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5.6 – To determine, using
stoichiometric calculations, the
quantity of a substance involved in
a chemical reaction.
5.8 – To solve numerical problems
related to stoichiometry.
436
436
STOICHIOMETRY
A mole is the amount of substance
that contains 6.02 x 1023
particles of
that substance
n (moles) = mass of substance (g)
molar mass of substance (g/mol)
 Stoichiometry:
uses ratios of a chemical reaction to
determine the amounts of elements/
compounds (reactants & products)
involved in a chemical change
2Mg + O2  2MgO
 Mole Ratio –
describes the ratio in which the substances
combine
Ex. for every 2 Mg, 1 O2 needed
used to predict what will happen
Ex. for every 2 Mg & 1 O2, 2 MgO will be
2 : 1 : 2
Magnesium metal reacts with oxygen
to produce magnesium oxide.
2Mg + O2  2MgO
2 : 1 : 2
4 moles of magnesium metal reacts
with oxygen to produce magnesium
oxide. How many moles of MgO are
produced?
Mole Ratio
Set up ratio
2 moles Mg 2 moles MgO
=
4 moles Mg ? moles MgO
from mole ratio
from question
Solve by cross multiplying
2 moles Mg 2 moles MgO
=
4 moles Mg ? moles MgO
4 moles MgO
are produced
4 x 2 ÷ 2
4Fe + 3O2  2Fe2O3
4 : 3 : 2
Iron metal reacts with oxygen to
produce 3 moles of iron (III) oxide.
How many moles of oxygen were
needed in the reaction?
Mole Ratio
Set up ratio
3 moles O2 2 moles Fe2O3
=
? moles O2 3 moles Fe2O3
from mole ratio
from question
Solve by cross multiplying
3 moles O2 2 moles Fe2O3
=
? moles O2 3 moles Fe2O3
4.5 moles O2 are
needed
3 x 3 ÷ 2
N2 + 3H2  2NH3
1 : 3 : 2
How many moles of nitrogen gas &
hydrogen gas are required to make
7.5 mol of ammonia?
Solve for moles of N2:
1 mole N2 2 moles NH3
=
? moles N2 7.5 moles NH3
3.75 moles N2
are required
Solve for moles of H2:
3 mole H2
=
2 moles NH3
? moles H2 7.5 moles NH3
11.25 moles H2
are required
We can now add mass into problems
involving stoichiometry.
Recall,
n (moles) = mass of substance (g)
molar mass of substance (g/mol)
How many moles are in 12.5g of Ca?
n (moles) = 12.5g
40g/mol
0.3125 mol of Ca
How many moles are in 2.4g of NO2?
n (moles) = 2.4g
46g/mol
0.052 mol of NO2
2Li + F2  2LiF
2 : 1 : 2
How many moles of Li are needed to
react with fluorine gas to make 435g
of lithium fluoride?
Solve for moles of LiF:
n (moles) = 435g
26g/mol
16.73 mol of LiF
Solve for moles of Li:
2 moles Li
= 2 moles LiF
? moles Li 16.73 mol LiF
16.73 moles Li
are needed
2NaClO3  2NaCl + 3O2
2 : 2 : 3
How many grams of NaClO3 must be
decomposed to produce sodium
chloride & 1.65 moles of oxygen?
Solve for moles of NaClO3:
1.1 mol of NaClO3
2 mol NaClO3
=
3 mol O2
? mol NaClO3 1.65 mol O2
Solve for mass of NaClO3:
1.1 mol = ? g
106 g/mol
116.6g of
NaClO3
Mg + 2HCl  MgCl2 + H2
1 : 2 : 1 : 1
3g of magnesium react with how many
grams of hydrochloric acid to produce
hydrogen gas & magnesium chloride?
Solve for moles of Mg:
0.125 mol of Mg
n = 3 g
24 g/mol
Solve for moles of HCl:
1 mol Mg = 2 mol HCl
0.125 mol Mg ? mol HCl 0.25 mol of HCl
Solve for mass of HCl:
0.25mol = ? g
36 g/mol
9g of HCl
 Always find moles first!!!
 Use mole ratio to find the moles of each
reactant & product
 Remember, the equation must be
balanced to give you the mole ratio
n (moles) = mass of substance (g)
molar mass of substance (g/mol)
 Worksheet #
 Fritz Haber

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Stoichiometry

  • 1. 5.6 – To determine, using stoichiometric calculations, the quantity of a substance involved in a chemical reaction. 5.8 – To solve numerical problems related to stoichiometry. 436 436 STOICHIOMETRY
  • 2. A mole is the amount of substance that contains 6.02 x 1023 particles of that substance n (moles) = mass of substance (g) molar mass of substance (g/mol)
  • 3.  Stoichiometry: uses ratios of a chemical reaction to determine the amounts of elements/ compounds (reactants & products) involved in a chemical change
  • 4. 2Mg + O2  2MgO  Mole Ratio – describes the ratio in which the substances combine Ex. for every 2 Mg, 1 O2 needed used to predict what will happen Ex. for every 2 Mg & 1 O2, 2 MgO will be 2 : 1 : 2 Magnesium metal reacts with oxygen to produce magnesium oxide.
  • 5. 2Mg + O2  2MgO 2 : 1 : 2 4 moles of magnesium metal reacts with oxygen to produce magnesium oxide. How many moles of MgO are produced? Mole Ratio Set up ratio 2 moles Mg 2 moles MgO = 4 moles Mg ? moles MgO from mole ratio from question
  • 6. Solve by cross multiplying 2 moles Mg 2 moles MgO = 4 moles Mg ? moles MgO 4 moles MgO are produced 4 x 2 ÷ 2
  • 7. 4Fe + 3O2  2Fe2O3 4 : 3 : 2 Iron metal reacts with oxygen to produce 3 moles of iron (III) oxide. How many moles of oxygen were needed in the reaction? Mole Ratio Set up ratio 3 moles O2 2 moles Fe2O3 = ? moles O2 3 moles Fe2O3 from mole ratio from question
  • 8. Solve by cross multiplying 3 moles O2 2 moles Fe2O3 = ? moles O2 3 moles Fe2O3 4.5 moles O2 are needed 3 x 3 ÷ 2
  • 9. N2 + 3H2  2NH3 1 : 3 : 2 How many moles of nitrogen gas & hydrogen gas are required to make 7.5 mol of ammonia? Solve for moles of N2: 1 mole N2 2 moles NH3 = ? moles N2 7.5 moles NH3 3.75 moles N2 are required Solve for moles of H2: 3 mole H2 = 2 moles NH3 ? moles H2 7.5 moles NH3 11.25 moles H2 are required
  • 10. We can now add mass into problems involving stoichiometry. Recall, n (moles) = mass of substance (g) molar mass of substance (g/mol) How many moles are in 12.5g of Ca? n (moles) = 12.5g 40g/mol 0.3125 mol of Ca How many moles are in 2.4g of NO2? n (moles) = 2.4g 46g/mol 0.052 mol of NO2
  • 11. 2Li + F2  2LiF 2 : 1 : 2 How many moles of Li are needed to react with fluorine gas to make 435g of lithium fluoride? Solve for moles of LiF: n (moles) = 435g 26g/mol 16.73 mol of LiF Solve for moles of Li: 2 moles Li = 2 moles LiF ? moles Li 16.73 mol LiF 16.73 moles Li are needed
  • 12. 2NaClO3  2NaCl + 3O2 2 : 2 : 3 How many grams of NaClO3 must be decomposed to produce sodium chloride & 1.65 moles of oxygen? Solve for moles of NaClO3: 1.1 mol of NaClO3 2 mol NaClO3 = 3 mol O2 ? mol NaClO3 1.65 mol O2 Solve for mass of NaClO3: 1.1 mol = ? g 106 g/mol 116.6g of NaClO3
  • 13. Mg + 2HCl  MgCl2 + H2 1 : 2 : 1 : 1 3g of magnesium react with how many grams of hydrochloric acid to produce hydrogen gas & magnesium chloride? Solve for moles of Mg: 0.125 mol of Mg n = 3 g 24 g/mol Solve for moles of HCl: 1 mol Mg = 2 mol HCl 0.125 mol Mg ? mol HCl 0.25 mol of HCl Solve for mass of HCl: 0.25mol = ? g 36 g/mol 9g of HCl
  • 14.  Always find moles first!!!  Use mole ratio to find the moles of each reactant & product  Remember, the equation must be balanced to give you the mole ratio n (moles) = mass of substance (g) molar mass of substance (g/mol)
  • 15.  Worksheet #  Fritz Haber