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IB Physics Power Points


                         Topic 07 and 13
                    Atomic and Nuclear Physics


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     Nuclear
    Reactions
Nuclear Transmutations
Definition: A nuclear reaction where one nuclide is
changed into another. Examples of nuclear
reactions include fission, fusion, and radioactive
decay
Artificial (induced) Transmutations

• target nucleus is bombarded with another particle
such as a nucleon, an alpha particle or another small
nucleus




• if the target nucleus „captures‟ an incoming particle a
transmutation reaction occurs
Artificial (induced) Transmutations

This reaction was first observed by Rutherford in 1919.


         4        2+   14       17        1   +
         2   He         7   N    8   O+ p 1


This nuclear reaction equation is balanced. The sums
of the mass and atomic numbers are equal for both
sides of the reaction arrow (don‟t worry about the
electrons ie the ionic charges).
Practice
A neutron is observed to strike a 16O nucleus and a
deuteron (2H) is given off. What is the nuclide that
results?


     1          16               2
     0   n       8  O            1   H       ?

    1          16              2            15
    0   n       8 O            1   H         7   N
Nuclear Reactions – common notations

                             4
    alpha particle           2   He or
                                 1
    neutron                      0   n or n
    electron                     0
                                 1   e or
                                 1
    proton                       p or p
                                 1
Unified atomic mass unit
                           1.660538782(83)×10−27 kg




       /12
     1 amu = 931.46 MeV/c2 = 0.93146 GeV/c2
Einstein’s mass – energy equivalence



                                   E=mc2

                                          Big Idea
                             mass and energy are interconvertible




  Einstein‟s equation relates rest mass to an equivalent energy

  1 kg = c2 J of energy (a lot!)
  1 amu = 931.46 MeV = 0.93146 GeV of energy
Now convert the energy value (in Joules) to electron volts




                    10               19
     1.494 10             1.6 10            934 MeV
mass defect
 Consider a helium nucleus: 2 protons and 2 neutrons




Total mass of                              mass 4.001504 u
protons and
neutrons?
 4.031882 u



  mass defect = 4.031882 – 4.001504 = 0.030378 u
   (Δm or σ)
Practice
1.The mass of an atom of Ne-20 is 19.992435 u.
Determine the mass defect for this nuclide.


 m 10 (0.000549 1.007276 1.008665) 19.992435
 m 0.172465 u
binding energy – explaining the missing mass
 “assembling” a nucleus


                                    binding energy
 Individual
 protons and
 neutrons
Practice
1. Determine the binding energy in O-16 (MeV and J).
The mass of an O-16 atom is 15.994915 u.

   m 8 (0.000549 1.007276 1.008665) 15.994915
   m 0.137005 u


        E   0.137005 u 931.5 127.6 MeV
binding energy per nucleon




               depends on nuclide

                iron has highest value – mental note
Practice
Use the graph to estimate the binding energy per nucleon for Fe-
56. Verify your estimate mathematically. Mass of Fe-56 ATOM
is 55.934940 u

  m (26 0.000549) (26 1.007276) (30 1.008665) 55.934940
  m 0.52846 amu
0.52846 amu 931.5 MeV c 2 492.26049 MeV
492.26049 MeV
               8.79 MeV / nucleon
      56
How much energy is required to remove a neutron from a C-13
nucleus? Write a balanced nuclear equation for this reaction.
C-13 atom mass = 13.003355 amu, and of course C-12 has a
mass of ?                  13          12          1
                             6   C      6   C    0   n

          m (12.000 1.008665) 13.003355
          m 0.00531 amu
                                             2
        0.00531 amu        931.5 MeV c           4.946 MeV
STOP HERE and Complete Worksheet 1
fusion and fission reactions




               where does the energy come from?
fusion and fission reactions




Fusion
 2 light nuclides (low binding energy per nucleon) combine
to make one heavy nuclide (higher binding energy per
nucleon)


Fission
 One heavy nuclide (lower binding energy per nucleon) splits
to form lighter nuclides (higher binding energy per nucleon)
(235.043924 1.008665) (90.910187 141.929630 3 1.008665)
  0.186777
 931.5 173.99MeV
1
H + 1H
1   1
               2
               H+
               1
                           0
                          +1   e + ν + 0.4 MeV
1      2       3
H+ H
1      1       2   He + 5.5 MeV
3          3         4             1
2   He + He2         2   He + 2 H + 12.9 MeV
                                   1
Big Fusion Problem Number 1: Confinement of plasma

Possibility 1 – inertial confinement: beams of laser
light or ions compress a fuel pellet from all sides while
heating it.

Possibility 2 – magnetic confinement: using a magnetic
field to cause plasma (charged gas particles) to
circulate endlessly within a confined space.



.
Big Fusion Problem Number 2: Extracting energy

Once a fusion reaction is initiated and confined, the
energy must be extracted in order to be any use (and
to stop the whole thing melting down).

One possibility is to use a molten lithium blanket
surrounding the fusion reaction to transfer the heat to
a water based heat transport system.

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Ppt djy 2011 2 topic 7 and 13 nuclear reactions

  • 1. IB Physics Power Points Topic 07 and 13 Atomic and Nuclear Physics www.pedagogics.ca Nuclear Reactions
  • 2. Nuclear Transmutations Definition: A nuclear reaction where one nuclide is changed into another. Examples of nuclear reactions include fission, fusion, and radioactive decay
  • 3. Artificial (induced) Transmutations • target nucleus is bombarded with another particle such as a nucleon, an alpha particle or another small nucleus • if the target nucleus „captures‟ an incoming particle a transmutation reaction occurs
  • 4. Artificial (induced) Transmutations This reaction was first observed by Rutherford in 1919. 4 2+ 14 17 1 + 2 He 7 N 8 O+ p 1 This nuclear reaction equation is balanced. The sums of the mass and atomic numbers are equal for both sides of the reaction arrow (don‟t worry about the electrons ie the ionic charges).
  • 5. Practice A neutron is observed to strike a 16O nucleus and a deuteron (2H) is given off. What is the nuclide that results? 1 16 2 0 n 8 O 1 H ? 1 16 2 15 0 n 8 O 1 H 7 N
  • 6. Nuclear Reactions – common notations 4 alpha particle 2 He or 1 neutron 0 n or n electron 0 1 e or 1 proton p or p 1
  • 7. Unified atomic mass unit 1.660538782(83)×10−27 kg /12 1 amu = 931.46 MeV/c2 = 0.93146 GeV/c2
  • 8. Einstein’s mass – energy equivalence E=mc2 Big Idea mass and energy are interconvertible Einstein‟s equation relates rest mass to an equivalent energy 1 kg = c2 J of energy (a lot!) 1 amu = 931.46 MeV = 0.93146 GeV of energy
  • 9. Now convert the energy value (in Joules) to electron volts 10 19 1.494 10 1.6 10 934 MeV
  • 10.
  • 11. mass defect Consider a helium nucleus: 2 protons and 2 neutrons Total mass of mass 4.001504 u protons and neutrons? 4.031882 u mass defect = 4.031882 – 4.001504 = 0.030378 u (Δm or σ)
  • 12. Practice 1.The mass of an atom of Ne-20 is 19.992435 u. Determine the mass defect for this nuclide. m 10 (0.000549 1.007276 1.008665) 19.992435 m 0.172465 u
  • 13. binding energy – explaining the missing mass “assembling” a nucleus binding energy Individual protons and neutrons
  • 14. Practice 1. Determine the binding energy in O-16 (MeV and J). The mass of an O-16 atom is 15.994915 u. m 8 (0.000549 1.007276 1.008665) 15.994915 m 0.137005 u E 0.137005 u 931.5 127.6 MeV
  • 15. binding energy per nucleon depends on nuclide iron has highest value – mental note
  • 16. Practice Use the graph to estimate the binding energy per nucleon for Fe- 56. Verify your estimate mathematically. Mass of Fe-56 ATOM is 55.934940 u m (26 0.000549) (26 1.007276) (30 1.008665) 55.934940 m 0.52846 amu 0.52846 amu 931.5 MeV c 2 492.26049 MeV 492.26049 MeV 8.79 MeV / nucleon 56
  • 17. How much energy is required to remove a neutron from a C-13 nucleus? Write a balanced nuclear equation for this reaction. C-13 atom mass = 13.003355 amu, and of course C-12 has a mass of ? 13 12 1 6 C 6 C 0 n m (12.000 1.008665) 13.003355 m 0.00531 amu 2 0.00531 amu 931.5 MeV c 4.946 MeV
  • 18. STOP HERE and Complete Worksheet 1
  • 19. fusion and fission reactions where does the energy come from?
  • 20. fusion and fission reactions Fusion 2 light nuclides (low binding energy per nucleon) combine to make one heavy nuclide (higher binding energy per nucleon) Fission One heavy nuclide (lower binding energy per nucleon) splits to form lighter nuclides (higher binding energy per nucleon)
  • 21. (235.043924 1.008665) (90.910187 141.929630 3 1.008665) 0.186777 931.5 173.99MeV
  • 22.
  • 23.
  • 24. 1 H + 1H 1 1 2 H+ 1 0 +1 e + ν + 0.4 MeV 1 2 3 H+ H 1 1 2 He + 5.5 MeV 3 3 4 1 2 He + He2 2 He + 2 H + 12.9 MeV 1
  • 25. Big Fusion Problem Number 1: Confinement of plasma Possibility 1 – inertial confinement: beams of laser light or ions compress a fuel pellet from all sides while heating it. Possibility 2 – magnetic confinement: using a magnetic field to cause plasma (charged gas particles) to circulate endlessly within a confined space. .
  • 26. Big Fusion Problem Number 2: Extracting energy Once a fusion reaction is initiated and confined, the energy must be extracted in order to be any use (and to stop the whole thing melting down). One possibility is to use a molten lithium blanket surrounding the fusion reaction to transfer the heat to a water based heat transport system.