You are using a standard microscope with a 0.18 NA 4× objective and switch to a 0.61 NA 40× objective. (Assume the microscope is immersed in air.) What are the acceptance angles for each (in degrees)? ? 0.18 NA 4× = _____ ° ? 0.61 NA 40× = _____° Solution The NA is related to the acceptance angle A, which indicates the size of a cone of light that can be accepted by the fibre. Both numerical aperture and acceptance angle are linked to the refractive index via: NA = n a Sin(A); where n a is refractive index of air (1.00); a) 0.81 = 1*Sin(A); A = 54.095 degrees. b) 0.61 =1*Sin(A); A = 37.589 degrees. .