Please answer the questions to D2, and D3 in the picture. The lab report is included in the pictures as a reference for the information that is needed to answer these questions. D2a) Absorbance of Metal Ion in Solution D2b) Concentration of metal ion from the calibration curve (mol/L) D2c) Concentration of metal ion in teh orginal sample corrected for dilution (mol/L) D2d) Show your calculation to account for the dilution of the orginal sample. D3a) Concentration of metal ion in the orginal sample (mass/volume). D3b) Show calculations. D. Unknown Metal Ion Concentration 1. Prepare the unknown. Descrihe the preparation for u preparation for the solution containing the unknown concentration of the I, Place 20 ml.runknounsol,??n In q 2Smi volumetric fl.sk 2. Adi 1-2«I-f t metal ion. ml volum etric flos d d:?te with ool HADo he Corple ng agent an Volume of unknown sample solution (ab) -20m Volume of diluted sample (mb)22 2. Concentration of metal ion. Absorbance of metal ion in solution Concentration of metal ion from the calibration curve (mol/L) Concentration of metal ion in the original sample corrected for dilution (mol/L) Show your calculations to account for the dilution of the original sample. 3. Expressing Concentration. Express the concentration of the metal ion in the sample in appropriate units of mass/ volume [i.e., pph (percent), rpm. rph, etc.]. Concentration of metal ion in the original sample (mason olume) Show calculations Solution Calculations: Calculated Molar ConcentrationStandard Solution [Concentration] = 717.58 x [Absorbance] The observed Beer’s proportionality constant for this analysis is then (1/717.58) or 1.39 x 10-3. 1) Volume of standard solution: 1 mLConcentration of stock solution: .02mol/L Final volume of solution: 25 mLM1V1= M2V2(.02 mol/L)(1mL) = (M2)(25mL) Calculated Molar Concentration: .0008mol/L Standard Solution 2) Volume of standard solution: 5 mL Concentration of stock solution: .02mol/L Final volume of solution: 25 mLM1V1= M2V2(.02 mol/L)(5mL) = (M2)(25mL) Calculated Molar Concentration: .004 mol/L Standard Solution 3) Volume of standard solution: 10 mL Concentration of stock solution: .02mol/L Final volume of solution: 25 mLM1V1= M2V2(.02 mol/L)(10mL) = (M2)(25mL) Calculated Molar Concentration: .008 mol/L Standard Solution .

1. Please answer the questions to D2, and D3 in the picture. The lab report is included in the
pictures as a reference for the information that is needed to answer these questions.
D2a) Absorbance of Metal Ion in Solution
D2b) Concentration of metal ion from the calibration curve (mol/L)
D2c) Concentration of metal ion in teh orginal sample corrected for dilution (mol/L)
D2d) Show your calculation to account for the dilution of the orginal sample.
D3a) Concentration of metal ion in the orginal sample (mass/volume).
D3b) Show calculations.
D. Unknown Metal Ion Concentration 1. Prepare the unknown. Descrihe the preparation for u
preparation for the solution containing the unknown concentration of the I, Place 20
ml.runknounsol,??n In q 2Smi volumetric fl.sk 2. Adi 1-2«I-f t metal ion. ml volum etric flos d
d:?te with ool HADo he Corple ng agent an Volume of unknown sample solution (ab) -20m
Volume of diluted sample (mb)22 2. Concentration of metal ion. Absorbance of metal ion in
solution Concentration of metal ion from the calibration curve (mol/L) Concentration of metal
ion in the original sample corrected for dilution (mol/L) Show your calculations to account for
the dilution of the original sample. 3. Expressing Concentration. Express the concentration of the
metal ion in the sample in appropriate units of mass/ volume [i.e., pph (percent), rpm. rph, etc.].
Concentration of metal ion in the original sample (mason olume) Show calculations
Solution
Calculations: Calculated Molar ConcentrationStandard Solution
[Concentration] = 717.58 x [Absorbance]
The observed Beer’s proportionality constant for this analysis is then (1/717.58) or 1.39 x
10-3.
1) Volume of standard solution: 1 mLConcentration of stock solution: .02mol/L
Final volume of solution:

2. 25 mLM1V1= M2V2(.02 mol/L)(1mL) = (M2)(25mL)
Calculated Molar Concentration:
.0008mol/L Standard Solution
2) Volume of standard solution: 5 mL
Concentration of stock solution: .02mol/L
Final volume of solution: 25 mLM1V1= M2V2(.02 mol/L)(5mL) = (M2)(25mL)
Calculated Molar Concentration: .004 mol/L Standard Solution
3) Volume of standard solution: 10 mL
Concentration of stock solution: .02mol/L
Final volume of solution: 25 mLM1V1= M2V2(.02 mol/L)(10mL) = (M2)(25mL)
Calculated Molar Concentration: .008 mol/L Standard Solution