A positive charge Q = 5 nC is located at the center of a cubic box. The electric flux through the surface is Φ. Another identical charge is added inside the box. The net flux through the surface will be 2Φ, according to Gauss's law, since the net charge inside the box is now 2Q.

1. A positive charge Q = 5 nC is located at the center of an imaginary Gaussian cube of sides a. The
flux of the electric field through the surface of the cube is . A second, positive charge Q = 5 nC is
now placed next to Q inside the cube. Which of the following statements will be true in this
case?
The magnitude of the net electric field is constant on the entire surface of the cube
The net flux through the surface of the cube is equal to zero
The net flux through the surface is equal to 2?
The electric field on the surface of the cube is perpendicular to the surface
The net electric field on the surface of the cube is equal to zero
The magnitude of the net electric field is
constant on the entire surface of the cube
The net flux through the surface of the cube is
equal to zero
The net flux through the surface is equal to 2?
The electric field on the surface of the cube is
perpendicular to the surface
The net electric field on the surface of the
cube is equal to zero
Solution
The net flux through the surface is equal to 2? (from Gauss Law)