fixed A positive charge Q is located several metres from a fixed positive charge as shown in the diagram. You are told to move charge Q a distance of 1.0 m so as to cause the greatest increase in its electrical potential energy. In which direction do you move it? b. What is the electric field 0.10 m from a point charge Q1 which carries a charge of 0.20 ?C? x 10P N/C away from Q1 C. What is the initial acceleration of an electron when placed in an electric field at a point where the electric field strength is 6.7 x 105 N/C? A/ x 1017 m/s2 d. 10.0 m 6.0m - The electric field at point P in the diagram is 8500 N/C directed to the right. What is the size and polarity of charge q2? Solution here, a) the electrical potential energy , PE = k * q1 * q2 /r q1 - fisrt charge q2 - seccond charge r - sepration between the charges for maximum increase in potential energy the change in distance between the charges must be decreased the charge Q must be moved along the line 4 .