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Prepared By:-
Garje Mahesh Arjun
Roll No.: 04
M. Pharm Sem-1
(Pharmaceutics)
Guide:-
Prof. A.W. Ambekar
M. Pharm
Dept. of Pharmaceutics
Dr. Vithalrao Vikhe Patil Foundation's
College of Pharmacy
Vilad Ghat, Ahmednagar
Introduction
Dissolution:-
The process in which a solid drug substance
solubilises in given solvent i.e. mass transfer from
solid surface to liquid phase.
Rate of dissolution:-
Amount of drug substance that goes in the solution
per unit time under standardised condition of liquid
pH , solvent, temperature.
1
2
To study the release of drug in desired amount from
dosage form.
To study the uniformity of drug release from dosage
form of different batches.
To show that drug release is equivalent to those
batches proven to be bioavailable and clinically
effective.
33
1. Model independent method:- F1 and f2 comparison
2. Graphical method
3. Statistical method
4. Zero order kinetic model
5. 1st order kinetic model
6. Higuchi model
7. Hixson- Crowell model
8. Korsmeyar Peppas model
4
Difference factor f1 and similarity factor f2
 These equations described by Moore and Flamner
 Both equations are endorsed by FDA as acceptable method for
dissolution profile comparison.
 f1 value – difference factor
 f2 value – similarity factor
 They are used to study the comparison of dissolution profiles
of the two dosage form.
 It can be calculated using Excel or various readymade
software's (E.g. PhEq_bootstrap)
5
 It calculate % difference between two curves at each time point
& measure relative error between two curves.
 f1 equation is sum of absolute values of vertical distance
between reference(Rt) and test(Tt) mean % release values i.e.
(Rt-Tt) at each dissolution point.
 Equation:-
Where, Rt:-Reference dissolution value,
N:- No. of dissolution time point
Tt:- Test dissolution value
66
 f2 equation is logarithmic transformation of average squared
vertical distance between reference and test mean dissolution
values at each time point, multiplied by an approximate
weighting i.e. Wt(Rt-Tt)
 Equation:-
Where, Rt-Reference dissolution value,
n- No. of dissolution time point
Tt- Test dissolution value
Wt- Optional weighting factor
7
1. If both the test and reference product show ≥ 85%
dissolution within 15 minutes,
 the profiles are considered to be similar
 No calculations are required
2.f1 value(difference Factor):-
 if f1=0 to 15
3. f2 value (similarity factor):-
 If f2 ≥ 50 , the profiles are regarded similar.
8
Additional Requirements
 At least 12 unit should used .
 Same test conditions should maintained.
 Dissolution time points for Immediate Release products
like 15,30,45,60 min
 For sustained release 1, 2, 3, 5, and 8 hrs until at least
85% of drug is released.
 Only one measurement should considered after 85%
dissolution of drug.
 SD: ≤ 20% at early time point &
≤ 10% at later time points
99
Time Rt Tt (Rt-Tt) (Rt-Tt)2
10 45 55 10 100
15 65 75 10 100
20 80 90 10 100
30 90 100 10 100
45 0 0
60 0 0
Sum Of (Rt-Tt)=40
Sum of (Rt-Tt)2=400
Sum of Rt=280
Difference Factor f1= 14
Similarity Factor f2=50
No of time points: 04
Insert No of points where both products ≥85 %
Rt= Cumulative % dissolved of reference product at time t
Tt= Cumulative % dissolved of Test product at time t
Example:
1010
In 1961 Higuchi developed mathematical model for
study of release of drug from its matrix.
 Initial drug concentration in matrix is much higher.
 As drug is released distance for diffusion is
progressively increases.
 Drug is leached out polymer matrix by entrance of
surrounding medium.
 In release environment perfect sink is maintained.
1111
 The Equation Of Higuchi model:
Q= [D(2A-Cs)Cs×t]1/2 or
Q=(2ADCst)1/2
By differentiating above equan we get,
dQ/dt=(ADCs/2t)1/2
The Drug release from granular matrix is given by
Where, dQ/dt – rate of drug release
Cs- Solubility of drug in matrix
A- Total Concentration of drug in matrix
D- Diffusion Coefficient
t- Time, ε -porosity of matrix, τ-Tortuosity
1212
Example
 Problem:- 1.What is amount of drug per unit area
released from tablet matrix at time t= 120 ? Total
concentration in homogeneous matrix A is 0.02
g/cm3. Solubility Cs is 1.0×10-3 g/cm3 in polymer.
Diffusion coefficient d at 250c is 360×10-6 cm2/min.
 Solution:- we have equation
Q= (2ADCst)1/2
= [ 2 (0.02 g/cm3) (360×10-6 cm2/min)
(1×10-3 g/cm3) (120 min) ]1/2
Q= 1.3 × 10-3 g/cm2
1313
 Problem.2: What is instantaneous rate of release of
drug occurring at 120 min?
 Solution:-
We have equation,
dQ/dt = (ADCs/2t)1/2
=[ (0.02)(360×10-6)(1.0×10-3)/ 2×120]1/2
= 5.5×10-6 gcm-2min-1
1414
Korsmeyer’s-Peppa’s model
 A simple relationship which described drug release from a polymeric
system equation was derived by Korsmeyer-Peppa in 1983
 To understand the mechanism of drug release and to compare the
release profile differences among these matrix formulations ,the
percent drug released time versus time were fitted using this equation
Mt / M∞ = k. tn
 Mt / M∞ = percent drug released at time t
 K= constant incorporating structural and geometrical
characteristics of the sustained release device.
 n =exponential which characterizes mechanism of drug release
15
15
 The n value characterises different releases from
matrix and specify release mechanisms as shown
below
 To study release kinetic data obtained plotted as log
cumulative % drug release versus time.
 Application: To study modified release dosage form
and release phenomenon of drug.
Release Exponent (n) Drug transport mechanism
0.5 Fickian diffusion
0.5<n=0.89 Non Fickian transport
0.89 Case II transport
Higher than 0.89 Super case II transport
1616
References
 Sinko PJ, Singh Y , “Martin’s Physical Pharmacy and
Pharmaceutical Sciences”, Fifth edition, Lippincott Williams
and Wilkins , p. 344 to 346.
 Lachman L, Lieberman HA, “Theory And Practice Of
Industrial Pharmacy” Fourth Edition, Reprint 1991, Varghese
Publishing House; p. 205, 206, 207.
 Bramhankar DM, Jaiswal SB , “Biopharmaceutics and
Pharmacokinetics-A Treatise”, Third Edition, Reprint 2016,
Vallabh Prakashan; p.334-336, 434-437.
17
18

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Similarity factor, higuchi plot, peppas plot

  • 1. Prepared By:- Garje Mahesh Arjun Roll No.: 04 M. Pharm Sem-1 (Pharmaceutics) Guide:- Prof. A.W. Ambekar M. Pharm Dept. of Pharmaceutics Dr. Vithalrao Vikhe Patil Foundation's College of Pharmacy Vilad Ghat, Ahmednagar
  • 2. Introduction Dissolution:- The process in which a solid drug substance solubilises in given solvent i.e. mass transfer from solid surface to liquid phase. Rate of dissolution:- Amount of drug substance that goes in the solution per unit time under standardised condition of liquid pH , solvent, temperature. 1
  • 3. 2
  • 4. To study the release of drug in desired amount from dosage form. To study the uniformity of drug release from dosage form of different batches. To show that drug release is equivalent to those batches proven to be bioavailable and clinically effective. 33
  • 5. 1. Model independent method:- F1 and f2 comparison 2. Graphical method 3. Statistical method 4. Zero order kinetic model 5. 1st order kinetic model 6. Higuchi model 7. Hixson- Crowell model 8. Korsmeyar Peppas model 4
  • 6. Difference factor f1 and similarity factor f2  These equations described by Moore and Flamner  Both equations are endorsed by FDA as acceptable method for dissolution profile comparison.  f1 value – difference factor  f2 value – similarity factor  They are used to study the comparison of dissolution profiles of the two dosage form.  It can be calculated using Excel or various readymade software's (E.g. PhEq_bootstrap) 5
  • 7.  It calculate % difference between two curves at each time point & measure relative error between two curves.  f1 equation is sum of absolute values of vertical distance between reference(Rt) and test(Tt) mean % release values i.e. (Rt-Tt) at each dissolution point.  Equation:- Where, Rt:-Reference dissolution value, N:- No. of dissolution time point Tt:- Test dissolution value 66
  • 8.  f2 equation is logarithmic transformation of average squared vertical distance between reference and test mean dissolution values at each time point, multiplied by an approximate weighting i.e. Wt(Rt-Tt)  Equation:- Where, Rt-Reference dissolution value, n- No. of dissolution time point Tt- Test dissolution value Wt- Optional weighting factor 7
  • 9. 1. If both the test and reference product show ≥ 85% dissolution within 15 minutes,  the profiles are considered to be similar  No calculations are required 2.f1 value(difference Factor):-  if f1=0 to 15 3. f2 value (similarity factor):-  If f2 ≥ 50 , the profiles are regarded similar. 8
  • 10. Additional Requirements  At least 12 unit should used .  Same test conditions should maintained.  Dissolution time points for Immediate Release products like 15,30,45,60 min  For sustained release 1, 2, 3, 5, and 8 hrs until at least 85% of drug is released.  Only one measurement should considered after 85% dissolution of drug.  SD: ≤ 20% at early time point & ≤ 10% at later time points 99
  • 11. Time Rt Tt (Rt-Tt) (Rt-Tt)2 10 45 55 10 100 15 65 75 10 100 20 80 90 10 100 30 90 100 10 100 45 0 0 60 0 0 Sum Of (Rt-Tt)=40 Sum of (Rt-Tt)2=400 Sum of Rt=280 Difference Factor f1= 14 Similarity Factor f2=50 No of time points: 04 Insert No of points where both products ≥85 % Rt= Cumulative % dissolved of reference product at time t Tt= Cumulative % dissolved of Test product at time t Example: 1010
  • 12. In 1961 Higuchi developed mathematical model for study of release of drug from its matrix.  Initial drug concentration in matrix is much higher.  As drug is released distance for diffusion is progressively increases.  Drug is leached out polymer matrix by entrance of surrounding medium.  In release environment perfect sink is maintained. 1111
  • 13.  The Equation Of Higuchi model: Q= [D(2A-Cs)Cs×t]1/2 or Q=(2ADCst)1/2 By differentiating above equan we get, dQ/dt=(ADCs/2t)1/2 The Drug release from granular matrix is given by Where, dQ/dt – rate of drug release Cs- Solubility of drug in matrix A- Total Concentration of drug in matrix D- Diffusion Coefficient t- Time, ε -porosity of matrix, τ-Tortuosity 1212
  • 14. Example  Problem:- 1.What is amount of drug per unit area released from tablet matrix at time t= 120 ? Total concentration in homogeneous matrix A is 0.02 g/cm3. Solubility Cs is 1.0×10-3 g/cm3 in polymer. Diffusion coefficient d at 250c is 360×10-6 cm2/min.  Solution:- we have equation Q= (2ADCst)1/2 = [ 2 (0.02 g/cm3) (360×10-6 cm2/min) (1×10-3 g/cm3) (120 min) ]1/2 Q= 1.3 × 10-3 g/cm2 1313
  • 15.  Problem.2: What is instantaneous rate of release of drug occurring at 120 min?  Solution:- We have equation, dQ/dt = (ADCs/2t)1/2 =[ (0.02)(360×10-6)(1.0×10-3)/ 2×120]1/2 = 5.5×10-6 gcm-2min-1 1414
  • 16. Korsmeyer’s-Peppa’s model  A simple relationship which described drug release from a polymeric system equation was derived by Korsmeyer-Peppa in 1983  To understand the mechanism of drug release and to compare the release profile differences among these matrix formulations ,the percent drug released time versus time were fitted using this equation Mt / M∞ = k. tn  Mt / M∞ = percent drug released at time t  K= constant incorporating structural and geometrical characteristics of the sustained release device.  n =exponential which characterizes mechanism of drug release 15 15
  • 17.  The n value characterises different releases from matrix and specify release mechanisms as shown below  To study release kinetic data obtained plotted as log cumulative % drug release versus time.  Application: To study modified release dosage form and release phenomenon of drug. Release Exponent (n) Drug transport mechanism 0.5 Fickian diffusion 0.5<n=0.89 Non Fickian transport 0.89 Case II transport Higher than 0.89 Super case II transport 1616
  • 18. References  Sinko PJ, Singh Y , “Martin’s Physical Pharmacy and Pharmaceutical Sciences”, Fifth edition, Lippincott Williams and Wilkins , p. 344 to 346.  Lachman L, Lieberman HA, “Theory And Practice Of Industrial Pharmacy” Fourth Edition, Reprint 1991, Varghese Publishing House; p. 205, 206, 207.  Bramhankar DM, Jaiswal SB , “Biopharmaceutics and Pharmacokinetics-A Treatise”, Third Edition, Reprint 2016, Vallabh Prakashan; p.334-336, 434-437. 17
  • 19. 18