An empty 15.0 L tank is connected to a 10.0 L tank of He at a pressure of 1.34 atm and a separate 20.0 L tank of Ne at a pressure of 2.25 atm. Both the He and Ne are pumped into the 15.0 L tank. What is the pressure of the He in the 15.0 L tank? What is the pressure of the Ne in the 15.0 L tank? What is the total pressure in the 15.0 L tank? Solution 1) Given: Pi = 1.34 atm Vi = 10.0 L Vf = 15.0 L use: Pi*Vi = Pf*Vf 1.34 atm * 10.0 L = Pf * 15.0 L Pf = 0.8933 atm Answer: 0.893 atm 2) Given: Pi = 2.25 atm Vi = 20.0 L Vf = 15.0 L use: Pi*Vi = Pf*Vf 2.25 atm * 20.0 L = Pf * 15.0 L Pf = 3 atm Answer: 3.00 atm 3) Total pressure = sum of individual pressure = 0.893 atm + 3.00 atm = 3.89 atm Answer: 3.89 atm .