Give the electron con-gurations for Ga- Ga+- Ga2+- and Ga3+- How would.docx

Weitere ähnliche Inhalte

Ähnlich wie Give the electron con-gurations for Ga- Ga+- Ga2+- and Ga3+- How would.docx

Chapter 8 the d and f block elements

suresh gdvm

SLATER’S RULE.pdf

ShivaniRaj40

I am Peterson N. I am a Physical Chemistry Assignment Expert at eduassignmenthelp.com. I hold a Ph.D. in Physical Chemistry, University of Melbourne, Australia. I have been helping students with their homework for the past 8 years. I solve assignments related to Physical Chemistry. Visit eduassignmenthelp.com or email info@eduassignmenthelp.com. You can also call on +1 678 648 4277 for any assistance with Physical Chemistry Assignments.

Physical Chemistry Homework Help

Edu Assignment Help

Spectroscopic methods 2018 Part 1 uv vis TM complexes

Chris Sonntag

.trashed-1684685946-SLATER’S RULE.pptx

ShivaniRaj40

Electronic spectra

Chris Sonntag

Arrange the following elements from greatest to least tendency to accept an electron. Mg, Si, Na, S, Cl Solution The ability to accept one or more electrons is known as electron affinity. The halogens( Group 7A) have the highest electron affinity values because by accepting an electron makes a stable noble gas configuration. Hence, Cl has greatest tendency to accept an electron. The valence electron configuration of the Mg metal is 3s2. The extra electron must enter the 3p subshell, which is effectively shielded by two 3s electrons ( Because ns electrons are more penetrating than np electrons) and the inner electrons. Consequently, Mg metal has little tendency to pick up an extra electron. Hence, Mg has least tendency to accept an electron. The valence electron configuration of the Na metal is 3s1. The extra electron must enter the 3s subshell, which is stable as it fulfills the s orbital. Hence, Na has greatest tendency to accept an electron than Mg. From left to right electron affinity increases. Hence, S > Si Therefore, the order of accepting an electron from greatest to least is as follows: Cl (349 kJ/mol) > S (200 kJ/mol) > Si (134 kJ/mol) > Na (53 kJ) > Mg (<(=) 0). .

Arrange the following elements from greatest to least tendency to acce.docx

vtuan3

Chemical Structure: Structure of Matter. Atoms – the building blocks of matter

ulcerd

a) The electronic configuration of arsenic is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3 [Ground state configuration] The number of electron in each subshell is 2 8 18 5 (K,L,M,N) b) one permissible quantum number would be 4,0,0,-1/2 c) paramagnetic element are those element that have unpaired electron in the outer most shell and diamagnetic are the one that have paired electron. Now in Arsenic, in the 4p there are 3 electron which are distributed among the three sub-orbitals of P (Px, Py and Pz) so they have 3 unpaired electron in 4p. Hence it is paramagnetic. d) Now the compound Na3As, AsCl3 and AsF3, if we look at it, in all the compound As combine with 3 atoms of another element either by covalent or ionic bond. This is because As requires 3 electron to attend the noble gas configuration or the octet state If we consider Na3As, Na will loses 1 e forming Na+ Na======>Na+ + 1e , Since there are 3 Na, so there will be 3 electron. These 3 e are taken up by As. So the configuration becomes 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6. Hence it has attain octet state. Therefore the ground state is consistent. Solution a) The electronic configuration of arsenic is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3 [Ground state configuration] The number of electron in each subshell is 2 8 18 5 (K,L,M,N) b) one permissible quantum number would be 4,0,0,-1/2 c) paramagnetic element are those element that have unpaired electron in the outer most shell and diamagnetic are the one that have paired electron. Now in Arsenic, in the 4p there are 3 electron which are distributed among the three sub-orbitals of P (Px, Py and Pz) so they have 3 unpaired electron in 4p. Hence it is paramagnetic. d) Now the compound Na3As, AsCl3 and AsF3, if we look at it, in all the compound As combine with 3 atoms of another element either by covalent or ionic bond. This is because As requires 3 electron to attend the noble gas configuration or the octet state If we consider Na3As, Na will loses 1 e forming Na+ Na======>Na+ + 1e , Since there are 3 Na, so there will be 3 electron. These 3 e are taken up by As. So the configuration becomes 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6. Hence it has attain octet state. Therefore the ground state is consistent..

a) The electronic configuration of arsenic is1s2 2s2 2p6 3s2 3p6 3.pdf

dilipanushkagallery

transition element

nidhin

I am Ben R. I am a Physical Chemistry Exam Helper at liveexamhelper.com. I hold a Masters' Degree in Physical Chemistry, from the University of Denver, USA. I have been helping students with their exams for the past 8 years. You can hire me to take your exam in Chemistry. Visit liveexamhelper.com or email info@liveexamhelper.com. You can also call on +1 678 648 4277 for any assistance with the Physical Chemistry Exam.

Physical Chemistry Exam Help

Live Exam Helper

lectur.pptx.......................................

Pandey141

Chemistry zimsec chapter 3 electrons in atoms

alproelearning

Inorganic chemistry

adinakazmi

Ionic bonding

DRSURYAKANTBORUL

Chapter 8 electron configuration and periodicity (1)

ElizabethAyala45

Electron Configuration

MHS, Macabebe Pampanga

Spectroscopic methods uv vis transition metal complexes

Chris Sonntag

L5theperiodictable 130906000951-

Cleophas Rwemera

Non metals generally want to gain electrons and a negative charge and metals generally want to donate electrons and gain a positive charge. In this case, you need to look at these elements on the periodic table and look at their common oxidation states (usually below the element on the table). As will probably be As3- Se2- Br- K+ Ca2+ Ga3+ These explanations might be beyond the chemistry level you\'re in right now, but I\'m not sure so I\'ll give brief explanations anyway. Arsenic can be tricky because it has multiple oxidation states. It would want to gain 3 electrons to fill its 4p orbital which in its base state has only 3/6 electrons. Gallium is tricky as well. It is willing to give up 3 electrons. This can be explained by filling orbital shells too. It only has 1 4p electron, but if it gives up 3 then the 3d shell can give up some electrons and put 1 electron in all of its 4p and 3d orbitals, which is more stable than having just 1/6 electrons in its 4p orbital. Now, drawing the dots on the element should be a little easier. Look at their normal amount of valence electrons and then add electrons for a negative charge and subtract electrons for a positive charge. Solution Non metals generally want to gain electrons and a negative charge and metals generally want to donate electrons and gain a positive charge. In this case, you need to look at these elements on the periodic table and look at their common oxidation states (usually below the element on the table). As will probably be As3- Se2- Br- K+ Ca2+ Ga3+ These explanations might be beyond the chemistry level you\'re in right now, but I\'m not sure so I\'ll give brief explanations anyway. Arsenic can be tricky because it has multiple oxidation states. It would want to gain 3 electrons to fill its 4p orbital which in its base state has only 3/6 electrons. Gallium is tricky as well. It is willing to give up 3 electrons. This can be explained by filling orbital shells too. It only has 1 4p electron, but if it gives up 3 then the 3d shell can give up some electrons and put 1 electron in all of its 4p and 3d orbitals, which is more stable than having just 1/6 electrons in its 4p orbital. Now, drawing the dots on the element should be a little easier. Look at their normal amount of valence electrons and then add electrons for a negative charge and subtract electrons for a positive charge..

Non metals generally want to gain electrons and a.pdf

ANGELMARKETINGJAIPUR

Ähnlich wie Give the electron con-gurations for Ga- Ga+- Ga2+- and Ga3+- How would.docx (20)

Chapter 8 the d and f block elements

SLATER’S RULE.pdf

Physical Chemistry Homework Help

Spectroscopic methods 2018 Part 1 uv vis TM complexes

.trashed-1684685946-SLATER’S RULE.pptx

Electronic spectra

Arrange the following elements from greatest to least tendency to acce.docx

Chemical Structure: Structure of Matter. Atoms – the building blocks of matter

a) The electronic configuration of arsenic is1s2 2s2 2p6 3s2 3p6 3.pdf

transition element

Physical Chemistry Exam Help

lectur.pptx.......................................

Chemistry zimsec chapter 3 electrons in atoms

Inorganic chemistry

Ionic bonding

Chapter 8 electron configuration and periodicity (1)

Electron Configuration

Spectroscopic methods uv vis transition metal complexes

L5theperiodictable 130906000951-

Non metals generally want to gain electrons and a.pdf

Mehr von rtodd751

Given an unsorted linked list, how to find the minimum element? Solution it is simple to find the minium element in the unsorted array or linked list. first you to look at all the elements of the linked list. the alforithm is as follows: minium=first element repeat untill last position { if(minimum>next element) minimum= next element } like this we compare all the elements in the linked list by updating the minimum element with minimum value occured duiring the comparision. the psudo code for this algorithm is minimum=list_node->data; while(list->next !=NULL) { if(minimum>list_node->data) minimum=list_node->data; list_node=list_node->link; } print minimum; .

Given an unsorted linked list- how to find the minimum element-Solutio.docx

rtodd751

Given the following Binary Tree, show the box trace of Depth(N). Solution the above depicted picture is not a binaryb tree because if the tree is said to be binary tree it should posses atmost two childs for a node possible child nodes are 0,1,2 tracing a binary tree: 1)compare the search element with root node if it is successful search then its finish 2)compare the search element with the root if search element is lesser than root then goto left subtree else goto right subtree the process continous until we find the element or reach the leaf node. leaf node: the node which doesnot have child nodes to proceed further the depth of a binary tree is nothing but the number of edges from the root node to the recquired node. becareful the nodes in the binary tree are in sorted order only .

Given the following Binary Tree- show the box trace of Depth(N)-Soluti.docx

rtodd751

Given the following class declaration, write the code in Java for the add function: public class ArrayList {Private Object []a; Public ArrayList() {a = new Object[10];} public ArrayList(int n) {a = new Object[n];} public int size() {if[a[0] = = null) return 0; else {int I = 0, count = 0; while(a[i]! = null){count ++; i++} return count;} public void add(Object n) { Solution public void add(Object n) { int count = size(); if(count != 0) { a[count++] = n; // add the object n to a } } .

Given the following class declaration- write the code in Java for the.docx

rtodd751

Given a list of numbers, count and return how many pairs there are. A pair exists when the same number appears in adjacent locations in the list. Do not alter the list in any way. Do not use any Python library functions with the list except len(). count_pairs([1, 30, 30, 0, 31, 31]) rightarrow 2 count_pairs([1, 2, 3, 1]) rightarrow 0 count_pairs([1, 1, 1, 7, 5]) rightarrow 2 Solution def count_pairs(list): # count holds the count of pairs count = 0 # iterate over the list till second last element # idx is index and element is the number onthat index for idx,element in enumerate(list[:-1]): # if we get a pair , increment the count if element == list[idx+1]: count = count + 1 # print the number of pairs print count count_pairs([1,30,30,0,31,31]) count_pairs([1,2,3,1]) count_pairs([1,1,1,7,5]) .

Given a list of numbers- count and return how many pairs there are- A.docx

rtodd751

Given 5 moles of H2SO4 react with excess NaOH how many moles of water are produced? NaOH + H2SO4 --> H2O + Na2SO4 (equation is unbalanced!) Solution Balanced equation: 2 NaOH + H 2 SO 4 ====> 2 H 2 O + Na 2 SO 4 Reaction type: double replacement Moles of H2SO4 = 5 Moles Moles of H2O produced = 10 Moles One mole of H2SO4 will react two moles of NaOH to produced one mole of sodium sulfate and 2 moles of water. HenceÂ Â 5 moles of H2SO4 will produce 10 Moles of water. .

Given 5 moles of H2SO4 react with excess NaOH how many moles of water.docx

rtodd751

Given an unsorted linked list, how to find the minimum element? Solution Solution : For finding the minimum element in an unsorted linked list various steps to be followed - Step 1 - Firstly from the unsorted linked list just remove all the duplicates. Step 2 - Secondly we can choose any method from which we can do sorting which are using loop or using simple sorting or using the hashing method. In using loop method, two loops will be presented in which first loop picks up the elements and second loop do comparison between the elements. In using simple sorting method, first removal of duplicates then sort the linked list using merge sort method. In using hashing method, Firstly traversing of elements wiil be made from head to the end . If the element is present in hash list then remove it other than this add the element to the list. Step 3 - Finally we can get a minimum element from linked list. .

Given an unsorted linked list- how to find the minimum element-Solutio (1).docx

rtodd751

Give five latest and uncommon research topics in intelligent vehicular networks. Solution 1. Multimedia Services 2.Routing , Challenges in Security and Navigation Systems 3.A ssisted geographic routing in urban environment. 4. Vehicular Wireless Medium Access Control 5. Automotive Electronics and Automatic Control 6.Traffic and Intelligent Transport System in Vehicular Networks 7. Cognitive and Context-aware Intelligence .

Give five latest and uncommon research topics in intelligent vehicular.docx

rtodd751

Give and explain the periodic trend of atomic radius for the 3rd period elements. Solution The elements of 3rd period are sodium , magnesium , aluminium , silicon , phosphorus , sulfur , chlorine and argon. Now as we move in the period from left to right , i.e. from sodium to argon , the atomic number of the element. This increases the number of electrons in the same shell of the atom of the element. The number of protons are also increased. And due to the negligible increase in the shielding of electrons (as they enter in the same shell n=3) , the attraction towards the nucleus also increases. So the atomic radius of the elements decrease from left to right in the 3rd period. .

Give and explain the periodic trend of atomic radius for the 3rd perio.docx

rtodd751

Give an example of a business objective and the related Key Performance Indicator (KPI). Explain why defining a Key Performance Indicator (KPI) is important to a business e-marketing plan. Solution Lets say the organization in this case is a ISP(Internet Service Provider) and provides internet service to different customer segments.There are large number of low income household customers and a moderate number of HNI(High Networth Individuals) and a small number of Corporate/Enterprise customers.Some of the KPI which can be used for such an organization are: E-Marketing Plan : There is a saying \"Nothing improves that is not measured\" and therefore we should have KPIs for such activity also.Some of the KPIs that may be uses are: .

Give an example of a business objective and the related Key Performanc.docx

rtodd751

General Motors exports cars to Spain, but the strong dollar against the Euro hurts sales of GM cars in Spain. In the Spanish market, GM faces competition from Italian and French car makers, such as Fiat and Renault, whose operating currencies are the Euro. Determine the best course for GM to take to maintain its market share in Spain. Explain your rationale. Solution Achievable quota that General Motors(GM) can take (1) expand the display,shot to display or market the cars not only in Spain and another European countries but further in Asia:(2) point out production effortlessness in Spain and cause aid narrowly:(3) point out production effortlessness say in Mexico where production prices are minimum and transport to Spain from Merico. .

General Motors exports cars to Spain- but the strong dollar against th.docx

rtodd751

Mehr von rtodd751 (10)