In a simple English sentence, describe what function the following P88 program computes, based upon the user input of an integer: (consider things inside / nonexistent - it\'s for the spacing) /................../in            ax /................../copy /...../m1, ax /.................../sub /....../ax, m1 /.................../cmp       ax, m1 /.................../jb /......../lab1 /.................../out         ax /.................../jmp        lab2 lab1:/.........../copy /..../ax, m1 /................../div /....../ax, m1 /................../out /....../ax lab2: /........./halt Solution I have explained each line of the program in simple english langauage. I have written by explanation in bold letters. /................../in            ax //ax is a primary accumulator for taking input /................../copy /...../m1, ax //copying input from ax to m1 /.................../sub /....../ax, m1 // ax having value that will be substracted with m1 and result will be store in ax /.................../cmp       ax, m1 // compare the current content of ax with m1. and accordingly condition flag (CF ) register value will be set //If AX < m1 then CF = B (it means memory is Bigger than ax) //If AX > m1 then CF = NB (memory is not Bigger) /.................../jb /......../lab1 //jb is jump instruction. Here value of CF wiil be check, if CF = B , then address of lab1 is loaded in IP register /.................../out         ax //it will ouput the current value of accumulator /.................../jmp        lab2 //it will assing IP register to address of lab2 lab1:/.........../copy /..../ax, m1 //copying currently value of ax in m1 /................../div /....../ax, m1 // ax having value that will be divided with m1 and result will be store in ax again /................../out /....../ax //output the current value of ax lab2: /........./halt //program will halt .

1. In a simple English sentence, describe what function the following P88 program computes, based
upon the user input of an integer: (consider things inside / nonexistent - it's for the spacing)
/................../in ax
/................../copy /...../m1, ax
/.................../sub /....../ax, m1
/.................../cmp ax, m1
/.................../jb /......../lab1
/.................../out ax
/.................../jmp lab2
lab1:/.........../copy /..../ax, m1
/................../div /....../ax, m1
/................../out /....../ax
lab2: /........./halt
Solution
I have explained each line of the program in simple english langauage. I have written by
explanation in bold letters.
/................../in ax //ax is a primary accumulator for taking input
/................../copy /...../m1, ax //copying input from ax to m1
/.................../sub /....../ax, m1 // ax having value that will be substracted with m1 and result
will be store in ax

2. /.................../cmp ax, m1 // compare the current content of ax with m1. and accordingly
condition flag (CF ) register value will be set
//If AX < m1 then CF = B (it means memory is Bigger than ax)
//If AX > m1 then CF = NB (memory is not Bigger)
/.................../jb /......../lab1 //jb is jump instruction. Here value of CF wiil be check, if CF = B
, then address of lab1 is loaded in IP register
/.................../out ax //it will ouput the current value of accumulator
/.................../jmp lab2 //it will assing IP register to address of lab2
lab1:/.........../copy /..../ax, m1 //copying currently value of ax in m1
/................../div /....../ax, m1 // ax having value that will be divided with m1 and result will be
store in ax again
/................../out /....../ax //output the current value of ax
lab2: /........./halt //program will halt