The line has an equation of 5y+3x=0. This line has a slope of -3/5 and passes through the point (5,-3), as determined by taking the general line equation y=mx+c, substituting the known slope and point, and solving for the equation of the line.
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Find the equation of the line that has slope of -35 and passes thro.pdf
1. Find the equation of the line that has slope of -3/5 and passes through the point (5,-3)
Solution
a general equation of a line is y=mx+c, where m= slope,c=intercept
if a point is given,then we can transform the above equation into y-y1=m(x-x1)
where,x1 and y1 are the points given from which the line passes.
here ,x1=5 and y1= -3
so y+3= (-3/5)(x-5)
thus equation of line is 5y+3x=0