The document discusses integrating the function 10 In (x)/x dx from x = 0 to 8 with a constant of integration C = 4. It uses u-substitution to rewrite the integral as an integral of 10u du, which evaluates to 5u^2 + C. Evaluating this at x = 8 with C = 4 gives the final numerical value of 5(ln 8)^2 + 4 = 62.04.