IMPLICIT DIFFERENTIATION
Let us take an example function:
f(x,y)=
=>f(x,y)'=( )'
=
Now differentiate the function partially:
By comaring above equations we get:
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So ,this is the general rule:
=M(x,y)+N(x,y)y'
=>To solve problems of the form:
M(x,y)+N(x,y)y'=0
What we do?
We should find: f(x,y)
EXAMPLE:
• Let the differential equation be :
•
• =>
commonpart
• &
• Common part=
• h(x)=
• g(y)= =>
If we try to find the general solution of
3y+2xy'=0
where
if we do
but f(x,y)=h(x)+commonpart+g(y)
but the above integrations doesn't
have commonpart or h(x) and g(y).
To find G.S for the above equation we
reduce it to exact equation.
let us know what is exact equation..
Let's know what is exact equation ?
• Remember , order doesn't matter for partial derivatives:
=>
•
• =>
• &
• =>
•
• =>
To solve the differential of the form M(x,y)+N(x,y)y'=0 the necessary
condition is
• => and the above equation is called exact.
To solve problems of the form
M(x,y)+N(x,y)y'=0
Step 1:- Observe
Step 2:-Compute Mdx + Ndy
Step 3:- write the general solution as
f(x,y)= M(x,y)dx+ N(x,y)dy
If a differential equation Mdx+Ndy=0
which is not exact can be made
exact by multiplying it with a
suitable µ(x,y)≠0 then µ(x,y) is called
an integrating factor of the equation
Mdx+Ndy=0.
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