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NAME Titration Quiz Calculate the volume of a 0.123 M NaOH solution needed to completely
titrate 125 mL of a 0.197 M malonic acid (H2C3H204) solution. (a) Write a balanced chemical
equation. (b) Perform your calculation.
Solution
H2C3H2O4(aq) + 2NaOH(aq) -------------> Na2C3H2O4(aq) + 2H2O(l)
1 mole 2 moles
H2C3H2O4 NaOH
M1 = 0.197M M2 =0.123M
V1 = 125ml V2 =
n1 = 1 n2 = 2
M1V1/n1 = M2V2/n2
V2 = M1V1n2/n1M2
= 0.197*125*2/1*0.123 = 400.4ml
volume of NaOH = 400.4ml >>>>answer
NAME Titration Quiz Calculate the volume of a 0-123 M NaOH solution ne.docx

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NAME Titration Quiz Calculate the volume of a 0-123 M NaOH solution ne.docx

  • 1. NAME Titration Quiz Calculate the volume of a 0.123 M NaOH solution needed to completely titrate 125 mL of a 0.197 M malonic acid (H2C3H204) solution. (a) Write a balanced chemical equation. (b) Perform your calculation. Solution H2C3H2O4(aq) + 2NaOH(aq) -------------> Na2C3H2O4(aq) + 2H2O(l) 1 mole 2 moles H2C3H2O4 NaOH M1 = 0.197M M2 =0.123M V1 = 125ml V2 = n1 = 1 n2 = 2 M1V1/n1 = M2V2/n2 V2 = M1V1n2/n1M2 = 0.197*125*2/1*0.123 = 400.4ml volume of NaOH = 400.4ml >>>>answer