which solute would provide the sharper end point in a titration with 0.10 M HCl: a) 0.10 M NaOCl or 0.10 M hydroxylamine? b) 0.10 M NH3 or 0.10 M sodium phenolate? c) 0.10 M methylamine or 0.10 hydroxylamine? d) 0.10 M hydrazine or 0.10 M NaCN? Solution Hcl is strong acid , so for sharp end point in the titration of HCl a strong base is needful. a strong base can be decided by dissociation constant value. lower the pKb value batter be the base in giving sharp end point with a strong acid like HCl. a) BETWEEN SODIUM HYPOCHLORITE AND HYDROXYL AMMINE , SODIUM HYPOCHLORITE IS BETTER OPTION FOR A SHRP END POINT WITH HCl DUE TO ITS pKb VALUE LESSER THAN THAT OF HHYDROXYL AMMINE. b)pKb for ammonia = 4.75, and that for sodium phenolate = 4, so sodium phenoxide seems better giving sharp end point with HCl c) pKb for methanamine = 3.36, and that for hydroxylamine = 7.97 so methanamine better gives sharp end point with HCl d) pKb for NaCN = 4.3 and thta for hydrazine = 5.5 so lower pKb value possessed by sodium cyanide. sodium cyanide give ssharp end point with HCl. UNIFORMALLY pKb VALUES ARE EXAMINED TO SELECT BETTER BASE FROM EACH PAIR GIVEN IN THE QUESTION. .