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Geometric Sequences
Geometric Sequences
A sequence a1, a2 , a3 , … is a geometric sequence if
an = crn, i.e. it is defined by an exponential formula.
Geometric Sequences
A sequence a1, a2 , a3 , … is a geometric sequence if
an = crn, i.e. it is defined by an exponential formula.
The sequence of powers of 2
a1= 2, a2= 4, a3= 8, a4= 16, …
is a geometric sequence because an = 2n.
Geometric Sequences
A sequence a1, a2 , a3 , … is a geometric sequence if
an = crn, i.e. it is defined by an exponential formula.
The sequence of powers of 2
a1= 2, a2= 4, a3= 8, a4= 16, …
is a geometric sequence because an = 2n.
Fact: If a1, a2 , a3 , …an = c*rn is a geometric sequence, then
the ratio between any two consecutive terms is r.
Geometric Sequences
A sequence a1, a2 , a3 , … is a geometric sequence if
an = crn, i.e. it is defined by an exponential formula.
The sequence of powers of 2
a1= 2, a2= 4, a3= 8, a4= 16, …
is a geometric sequence because an = 2n.
Fact: If a1, a2 , a3 , …an = c*rn is a geometric sequence, then
the ratio between any two consecutive terms is r.
The converse of this fact is also true.
Geometric Sequences
A sequence a1, a2 , a3 , … is a geometric sequence if
an = crn, i.e. it is defined by an exponential formula.
The sequence of powers of 2
a1= 2, a2= 4, a3= 8, a4= 16, …
is a geometric sequence because an = 2n.
Fact: If a1, a2 , a3 , …an = c*rn is a geometric sequence, then
the ratio between any two consecutive terms is r.
The converse of this fact is also true. Below is the formula
that we used for working with geometric sequences.
Geometric Sequences
A sequence a1, a2 , a3 , … is a geometric sequence if
an = crn, i.e. it is defined by an exponential formula.
The sequence of powers of 2
a1= 2, a2= 4, a3= 8, a4= 16, …
is a geometric sequence because an = 2n.
Fact: If a1, a2 , a3 , …an = c*rn is a geometric sequence, then
the ratio between any two consecutive terms is r.
The converse of this fact is also true.
For example, from the sequence above we see that
16/8 = 8/4 = 4/2 = 2 = ratio r. Below is the formula that we
used for working with geometric sequences.
Geometric Sequences
A sequence a1, a2 , a3 , … is a geometric sequence if
an = crn, i.e. it is defined by an exponential formula.
The sequence of powers of 2
a1= 2, a2= 4, a3= 8, a4= 16, …
is a geometric sequence because an = 2n.
Fact: If a1, a2 , a3 , …an = c*rn is a geometric sequence, then
the ratio between any two consecutive terms is r.
The converse of this fact is also true. Below is the formula
that we used for working with geometric sequences.
For example, from the sequence above we see that
16/8 = 8/4 = 4/2 = 2 = ratio r
Theorem: If a1, a2 , a3 , …an is a sequence such that
an+1 / an = r for all n, then a1, a2, a3,… is a geometric
sequence and an = a1*rn-1.
Geometric Sequences
A sequence a1, a2 , a3 , … is a geometric sequence if
an = crn, i.e. it is defined by an exponential formula.
The sequence of powers of 2
a1= 2, a2= 4, a3= 8, a4= 16, …
is a geometric sequence because an = 2n.
Fact: If a1, a2 , a3 , …an = c*rn is a geometric sequence, then
the ratio between any two consecutive terms is r.
The converse of this fact is also true. Below is the formula
that we used for working with geometric sequences.
For example, from the sequence above we see that
16/8 = 8/4 = 4/2 = 2 = ratio r
Theorem: If a1, a2 , a3 , …an is a sequence such that
an+1 / an = r for all n, then a1, a2, a3,… is a geometric
sequence and an = a1*rn-1. This is the general formula for
geometric sequences.
Geometric Sequences
Given the description of a geometric sequence, we use the
general formula to find the specific formula for that sequence.
Geometric Sequences
Given the description of a geometric sequence, we use the
general formula to find the specific formula for that sequence.
Example A. The sequence 2, 6, 18, 54, … is a geometric
sequence because 6/2 = 18/6
Geometric Sequences
Given the description of a geometric sequence, we use the
general formula to find the specific formula for that sequence.
Example A. The sequence 2, 6, 18, 54, … is a geometric
sequence because 6/2 = 18/6 = 54/18
Geometric Sequences
Given the description of a geometric sequence, we use the
general formula to find the specific formula for that sequence.
Example A. The sequence 2, 6, 18, 54, … is a geometric
sequence because 6/2 = 18/6 = 54/18 = … = 3 = r.
Geometric Sequences
Given the description of a geometric sequence, we use the
general formula to find the specific formula for that sequence.
Example A. The sequence 2, 6, 18, 54, … is a geometric
sequence because 6/2 = 18/6 = 54/18 = … = 3 = r.
Since a1 = 2, set them in the general formula of the geometric
sequences an = a1r n – 1
Geometric Sequences
Given the description of a geometric sequence, we use the
general formula to find the specific formula for that sequence.
Example A. The sequence 2, 6, 18, 54, … is a geometric
sequence because 6/2 = 18/6 = 54/18 = … = 3 = r.
Since a1 = 2, set them in the general formula of the geometric
sequences an = a1r n – 1 , we get the specific formula for this
sequence an = 2*3(n – 1)
Geometric Sequences
Given the description of a geometric sequence, we use the
general formula to find the specific formula for that sequence.
Example A. The sequence 2, 6, 18, 54, … is a geometric
sequence because 6/2 = 18/6 = 54/18 = … = 3 = r.
Since a1 = 2, set them in the general formula of the geometric
sequences an = a1r n – 1 , we get the specific formula for this
sequence an = 2*3(n – 1)
If a1, a2 , a3 , …an is a geometric sequence such that the terms
alternate between positive and negative signs,
then r is negative.
Geometric Sequences
Given the description of a geometric sequence, we use the
general formula to find the specific formula for that sequence.
Example A. The sequence 2, 6, 18, 54, … is a geometric
sequence because 6/2 = 18/6 = 54/18 = … = 3 = r.
Since a1 = 2, set them in the general formula of the geometric
sequences an = a1r n – 1 , we get the specific formula for this
sequence an = 2*3(n – 1)
If a1, a2 , a3 , …an is a geometric sequence such that the terms
alternate between positive and negative signs,
then r is negative.
Example B. The sequence 2/3, -1, 3/2, -9/4, … is a geometric
sequence because
-1/(2/3) = (3/2) / (-1)
Geometric Sequences
Given the description of a geometric sequence, we use the
general formula to find the specific formula for that sequence.
Example A. The sequence 2, 6, 18, 54, … is a geometric
sequence because 6/2 = 18/6 = 54/18 = … = 3 = r.
Since a1 = 2, set them in the general formula of the geometric
sequences an = a1r n – 1 , we get the specific formula for this
sequence an = 2*3(n – 1)
If a1, a2 , a3 , …an is a geometric sequence such that the terms
alternate between positive and negative signs,
then r is negative.
Example B. The sequence 2/3, -1, 3/2, -9/4, … is a geometric
sequence because
-1/(2/3) = (3/2) / (-1) = (-9/4) /(3/2)
Geometric Sequences
Given the description of a geometric sequence, we use the
general formula to find the specific formula for that sequence.
Example A. The sequence 2, 6, 18, 54, … is a geometric
sequence because 6/2 = 18/6 = 54/18 = … = 3 = r.
Since a1 = 2, set them in the general formula of the geometric
sequences an = a1r n – 1 , we get the specific formula for this
sequence an = 2*3(n – 1)
If a1, a2 , a3 , …an is a geometric sequence such that the terms
alternate between positive and negative signs,
then r is negative.
Example B. The sequence 2/3, -1, 3/2, -9/4, … is a geometric
sequence because
-1/(2/3) = (3/2) / (-1) = (-9/4) /(3/2) = … = -3/2 = r.
Geometric Sequences
Given the description of a geometric sequence, we use the
general formula to find the specific formula for that sequence.
Example A. The sequence 2, 6, 18, 54, … is a geometric
sequence because 6/2 = 18/6 = 54/18 = … = 3 = r.
Since a1 = 2, set them in the general formula of the geometric
sequences an = a1r n – 1 , we get the specific formula for this
sequence an = 2*3(n – 1)
If a1, a2 , a3 , …an is a geometric sequence such that the terms
alternate between positive and negative signs,
then r is negative.
Example B. The sequence 2/3, -1, 3/2, -9/4, … is a geometric
sequence because
-1/(2/3) = (3/2) / (-1) = (-9/4) /(3/2) = … = -3/2 = r.
Since a1 = 2/3, the specific formula is
                                 2 –3 n–1
                            an = 3 ( 2 )
Geometric Sequences
To use the geometric general formula to find the specific
formula, we need the first term a1 and the ratio r.
Geometric Sequences
To use the geometric general formula to find the specific
formula, we need the first term a1 and the ratio r.
Example C. Given that a1, a2 , a3 , …is a geometric sequence
with r = -2 and a5 = 12,
Geometric Sequences
To use the geometric general formula to find the specific
formula, we need the first term a1 and the ratio r.
Example C. Given that a1, a2 , a3 , …is a geometric sequence
with r = -2 and a5 = 12,
a. find a1
Geometric Sequences
To use the geometric general formula to find the specific
formula, we need the first term a1 and the ratio r.
Example C. Given that a1, a2 , a3 , …is a geometric sequence
with r = -2 and a5 = 12,
a. find a1
By that the general geometric formula
an = a1r n – 1, we get
a5 = a1(-2)(5 – 1)
Geometric Sequences
To use the geometric general formula to find the specific
formula, we need the first term a1 and the ratio r.
Example C. Given that a1, a2 , a3 , …is a geometric sequence
with r = -2 and a5 = 12,
a. find a1
By that the general geometric formula
an = a1r n – 1, we get
a5 = a1(-2)(5 – 1) = 12
Geometric Sequences
To use the geometric general formula to find the specific
formula, we need the first term a1 and the ratio r.
Example C. Given that a1, a2 , a3 , …is a geometric sequence
with r = -2 and a5 = 12,
a. find a1
By that the general geometric formula
an = a1r n – 1, we get
a5 = a1(-2)(5 – 1) = 12
         a1(-2)4 = 12
Geometric Sequences
To use the geometric general formula to find the specific
formula, we need the first term a1 and the ratio r.
Example C. Given that a1, a2 , a3 , …is a geometric sequence
with r = -2 and a5 = 12,
a. find a1
By that the general geometric formula
an = a1r n – 1, we get
a5 = a1(-2)(5 – 1) = 12
         a1(-2)4 = 12
             16a1 = 12
Geometric Sequences
To use the geometric general formula to find the specific
formula, we need the first term a1 and the ratio r.
Example C. Given that a1, a2 , a3 , …is a geometric sequence
with r = -2 and a5 = 12,
a. find a1
By that the general geometric formula
an = a1r n – 1, we get
a5 = a1(-2)(5 – 1) = 12
         a1(-2)4 = 12
             16a1 = 12
                a1 = 12/16 = ¾
Geometric Sequences
To use the geometric general formula to find the specific
formula, we need the first term a1 and the ratio r.
Example C. Given that a1, a2 , a3 , …is a geometric sequence
with r = -2 and a5 = 12,
a. find a1
By that the general geometric formula
an = a1r n – 1, we get
a5 = a1(-2)(5 – 1) = 12
          a1(-2)4 = 12
             16a1 = 12
                a1 = 12/16 = ¾
b. find the specific equation.
Geometric Sequences
To use the geometric general formula to find the specific
formula, we need the first term a1 and the ratio r.
Example C. Given that a1, a2 , a3 , …is a geometric sequence
with r = -2 and a5 = 12,
a. find a1
By that the general geometric formula
an = a1r n – 1, we get
a5 = a1(-2)(5 – 1) = 12
          a1(-2)4 = 12
             16a1 = 12
                a1 = 12/16 = ¾
b. find the specific equation.
Set a1 = ¾ and r = -2 into the general formula an = a1rn – 1 ,
Geometric Sequences
To use the geometric general formula to find the specific
formula, we need the first term a1 and the ratio r.
Example C. Given that a1, a2 , a3 , …is a geometric sequence
with r = -2 and a5 = 12,
a. find a1
By that the general geometric formula
an = a1r n – 1, we get
a5 = a1(-2)(5 – 1) = 12
          a1(-2)4 = 12
             16a1 = 12
                a1 = 12/16 = ¾
b. find the specific equation.
Set a1 = ¾ and r = -2 into the general formula an = a1rn – 1 ,
we get the specific formula of this sequence
                         an= 3 (-2)n–1
                              4
Geometric Sequences
C. Find a9.
Geometric Sequences
C. Find a9.
Since an= 3 (-2)n–1,
           4
Geometric Sequences
C. Find a9.
Since an= 3 (-2)n–1,
            4
set n = 9, we get
a9= 3 (-2)9–1
     4
Geometric Sequences
C. Find a9.
Since an= 3 (-2)n–1,
            4
set n = 9, we get
a9= 3 (-2)9–1
     4
     3
a9 = 4 (-2)8
Geometric Sequences
C. Find a9.
Since an= 3 (-2)n–1,
            4
set n = 9, we get
a9= 3 (-2)9–1
     4
     3         3
a9 = 4 (-2)8 = 4 (256) = 192
Geometric Sequences
C. Find a9.
Since an= 3 (-2)n–1,
            4
set n = 9, we get
a9= 3 (-2)9–1
     4
     3          3
a9 = 4 (-2)8 = 4 (256) = 192
Example D. Given that a1, a2 , a3 , …is a geometric sequence
with a3 = -2 and a6 = 54,
Geometric Sequences
C. Find a9.
Since an= 3 (-2)n–1,
            4
set n = 9, we get
a9= 3 (-2)9–1
     4
     3          3
a9 = 4 (-2)8 = 4 (256) = 192
Example D. Given that a1, a2 , a3 , …is a geometric sequence
with a3 = -2 and a6 = 54,
a. Find r and a1
Geometric Sequences
C. Find a9.
Since an= 3 (-2)n–1,
            4
set n = 9, we get
a9= 3 (-2)9–1
     4
     3          3
a9 = 4 (-2)8 = 4 (256) = 192
Example D. Given that a1, a2 , a3 , …is a geometric sequence
with a3 = -2 and a6 = 54,
a. Find r and a1
Given that the general geometric formula an = a1rn – 1,
Geometric Sequences
C. Find a9.
Since an= 3 (-2)n–1,
            4
set n = 9, we get
a9= 3 (-2)9–1
     4
     3          3
a9 = 4 (-2)8 = 4 (256) = 192
Example D. Given that a1, a2 , a3 , …is a geometric sequence
with a3 = -2 and a6 = 54,
a. Find r and a1
Given that the general geometric formula an = a1rn – 1,
we have
    a3 = -2 = a1r3–1
Geometric Sequences
C. Find a9.
Since an= 3 (-2)n–1,
            4
set n = 9, we get
a9= 3 (-2)9–1
     4
     3          3
a9 = 4 (-2)8 = 4 (256) = 192
Example D. Given that a1, a2 , a3 , …is a geometric sequence
with a3 = -2 and a6 = 54,
a. Find r and a1
Given that the general geometric formula an = a1rn – 1,
we have
    a3 = -2 = a1r3–1  and         a6 = 54 = a1r6–1
Geometric Sequences
C. Find a9.
Since an= 3 (-2)n–1,
            4
set n = 9, we get
a9= 3 (-2)9–1
     4
     3          3
a9 = 4 (-2)8 = 4 (256) = 192
Example D. Given that a1, a2 , a3 , …is a geometric sequence
with a3 = -2 and a6 = 54,
a. Find r and a1
Given that the general geometric formula an = a1rn – 1,
we have
    a3 = -2 = a1r3–1  and         a6 = 54 = a1r6–1
        -2 = a1r2
Geometric Sequences
C. Find a9.
Since an= 3 (-2)n–1,
            4
set n = 9, we get
a9= 3 (-2)9–1
     4
     3          3
a9 = 4 (-2)8 = 4 (256) = 192
Example D. Given that a1, a2 , a3 , …is a geometric sequence
with a3 = -2 and a6 = 54,
a. Find r and a1
Given that the general geometric formula an = a1rn – 1,
we have
    a3 = -2 = a1r3–1  and         a6 = 54 = a1r6–1
        -2 = a1r2                      54 = a1r5
Geometric Sequences
C. Find a9.
Since an= 3 (-2)n–1,
            4
set n = 9, we get
a9= 3 (-2)9–1
     4
     3          3
a9 = 4 (-2)8 = 4 (256) = 192
Example D. Given that a1, a2 , a3 , …is a geometric sequence
with a3 = -2 and a6 = 54,
a. Find r and a1
Given that the general geometric formula an = a1rn – 1,
we have
    a3 = -2 = a1r3–1  and         a6 = 54 = a1r6–1
        -2 = a1r2                      54 = a1r5
Divide these equations:
Geometric Sequences
54   a1r5
   = a r2
-2    1
Geometric Sequences
-27 54 = a1r
             5

    -2   a1r2
Geometric Sequences
-27 54 = a1r
             5

    -2   a1r2
Geometric Sequences
                 3 = 5-2
-27 54 = a1r
             5

    -2   a1r2
Geometric Sequences
                  3 = 5-2
-27 54 = a1r
              5

    -2     a1r2
    -27 = r3
Geometric Sequences
                   3 = 5-2
-27 54 = a1r
               5

    -2      a1r2
    -27 = r3
     -3 = r
Geometric Sequences
                 5 3 = 5-2
-27 54 = a1r
      -2      a1r2
      -27 = r3
       -3 = r
Put r = -3 into the equation -2 = a1r2
Geometric Sequences
                 5 3 = 5-2
-27 54 = a1r
      -2      a1r2
      -27 = r3
       -3 = r
Put r = -3 into the equation -2 = a1r2
Hence -2 = a1(-3)2
Geometric Sequences
                 5 3 = 5-2
-27 54 = a1r
      -2      a1r2
      -27 = r3
       -3 = r
Put r = -3 into the equation -2 = a1r2
Hence -2 = a1(-3)2
         -2 = a19
Geometric Sequences
                 5 3 = 5-2
-27 54 = a1r
      -2      a1r2
      -27 = r3
       -3 = r
Put r = -3 into the equation -2 = a1r2
Hence -2 = a1(-3)2
         -2 = a19
       -2/9 = a1
Geometric Sequences
                 5 3 = 5-2
-27 54 = a1r
      -2      a1r2
      -27 = r3
       -3 = r
Put r = -3 into the equation -2 = a1r2
Hence -2 = a1(-3)2
         -2 = a19
       -2/9 = a1
b. Find the specific formula and a2
Geometric Sequences
                 5 3 = 5-2
 -27 54 = a1r
      -2      a1r2
      -27 = r3
       -3 = r
Put r = -3 into the equation -2 = a1r2
Hence -2 = a1(-3)2
         -2 = a19
       -2/9 = a1
b. Find the specific formula and a2
Use the general geometric formula an = a1rn – 1,
set a1 = -2/9, and r = -3
Geometric Sequences
                  5 3 = 5-2
 -27 54 = a1r
      -2       a1r2
      -27 = r3
        -3 = r
Put r = -3 into the equation -2 = a1r2
Hence -2 = a1(-3)2
         -2 = a19
       -2/9 = a1
b. Find the specific formula and a2
Use the general geometric formula an = a1rn – 1,
set a1 = -2/9, and r = -3 we have the specific formula
an = -2 (-3)n–1
       9
Geometric Sequences
                   5 3 = 5-2
 -27 54 = a1r
      -2       a1r2
      -27 = r3
        -3 = r
Put r = -3 into the equation -2 = a1r2
Hence -2 = a1(-3)2
         -2 = a19
       -2/9 = a1
b. Find the specific formula and a2
Use the general geometric formula an = a1rn – 1,
set a1 = -2/9, and r = -3 we have the specific formula
an = -2 (-3)n–1
       9
To find a2, set n = 2, we get
a2 = -2 (-3)
               2–1
      9
Geometric Sequences
                   5 3 = 5-2
 -27 54 = a1r
      -2       a1r2
      -27 = r3
        -3 = r
Put r = -3 into the equation -2 = a1r2
Hence -2 = a1(-3)2
         -2 = a19
       -2/9 = a1
b. Find the specific formula and a2
Use the general geometric formula an = a1rn – 1,
set a1 = -2/9, and r = -3 we have the specific formula
an = -2 (-3)n–1
       9
To find a2, set n = 2, we get
a2 = -2 (-3) = -2 (-3)
               2–1
      9                 9
Geometric Sequences
                   5 3 = 5-2
 -27 54 = a1r
      -2       a1r2
      -27 = r3
        -3 = r
Put r = -3 into the equation -2 = a1r2
Hence -2 = a1(-3)2
         -2 = a19
       -2/9 = a1
b. Find the specific formula and a2
Use the general geometric formula an = a1rn – 1,
set a1 = -2/9, and r = -3 we have the specific formula
an = -2 (-3)n–1
       9
To find a2, set n = 2, we get
a2 = -2 (-3) = -2 3 (-3)
               2–1
      9                 9
Geometric Sequences
                   5 3 = 5-2
 -27 54 = a1r
      -2       a1r2
      -27 = r3
        -3 = r
Put r = -3 into the equation -2 = a1r2
Hence -2 = a1(-3)2
         -2 = a19
       -2/9 = a1
b. Find the specific formula and a2
Use the general geometric formula an = a1rn – 1,
set a1 = -2/9, and r = -3 we have the specific formula
an = -2 (-3)n–1
       9
To find a2, set n = 2, we get
a2 = -2 (-3) = -2 3 (-3) = 2
               2–1
      9                 9     3
Geometric Sequences
Geometric Sequences
Sum of Geometric Sequences
Geometric Sequences
Sum of Geometric Sequences
We observe the algebraic patterns:
(1 – r)(1 + r) = 1 – r2
Geometric Sequences
Sum of Geometric Sequences
We observe the algebraic patterns:
(1 – r)(1 + r) = 1 – r2
(1 – r)(1 + r + r2) = 1 – r3
Geometric Sequences
Sum of Geometric Sequences
We observe the algebraic patterns:
(1 – r)(1 + r) = 1 – r2
(1 – r)(1 + r + r2) = 1 – r3
(1 – r)(1 + r + r2 + r3) = 1 – r4
Geometric Sequences
Sum of Geometric Sequences
We observe the algebraic patterns:
(1 – r)(1 + r) = 1 – r2
(1 – r)(1 + r + r2) = 1 – r3
(1 – r)(1 + r + r2 + r3) = 1 – r4
(1 – r)(1 + r + r2 + r3 + r4) = 1 – r5
Geometric Sequences
Sum of Geometric Sequences
We observe the algebraic patterns:
(1 – r)(1 + r) = 1 – r2
(1 – r)(1 + r + r2) = 1 – r3
(1 – r)(1 + r + r2 + r3) = 1 – r4
(1 – r)(1 + r + r2 + r3 + r4) = 1 – r5
...
…
(1 – r)(1 + r + r2 … + rn-1) = 1 – rn
Geometric Sequences
Sum of Geometric Sequences
We observe the algebraic patterns:
(1 – r)(1 + r) = 1 – r2
(1 – r)(1 + r + r2) = 1 – r3
(1 – r)(1 + r + r2 + r3) = 1 – r4
(1 – r)(1 + r + r2 + r3 + r4) = 1 – r5
...
…
(1 – r)(1 + r + r2 … + rn-1) = 1 – rn
Hence 1 + r + r + … + r =
                  2          n-1   1 – rn
                                   1–r
Geometric Sequences
Sum of Geometric Sequences
We observe the algebraic patterns:
(1 – r)(1 + r) = 1 – r2
(1 – r)(1 + r + r2) = 1 – r3
(1 – r)(1 + r + r2 + r3) = 1 – r4
(1 – r)(1 + r + r2 + r3 + r4) = 1 – r5
...
…
(1 – r)(1 + r + r2 … + rn-1) = 1 – rn
Hence 1 + r + r + … + r =
                  2          n-1   1 – rn
                                   1–r
Therefore a1 + a1r + a1r2 + … +a1rn-1
Geometric Sequences
Sum of Geometric Sequences
We observe the algebraic patterns:
(1 – r)(1 + r) = 1 – r2
(1 – r)(1 + r + r2) = 1 – r3
(1 – r)(1 + r + r2 + r3) = 1 – r4
(1 – r)(1 + r + r2 + r3 + r4) = 1 – r5
...
…
(1 – r)(1 + r + r2 … + rn-1) = 1 – rn
Hence 1 + r + r + … + r =
                  2          n-1   1 – rn
                                   1–r
Therefore a1 + a1r + a1r2 + … +a1rn-1
                      n terms
Geometric Sequences
Sum of Geometric Sequences
We observe the algebraic patterns:
(1 – r)(1 + r) = 1 – r2
(1 – r)(1 + r + r2) = 1 – r3
(1 – r)(1 + r + r2 + r3) = 1 – r4
(1 – r)(1 + r + r2 + r3 + r4) = 1 – r5
...
…
(1 – r)(1 + r + r2 … + rn-1) = 1 – rn
Hence 1 + r + r + … + r =
                  2          n-1   1 – rn
                                   1–r
Therefore a1 + a1r + a1r2 + … +a1rn-1
                    n terms
= a1(1 + r + r2 + … + r n-1)
Geometric Sequences
Sum of Geometric Sequences
We observe the algebraic patterns:
(1 – r)(1 + r) = 1 – r2
(1 – r)(1 + r + r2) = 1 – r3
(1 – r)(1 + r + r2 + r3) = 1 – r4
(1 – r)(1 + r + r2 + r3 + r4) = 1 – r5
...
…
(1 – r)(1 + r + r2 … + rn-1) = 1 – rn
Hence 1 + r + r + … + r =
                  2          n-1   1 – rn
                                   1–r
Therefore a1 + a1r + a1r2 + … +a1rn-1
                   n terms
                           a1 1 – r
                                    n
= a1(1 + r + r + … + r ) =
              2       n-1
                              1–r
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2        n-1   1 – rn
                             1–r
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2         n-1     1 – rn
                                1–r
Example E. Find the geometric sum :
2/3 + (-1) + 3/2 + … + (-81/16)
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2         n-1     1 – rn
                                1–r
Example E. Find the geometric sum :
2/3 + (-1) + 3/2 + … + (-81/16)
We have a1 = 2/3 and r = -3/2,
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2         n-1     1 – rn
                                1–r
Example E. Find the geometric sum :
2/3 + (-1) + 3/2 + … + (-81/16)
We have a1 = 2/3 and r = -3/2, and an = -81/16.
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2         n-1     1 – rn
                                1–r
Example E. Find the geometric sum :
2/3 + (-1) + 3/2 + … + (-81/16)
We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the
number of terms.
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2         n-1     1 – rn
                                1–r
Example E. Find the geometric sum :
2/3 + (-1) + 3/2 + … + (-81/16)
We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the
number of terms. Put a1 and r in the general formula we get
the specific formula
an= 2 ( - 3 ) n-1
     3    2
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2         n-1     1 – rn
                                1–r
Example E. Find the geometric sum :
2/3 + (-1) + 3/2 + … + (-81/16)
We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the
number of terms. Put a1 and r in the general formula we get
the specific formula
an= 2 ( - 3 ) n-1
      3    2
To find n, set an = -81
                     16
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2         n-1     1 – rn
                                1–r
Example E. Find the geometric sum :
2/3 + (-1) + 3/2 + … + (-81/16)
We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the
number of terms. Put a1 and r in the general formula we get
the specific formula
an= 2 ( - 3 ) n-1
      3    2
To find n, set an = -81 = 2 ( - 3 ) n – 1
                     16    3     2
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2         n-1     1 – rn
                                1–r
Example E. Find the geometric sum :
2/3 + (-1) + 3/2 + … + (-81/16)
We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the
number of terms. Put a1 and r in the general formula we get
the specific formula
an= 2 ( - 3 ) n-1
      3    2
To find n, set an = -81 = 2 ( - 3 ) n – 1
                     16    3     2
                    -243 = ( - 3 ) n – 1
                     32       2
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2         n-1     1 – rn
                                1–r
Example E. Find the geometric sum :
2/3 + (-1) + 3/2 + … + (-81/16)
We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the
number of terms. Put a1 and r in the general formula we get
the specific formula
an= 2 ( - 3 ) n-1
      3    2
To find n, set an = -81 = 2 ( - 3 ) n – 1
                     16    3     2
                    -243 = ( - 3 ) n – 1
                     32       2
Compare the denominators we see that 32 = 2n – 1.
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2         n-1     1 – rn
                                1–r
Example E. Find the geometric sum :
2/3 + (-1) + 3/2 + … + (-81/16)
We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the
number of terms. Put a1 and r in the general formula we get
the specific formula
an= 2 ( - 3 ) n-1
      3    2
To find n, set an = -81 = 2 ( - 3 ) n – 1
                      16   3     2
                    -243 = ( - 3 ) n – 1
                      32      2
Compare the denominators we see that 32 = 2n – 1.
Since 32 = 25 = 2n – 1
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2         n-1     1 – rn
                                1–r
Example E. Find the geometric sum :
2/3 + (-1) + 3/2 + … + (-81/16)
We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the
number of terms. Put a1 and r in the general formula we get
the specific formula
an= 2 ( - 3 ) n-1
      3    2
To find n, set an = -81 = 2 ( - 3 ) n – 1
                      16   3     2
                    -243 = ( - 3 ) n – 1
                      32      2
Compare the denominators we see that 32 = 2n – 1.
Since 32 = 25 = 2n – 1
    n–1=5
Geometric Sequences
Formula for the Sum Geometric Sequences
a1 + a1r + a1r + … +a1r = a1
              2         n-1     1 – rn
                                1–r
Example E. Find the geometric sum :
2/3 + (-1) + 3/2 + … + (-81/16)
We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the
number of terms. Put a1 and r in the general formula we get
the specific formula
an= 2 ( - 3 ) n-1
      3    2
To find n, set an = -81 = 2 ( - 3 ) n – 1
                      16   3     2
                    -243 = ( - 3 ) n – 1
                      32      2
Compare the denominators we see that 32 = 2n – 1.
Since 32 = 25 = 2n – 1
    n–1=5
        n=6
Geometric Sequences
Therefore there are 6 terms in the sum,
2/3 + (-1) + 3/2 + … + (-81/16)
Geometric Sequences
Therefore there are 6 terms in the sum,
2/3 + (-1) + 3/2 + … + (-81/16)
Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn
                                                       1–r
Geometric Sequences
Therefore there are 6 terms in the sum,
2/3 + (-1) + 3/2 + … + (-81/16)
Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn
                                                       1–r
we get the sum S
     2 1 – (-3/2)6
S = 3 1 – (-3/2)
Geometric Sequences
Therefore there are 6 terms in the sum,
2/3 + (-1) + 3/2 + … + (-81/16)
Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn
                                                       1–r
we get the sum S
     2 1 – (-3/2)6
S = 3 1 – (-3/2)

 = 2 1 – (729/64)
    3     1 + (3/2)
Geometric Sequences
Therefore there are 6 terms in the sum,
2/3 + (-1) + 3/2 + … + (-81/16)
Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn
                                                       1–r
we get the sum S
     2 1 – (-3/2)6
S = 3 1 – (-3/2)

 = 2 1 – (729/64)
    3     1 + (3/2)
  = 2      -665/64
     3        5/2
Geometric Sequences
Therefore there are 6 terms in the sum,
2/3 + (-1) + 3/2 + … + (-81/16)
Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn
                                                       1–r
we get the sum S
     2 1 – (-3/2)6
S = 3 1 – (-3/2)

 = 2 1 – (729/64)
    3     1 + (3/2)
  = 2      -665/64
     3        5/2
  = -133
      48
Geometric Sequences
Therefore there are 6 terms in the sum,
2/3 + (-1) + 3/2 + … + (-81/16)
Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn
                                                       1–r
we get the sum S
     2 1 – (-3/2)6
S = 3 1 – (-3/2)

 = 2 1 – (729/64)
    3     1 + (3/2)
  = 2      -665/64
     3        5/2
  = -133
      48
Geometric Sequences
Therefore there are 6 terms in the sum,
2/3 + (-1) + 3/2 + … + (-81/16)
Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn
                                                       1–r
we get the sum S
     2 1 – (-3/2)6
S = 3 1 – (-3/2)

 = 2 1 – (729/64)
    3     1 + (3/2)
  = 2      -665/64
     3        5/2
  = -133
      48

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5.3 geometric sequences

  • 2. Geometric Sequences A sequence a1, a2 , a3 , … is a geometric sequence if an = crn, i.e. it is defined by an exponential formula.
  • 3. Geometric Sequences A sequence a1, a2 , a3 , … is a geometric sequence if an = crn, i.e. it is defined by an exponential formula. The sequence of powers of 2 a1= 2, a2= 4, a3= 8, a4= 16, … is a geometric sequence because an = 2n.
  • 4. Geometric Sequences A sequence a1, a2 , a3 , … is a geometric sequence if an = crn, i.e. it is defined by an exponential formula. The sequence of powers of 2 a1= 2, a2= 4, a3= 8, a4= 16, … is a geometric sequence because an = 2n. Fact: If a1, a2 , a3 , …an = c*rn is a geometric sequence, then the ratio between any two consecutive terms is r.
  • 5. Geometric Sequences A sequence a1, a2 , a3 , … is a geometric sequence if an = crn, i.e. it is defined by an exponential formula. The sequence of powers of 2 a1= 2, a2= 4, a3= 8, a4= 16, … is a geometric sequence because an = 2n. Fact: If a1, a2 , a3 , …an = c*rn is a geometric sequence, then the ratio between any two consecutive terms is r. The converse of this fact is also true.
  • 6. Geometric Sequences A sequence a1, a2 , a3 , … is a geometric sequence if an = crn, i.e. it is defined by an exponential formula. The sequence of powers of 2 a1= 2, a2= 4, a3= 8, a4= 16, … is a geometric sequence because an = 2n. Fact: If a1, a2 , a3 , …an = c*rn is a geometric sequence, then the ratio between any two consecutive terms is r. The converse of this fact is also true. Below is the formula that we used for working with geometric sequences.
  • 7. Geometric Sequences A sequence a1, a2 , a3 , … is a geometric sequence if an = crn, i.e. it is defined by an exponential formula. The sequence of powers of 2 a1= 2, a2= 4, a3= 8, a4= 16, … is a geometric sequence because an = 2n. Fact: If a1, a2 , a3 , …an = c*rn is a geometric sequence, then the ratio between any two consecutive terms is r. The converse of this fact is also true. For example, from the sequence above we see that 16/8 = 8/4 = 4/2 = 2 = ratio r. Below is the formula that we used for working with geometric sequences.
  • 8. Geometric Sequences A sequence a1, a2 , a3 , … is a geometric sequence if an = crn, i.e. it is defined by an exponential formula. The sequence of powers of 2 a1= 2, a2= 4, a3= 8, a4= 16, … is a geometric sequence because an = 2n. Fact: If a1, a2 , a3 , …an = c*rn is a geometric sequence, then the ratio between any two consecutive terms is r. The converse of this fact is also true. Below is the formula that we used for working with geometric sequences. For example, from the sequence above we see that 16/8 = 8/4 = 4/2 = 2 = ratio r Theorem: If a1, a2 , a3 , …an is a sequence such that an+1 / an = r for all n, then a1, a2, a3,… is a geometric sequence and an = a1*rn-1.
  • 9. Geometric Sequences A sequence a1, a2 , a3 , … is a geometric sequence if an = crn, i.e. it is defined by an exponential formula. The sequence of powers of 2 a1= 2, a2= 4, a3= 8, a4= 16, … is a geometric sequence because an = 2n. Fact: If a1, a2 , a3 , …an = c*rn is a geometric sequence, then the ratio between any two consecutive terms is r. The converse of this fact is also true. Below is the formula that we used for working with geometric sequences. For example, from the sequence above we see that 16/8 = 8/4 = 4/2 = 2 = ratio r Theorem: If a1, a2 , a3 , …an is a sequence such that an+1 / an = r for all n, then a1, a2, a3,… is a geometric sequence and an = a1*rn-1. This is the general formula for geometric sequences.
  • 10. Geometric Sequences Given the description of a geometric sequence, we use the general formula to find the specific formula for that sequence.
  • 11. Geometric Sequences Given the description of a geometric sequence, we use the general formula to find the specific formula for that sequence. Example A. The sequence 2, 6, 18, 54, … is a geometric sequence because 6/2 = 18/6
  • 12. Geometric Sequences Given the description of a geometric sequence, we use the general formula to find the specific formula for that sequence. Example A. The sequence 2, 6, 18, 54, … is a geometric sequence because 6/2 = 18/6 = 54/18
  • 13. Geometric Sequences Given the description of a geometric sequence, we use the general formula to find the specific formula for that sequence. Example A. The sequence 2, 6, 18, 54, … is a geometric sequence because 6/2 = 18/6 = 54/18 = … = 3 = r.
  • 14. Geometric Sequences Given the description of a geometric sequence, we use the general formula to find the specific formula for that sequence. Example A. The sequence 2, 6, 18, 54, … is a geometric sequence because 6/2 = 18/6 = 54/18 = … = 3 = r. Since a1 = 2, set them in the general formula of the geometric sequences an = a1r n – 1
  • 15. Geometric Sequences Given the description of a geometric sequence, we use the general formula to find the specific formula for that sequence. Example A. The sequence 2, 6, 18, 54, … is a geometric sequence because 6/2 = 18/6 = 54/18 = … = 3 = r. Since a1 = 2, set them in the general formula of the geometric sequences an = a1r n – 1 , we get the specific formula for this sequence an = 2*3(n – 1)
  • 16. Geometric Sequences Given the description of a geometric sequence, we use the general formula to find the specific formula for that sequence. Example A. The sequence 2, 6, 18, 54, … is a geometric sequence because 6/2 = 18/6 = 54/18 = … = 3 = r. Since a1 = 2, set them in the general formula of the geometric sequences an = a1r n – 1 , we get the specific formula for this sequence an = 2*3(n – 1) If a1, a2 , a3 , …an is a geometric sequence such that the terms alternate between positive and negative signs, then r is negative.
  • 17. Geometric Sequences Given the description of a geometric sequence, we use the general formula to find the specific formula for that sequence. Example A. The sequence 2, 6, 18, 54, … is a geometric sequence because 6/2 = 18/6 = 54/18 = … = 3 = r. Since a1 = 2, set them in the general formula of the geometric sequences an = a1r n – 1 , we get the specific formula for this sequence an = 2*3(n – 1) If a1, a2 , a3 , …an is a geometric sequence such that the terms alternate between positive and negative signs, then r is negative. Example B. The sequence 2/3, -1, 3/2, -9/4, … is a geometric sequence because -1/(2/3) = (3/2) / (-1)
  • 18. Geometric Sequences Given the description of a geometric sequence, we use the general formula to find the specific formula for that sequence. Example A. The sequence 2, 6, 18, 54, … is a geometric sequence because 6/2 = 18/6 = 54/18 = … = 3 = r. Since a1 = 2, set them in the general formula of the geometric sequences an = a1r n – 1 , we get the specific formula for this sequence an = 2*3(n – 1) If a1, a2 , a3 , …an is a geometric sequence such that the terms alternate between positive and negative signs, then r is negative. Example B. The sequence 2/3, -1, 3/2, -9/4, … is a geometric sequence because -1/(2/3) = (3/2) / (-1) = (-9/4) /(3/2)
  • 19. Geometric Sequences Given the description of a geometric sequence, we use the general formula to find the specific formula for that sequence. Example A. The sequence 2, 6, 18, 54, … is a geometric sequence because 6/2 = 18/6 = 54/18 = … = 3 = r. Since a1 = 2, set them in the general formula of the geometric sequences an = a1r n – 1 , we get the specific formula for this sequence an = 2*3(n – 1) If a1, a2 , a3 , …an is a geometric sequence such that the terms alternate between positive and negative signs, then r is negative. Example B. The sequence 2/3, -1, 3/2, -9/4, … is a geometric sequence because -1/(2/3) = (3/2) / (-1) = (-9/4) /(3/2) = … = -3/2 = r.
  • 20. Geometric Sequences Given the description of a geometric sequence, we use the general formula to find the specific formula for that sequence. Example A. The sequence 2, 6, 18, 54, … is a geometric sequence because 6/2 = 18/6 = 54/18 = … = 3 = r. Since a1 = 2, set them in the general formula of the geometric sequences an = a1r n – 1 , we get the specific formula for this sequence an = 2*3(n – 1) If a1, a2 , a3 , …an is a geometric sequence such that the terms alternate between positive and negative signs, then r is negative. Example B. The sequence 2/3, -1, 3/2, -9/4, … is a geometric sequence because -1/(2/3) = (3/2) / (-1) = (-9/4) /(3/2) = … = -3/2 = r. Since a1 = 2/3, the specific formula is 2 –3 n–1 an = 3 ( 2 )
  • 21. Geometric Sequences To use the geometric general formula to find the specific formula, we need the first term a1 and the ratio r.
  • 22. Geometric Sequences To use the geometric general formula to find the specific formula, we need the first term a1 and the ratio r. Example C. Given that a1, a2 , a3 , …is a geometric sequence with r = -2 and a5 = 12,
  • 23. Geometric Sequences To use the geometric general formula to find the specific formula, we need the first term a1 and the ratio r. Example C. Given that a1, a2 , a3 , …is a geometric sequence with r = -2 and a5 = 12, a. find a1
  • 24. Geometric Sequences To use the geometric general formula to find the specific formula, we need the first term a1 and the ratio r. Example C. Given that a1, a2 , a3 , …is a geometric sequence with r = -2 and a5 = 12, a. find a1 By that the general geometric formula an = a1r n – 1, we get a5 = a1(-2)(5 – 1)
  • 25. Geometric Sequences To use the geometric general formula to find the specific formula, we need the first term a1 and the ratio r. Example C. Given that a1, a2 , a3 , …is a geometric sequence with r = -2 and a5 = 12, a. find a1 By that the general geometric formula an = a1r n – 1, we get a5 = a1(-2)(5 – 1) = 12
  • 26. Geometric Sequences To use the geometric general formula to find the specific formula, we need the first term a1 and the ratio r. Example C. Given that a1, a2 , a3 , …is a geometric sequence with r = -2 and a5 = 12, a. find a1 By that the general geometric formula an = a1r n – 1, we get a5 = a1(-2)(5 – 1) = 12 a1(-2)4 = 12
  • 27. Geometric Sequences To use the geometric general formula to find the specific formula, we need the first term a1 and the ratio r. Example C. Given that a1, a2 , a3 , …is a geometric sequence with r = -2 and a5 = 12, a. find a1 By that the general geometric formula an = a1r n – 1, we get a5 = a1(-2)(5 – 1) = 12 a1(-2)4 = 12 16a1 = 12
  • 28. Geometric Sequences To use the geometric general formula to find the specific formula, we need the first term a1 and the ratio r. Example C. Given that a1, a2 , a3 , …is a geometric sequence with r = -2 and a5 = 12, a. find a1 By that the general geometric formula an = a1r n – 1, we get a5 = a1(-2)(5 – 1) = 12 a1(-2)4 = 12 16a1 = 12 a1 = 12/16 = ¾
  • 29. Geometric Sequences To use the geometric general formula to find the specific formula, we need the first term a1 and the ratio r. Example C. Given that a1, a2 , a3 , …is a geometric sequence with r = -2 and a5 = 12, a. find a1 By that the general geometric formula an = a1r n – 1, we get a5 = a1(-2)(5 – 1) = 12 a1(-2)4 = 12 16a1 = 12 a1 = 12/16 = ¾ b. find the specific equation.
  • 30. Geometric Sequences To use the geometric general formula to find the specific formula, we need the first term a1 and the ratio r. Example C. Given that a1, a2 , a3 , …is a geometric sequence with r = -2 and a5 = 12, a. find a1 By that the general geometric formula an = a1r n – 1, we get a5 = a1(-2)(5 – 1) = 12 a1(-2)4 = 12 16a1 = 12 a1 = 12/16 = ¾ b. find the specific equation. Set a1 = ¾ and r = -2 into the general formula an = a1rn – 1 ,
  • 31. Geometric Sequences To use the geometric general formula to find the specific formula, we need the first term a1 and the ratio r. Example C. Given that a1, a2 , a3 , …is a geometric sequence with r = -2 and a5 = 12, a. find a1 By that the general geometric formula an = a1r n – 1, we get a5 = a1(-2)(5 – 1) = 12 a1(-2)4 = 12 16a1 = 12 a1 = 12/16 = ¾ b. find the specific equation. Set a1 = ¾ and r = -2 into the general formula an = a1rn – 1 , we get the specific formula of this sequence an= 3 (-2)n–1 4
  • 33. Geometric Sequences C. Find a9. Since an= 3 (-2)n–1, 4
  • 34. Geometric Sequences C. Find a9. Since an= 3 (-2)n–1, 4 set n = 9, we get a9= 3 (-2)9–1 4
  • 35. Geometric Sequences C. Find a9. Since an= 3 (-2)n–1, 4 set n = 9, we get a9= 3 (-2)9–1 4 3 a9 = 4 (-2)8
  • 36. Geometric Sequences C. Find a9. Since an= 3 (-2)n–1, 4 set n = 9, we get a9= 3 (-2)9–1 4 3 3 a9 = 4 (-2)8 = 4 (256) = 192
  • 37. Geometric Sequences C. Find a9. Since an= 3 (-2)n–1, 4 set n = 9, we get a9= 3 (-2)9–1 4 3 3 a9 = 4 (-2)8 = 4 (256) = 192 Example D. Given that a1, a2 , a3 , …is a geometric sequence with a3 = -2 and a6 = 54,
  • 38. Geometric Sequences C. Find a9. Since an= 3 (-2)n–1, 4 set n = 9, we get a9= 3 (-2)9–1 4 3 3 a9 = 4 (-2)8 = 4 (256) = 192 Example D. Given that a1, a2 , a3 , …is a geometric sequence with a3 = -2 and a6 = 54, a. Find r and a1
  • 39. Geometric Sequences C. Find a9. Since an= 3 (-2)n–1, 4 set n = 9, we get a9= 3 (-2)9–1 4 3 3 a9 = 4 (-2)8 = 4 (256) = 192 Example D. Given that a1, a2 , a3 , …is a geometric sequence with a3 = -2 and a6 = 54, a. Find r and a1 Given that the general geometric formula an = a1rn – 1,
  • 40. Geometric Sequences C. Find a9. Since an= 3 (-2)n–1, 4 set n = 9, we get a9= 3 (-2)9–1 4 3 3 a9 = 4 (-2)8 = 4 (256) = 192 Example D. Given that a1, a2 , a3 , …is a geometric sequence with a3 = -2 and a6 = 54, a. Find r and a1 Given that the general geometric formula an = a1rn – 1, we have a3 = -2 = a1r3–1
  • 41. Geometric Sequences C. Find a9. Since an= 3 (-2)n–1, 4 set n = 9, we get a9= 3 (-2)9–1 4 3 3 a9 = 4 (-2)8 = 4 (256) = 192 Example D. Given that a1, a2 , a3 , …is a geometric sequence with a3 = -2 and a6 = 54, a. Find r and a1 Given that the general geometric formula an = a1rn – 1, we have a3 = -2 = a1r3–1 and a6 = 54 = a1r6–1
  • 42. Geometric Sequences C. Find a9. Since an= 3 (-2)n–1, 4 set n = 9, we get a9= 3 (-2)9–1 4 3 3 a9 = 4 (-2)8 = 4 (256) = 192 Example D. Given that a1, a2 , a3 , …is a geometric sequence with a3 = -2 and a6 = 54, a. Find r and a1 Given that the general geometric formula an = a1rn – 1, we have a3 = -2 = a1r3–1 and a6 = 54 = a1r6–1 -2 = a1r2
  • 43. Geometric Sequences C. Find a9. Since an= 3 (-2)n–1, 4 set n = 9, we get a9= 3 (-2)9–1 4 3 3 a9 = 4 (-2)8 = 4 (256) = 192 Example D. Given that a1, a2 , a3 , …is a geometric sequence with a3 = -2 and a6 = 54, a. Find r and a1 Given that the general geometric formula an = a1rn – 1, we have a3 = -2 = a1r3–1 and a6 = 54 = a1r6–1 -2 = a1r2 54 = a1r5
  • 44. Geometric Sequences C. Find a9. Since an= 3 (-2)n–1, 4 set n = 9, we get a9= 3 (-2)9–1 4 3 3 a9 = 4 (-2)8 = 4 (256) = 192 Example D. Given that a1, a2 , a3 , …is a geometric sequence with a3 = -2 and a6 = 54, a. Find r and a1 Given that the general geometric formula an = a1rn – 1, we have a3 = -2 = a1r3–1 and a6 = 54 = a1r6–1 -2 = a1r2 54 = a1r5 Divide these equations:
  • 45. Geometric Sequences 54 a1r5 = a r2 -2 1
  • 46. Geometric Sequences -27 54 = a1r 5 -2 a1r2
  • 47. Geometric Sequences -27 54 = a1r 5 -2 a1r2
  • 48. Geometric Sequences 3 = 5-2 -27 54 = a1r 5 -2 a1r2
  • 49. Geometric Sequences 3 = 5-2 -27 54 = a1r 5 -2 a1r2 -27 = r3
  • 50. Geometric Sequences 3 = 5-2 -27 54 = a1r 5 -2 a1r2 -27 = r3 -3 = r
  • 51. Geometric Sequences 5 3 = 5-2 -27 54 = a1r -2 a1r2 -27 = r3 -3 = r Put r = -3 into the equation -2 = a1r2
  • 52. Geometric Sequences 5 3 = 5-2 -27 54 = a1r -2 a1r2 -27 = r3 -3 = r Put r = -3 into the equation -2 = a1r2 Hence -2 = a1(-3)2
  • 53. Geometric Sequences 5 3 = 5-2 -27 54 = a1r -2 a1r2 -27 = r3 -3 = r Put r = -3 into the equation -2 = a1r2 Hence -2 = a1(-3)2 -2 = a19
  • 54. Geometric Sequences 5 3 = 5-2 -27 54 = a1r -2 a1r2 -27 = r3 -3 = r Put r = -3 into the equation -2 = a1r2 Hence -2 = a1(-3)2 -2 = a19 -2/9 = a1
  • 55. Geometric Sequences 5 3 = 5-2 -27 54 = a1r -2 a1r2 -27 = r3 -3 = r Put r = -3 into the equation -2 = a1r2 Hence -2 = a1(-3)2 -2 = a19 -2/9 = a1 b. Find the specific formula and a2
  • 56. Geometric Sequences 5 3 = 5-2 -27 54 = a1r -2 a1r2 -27 = r3 -3 = r Put r = -3 into the equation -2 = a1r2 Hence -2 = a1(-3)2 -2 = a19 -2/9 = a1 b. Find the specific formula and a2 Use the general geometric formula an = a1rn – 1, set a1 = -2/9, and r = -3
  • 57. Geometric Sequences 5 3 = 5-2 -27 54 = a1r -2 a1r2 -27 = r3 -3 = r Put r = -3 into the equation -2 = a1r2 Hence -2 = a1(-3)2 -2 = a19 -2/9 = a1 b. Find the specific formula and a2 Use the general geometric formula an = a1rn – 1, set a1 = -2/9, and r = -3 we have the specific formula an = -2 (-3)n–1 9
  • 58. Geometric Sequences 5 3 = 5-2 -27 54 = a1r -2 a1r2 -27 = r3 -3 = r Put r = -3 into the equation -2 = a1r2 Hence -2 = a1(-3)2 -2 = a19 -2/9 = a1 b. Find the specific formula and a2 Use the general geometric formula an = a1rn – 1, set a1 = -2/9, and r = -3 we have the specific formula an = -2 (-3)n–1 9 To find a2, set n = 2, we get a2 = -2 (-3) 2–1 9
  • 59. Geometric Sequences 5 3 = 5-2 -27 54 = a1r -2 a1r2 -27 = r3 -3 = r Put r = -3 into the equation -2 = a1r2 Hence -2 = a1(-3)2 -2 = a19 -2/9 = a1 b. Find the specific formula and a2 Use the general geometric formula an = a1rn – 1, set a1 = -2/9, and r = -3 we have the specific formula an = -2 (-3)n–1 9 To find a2, set n = 2, we get a2 = -2 (-3) = -2 (-3) 2–1 9 9
  • 60. Geometric Sequences 5 3 = 5-2 -27 54 = a1r -2 a1r2 -27 = r3 -3 = r Put r = -3 into the equation -2 = a1r2 Hence -2 = a1(-3)2 -2 = a19 -2/9 = a1 b. Find the specific formula and a2 Use the general geometric formula an = a1rn – 1, set a1 = -2/9, and r = -3 we have the specific formula an = -2 (-3)n–1 9 To find a2, set n = 2, we get a2 = -2 (-3) = -2 3 (-3) 2–1 9 9
  • 61. Geometric Sequences 5 3 = 5-2 -27 54 = a1r -2 a1r2 -27 = r3 -3 = r Put r = -3 into the equation -2 = a1r2 Hence -2 = a1(-3)2 -2 = a19 -2/9 = a1 b. Find the specific formula and a2 Use the general geometric formula an = a1rn – 1, set a1 = -2/9, and r = -3 we have the specific formula an = -2 (-3)n–1 9 To find a2, set n = 2, we get a2 = -2 (-3) = -2 3 (-3) = 2 2–1 9 9 3
  • 63. Geometric Sequences Sum of Geometric Sequences
  • 64. Geometric Sequences Sum of Geometric Sequences We observe the algebraic patterns: (1 – r)(1 + r) = 1 – r2
  • 65. Geometric Sequences Sum of Geometric Sequences We observe the algebraic patterns: (1 – r)(1 + r) = 1 – r2 (1 – r)(1 + r + r2) = 1 – r3
  • 66. Geometric Sequences Sum of Geometric Sequences We observe the algebraic patterns: (1 – r)(1 + r) = 1 – r2 (1 – r)(1 + r + r2) = 1 – r3 (1 – r)(1 + r + r2 + r3) = 1 – r4
  • 67. Geometric Sequences Sum of Geometric Sequences We observe the algebraic patterns: (1 – r)(1 + r) = 1 – r2 (1 – r)(1 + r + r2) = 1 – r3 (1 – r)(1 + r + r2 + r3) = 1 – r4 (1 – r)(1 + r + r2 + r3 + r4) = 1 – r5
  • 68. Geometric Sequences Sum of Geometric Sequences We observe the algebraic patterns: (1 – r)(1 + r) = 1 – r2 (1 – r)(1 + r + r2) = 1 – r3 (1 – r)(1 + r + r2 + r3) = 1 – r4 (1 – r)(1 + r + r2 + r3 + r4) = 1 – r5 ... … (1 – r)(1 + r + r2 … + rn-1) = 1 – rn
  • 69. Geometric Sequences Sum of Geometric Sequences We observe the algebraic patterns: (1 – r)(1 + r) = 1 – r2 (1 – r)(1 + r + r2) = 1 – r3 (1 – r)(1 + r + r2 + r3) = 1 – r4 (1 – r)(1 + r + r2 + r3 + r4) = 1 – r5 ... … (1 – r)(1 + r + r2 … + rn-1) = 1 – rn Hence 1 + r + r + … + r = 2 n-1 1 – rn 1–r
  • 70. Geometric Sequences Sum of Geometric Sequences We observe the algebraic patterns: (1 – r)(1 + r) = 1 – r2 (1 – r)(1 + r + r2) = 1 – r3 (1 – r)(1 + r + r2 + r3) = 1 – r4 (1 – r)(1 + r + r2 + r3 + r4) = 1 – r5 ... … (1 – r)(1 + r + r2 … + rn-1) = 1 – rn Hence 1 + r + r + … + r = 2 n-1 1 – rn 1–r Therefore a1 + a1r + a1r2 + … +a1rn-1
  • 71. Geometric Sequences Sum of Geometric Sequences We observe the algebraic patterns: (1 – r)(1 + r) = 1 – r2 (1 – r)(1 + r + r2) = 1 – r3 (1 – r)(1 + r + r2 + r3) = 1 – r4 (1 – r)(1 + r + r2 + r3 + r4) = 1 – r5 ... … (1 – r)(1 + r + r2 … + rn-1) = 1 – rn Hence 1 + r + r + … + r = 2 n-1 1 – rn 1–r Therefore a1 + a1r + a1r2 + … +a1rn-1 n terms
  • 72. Geometric Sequences Sum of Geometric Sequences We observe the algebraic patterns: (1 – r)(1 + r) = 1 – r2 (1 – r)(1 + r + r2) = 1 – r3 (1 – r)(1 + r + r2 + r3) = 1 – r4 (1 – r)(1 + r + r2 + r3 + r4) = 1 – r5 ... … (1 – r)(1 + r + r2 … + rn-1) = 1 – rn Hence 1 + r + r + … + r = 2 n-1 1 – rn 1–r Therefore a1 + a1r + a1r2 + … +a1rn-1 n terms = a1(1 + r + r2 + … + r n-1)
  • 73. Geometric Sequences Sum of Geometric Sequences We observe the algebraic patterns: (1 – r)(1 + r) = 1 – r2 (1 – r)(1 + r + r2) = 1 – r3 (1 – r)(1 + r + r2 + r3) = 1 – r4 (1 – r)(1 + r + r2 + r3 + r4) = 1 – r5 ... … (1 – r)(1 + r + r2 … + rn-1) = 1 – rn Hence 1 + r + r + … + r = 2 n-1 1 – rn 1–r Therefore a1 + a1r + a1r2 + … +a1rn-1 n terms a1 1 – r n = a1(1 + r + r + … + r ) = 2 n-1 1–r
  • 74. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r
  • 75. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r Example E. Find the geometric sum : 2/3 + (-1) + 3/2 + … + (-81/16)
  • 76. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r Example E. Find the geometric sum : 2/3 + (-1) + 3/2 + … + (-81/16) We have a1 = 2/3 and r = -3/2,
  • 77. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r Example E. Find the geometric sum : 2/3 + (-1) + 3/2 + … + (-81/16) We have a1 = 2/3 and r = -3/2, and an = -81/16.
  • 78. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r Example E. Find the geometric sum : 2/3 + (-1) + 3/2 + … + (-81/16) We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the number of terms.
  • 79. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r Example E. Find the geometric sum : 2/3 + (-1) + 3/2 + … + (-81/16) We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the number of terms. Put a1 and r in the general formula we get the specific formula an= 2 ( - 3 ) n-1 3 2
  • 80. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r Example E. Find the geometric sum : 2/3 + (-1) + 3/2 + … + (-81/16) We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the number of terms. Put a1 and r in the general formula we get the specific formula an= 2 ( - 3 ) n-1 3 2 To find n, set an = -81 16
  • 81. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r Example E. Find the geometric sum : 2/3 + (-1) + 3/2 + … + (-81/16) We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the number of terms. Put a1 and r in the general formula we get the specific formula an= 2 ( - 3 ) n-1 3 2 To find n, set an = -81 = 2 ( - 3 ) n – 1 16 3 2
  • 82. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r Example E. Find the geometric sum : 2/3 + (-1) + 3/2 + … + (-81/16) We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the number of terms. Put a1 and r in the general formula we get the specific formula an= 2 ( - 3 ) n-1 3 2 To find n, set an = -81 = 2 ( - 3 ) n – 1 16 3 2 -243 = ( - 3 ) n – 1 32 2
  • 83. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r Example E. Find the geometric sum : 2/3 + (-1) + 3/2 + … + (-81/16) We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the number of terms. Put a1 and r in the general formula we get the specific formula an= 2 ( - 3 ) n-1 3 2 To find n, set an = -81 = 2 ( - 3 ) n – 1 16 3 2 -243 = ( - 3 ) n – 1 32 2 Compare the denominators we see that 32 = 2n – 1.
  • 84. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r Example E. Find the geometric sum : 2/3 + (-1) + 3/2 + … + (-81/16) We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the number of terms. Put a1 and r in the general formula we get the specific formula an= 2 ( - 3 ) n-1 3 2 To find n, set an = -81 = 2 ( - 3 ) n – 1 16 3 2 -243 = ( - 3 ) n – 1 32 2 Compare the denominators we see that 32 = 2n – 1. Since 32 = 25 = 2n – 1
  • 85. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r Example E. Find the geometric sum : 2/3 + (-1) + 3/2 + … + (-81/16) We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the number of terms. Put a1 and r in the general formula we get the specific formula an= 2 ( - 3 ) n-1 3 2 To find n, set an = -81 = 2 ( - 3 ) n – 1 16 3 2 -243 = ( - 3 ) n – 1 32 2 Compare the denominators we see that 32 = 2n – 1. Since 32 = 25 = 2n – 1 n–1=5
  • 86. Geometric Sequences Formula for the Sum Geometric Sequences a1 + a1r + a1r + … +a1r = a1 2 n-1 1 – rn 1–r Example E. Find the geometric sum : 2/3 + (-1) + 3/2 + … + (-81/16) We have a1 = 2/3 and r = -3/2, and an = -81/16. We need the number of terms. Put a1 and r in the general formula we get the specific formula an= 2 ( - 3 ) n-1 3 2 To find n, set an = -81 = 2 ( - 3 ) n – 1 16 3 2 -243 = ( - 3 ) n – 1 32 2 Compare the denominators we see that 32 = 2n – 1. Since 32 = 25 = 2n – 1 n–1=5 n=6
  • 87. Geometric Sequences Therefore there are 6 terms in the sum, 2/3 + (-1) + 3/2 + … + (-81/16)
  • 88. Geometric Sequences Therefore there are 6 terms in the sum, 2/3 + (-1) + 3/2 + … + (-81/16) Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn 1–r
  • 89. Geometric Sequences Therefore there are 6 terms in the sum, 2/3 + (-1) + 3/2 + … + (-81/16) Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn 1–r we get the sum S 2 1 – (-3/2)6 S = 3 1 – (-3/2)
  • 90. Geometric Sequences Therefore there are 6 terms in the sum, 2/3 + (-1) + 3/2 + … + (-81/16) Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn 1–r we get the sum S 2 1 – (-3/2)6 S = 3 1 – (-3/2) = 2 1 – (729/64) 3 1 + (3/2)
  • 91. Geometric Sequences Therefore there are 6 terms in the sum, 2/3 + (-1) + 3/2 + … + (-81/16) Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn 1–r we get the sum S 2 1 – (-3/2)6 S = 3 1 – (-3/2) = 2 1 – (729/64) 3 1 + (3/2) = 2 -665/64 3 5/2
  • 92. Geometric Sequences Therefore there are 6 terms in the sum, 2/3 + (-1) + 3/2 + … + (-81/16) Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn 1–r we get the sum S 2 1 – (-3/2)6 S = 3 1 – (-3/2) = 2 1 – (729/64) 3 1 + (3/2) = 2 -665/64 3 5/2 = -133 48
  • 93. Geometric Sequences Therefore there are 6 terms in the sum, 2/3 + (-1) + 3/2 + … + (-81/16) Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn 1–r we get the sum S 2 1 – (-3/2)6 S = 3 1 – (-3/2) = 2 1 – (729/64) 3 1 + (3/2) = 2 -665/64 3 5/2 = -133 48
  • 94. Geometric Sequences Therefore there are 6 terms in the sum, 2/3 + (-1) + 3/2 + … + (-81/16) Set a1 = 2/3, r = -3/2 and n = 6 in the formula S = a1 1 – rn 1–r we get the sum S 2 1 – (-3/2)6 S = 3 1 – (-3/2) = 2 1 – (729/64) 3 1 + (3/2) = 2 -665/64 3 5/2 = -133 48