C++ Design a special tree data structure such that the branching fact.docx

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The document discusses designing a special tree data structure in C++ where the root node has a branching factor of 3, its children have a branching factor of 2, and the branching factor of subsequent nodes alternates between 2 and 3 depending on whether its parent has a branching factor of 3 or 2, respectively. It expresses uncertainty on how to implement this and requests help.

C++
Design a special tree data structure such that the branching factor of the root is 3 and the
branching factor of its children is two. After that the branching factor of a node is 2 if the node is
child of a node with branching factor of 3 and its branching factor is 3 if it is the child of a node
with branching factor of 2 in C++. Not sure what to do. Would appreciate any help
C++
Design a special tree data structure such that the branching factor of the root is 3 and the
branching factor of its children is two. After that the branching factor of a node is 2 if the node is
child of a node with branching factor of 3 and its branching factor is 3 if it is the child of a node
with branching factor of 2 in C++. Not sure what to do. Would appreciate any help
Design a special tree data structure such that the branching factor of the root is 3 and the
branching factor of its children is two. After that the branching factor of a node is 2 if the node is
child of a node with branching factor of 3 and its branching factor is 3 if it is the child of a node
with branching factor of 2 in C++. Not sure what to do. Would appreciate any help
Solution
B-Tree-Insert(T, k)
B-Tree-Insert-Nonfull(x, k)

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Calculate fost of goods sold and ending inventory and analyze effect of each method on financial statements. Jefferson company had the following sales and purchases during 2011, its first year of business: January 5 Purchased 40 units at $100 each February 15 Sold 15 units at $150 each April 10 Sold 10 units at $150 each June 30 Purchased 30 units at $105 each August 15 Sold 25 units at $150 each November 28 Purchased 30 untis at $110 each Solution Part A: Record the effect of the following transactions on the accounting equation assuming LIFO perpetual: Transactions in January, 2011: Assets Liabilities Shareholders .

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Calculate fost of goods sold and ending inventory and analyze effect of each method on financial statements. Jefferson company had the following sales and purchases during 2011, its first year of business: January 5 Purchased 40 units at $100 each February 15 Sold 15 units at $150 each April 10 Sold 10 units at $150 each June 30 Purchased 30 units at $105 each August 15 Sold 25 units at $150 each November 28 Purchased 30 untis at $110 each Solution Part A: Record the effect of the following transactions on the accounting equation assuming LIFO perpetual: Transactions in January, 2011: Assets Liabilities Shareholders .

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Ca(OH)2 is insoluble. What is the total concentration of ions if 2M of Ca(OH)2 dissolves in water. Ca(OH)2 is insoluble. What is the total concentration of ions if 2M of Ca(OH)2 dissolves in water. Solution Ca(OH)2 is partially soluble in water and we can find solubility based on solubility product Ca(OH)2 (s) <-----> Ca2+ (aq) + 2OH- (aq) at equilibrium [Ca2+] = S , [OH-] = 2S Ksp = [Ca2+] [OH-]^2 ( where Ksp is solubility product of Ca(OH)2 in water) 5.5 x 10^ -6 = (S) (2S)^2 S = 0.0111 M Thus [Ca2+] = 0.0111 , [OH-] = 2 x 0.0111 = 0.0222 M Total concetrations of ions = [Ca2+] + 2 [OH-] = ( 0.0111) + 2 ( 0.0222) = 0.0555 M .

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9. Fill in the following table with names or formulas, as appropriate: Names silver sulfate hydrocyanic acid gold(III) chlorite perbromic acid calcium phosphide mercury(I) nitrate sulfurous acid aluminum chromate tin(IV) carbonate oxalic acid Formulas Fe(HC03)2 HNO2(aq (NH4)3BO3 Li2Cr20, Hl(aq) Solution silver sulfate = Ag2So4 hydrocyanic acid = HCN gold(III) chlorite = Au(Clo2)3 perbromic acid = Hbro4 calcium phosphide = ca3p2 mercury(I)nitrate = hg2(no3)2 sulfurous acid = H2So3 aluminum chromate = Al2(cro4)3 tin(iv)carbonate = sn(co3)2 oxalic acid = (cooh)2 iron(ii)hydrogen carbonate = Fe(hco3)2 aqueous nitrous acid =HNo2(aq) ammonium borate = (NH4)3Bo3 lithium dichromate = Li2Cr2o7 aqueous hydro iodic acid = HI(aq) the above names based on the type of elements or substituents attached to the compounds .

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9. A combination of sand, salt, and water is an example of a A) homogeneous mixture B) heterogeneous mixture C) compound D) pure substance E) solid 10. Forthe following reaction Chldh +Oz ? CO2 + 11,0 what is the coefficient of oxygen? a. 2 b. 4 c. 6 d. 8 e. None of the above Solution 9) Salt, sand and water mixture contains two different phases. liquid phase and solid phase. and moreover they dont mix and form separate phases. So, this is example of heterogeneous mixture. (B) 10) Balance the reaction : C 3 H 4 O2 + O 2 -----------> CO 2 + H 2 O balance the reaction for Carbon , C 3 H 4 O2 + O 2 -----------> 3 CO 2 + H 2 O balance the reaction for hydrogen, C 3 H 4 O2 + O 2 -----------> 3 CO 2 + 2 H 2 O now balance the reaction for oxygen, C 3 H 4 O2 + 3 O 2 -----------> 3 CO 2 + 2 H 2 O So, the answer is 3 and option is none of the above. .

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8.6. Which of the highlighted elements in Figure P8.6 has the greatest electronegativity? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 FIGURE P8.6 Solution Electronegativity is a chemical property of an atom that describes how well the atom withdraws shared pair of electrons towards it. It is measured in terms of Pauling Scale from Â Â 0 to 4. The higher the value, the more the electronegativity of the atom. The highlighted element 17 (Fluorine, F) has the highest electronegativity value is 3.98 . The highlighted element 1 (Lithium, Li) has the highest electronegativity value is 0.98. The highlighted element 2 (Beryllium, Be) has the highest electronegativity value is 1.57. The highlighted element 13 (Boron, B) has the highest electronegativity value is 2.04. The highlighted element 14 (Carbon, C) has the highest electronegativity value is 2.55. The highlighted element 15 (Nitrogen, N) has the highest electronegativity value is 3.04. The highlighted element 16 (Oxygen, O) has the highest electronegativity value is 3.44. The highlighted element 18 (Neon, Ne) has the highest electronegativity value is 0. .

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870 The plates of a capacitor are not quite parallel, the distance between them at the bottom being (D a) and at the top (Dta), where a Solution let length of each plate be L and width be W. then area A=L*W at a distance x from the bottom end of the plate, distance between the plates as a function of x is given as d=D-a+(2*a/L)*x consider a small segment of length dx at a distance of x from the bottom end area of the segment=W*dx distance between the two plates=d=(D-a+(2*a/L)*x) then capacitance=dC=epsilon*area/distance between plates =epsilon*W*dx/(D-a+(2*a/L)*x) let D-a+(2*a/L)*x=y ==>(2*a/L)*dx=dy ==>dx=L*dy/(2*a) substituting, dC=epsilon*W*L*dy/(2*a*y) integrating both sides, C=(epsilon*W*L/(2*a))*ln(y) as y varies from D-a to D+a C=(epsilon*W*L/(2*a))*ln((D+a)/(D-a)) as A=W*L and ln((D+a)/(D-a)) =ln((1+(a/D))/(1-(a/D))) =2*(a/D)*(1+(a^2/(3*D^2))) then C=(epslion*A/(2*a))*(2*a/D)*(1+(a^2/(3*D^2))) =(epsilon*A/D)*(1+(a^2/(3*D^2))) .

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1. C++ Design a special tree data structure such that the branching factor of the root is 3 and the branching factor of its children is two. After that the branching factor of a node is 2 if the node is child of a node with branching factor of 3 and its branching factor is 3 if it is the child of a node with branching factor of 2 in C++. Not sure what to do. Would appreciate any help C++ Design a special tree data structure such that the branching factor of the root is 3 and the branching factor of its children is two. After that the branching factor of a node is 2 if the node is child of a node with branching factor of 3 and its branching factor is 3 if it is the child of a node with branching factor of 2 in C++. Not sure what to do. Would appreciate any help Design a special tree data structure such that the branching factor of the root is 3 and the branching factor of its children is two. After that the branching factor of a node is 2 if the node is child of a node with branching factor of 3 and its branching factor is 3 if it is the child of a node with branching factor of 2 in C++. Not sure what to do. Would appreciate any help Solution B-Tree-Insert(T, k) B-Tree-Insert-Nonfull(x, k)