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Book Reference : Pages 24-25

1.

To consider speed & velocity around a circle

2.

To consider acceleration as a change in
velocity

3.

To define an equation for centripetal
acceleration

4.

To define an equation for centripetal force
Velocity v

n
atio
er
cel
ac

If an object is moving in a circle
with a constant speed, it’s
velocity is constantly changing....
Because the direction is
constantly changing....
If the velocity is constantly
changing then by definition the
object is accelerating
If the object is accelerating, then
an unbalanced force must exist
Velocity vB
B
δθ
C

δv

Velocity vB δθ

Consider an object moving
in circular motion with a
speed v which moves from
Velocity v
point A to point B in δ t
A
seconds
(From speed=distance / time),
the distance moved along the arc
AB, δ s is vδ t

Velocity vA

A

The vector diagram shows
the change in velocity δ v :
(vB – vA)
The triangles ABC & the
vector diagram are similar

Velocity vB
B
δθ
C

Velocity vA
A

Substituting for δs = vδt

δv

Velocity vB δθ

If δθ is small, then δv / v = δs / r

δv / v = vδt / r
Velocity vA

(a = change in velocity / time)
a = δ v / δ t = v2 / r
We can substitute for angular velocity....
a = v2 / r
From the last lesson we saw that:
v = rω (substituting for v into above)
a = (rω)2 / r
a = rω 2
In exactly the same way as we can connect force
f and acceleration a using Newton’s 2nd law of
motion, we can arrive at the centripetal force
which is keeping the object moving in a circle
f = mv2 / r
or
f = mrω 2
Any object moving in a circle is acted upon by a
single resultant force towards the centre of the
circle. We call this the centripetal force
Gravity which keeps satellites in orbit around
Earth and the Earth in orbit around the sun is a
classic example of a centripetal force.
satellite
Gravity

Planet
The wheel of the London Eye has a diameter of
130m and takes 30mins for 1 revolution.
Calculate:
a. The speed of the capsule
b. The centripetal acceleration
c. The centripetal force on a person with a
mass of 65kg
The speed of the capsule :
Using v = rω
we know that we do a full revolution (2π rad)
in 30mins (1800s)
v = (130/2) x (2π / 1800)
v = 0.23 ms-1
The centripetal acceleration:
Using a = v2 / r
a = (0.23)2 / (130/2)
a = 7.92 x 10-4 ms-2
The centripetal force:
Using f = ma
F = 65 x 7.92 x 10-4
F = 0.051 N
An object of mass 0.15kg moves around a circular
path which has a radius of 0.42m once every 5s at
a steady rate. Calculate:
a. The speed and acceleration of the object
b. The centripetal force on the object
[.528 ms-1, 0.663ms-2, 0.100N]

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Centripetal force and circular motion

  • 1.
  • 2. Book Reference : Pages 24-25 1. To consider speed & velocity around a circle 2. To consider acceleration as a change in velocity 3. To define an equation for centripetal acceleration 4. To define an equation for centripetal force
  • 3. Velocity v n atio er cel ac If an object is moving in a circle with a constant speed, it’s velocity is constantly changing.... Because the direction is constantly changing.... If the velocity is constantly changing then by definition the object is accelerating If the object is accelerating, then an unbalanced force must exist
  • 4. Velocity vB B δθ C δv Velocity vB δθ Consider an object moving in circular motion with a speed v which moves from Velocity v point A to point B in δ t A seconds (From speed=distance / time), the distance moved along the arc AB, δ s is vδ t Velocity vA A The vector diagram shows the change in velocity δ v : (vB – vA)
  • 5. The triangles ABC & the vector diagram are similar Velocity vB B δθ C Velocity vA A Substituting for δs = vδt δv Velocity vB δθ If δθ is small, then δv / v = δs / r δv / v = vδt / r Velocity vA (a = change in velocity / time) a = δ v / δ t = v2 / r
  • 6. We can substitute for angular velocity.... a = v2 / r From the last lesson we saw that: v = rω (substituting for v into above) a = (rω)2 / r a = rω 2
  • 7. In exactly the same way as we can connect force f and acceleration a using Newton’s 2nd law of motion, we can arrive at the centripetal force which is keeping the object moving in a circle f = mv2 / r or f = mrω 2 Any object moving in a circle is acted upon by a single resultant force towards the centre of the circle. We call this the centripetal force
  • 8. Gravity which keeps satellites in orbit around Earth and the Earth in orbit around the sun is a classic example of a centripetal force. satellite Gravity Planet
  • 9. The wheel of the London Eye has a diameter of 130m and takes 30mins for 1 revolution. Calculate: a. The speed of the capsule b. The centripetal acceleration c. The centripetal force on a person with a mass of 65kg
  • 10. The speed of the capsule : Using v = rω we know that we do a full revolution (2π rad) in 30mins (1800s) v = (130/2) x (2π / 1800) v = 0.23 ms-1
  • 11. The centripetal acceleration: Using a = v2 / r a = (0.23)2 / (130/2) a = 7.92 x 10-4 ms-2 The centripetal force: Using f = ma F = 65 x 7.92 x 10-4 F = 0.051 N
  • 12. An object of mass 0.15kg moves around a circular path which has a radius of 0.42m once every 5s at a steady rate. Calculate: a. The speed and acceleration of the object b. The centripetal force on the object [.528 ms-1, 0.663ms-2, 0.100N]