
      How much work is done by the two horses?

     Answers:   1.0 x 103 W and 6.0 x 105 J
+
            Now what do you think?

     Twocars are identical with one exception.
     One of the cars has a more powerful engine.
     How does having more power make the car
     behave differently?
      What does power mean?
      What units are used to measure power?

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Work and energy

  • 3. + What do you think?  List five examples of things you have done in the last year that you would consider work.  Based on these examples, how do you define work?
  • 4. + Work  Inphysics, work is the magnitude of the force (F) times the magnitude of the displacement (d) in the same direction as the force. W = Fd  What are the SI units for work?  Force units (N) distance units (m)  N•m are also called joules (J).  How much work is 1 joule?  Liftan apple weighing about 1 N from the floor to the desk, a distance of about 1 m.
  • 5. + Work  Ifwe lift two loads, we do twice as much work as lifting one load the same distance, because the force needed is twice as great.  Ifwe lift one load twice as far, we do twice as much work because the distance is twice as great.
  • 6. + Work  Work is done in lifting the barbell. If the barbell could be lifted twice as high, the weight lifter would have to do twice as much work.
  • 7. + Work  Whilethe weight lifter is holding a barbell over his head, he may get really tired, but he does no work on the barbell.  Work may be done on the muscles by stretching and squeezing them, but this work is not done on the barbell.  When the weight lifter raises the barbell, he is doing work on it.
  • 8. + Classroom Practice Problem  A 20.0kg suitcase is raised 3.0 m above a platform. How much work is done on the suitcase?  Answer: 600 J  Suppose that you apply a 60-N horizontal force to a 32-kg package, which pushes it 4 meters across a mailroom floor. How much work do you do on the package? W = Fd = 60 N × 4 m = 240 J
  • 9. + Work is a Scalar  Work can be positive or negative but does not have a direction.
  • 10. + Sign of Work is Important  Work is positive  Force is in the same direction as the displacement  Work is negative  Forceis in a different direction as the displacement  Sing of the net work lets you know if the object is speeding up or down + for speeding up and work is being on object  - for slowing down and work is done by object
  • 12. + Kinetic Energy Energy associated with an object in motion Wnet = Fd = mad Since v2f = v2i + 2ad v2 f vi2 Then 2 2 Wnet m( ) v f v i 2 ad 2 Finally 1 2 1 2 Wnet mv f mvi 2 2
  • 13. + Kinetic Energy Kinetic energy depends on speed and mass The net work done on a body equals its change in kinetic energy SI units for KE  kg•m2/s2 or N•m or Joule (J)
  • 14. + Example  A 7.0 Kg bowling ball moves at 3.0 m/s. How fast must a 2.45g ping pong ball move in order to have the same kinetic energy as the bowling ball? Is the speed reasonable for the ping pong ball?  Given:  Bowling ball: m- 7.0 kg v= 3.0m/s  Ping pong: m= 2.45 g (this= 0.00245kg) v-??
  • 15. + Example 2KE  KE= ½ mv2 v m  KE= ½ (7)(32)  KE= 31.5 J 2(31.5) v 0.00245  Rearrange Equation to get v by itself v = 160.36 m/s
  • 16. + Classroom Practice Problems  A 6.00 kg cat runs after a mouse at 10.0 m/s. What is the cat’s kinetic energy?  Answer: 3.00 x 102 J or 300 J  Suppose the above cat accelerated to a speed of 12.0 m/s while chasing the mouse. How much work was done on the cat to produce this change in speed?  Answer: 1.32 x 102 J or 132 J
  • 17. + Work and Kinetic Energy  KEis the work an object can do if the speed changes.  Wnet is positive if the speed increases, and negative is speeds decrease  You must include all the forces that do work on the object in calculating the net work done
  • 18. + Potential Energy  Energyassociated with an object’s potential to move due to an interaction with its environment basically its stored energy  A book held above the desk  An arrow ready to be released from the bow  Some types of PE are listed below.  Gravitational  Elastic  Electromagnetic
  • 19. + Gravitational Potential Energy  Energy associated with an object due to the object’s position relative to a gravitational source  SI unit is still a Joule  Theheight (h) depends on the “zero level” chosen where PEg= 0.
  • 20. + Elastic Potential Energy  Theenergy available for use in deformed elastic objects  Rubber bands, springs in trampolines, pole-vault poles, muscles  For springs, the distance compressed or stretched = x
  • 21. + Elastic Potential Energy The spring constant (k) depends on the stiffness of the spring.  Stiffer springs have higher k values.  Measured in N/m  Force in newtons needed to stretch a spring 1.0 meters
  • 22. + Example  A 70.0kg stuntman is attached to a bungee cord with an unstretched length of 15m. He jumps off a bridge from a height of 50m. When he finally stops the cord has a stretched length of 44m. Assuming the spring constant is 71.8 N/m, what is the total PE relative to the water when the man stops falling?
  • 23. + Example  Given:  m= 70kg k= 71.8 N/mg= 10m/s2  h= 50m – 44m= 6m  x= 44m – 15m= 29m  PEg= mgh  PEelastic = ½ k x2  PEtotal= PEg + PEelastic
  • 24. + Example  PEg= mgh  PEelastic = ½ k x2  PEg= (70)(10)(6)  PEelastic= ½ (71.8)(292)  PEg= 4200 J  PEelastic= 30191.9J  PEtotal= PEg + PEelastic  PEtotal= 4200 + 30191.9  PEtotal= 34391.9J
  • 25. + Classroom Practice Problems  When a 2.00 kg mass is attached to a vertical spring, the spring is stretched 10.0 cm such that the mass is 50.0 cm above the table.  What is the gravitational potential energy associated with the mass relative to the table?  Answer: 9.81 J  What is the spring’s elastic potential energy if the spring constant is 400.0 N/m?  Answer: 2.00 J
  • 26. + 5.3 Conservation of Energy Pg. 173-178
  • 27. + Mechanical Energy (ME)  ME = KE + PEg + PEelastic  Doesnot include the many other types of energy, such as thermal energy, chemical potential energy, and others  ME is not a new form of energy.  Just a combination of KE and PE
  • 28. + Conservation of Mechanical Energy  The sum of KE and PE remains constant.  One type of energy changes into another type.  For the falling book, the PE of the book changed into KE as it fell.  As a ball rolls up a hill, KE is changed into PE.
  • 29. + Example  Starting from rest, a child zooms down a frictionless slide from an initial height of 3.0m. What is her speed at the bottom of the slide? Her mass is 25kg.  Given:  vi= 0m/s hi= 3m m=25kg  vf= ?? hf=0m
  • 30. + Example *Choose your equations  PE= mgh  KE= ½ mv2  PEf= (25)(10)(0)  KEf= ½ (25)v2  PEf= 0J  KEf= ??  PEi= (25)(10)(3)  KEi= ½ (25)(02)  PEi= 750J  KEi= 0J
  • 31. + Example *Put together  PEi+ KEi= PEf+ KEf  750 + 0 = 0 + ½ (25)vf2  750= 12.5 vf2  vf2 = √60  vf= 7.75m/s
  • 32. + Classroom Practice Problems  Suppose a 1.00 kg book is dropped from a height of 2.00 m. Assume no air resistance.  Calculate the PE and the KE at the instant the book is released.  Answer: PE = 19.6 J, KE = 0 J  Calculate the KE and PE when the book has fallen 1.0 m. (Hint: you will need an equation from Chapter 2.)  Answer: PE = 9.81 J, KE = 9.81 J  Calculate the PE and the KE just as the book reaches the floor.  Answer: PE = 0 J, KE = 19.6 J
  • 33. + Table of Values for the Falling Book h (m) PE(J) KE(J) ME(J) 0 19.6 0 19.6 0.5 14.7 4.9 19.6 1.0 9.8 9.8 19.6 1.5 4.9 14.7 19.6 2.0 0 19.6 19.6
  • 34. + Conservation of Energy  Acceleration does not have to be constant.  ME is not conserved if friction is present.  If friction is negligible, conservation of ME is reasonably accurate.  A pendulum as it swings back and forth a few times  Consider a child going down a slide with friction.  What happens to the ME as he slides down?  Answer: It is not conserved but, instead, becomes less and less.  The “lost” energy? is converted into nonmechanical energy (thermal energy).
  • 35. + Classroom Practice Problems  A small 10.0 g ball is held to a slingshot that is stretched 6.0 cm. The spring constant is 2.0 102 N/m.  What is the elastic potential energy of the slingshot before release?  What is the kinetic energy of the ball right after the slingshot is released?  What is the ball’s speed at the instant it leaves the slingshot?  How high does the ball rise if it is shot directly upward?
  • 37. + What do you think?  Twocars are identical with one exception. One of the cars has a more powerful engine. How does having more power make the car behave differently?  What does power mean?  What units are used to measure power?
  • 38. + Power Therate at which work is done or energy is transferred  Energy used or work done per second  If we substitute W for Fd then Fd P t
  • 39. + Power  The unit of power is the joule per second, also known as the watt.  One watt (W) of power is expended when one joule of work is done in one second.  One kilowatt (kW) equals 1000 watts.  One megawatt (MW) equals one million watts.
  • 40. + Power  SI units for power are J/s.  Calledwatts (W)  Equivalent to kg•m2/s3  Horsepower (hp) is a unit used in the Avoirdupois system.  1.00 hp = 746 W
  • 41. + Watts  These bulbs all consume different amounts of power.  A 100watt bulb consumes 100 joules of energy every second.
  • 42. + Example  A 193kg curtain need to be raised 7.5m, at a constant speed, in as close to 5 sec as possible. Unsure which motor would be the best 3 motors were bought. Power ratings are 1.0kW, 3.5kW, and 5.5kW. Which motor is best for the job?  Given:  m= 193kg d= 7.5m t= 5 sec P=??
  • 43. + Example  P=2895 W or 2.895kW  So the best motor would be the 3.5kW motor
  • 44. + Classroom Practice Problems  Two horses pull a cart. Each exerts a force of 250.0 N at a speed of 2.0 m/s for 10.0 min.  Calculate the power delivered by the horses.  How much work is done by the two horses?  Answers: 1.0 x 103 W and 6.0 x 105 J
  • 45. + Now what do you think?  Twocars are identical with one exception. One of the cars has a more powerful engine. How does having more power make the car behave differently?  What does power mean?  What units are used to measure power?