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A contestant in a winter games event pushes a 41.0 kg block of ice across a frozen lake with a rope over his shoulder as shown in the figure. The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03. (a) Calculate the minimum force F (in N) he must exert to get the block moving. (b) What is its acceleration (in m/s2) once it starts to move, if that force is maintained? F\' 1 25Â° Solution a) Apply, Fnety = 0 N + F*sin(25) - m*g = 0 N = m*g - F*sin(25) Let F the minimum force he must exert to get the block moving so, F*cos(25) = fs_max = mue_s*N F*cos(25) = mue_s*(m*g - F*sin(25)) F*cos(25) = mue_s*m*g - mue_s*F*sin(25) F*(cos(25) + mue_s*sin(25)) = mue_s*m*g ==> F = mue_s*m*g/(cos(25) + mue_s*sin(25)) = 0.1*41*9.8/(cos(25) + 0.1*sin(25)) = 42.3 N <<<<<<<<------------------------------Answer b) let a is the accleration of the object. Normal force on the object, N = m*g - F*sin(25) = 41*9.8 - 42.3*sin(25) = 384 N Fnetx = F*cos(25) - fk m*a = F*cos(25) - mue_k*N a = (F*cos(25) - mue_k*N)/m = (42.3*cos(25) - 0.03*383)/41 = 0.655 m/s^2Â Â <<<<<<<<------------------------------Answer .

Bildung

b)
let a is the accleration of the object.
Normal force on the object,
N = m*g - F*sin(25)
= 41*9.8 - 42.3*sin(25)
= 384 N
Fnetx = F*cos(25) - fk
m*a = F*cos(25) - mue_k*N
a = (F*cos(25) - mue_k*N)/m
= (42.3*cos(25) - 0.03*383)/41
= 0.655 m/s^2Â Â <<<<<<<<------------------------------Answer

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