Determine the vertex of the graph of this quadratic function: f(x) = x2 + 4. Note: The vertex is the optimum point. It is the highest or lowest point of the function. a.(0, -4) b.(4,0) c.(0,4) d.(-4,0) Find the equation of a parabola that has a vertex at (-1,2) and whose graph passes through the point (2,11). a.y = - (x+1)^2 - 2 b.y = (x+1)^2 + 2 c.y = - (x+1)^2 + 2 d.y = (x+1)^2 + 1 Solution c) (0,4) b).y = (x+1)^2 + 2.