explain clearSolution 1)this is false as a=6.pdf

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This document discusses properties of integers a and b where a divides b (a|b). It states that the second statement is true, as if a is odd and a|b, then b must be divisible by a with no remainder, making b also odd. The first, third, and fourth statements are false based on the values given for a and b not satisfying the property of a dividing b.

explain clear
Solution
1)this is false as a=6, b=3 then b is not even as a is even and a|b 2)this is true as
a=3, if a|b then therethe divident will be an integer if and only if there is a odd divisor as a is odd.
3)this is false as a=6 and b=3 => a|b 4)this is true as a|b so a=bq ,b even does mean a will be
even

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