I. Mi and M2 are two masses connected as shown in Fig. 1. The pulley is light and trictionless. (a) Find the mass Mi, given that M2 (2.0kg) accelerates downwards at 1.0m/sec2, that ? is 30°, and that e is 0.30. (b) What is the tension?
Solution
for mass M1
Fnet = M1*a
T - M1*g*sintheta - uk*M1*g*costheta = M1*a...........(2)
1 + 2
M2*g - M1*g*sintheta - uk*M1*g*costheta = (M1+M2)*a
given a = 1 m/s^2
2*9.8 - M1*9.8*sin30 - 0.3*M1*9.8*cos30 = (M1+2)*1
M1 = 2.1 kg <<<-----------ANSWER
============
from (1 )
M2*g - T = M2*a
T = M2*g - M2*a
T = 2*9.8 - 2
Tension T = 17.6 N <<<<-------------ANSWER
.
I- Mi and M2 are two masses connected as shown in Fig- 1- The pulley i.docx
1. I. Mi and M2 are two masses connected as shown in Fig. 1. The pulley is light and trictionless.
(a) Find the mass Mi, given that M2 (2.0kg) accelerates downwards at 1.0m/sec2, that ? is 30°,
and that e is 0.30. (b) What is the tension?
Solution
for mass M1
Fnet = M1*a
T - M1*g*sintheta - uk*M1*g*costheta = M1*a...........(2)
1 + 2
M2*g - M1*g*sintheta - uk*M1*g*costheta = (M1+M2)*a
given a = 1 m/s^2
2*9.8 - M1*9.8*sin30 - 0.3*M1*9.8*cos30 = (M1+2)*1
M1 = 2.1 kg <<<-----------ANSWER
============
from (1 )
M2*g - T = M2*a
T = M2*g - M2*a
T = 2*9.8 - 2
