c) For each of the three products that are observed in Spectrum C, there is a diagnostic proton that can be used to accurately calculate the product ratios. (Remember that a good diagnostic proton has a \"clean\" signal that has minimal overlap with other signals- see \"Handout 05: Calculating Compound Ratios\" on CourseWeb.) What diagnostic proton can be used to calculate product ratios for each isomer? If the isomer was not formed, write \"N/A.\" (4 points) p-bromoaniline o-bromoaniline o,p- dibromoaniline O,o,p tribromoaniline d) Using the diagnostic protons you listed in part c, calculate the percent of each isomer. Show calculations for each isomer. If an isomer was not formed, write \"0%\" (8 points) %p-bromoaniline % o-bromoaniline % o,o,p- tribromoaniline 960,p. dibromoaniline
Solution
Solution:
The spectrum interpretation are as shown below,
Part (C)
p - bromoaniline = 7.529
o - bromoaniline = 7.230
o,p - dibromoaniline = 6.651
o,o,p - tribromoaniline = 6.566
Part (D)
p - bromoaniline = (2*1):(2*0.83) = 2/(2+1.66)*100% = 54.65 %
o - bromoaniline = 0
o,p - dibromoaniline = 1.15 /(5.43+1.15+0.61)*100% = 15.99 = 16%
o,o,p - tribromoaniline = 5.95/(0.80+1.35+5.95) *100% = 73.46 = 74%
.
c) For each of the three products that are observed in Spectrum C- the.docx
1. c) For each of the three products that are observed in Spectrum C, there is a diagnostic proton
that can be used to accurately calculate the product ratios. (Remember that a good diagnostic
proton has a "clean" signal that has minimal overlap with other signals- see "Handout 05:
Calculating Compound Ratios" on CourseWeb.) What diagnostic proton can be used to calculate
product ratios for each isomer? If the isomer was not formed, write "N/A." (4 points) p-
bromoaniline o-bromoaniline o,p- dibromoaniline O,o,p tribromoaniline d) Using the diagnostic
protons you listed in part c, calculate the percent of each isomer. Show calculations for each
isomer. If an isomer was not formed, write "0%" (8 points) %p-bromoaniline % o-bromoaniline
% o,o,p- tribromoaniline 960,p. dibromoaniline
Solution
Solution:
The spectrum interpretation are as shown below,
Part (C)
p - bromoaniline = 7.529
o - bromoaniline = 7.230
o,p - dibromoaniline = 6.651
o,o,p - tribromoaniline = 6.566
Part (D)
p - bromoaniline = (2*1):(2*0.83) = 2/(2+1.66)*100% = 54.65 %
o - bromoaniline = 0
o,p - dibromoaniline = 1.15 /(5.43+1.15+0.61)*100% = 15.99 = 16%
o,o,p - tribromoaniline = 5.95/(0.80+1.35+5.95) *100% = 73.46 = 74%
